CodeModel.IsValidID(String) 方法
定义
重要
一些信息与预发行产品相关，相应产品在发行之前可能会进行重大修改。 对于此处提供的信息，Microsoft 不作任何明示或暗示的担保。
返回指定名称是否是对当前语言有效的编程标识符。
public:
bool IsValidID(System::String ^ Name);public:
bool IsValidID(Platform::String ^ Name);bool IsValidID(std::wstring const & Name);[System.Runtime.InteropServices.DispId(16)]
public bool IsValidID (string Name);[<System.Runtime.InteropServices.DispId(16)>]
abstract member IsValidID : string -> boolPublic Function IsValidID (Name As String) As Boolean参数
- Name
- String
必需。 要检查的标识符的名称。
返回
一个布尔值，指示 True 标识符何时有效; 如果不是，则为; 否则为 False 关键字。
在进行了某些类型的编辑之后，代码模型元素（例如类、结构、函数、特性、委托等）的值可能变为非确定性的，这意味着不能确定它们的值始终保持不变。 有关详细信息，请参阅 "代码模型元素值在 使用代码模型查找代码时 可能发生变化" (Visual Basic) "。
- 属性
示例
Sub IsValidIDExample(ByVal dte As DTE2)
' Before running this example, open a project.
Dim idents() As String = {"Sub", "class", "void", "var"}
Dim name, results As String
Dim proj As Project
For Each proj In dte.Solution
results &= "In " & proj.Name & ":" & vbCrLf & vbCrLf
' Validate the names in idents.
For Each name In idents
If proj.CodeModel.IsValidID(name) Then
results &= """" & name & """ is a valid identifier." _
& vbCrLf
Else
results &= """" & name & _
""" is not a valid identifier." & vbCrLf
End If
Next
results &= vbCrLf & vbCrLf
Next
MsgBox(results)
End Sub
public void IsValidIDExample(DTE2 dte)
{
// Before running this example, open a project.
string[] idents = {"Sub", "class", "void", "var"};
string results = "";
foreach (Project proj in dte.Solution)
{
results += "In " + proj.Name + ":" + Environment.NewLine +
Environment.NewLine;
// Validate the names in idents.
foreach (string name in idents)
{
if (proj.CodeModel.IsValidID(name))
results += "\"" + name + "\" is a valid identifier." +
Environment.NewLine;
else
results += "\"" + name +
"\" is not a valid identifier." +
Environment.NewLine;
}
results += Environment.NewLine + Environment.NewLine;
}
MessageBox.Show(results);
}