IActionBlockService.SendAsync(Func<Task>) 方法

定义

将操作块发布到工作区

public:
 System::Threading::Tasks::Task ^ SendAsync(Func<System::Threading::Tasks::Task ^> ^ action);
public System.Threading.Tasks.Task SendAsync (Func<System.Threading.Tasks.Task> action);
abstract member SendAsync : Func<System.Threading.Tasks.Task> -> System.Threading.Tasks.Task
Public Function SendAsync (action As Func(Of Task)) As Task

参数

action
Func<Task>

要在我们的服务中执行的回调

返回

Task

发布操作时的完成任务

适用于