OutArgument<T>.FromExpression(Activity<Location<T>>) 方法

定义

初始化和返回使用指定的 OutArgument<T> 构造的新 Activity<TResult>Initializes and returns a new OutArgument<T> constructed using the specified Activity<TResult>.

public:
 static System::Activities::OutArgument<T> ^ FromExpression(System::Activities::Activity<System::Activities::Location<T> ^> ^ expression);
public static System.Activities.OutArgument<T> FromExpression (System.Activities.Activity<System.Activities.Location<T>> expression);
static member FromExpression : System.Activities.Activity<System.Activities.Location<'T>> -> System.Activities.OutArgument<'T>
Public Shared Function FromExpression (expression As Activity(Of Location(Of T))) As OutArgument(Of T)

参数

expression
Activity<Location<T>>

参数的值。The value of the argument,

返回

OutArgument<T>

新自变量。The new argument.

适用于