Random Class
Definition
表示伪随机数生成器，这是一种能够产生满足某些随机性统计要求的数字序列的算法。Represents a pseudo-random number generator, which is an algorithm that produces a sequence of numbers that meet certain statistical requirements for randomness.
public ref class Randompublic class Random[System.Serializable]
public class Random[System.Runtime.InteropServices.ComVisible(true)]
[System.Serializable]
public class Randomtype Random = classPublic Class Random- Inheritance
-
Random
- Attributes
Examples
下面的示例创建一个随机数生成器，并调用它的 NextBytes、Next和 NextDouble 方法，以生成不同范围内的随机数序列。The following example creates a single random number generator and calls its NextBytes, Next, and NextDouble methods to generate sequences of random numbers within different ranges.
using namespace System;
void main()
{
// Instantiate random number generator using system-supplied value as seed.
Random^ rand = gcnew Random();
// Generate and display 5 random byte (integer) values.
array<Byte>^ bytes = gcnew array<Byte>(4);
rand->NextBytes(bytes);
Console::WriteLine("Five random byte values:");
for each (Byte byteValue in bytes)
Console::Write("{0, 5}", byteValue);
Console::WriteLine();
// Generate and display 5 random integers.
Console::WriteLine("Five random integer values:");
for (int ctr = 0; ctr <= 4; ctr++)
Console::Write("{0,15:N0}", rand->Next());
Console::WriteLine();
// Generate and display 5 random integers between 0 and 100.//
Console::WriteLine("Five random integers between 0 and 100:");
for (int ctr = 0; ctr <= 4; ctr++)
Console::Write("{0,8:N0}", rand->Next(101));
Console::WriteLine();
// Generate and display 5 random integers from 50 to 100.
Console::WriteLine("Five random integers between 50 and 100:");
for (int ctr = 0; ctr <= 4; ctr++)
Console::Write("{0,8:N0}", rand->Next(50, 101));
Console::WriteLine();
// Generate and display 5 random floating point values from 0 to 1.
Console::WriteLine("Five Doubles.");
for (int ctr = 0; ctr <= 4; ctr++)
Console::Write("{0,8:N3}", rand->NextDouble());
Console::WriteLine();
// Generate and display 5 random floating point values from 0 to 5.
Console::WriteLine("Five Doubles between 0 and 5.");
for (int ctr = 0; ctr <= 4; ctr++)
Console::Write("{0,8:N3}", rand->NextDouble() * 5);
}
// The example displays output like the following:
// Five random byte values:
// 194 185 239 54 116
// Five random integer values:
// 507,353,531 1,509,532,693 2,125,074,958 1,409,512,757 652,767,128
// Five random integers between 0 and 100:
// 16 78 94 79 52
// Five random integers between 50 and 100:
// 56 66 96 60 65
// Five Doubles.
// 0.943 0.108 0.744 0.563 0.415
// Five Doubles between 0 and 5.
// 2.934 3.130 0.292 1.432 4.369
// Instantiate random number generator using system-supplied value as seed.
var rand = new Random();
// Generate and display 5 random byte (integer) values.
var bytes = new byte[5];
rand.NextBytes(bytes);
Console.WriteLine("Five random byte values:");
foreach (byte byteValue in bytes)
Console.Write("{0, 5}", byteValue);
Console.WriteLine();
// Generate and display 5 random integers.
Console.WriteLine("Five random integer values:");
for (int ctr = 0; ctr <= 4; ctr++)
Console.Write("{0,15:N0}", rand.Next());
Console.WriteLine();
// Generate and display 5 random integers between 0 and 100.
Console.WriteLine("Five random integers between 0 and 100:");
for (int ctr = 0; ctr <= 4; ctr++)
Console.Write("{0,8:N0}", rand.Next(101));
Console.WriteLine();
// Generate and display 5 random integers from 50 to 100.
Console.WriteLine("Five random integers between 50 and 100:");
for (int ctr = 0; ctr <= 4; ctr++)
Console.Write("{0,8:N0}", rand.Next(50, 101));
Console.WriteLine();
// Generate and display 5 random floating point values from 0 to 1.
Console.WriteLine("Five Doubles.");
for (int ctr = 0; ctr <= 4; ctr++)
Console.Write("{0,8:N3}", rand.NextDouble());
Console.WriteLine();
// Generate and display 5 random floating point values from 0 to 5.
