NetworkInformationPermission.Intersect(IPermission) 方法

定义

命名空间:

System.Net.NetworkInformation

程序集:

System.Security.Permissions.dll

包:

System.Security.Permissions v8.0.0

Source:

NetworkInformationPermission.cs

创建并返回一个权限，该权限是当前权限与指定权限的交集。

public:
 override System::Security::IPermission ^ Intersect(System::Security::IPermission ^ target);

public override System.Security.IPermission Intersect (System.Security.IPermission target);

override this.Intersect : System.Security.IPermission -> System.Security.IPermission

Public Overrides Function Intersect (target As IPermission) As IPermission

参数

target

IPermission

与当前权限相交的 IPermission。 它必须与当前权限属于同一类型。

返回

IPermission

NetworkInformationPermission，表示当前权限与指定权限的交集。 如果交集为空或 target 为 null，则此新权限为 null。

例外

ArgumentException

target 不是 NetworkInformationPermission。

示例

以下示例创建一个权限对象，该对象是现有权限对象的交集。

System::Net::NetworkInformation::NetworkInformationPermission^ unrestricted = gcnew System::Net::NetworkInformation::NetworkInformationPermission( System::Security::Permissions::PermissionState::Unrestricted );

Console::WriteLine( L"Is unrestricted? {0}", unrestricted->IsUnrestricted() );

System::Net::NetworkInformation::NetworkInformationPermission^ read = gcnew System::Net::NetworkInformation::NetworkInformationPermission( System::Net::NetworkInformation::NetworkInformationAccess::Read );

System::Net::NetworkInformation::NetworkInformationPermission^ copyPermission = dynamic_cast<System::Net::NetworkInformation::NetworkInformationPermission^>(read->Copy());

System::Net::NetworkInformation::NetworkInformationPermission^ unionPermission = dynamic_cast<System::Net::NetworkInformation::NetworkInformationPermission^>(read->Union( unrestricted ));
Console::WriteLine( L"Is subset?{0}", read->IsSubsetOf( unionPermission ) );

System::Net::NetworkInformation::NetworkInformationPermission^ intersectPermission = dynamic_cast<System::Net::NetworkInformation::NetworkInformationPermission^>(read->Intersect( unrestricted ));

System.Net.NetworkInformation.NetworkInformationPermission unrestricted =
    new System.Net.NetworkInformation.NetworkInformationPermission(
        System.Security.Permissions.PermissionState.Unrestricted);

Console.WriteLine("Is unrestricted? " + unrestricted.IsUnrestricted());

System.Net.NetworkInformation.NetworkInformationPermission read =
    new System.Net.NetworkInformation.NetworkInformationPermission(
        System.Net.NetworkInformation.NetworkInformationAccess.Read);
System.Net.NetworkInformation.NetworkInformationPermission copyPermission =
   (System.Net.NetworkInformation.NetworkInformationPermission) read.Copy();
System.Net.NetworkInformation.NetworkInformationPermission unionPermission =
   (System.Net.NetworkInformation.NetworkInformationPermission) read.Union(unrestricted);
Console.WriteLine("Is subset?" + read.IsSubsetOf(unionPermission));
System.Net.NetworkInformation.NetworkInformationPermission intersectPermission =
   (System.Net.NetworkInformation.NetworkInformationPermission) read.Intersect(unrestricted);

Dim unrestricted As New System.Net.NetworkInformation.NetworkInformationPermission( _
    System.Security.Permissions.PermissionState.Unrestricted)
Console.WriteLine("Is unrestricted? " + unrestricted.IsUnrestricted().ToString())
Dim read As New System.Net.NetworkInformation.NetworkInformationPermission( _ 
    System.Net.NetworkInformation.NetworkInformationAccess.Read)
Dim copyPermission As System.Net.NetworkInformation.NetworkInformationPermission = _
    CType(read.Copy(), System.Net.NetworkInformation.NetworkInformationPermission)
Dim unionPermission As System.Net.NetworkInformation.NetworkInformationPermission = _
    CType(read.Union(unrestricted), System.Net.NetworkInformation.NetworkInformationPermission)
Console.WriteLine("Is subset?" + read.IsSubsetOf(unionPermission).ToString())
Dim intersectPermission As System.Net.NetworkInformation.NetworkInformationPermission = _ 
    CType(read.Intersect(unrestricted), _ 
          System.Net.NetworkInformation.NetworkInformationPermission)

注解

两个权限的交集是描述它们共同描述的状态的权限。 只有传递两个原始权限的要求才会通过交集。