IJSVsaItems 接口

定义

警告

此 API 现已过时。

定义 IJSVsaItem 对象集合的接口,可通过名称或索引对其进行定位。Defines an interface for a collection of IJSVsaItem objects, which can be addressed either by name or by index.

public interface class IJSVsaItems : System::Collections::IEnumerable
[System.Obsolete("Use of this type is not recommended because it is being deprecated in Visual Studio 2005; there will be no replacement for this feature. Please see the ICodeCompiler documentation for additional help.")]
[System.Runtime.InteropServices.ComVisible(true)]
[System.Runtime.InteropServices.Guid("172341E0-9B0D-43E6-9EFF-75E030A46461")]
[System.Runtime.InteropServices.InterfaceType(System.Runtime.InteropServices.ComInterfaceType.InterfaceIsIUnknown)]
public interface IJSVsaItems : System.Collections.IEnumerable
type IJSVsaItems = interface
    interface IEnumerable
Public Interface IJSVsaItems
Implements IEnumerable
派生
属性
实现

属性

Count

获取指定集合的项数。Gets the number of items in the specified collection.

Item[Int32]

通过项的索引值从集合中获取项。Gets an item from the collection by its index value.

Item[String]

通过项的名称从集合中获取项。Gets an item from the collection by its name.

方法

CreateItem(String, JSVsaItemType, JSVsaItemFlag)

按照 JSVsaItemType 枚举中的定义,创建其中一个IJSVsaItem 类型的新实例。Creates a new instance of one of the IJSVsaItem types, as defined in the JSVsaItemType enumeration.

GetEnumerator()

返回循环访问集合的枚举数。Returns an enumerator that iterates through a collection.

(继承自 IEnumerable)
Remove(Int32)

从集合中移除按照项的索引值指定的项。Removes an item from the collection, as specified by its index value.

Remove(String)

从集合中移除按照项的名称指定的项。Removes an item from the collection, as specified by its name.

扩展方法

Cast<TResult>(IEnumerable)

IEnumerable 的元素强制转换为指定的类型。Casts the elements of an IEnumerable to the specified type.

OfType<TResult>(IEnumerable)

根据指定类型筛选 IEnumerable 的元素。Filters the elements of an IEnumerable based on a specified type.

AsParallel(IEnumerable)

启用查询的并行化。Enables parallelization of a query.

AsQueryable(IEnumerable)

IEnumerable 转换为 IQueryableConverts an IEnumerable to an IQueryable.

适用于