Console.WriteLine("Five Doubles between 0 and 5.");
for (int ctr = 0; ctr <= 4; ctr++)
Console.Write("{0,8:N3}", rand.NextDouble() * 5);
// The example displays output like the following:
// Five random byte values:
// 194 185 239 54 116
// Five random integer values:
// 507,353,531 1,509,532,693 2,125,074,958 1,409,512,757 652,767,128
// Five random integers between 0 and 100:
// 16 78 94 79 52
// Five random integers between 50 and 100:
// 56 66 96 60 65
// Five Doubles.
// 0.943 0.108 0.744 0.563 0.415
// Five Doubles between 0 and 5.
// 2.934 3.130 0.292 1.432 4.369
Module Example
Public Sub Main()
' Instantiate random number generator using system-supplied value as seed.
Dim rand As New Random()
' Generate and display 5 random byte (integer) values.
Dim bytes(4) As Byte
rand.NextBytes(bytes)
Console.WriteLine("Five random byte values:")
For Each byteValue As Byte In bytes
Console.Write("{0, 5}", byteValue)
Next
Console.WriteLine()
' Generate and display 5 random integers.
Console.WriteLine("Five random integer values:")
For ctr As Integer = 0 To 4
Console.Write("{0,15:N0}", rand.Next)
Next
Console.WriteLine()
' Generate and display 5 random integers between 0 and 100.'
Console.WriteLine("Five random integers between 0 and 100:")
For ctr As Integer = 0 To 4
Console.Write("{0,8:N0}", rand.Next(101))
Next
Console.WriteLine()
' Generate and display 5 random integers from 50 to 100.
Console.WriteLine("Five random integers between 50 and 100:")
For ctr As Integer = 0 To 4
Console.Write("{0,8:N0}", rand.Next(50, 101))
Next
Console.WriteLine()
' Generate and display 5 random floating point values from 0 to 1.
Console.WriteLine("Five Doubles.")
For ctr As Integer = 0 To 4
Console.Write("{0,8:N3}", rand.NextDouble())
Next
Console.WriteLine()
' Generate and display 5 random floating point values from 0 to 5.
Console.WriteLine("Five Doubles between 0 and 5.")
For ctr As Integer = 0 To 4
Console.Write("{0,8:N3}", rand.NextDouble() * 5)
Next
End Sub
End Module
' The example displays output like the following:
' Five random byte values:
' 194 185 239 54 116
' Five random integer values:
' 507,353,531 1,509,532,693 2,125,074,958 1,409,512,757 652,767,128
' Five random integers between 0 and 100:
' 16 78 94 79 52
' Five random integers between 50 and 100:
' 56 66 96 60 65
' Five Doubles.
' 0.943 0.108 0.744 0.563 0.415
' Five Doubles between 0 and 5.
' 2.934 3.130 0.292 1.432 4.369
下面的示例生成一个随机整数，该整数将用作索引以检索数组中的字符串值。The following example generates a random integer that it uses as an index to retrieve a string value from an array.
using namespace System;
void main()
{
Random^ rnd = gcnew Random();
array<String^>^ malePetNames = { "Rufus", "Bear", "Dakota", "Fido",
"Vanya", "Samuel", "Koani", "Volodya",
"Prince", "Yiska" };
array<String^>^ femalePetNames = { "Maggie", "Penny", "Saya", "Princess",
"Abby", "Laila", "Sadie", "Olivia",
"Starlight", "Talla" };
// Generate random indexes for pet names.
int mIndex = rnd->Next(malePetNames->Length);
int fIndex = rnd->Next(femalePetNames->Length);
// Display the result.
Console::WriteLine("Suggested pet name of the day: ");
Console::WriteLine(" For a male: {0}", malePetNames[mIndex]);
Console::WriteLine(" For a female: {0}", femalePetNames[fIndex]);
}
// The example displays output similar to the following:
// Suggested pet name of the day:
// For a male: Koani
// For a female: Maggie
Random rnd = new Random();
string[] malePetNames = { "Rufus", "Bear", "Dakota", "Fido",
"Vanya", "Samuel", "Koani", "Volodya",
"Prince", "Yiska" };
string[] femalePetNames = { "Maggie", "Penny", "Saya", "Princess",
"Abby", "Laila", "Sadie", "Olivia",
"Starlight", "Talla" };
// Generate random indexes for pet names.
int mIndex = rnd.Next(malePetNames.Length);
int fIndex = rnd.Next(femalePetNames.Length);
// Display the result.
