CodeGenerationUtilities.GetBaseDomainClassXmlTagName 方法

定义

获取所提供域类的基类的 XmlTagName。

public:
 static System::String ^ GetBaseDomainClassXmlTagName(Microsoft::VisualStudio::Modeling::DslDefinition::DomainClass ^ domainClass, System::String ^ currentNamespace, System::Collections::Generic::Dictionary<Microsoft::VisualStudio::Modeling::DslDefinition::DslLibrary ^, System::String ^> ^ xmlNamespaceQualifiers);
public static string GetBaseDomainClassXmlTagName (Microsoft.VisualStudio.Modeling.DslDefinition.DomainClass domainClass, string currentNamespace, System.Collections.Generic.Dictionary<Microsoft.VisualStudio.Modeling.DslDefinition.DslLibrary,string> xmlNamespaceQualifiers);
static member GetBaseDomainClassXmlTagName : Microsoft.VisualStudio.Modeling.DslDefinition.DomainClass * string * System.Collections.Generic.Dictionary<Microsoft.VisualStudio.Modeling.DslDefinition.DslLibrary, string> -> string
Public Shared Function GetBaseDomainClassXmlTagName (domainClass As DomainClass, currentNamespace As String, xmlNamespaceQualifiers As Dictionary(Of DslLibrary, String)) As String

参数

domainClass
DomainClass

将返回其基类 XmlTagName 的 DomainClass。

currentNamespace
String
xmlNamespaceQualifiers
Dictionary<DslLibrary,String>

返回

String

给定 DomainClass 的 Xml 标记名称; 如果无法确定基类,则为 null。

适用于