Double.IsPositiveInfinity(Double) Double.IsPositiveInfinity(Double) Double.IsPositiveInfinity(Double) Double.IsPositiveInfinity(Double) Method

定义

返回一个值,通过该值指示指定数字是否计算为正无穷大。Returns a value indicating whether the specified number evaluates to positive infinity.

public:
 static bool IsPositiveInfinity(double d);
public static bool IsPositiveInfinity (double d);
static member IsPositiveInfinity : double -> bool
Public Shared Function IsPositiveInfinity (d As Double) As Boolean

参数

d
Double Double Double Double

一个双精度浮点数。A double-precision floating-point number.

返回

如果 d 的计算结果为 PositiveInfinity,则为 true;否则为 falsetrue if d evaluates to PositiveInfinity; otherwise, false.

示例

下面的代码示例阐释了的IsPositiveInfinity用法:The following code example illustrates the use of IsPositiveInfinity:

// This will return S"true".
Console::WriteLine( "IsPositiveInfinity(4.0 / 0) == {0}.", Double::IsPositiveInfinity( 4.0 / zero ) ? (String^)"true" : "false" );
// This will return "true".
Console.WriteLine("IsPositiveInfinity(4.0 / 0) == {0}.", Double.IsPositiveInfinity(4.0 / 0) ? "true" : "false");
' This will return "True".
Console.Write("IsPositiveInfinity(4.0 / 0) = ")
If Double.IsPositiveInfinity(4 / 0) Then
    Console.WriteLine("True.")
Else
    Console.WriteLine("False.")
End If

注解

浮点运算返回PositiveInfinity信号表示溢出情况。Floating-point operations return PositiveInfinity to signal an overflow condition.

适用于

另请参阅