Console.WriteLine("Suggested pet name of the day: ");
Console.WriteLine(" For a male: {0}", malePetNames[mIndex]);
Console.WriteLine(" For a female: {0}", femalePetNames[fIndex]);
// The example displays output similar to the following:
// Suggested pet name of the day:
// For a male: Koani
// For a female: Maggie
Module Example
Public Sub Main()
Dim rnd As New Random()
Dim malePetNames() As String = { "Rufus", "Bear", "Dakota", "Fido",
"Vanya", "Samuel", "Koani", "Volodya",
"Prince", "Yiska" }
Dim femalePetNames() As String = { "Maggie", "Penny", "Saya", "Princess",
"Abby", "Laila", "Sadie", "Olivia",
"Starlight", "Talla" }
' Generate random indexes for pet names.
Dim mIndex As Integer = rnd.Next(malePetNames.Length)
Dim fIndex As Integer = rnd.Next(femalePetNames.Length)
' Display the result.
Console.WriteLine("Suggested pet name of the day: ")
Console.WriteLine(" For a male: {0}", malePetNames(mIndex))
Console.WriteLine(" For a female: {0}", femalePetNames(fIndex))
End Sub
End Module
' The example displays output similar to the following:
' Suggested pet name of the day:
' For a male: Koani
' For a female: Maggie
Remarks
伪随机数的选择与有限的一组数字相同。Pseudo-random numbers are chosen with equal probability from a finite set of numbers. 选择的数字不是完全随机的，因为使用数学算法来选择它们，但它们在实际情况下是完全随机的。The chosen numbers are not completely random because a mathematical algorithm is used to select them, but they are sufficiently random for practical purposes. Random 类的当前实现基于 Donald Knuth 的 subtractive 随机数生成器算法的修改版本。The current implementation of the Random class is based on a modified version of Donald E. Knuth's subtractive random number generator algorithm. 有关详细信息，请参阅 d。For more information, see D. E. Knuth.Knuth. 计算机编程（卷2： Seminumerical 算法）的艺术。The Art of Computer Programming, Volume 2: Seminumerical Algorithms. Addison-Wesley，读取，MA，第三版，1997。Addison-Wesley, Reading, MA, third edition, 1997.
若要生成加密的安全随机数（如适合创建随机密码的随机数），请使用 RNGCryptoServiceProvider 类或从 System.Security.Cryptography.RandomNumberGenerator派生类。To generate a cryptographically secure random number, such as one that's suitable for creating a random password, use the RNGCryptoServiceProvider class or derive a class from System.Security.Cryptography.RandomNumberGenerator.
本主题内容：In this topic:
实例化随机数生成器 Instantiating the random number generator
避免多个实例化 Avoiding multiple instantiations
System.web 类和 thread 安全网 The System.Random class and thread safety
生成不同类型的随机数 Generating different types of random numbers
替换自己的算法 Substituting your own algorithm
如何使用 "系统随机..." How do you use System.Random to…
检索相同的随机值序列Retrieve the same sequence of random values
检索随机值的唯一序列Retrieve unique sequences of random values
检索指定范围内的整数Retrieve integers in a specified range
检索指定位数的整数Retrieve integers with a specified number of digits
检索指定范围内的浮点值Retrieve floating-point values in a specified range
生成随机布尔值Generate random Boolean values
生成随机的64位整数Generate random 64-bit integers
检索指定范围内的字节Retrieve bytes in a specified range
随机检索数组或集合中的元素Retrieve an element from an array or collection at random
从数组或集合中检索唯一元素Retrieve a unique element from an array or collection
实例化随机数生成器Instantiating the random number generator
通过向 Random 类构造函数提供种子值（伪随机数生成算法的起始值）来实例化随机数生成器。You instantiate the random number generator by providing a seed value (a starting value for the pseudo-random number generation algorithm) to a Random class constructor. 可以显式或隐式提供种子值：You can supply the seed value either explicitly or implicitly:
Random(Int32) 构造函数使用您提供的显式种子值。The Random(Int32) constructor uses an explicit seed value that you supply.
Random() 构造函数使用默认种子值。The Random() constructor uses the default seed value. 这是实例化随机数生成器最常见的方法。This is the most common way of instantiating the random number generator.
在 .NET Framework 中，默认种子值取决于时间。In .NET Framework, the default seed value is time-dependent. 在 .NET Core 中，默认种子值由线程静态伪随机数生成器生成。In .NET Core, the default seed value is produced by the thread-static, pseudo-random number generator.
如果对单独的 Random 对象使用相同的种子，则它们将生成相同的随机数字序列。If the same seed is used for separate Random objects, they will generate the same series of random numbers. 这对于创建处理随机值的测试套件或用于重放从随机数派生其数据的游戏很有用。This can be useful for creating a test suite that processes random values, or for replaying games that derive their data from random numbers. 但请注意，在不同版本的 .NET Framework 下运行的进程中的 Random 对象可能会返回不同的随机数字序列，即使它们是用相同的种子值实例化的，也是如此。However, note that Random objects in processes running under different versions of the .NET Framework may return different series of random numbers even if they're instantiated with identical seed values.
