Path.TryJoin 方法
定义
尝试将各个路径组件连接到预分配的字符范围,并返回一个值指示操作是否成功。Attempts to concatenate individual path components to a preallocated character span, and returns a value that indicates whether the operation succeeded.
重载
TryJoin(ReadOnlySpan<Char>, ReadOnlySpan<Char>, ReadOnlySpan<Char>, Span<Char>, Int32) |
尝试将两个路径组件连接到一个预分配的字符范围,并返回一个值,该值指示操作是否成功。Attempts to concatenate two path components to a single preallocated character span, and returns a value that indicates whether the operation succeeded. |
TryJoin(ReadOnlySpan<Char>, ReadOnlySpan<Char>, Span<Char>, Int32) |
尝试将两个路径组件连接到一个预分配的字符范围,并返回一个值,该值指示操作是否成功。Attempts to concatenate two path components to a single preallocated character span, and returns a value that indicates whether the operation succeeded. |
注解
目标字符跨度必须足够大才能容纳连接的路径。The destination character span must be large enough to hold the concatenated path. 然后,可以通过调用方法来检索串联路径 Span<T>.Slice ,如下面的示例所示。You can then retrieve the concatenated path by calling the Span<T>.Slice method, as the following example illustrates.
using System;
using System.IO;
class Program
{
static void Main()
{
int nChars = 0;
var buffer = new Span<Char>(new String(' ', 100).ToCharArray());
var flag = Path.TryJoin("C:/".AsSpan(), "Users/user1".AsSpan(), buffer, out nChars);
if (flag)
Console.WriteLine($"Wrote {nChars} characters: '{buffer.Slice(0, nChars).ToString()}'");
else
Console.WriteLine("Concatenation operation failed.");
}
}
TryJoin(ReadOnlySpan<Char>, ReadOnlySpan<Char>, ReadOnlySpan<Char>, Span<Char>, Int32)
尝试将两个路径组件连接到一个预分配的字符范围,并返回一个值,该值指示操作是否成功。Attempts to concatenate two path components to a single preallocated character span, and returns a value that indicates whether the operation succeeded.
public:
static bool TryJoin(ReadOnlySpan<char> path1, ReadOnlySpan<char> path2, ReadOnlySpan<char> path3, Span<char> destination, [Runtime::InteropServices::Out] int % charsWritten);
public static bool TryJoin (ReadOnlySpan<char> path1, ReadOnlySpan<char> path2, ReadOnlySpan<char> path3, Span<char> destination, out int charsWritten);
static member TryJoin : ReadOnlySpan<char> * ReadOnlySpan<char> * ReadOnlySpan<char> * Span<char> * int -> bool
Public Shared Function TryJoin (path1 As ReadOnlySpan(Of Char), path2 As ReadOnlySpan(Of Char), path3 As ReadOnlySpan(Of Char), destination As Span(Of Char), ByRef charsWritten As Integer) As Boolean
参数
- path1
- ReadOnlySpan<Char>
包含要加入的第一个路径的字符范围。A character span that contains the first path to join.
- path2
- ReadOnlySpan<Char>
包含要加入的第二个路径的字符范围。A character span that contains the second path to join.
- path3
- ReadOnlySpan<Char>
包含要加入的第三个路径的字符范围。A character span that contains the third path to join.
- charsWritten
- Int32
方法返回时,为一个指示写入 destination
的字符数的值。When the method returns, a value that indicates the number of characters written to the destination
.
返回
如果此串联运算成功,则为 true
;否则为 false
。true
if the concatenation operation is successful; otherwise, false
.
注解
destination
必须足够大才能容纳连接的路径。destination
must be large enough to hold the concatenated path. 然后,可以通过调用方法来检索串联路径 Span<T>.Slice ,如示例所示。You can then retrieve the concatenated path by calling the Span<T>.Slice method, as the example illustrates.
另请参阅
适用于
TryJoin(ReadOnlySpan<Char>, ReadOnlySpan<Char>, Span<Char>, Int32)
尝试将两个路径组件连接到一个预分配的字符范围,并返回一个值,该值指示操作是否成功。Attempts to concatenate two path components to a single preallocated character span, and returns a value that indicates whether the operation succeeded.
public:
static bool TryJoin(ReadOnlySpan<char> path1, ReadOnlySpan<char> path2, Span<char> destination, [Runtime::InteropServices::Out] int % charsWritten);
public static bool TryJoin (ReadOnlySpan<char> path1, ReadOnlySpan<char> path2, Span<char> destination, out int charsWritten);
static member TryJoin : ReadOnlySpan<char> * ReadOnlySpan<char> * Span<char> * int -> bool
Public Shared Function TryJoin (path1 As ReadOnlySpan(Of Char), path2 As ReadOnlySpan(Of Char), destination As Span(Of Char), ByRef charsWritten As Integer) As Boolean
参数
- path1
- ReadOnlySpan<Char>
包含要加入的第一个路径的字符范围。A character span that contains the first path to join.
- path2
- ReadOnlySpan<Char>
包含要加入的第二个路径的字符范围。A character span that contains the second path to join.
- charsWritten
- Int32
方法返回时,为一个指示写入 destination
的字符数的值。When the method returns, a value that indicates the number of characters written to the destination
.
返回
如果此串联运算成功,则为 true
;否则为 false
。true
if the concatenation operation is successful; otherwise, false
.
注解
destination
必须足够大才能容纳连接的路径。destination
must be large enough to hold the concatenated path. 然后,可以通过调用方法来检索串联路径 Span<T>.Slice ,如示例所示。You can then retrieve the concatenated path by calling the Span<T>.Slice method, as the example illustrates.