DesignerHasDiagram.GetLink(Designer, Diagram) 方法

参考

定义

命名空间:: Microsoft.VisualStudio.Modeling.DslDefinition

程序集:: Microsoft.VisualStudio.Modeling.Sdk.DslDefinition.15.0.dll

重要

一些信息与预发行产品相关，相应产品在发行之前可能会进行重大修改。对于此处提供的信息，Microsoft 不作任何明示或暗示的担保。

获取给定 Designerand 之间的一个 DesignerHasDiagram 链接。

public:
 static Microsoft::VisualStudio::Modeling::DslDefinition::DesignerHasDiagram ^ GetLink(Microsoft::VisualStudio::Modeling::DslDefinition::Designer ^ source, Microsoft::VisualStudio::Modeling::DslDefinition::Diagram ^ target);

[System.Diagnostics.DebuggerStepThrough]
public static Microsoft.VisualStudio.Modeling.DslDefinition.DesignerHasDiagram GetLink (Microsoft.VisualStudio.Modeling.DslDefinition.Designer source, Microsoft.VisualStudio.Modeling.DslDefinition.Diagram target);

[<System.Diagnostics.DebuggerStepThrough>]
static member GetLink : Microsoft.VisualStudio.Modeling.DslDefinition.Designer * Microsoft.VisualStudio.Modeling.DslDefinition.Diagram -> Microsoft.VisualStudio.Modeling.DslDefinition.DesignerHasDiagram

Public Shared Function GetLink (source As Designer, target As Diagram) As DesignerHasDiagram

参数

source: Designer

target: Diagram

返回

DesignerHasDiagram

属性: DebuggerStepThroughAttribute

适用于