SumType<T1,T2,T3,T4>.Explicit 运算符

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定义

命名空间:

Microsoft.VisualStudio.LanguageServer.Protocol

程序集:

Microsoft.VisualStudio.LanguageServer.Protocol.dll

程序集:

重载

Explicit(SumType<T1,T2,T3,T4> to T4)	尝试将的实例转换 SumType<T1,T2,T3,T4> 为的实例 T4 。
Explicit(SumType<T1,T2,T3,T4> to T3)	尝试将的实例转换 SumType<T1,T2,T3,T4> 为的实例 T3 。
Explicit(SumType<T1,T2,T3,T4> to T2)	尝试将的实例转换 SumType<T1,T2,T3,T4> 为的实例 T2 。
Explicit(SumType<T1,T2,T3,T4> to T1)	尝试将的实例转换 SumType<T1,T2,T3,T4> 为的实例 T1 。
Explicit(SumType<T1,T2,T3,T4> to SumType<T1,T2>)
Explicit(SumType<T1,T2,T3,T4> to SumType<T1,T2,T3>)

Explicit(SumType<T1,T2,T3,T4> to T4)

尝试将的实例转换 SumType<T1,T2,T3,T4> 为的实例 T4 。

public:
 static explicit operator T4(Microsoft::VisualStudio::LanguageServer::Protocol::SumType<T1, T2, T3, T4> sum);

public static explicit operator T4 (Microsoft.VisualStudio.LanguageServer.Protocol.SumType<T1,T2,T3,T4> sum);

static member op_Explicit : Microsoft.VisualStudio.LanguageServer.Protocol.SumType<'T1, 'T2, 'T3, 'T4> -> 'T4

Public Shared Narrowing Operator CType (sum As SumType(Of T1, T2, T3, T4)) As T4

参数

sum

SumType<T1,T2,T3,T4>

要解包的实例。

返回

T4

例外

InvalidCastException

如果的此实例 SumType<T1,T2,T3,T4> 不包含的实例，则引发此异常 T4 。

Explicit(SumType<T1,T2,T3,T4> to T3)

尝试将的实例转换 SumType<T1,T2,T3,T4> 为的实例 T3 。

public:
 static explicit operator T3(Microsoft::VisualStudio::LanguageServer::Protocol::SumType<T1, T2, T3, T4> sum);

public static explicit operator T3 (Microsoft.VisualStudio.LanguageServer.Protocol.SumType<T1,T2,T3,T4> sum);

static member op_Explicit : Microsoft.VisualStudio.LanguageServer.Protocol.SumType<'T1, 'T2, 'T3, 'T4> -> 'T3

Public Shared Narrowing Operator CType (sum As SumType(Of T1, T2, T3, T4)) As T3

参数

sum

SumType<T1,T2,T3,T4>

要解包的实例。

返回

T3

例外

InvalidCastException

如果的此实例 SumType<T1,T2,T3,T4> 不包含的实例，则引发此异常 T3 。

Explicit(SumType<T1,T2,T3,T4> to T2)

尝试将的实例转换 SumType<T1,T2,T3,T4> 为的实例 T2 。

public:
 static explicit operator T2(Microsoft::VisualStudio::LanguageServer::Protocol::SumType<T1, T2, T3, T4> sum);

public static explicit operator T2 (Microsoft.VisualStudio.LanguageServer.Protocol.SumType<T1,T2,T3,T4> sum);

static member op_Explicit : Microsoft.VisualStudio.LanguageServer.Protocol.SumType<'T1, 'T2, 'T3, 'T4> -> 'T2

Public Shared Narrowing Operator CType (sum As SumType(Of T1, T2, T3, T4)) As T2

参数

sum

SumType<T1,T2,T3,T4>

要解包的实例。

返回

T2

例外

InvalidCastException

如果的此实例 SumType<T1,T2,T3,T4> 不包含的实例，则引发此异常 T2 。

Explicit(SumType<T1,T2,T3,T4> to T1)

尝试将的实例转换 SumType<T1,T2,T3,T4> 为的实例 T1 。

public:
 static explicit operator T1(Microsoft::VisualStudio::LanguageServer::Protocol::SumType<T1, T2, T3, T4> sum);

public static explicit operator T1 (Microsoft.VisualStudio.LanguageServer.Protocol.SumType<T1,T2,T3,T4> sum);

static member op_Explicit : Microsoft.VisualStudio.LanguageServer.Protocol.SumType<'T1, 'T2, 'T3, 'T4> -> 'T1

Public Shared Narrowing Operator CType (sum As SumType(Of T1, T2, T3, T4)) As T1

参数

sum

SumType<T1,T2,T3,T4>

要解包的实例。

返回

T1

例外

InvalidCastException

如果的此实例 SumType<T1,T2,T3,T4> 不包含的实例，则引发此异常 T1 。

Explicit(SumType<T1,T2,T3,T4> to SumType<T1,T2>)

public:
 static explicit operator Microsoft::VisualStudio::LanguageServer::Protocol::SumType<T1, T2>(Microsoft::VisualStudio::LanguageServer::Protocol::SumType<T1, T2, T3, T4> sum);

public static explicit operator Microsoft.VisualStudio.LanguageServer.Protocol.SumType<T1,T2> (Microsoft.VisualStudio.LanguageServer.Protocol.SumType<T1,T2,T3,T4> sum);

static member op_Explicit : Microsoft.VisualStudio.LanguageServer.Protocol.SumType<'T1, 'T2, 'T3, 'T4> -> Microsoft.VisualStudio.LanguageServer.Protocol.SumType<'T1, 'T2>

Public Shared Narrowing Operator CType (sum As SumType(Of T1, T2, T3, T4)) As SumType(Of T1, T2)

参数

sum

SumType<T1,T2,T3,T4>

返回

SumType<T1,T2>

Explicit(SumType<T1,T2,T3,T4> to SumType<T1,T2,T3>)

public:
 static explicit operator Microsoft::VisualStudio::LanguageServer::Protocol::SumType<T1, T2, T3>(Microsoft::VisualStudio::LanguageServer::Protocol::SumType<T1, T2, T3, T4> sum);

public static explicit operator Microsoft.VisualStudio.LanguageServer.Protocol.SumType<T1,T2,T3> (Microsoft.VisualStudio.LanguageServer.Protocol.SumType<T1,T2,T3,T4> sum);

static member op_Explicit : Microsoft.VisualStudio.LanguageServer.Protocol.SumType<'T1, 'T2, 'T3, 'T4> -> Microsoft.VisualStudio.LanguageServer.Protocol.SumType<'T1, 'T2, 'T3>

Public Shared Narrowing Operator CType (sum As SumType(Of T1, T2, T3, T4)) As SumType(Of T1, T2, T3)

参数

sum

SumType<T1,T2,T3,T4>

返回

SumType<T1,T2,T3>