Complex.Cos(Complex) 方法

定义

返回指定复数的余弦值。

public:
 static System::Numerics::Complex Cos(System::Numerics::Complex value);
public static System.Numerics.Complex Cos (System.Numerics.Complex value);
static member Cos : System.Numerics.Complex -> System.Numerics.Complex
Public Shared Function Cos (value As Complex) As Complex

参数

value
Complex

一个复数。

返回

value 的余弦值。

示例

下面的示例演示 Acos 了 方法。 它表明,将 方法返回 Acos 的值传递给 Cos 方法将返回原始 Complex 值。

using System;
using System.Numerics;

public class Example
{
   public static void Main()
   {
      Complex[] values = { new Complex(.5, 2),
                           new Complex(.5, -2),
                           new Complex(-.5, 2),
                           new Complex(-.3, -.8) };
      foreach (Complex value in values)
         Console.WriteLine("Cos(ACos({0})) = {1}", value,
                           Complex.Cos(Complex.Acos(value)));
   }
}
// The example displays the following output:
//       Cos(ACos((0.5, 2))) = (0.5, 2)
//       Cos(ACos((0.5, -2))) = (0.5, -2)
//       Cos(ACos((-0.5, 2))) = (-0.5, 2)
//       Cos(ACos((-0.3, -0.8))) = (-0.3, -0.8)
Imports System.Numerics

Module Example
   Public Sub Main()
      Dim values() As Complex = { New Complex(.5, 2), 
                                  New Complex(.5, -2),
                                  New Complex(-.5, 2),
                                  New Complex(-.3, -.8) }
      For Each value As Complex In values
         Console.WriteLine("Cos(ACos({0})) = {1}", value, 
                           Complex.Cos(Complex.Acos(value)))
      Next
   End Sub
End Module
' The example displays the following output:
'       Cos(ACos((0.5, 2))) = (0.5, 2)
'       Cos(ACos((0.5, -2))) = (0.5, -2)
'       Cos(ACos((-0.5, 2))) = (-0.5, 2)
'       Cos(ACos((-0.3, -0.8))) = (-0.3, -0.8)

注解

Cos复数的 方法对应于Math.Cos实数的 方法。

方法 Cos 使用以下公式计算复数 a + bi 的余弦值:

(Cos () * Cosh (b) , - (Sin () * Sinh (b) ) )

适用于

另请参阅