ConfigurationHelperService.GetUserConfigurationPath 方法
定义
重要
一些信息与预发行产品相关,相应产品在发行之前可能会进行重大修改。 对于此处提供的信息,Microsoft 不作任何明示或暗示的担保。
基于不同项目属性的值获取当前项目的最可能的用户配置文件路径。
public:
System::String ^ GetUserConfigurationPath(IServiceProvider ^ provider, EnvDTE::Project ^ project, System::Configuration::ConfigurationUserLevel userLevel, bool underHostingProcess, EnvDTE::Configuration ^ buildConfiguration);
public string GetUserConfigurationPath (IServiceProvider provider, EnvDTE.Project project, System.Configuration.ConfigurationUserLevel userLevel, bool underHostingProcess, EnvDTE.Configuration buildConfiguration);
member this.GetUserConfigurationPath : IServiceProvider * EnvDTE.Project * System.Configuration.ConfigurationUserLevel * bool * EnvDTE.Configuration -> string
Public Function GetUserConfigurationPath (provider As IServiceProvider, project As Project, userLevel As ConfigurationUserLevel, underHostingProcess As Boolean, buildConfiguration As Configuration) As String
参数
- provider
- IServiceProvider
- userLevel
- ConfigurationUserLevel
- underHostingProcess
- Boolean
true 如果在托管进程中,则为; 否则为 false 。
- buildConfiguration
- Configuration
EnvDTE.BuildConfiguration.
返回
用户配置路径,或者, null 如果无法从项目中的信息构造有效路径,则为。