若要生成不同的随机数序列，可以使种子值依赖于时间，从而使用 Random的每个新实例生成不同的序列。To produce different sequences of random numbers, you can make the seed value time-dependent, thereby producing a different series with each new instance of Random. 参数化 Random(Int32) 构造函数可以根据当前时间中的计时周期数来获取 Int32 值，而无参数 Random() 构造函数使用系统时钟生成其种子值。The parameterized Random(Int32) constructor can take an Int32 value based on the number of ticks in the current time, whereas the parameterless Random() constructor uses the system clock to generate its seed value. 但是，仅在 .NET Framework 上，由于时钟具有有限的分辨率，因此使用无参数构造函数在 close 中创建不同的 Random 对象会创建随机数字生成器，它们生成相同的随机数序列。However, on the .NET Framework only, because the clock has finite resolution, using the parameterless constructor to create different Random objects in close succession creates random number generators that produce identical sequences of random numbers. 下面的示例演示了在 .NET Framework 应用程序中连续实例化的两个 Random 对象如何生成相同系列的随机数。The following example illustrates how two Random objects that are instantiated in close succession in a .NET Framework application generate an identical series of random numbers. 在大多数 Windows 系统上，Random 在15毫秒内创建的对象可能具有相同的种子值。On most Windows systems, Random objects created within 15 milliseconds of one another are likely to have identical seed values.
using namespace System;
void main()
{
array<Byte>^ bytes1 = gcnew array<Byte>(100);
array<Byte>^ bytes2 = gcnew array<Byte>(100);
Random^ rnd1 = gcnew Random();
Random^ rnd2 = gcnew Random();
rnd1->NextBytes(bytes1);
rnd2->NextBytes(bytes2);
Console::WriteLine("First Series:");
for (int ctr = bytes1->GetLowerBound(0);
ctr <= bytes1->GetUpperBound(0);
ctr++) {
Console::Write("{0, 5}", bytes1[ctr]);
if ((ctr + 1) % 10 == 0) Console::WriteLine();
}
Console::WriteLine();
Console::WriteLine("Second Series:");
for (int ctr = bytes2->GetLowerBound(0);
ctr <= bytes2->GetUpperBound(0);
ctr++) {
Console::Write("{0, 5}", bytes2[ctr]);
if ((ctr + 1) % 10 == 0) Console::WriteLine();
}
}
// The example displays output like the following:
// First Series:
// 97 129 149 54 22 208 120 105 68 177
// 113 214 30 172 74 218 116 230 89 18
// 12 112 130 105 116 180 190 200 187 120
// 7 198 233 158 58 51 50 170 98 23
// 21 1 113 74 146 245 34 255 96 24
// 232 255 23 9 167 240 255 44 194 98
// 18 175 173 204 169 171 236 127 114 23
// 167 202 132 65 253 11 254 56 214 127
// 145 191 104 163 143 7 174 224 247 73
// 52 6 231 255 5 101 83 165 160 231
//
// Second Series:
// 97 129 149 54 22 208 120 105 68 177
// 113 214 30 172 74 218 116 230 89 18
// 12 112 130 105 116 180 190 200 187 120
// 7 198 233 158 58 51 50 170 98 23
// 21 1 113 74 146 245 34 255 96 24
// 232 255 23 9 167 240 255 44 194 98
// 18 175 173 204 169 171 236 127 114 23
// 167 202 132 65 253 11 254 56 214 127
// 145 191 104 163 143 7 174 224 247 73
// 52 6 231 255 5 101 83 165 160 231
byte[] bytes1 = new byte[100];
byte[] bytes2 = new byte[100];
Random rnd1 = new Random();
Random rnd2 = new Random();
rnd1.NextBytes(bytes1);
rnd2.NextBytes(bytes2);
Console.WriteLine("First Series:");
for (int ctr = bytes1.GetLowerBound(0);
ctr <= bytes1.GetUpperBound(0);
ctr++) {
Console.Write("{0, 5}", bytes1[ctr]);
if ((ctr + 1) % 10 == 0) Console.WriteLine();
}
Console.WriteLine();
Console.WriteLine("Second Series:");
for (int ctr = bytes2.GetLowerBound(0);
ctr <= bytes2.GetUpperBound(0);
ctr++) {
Console.Write("{0, 5}", bytes2[ctr]);
if ((ctr + 1) % 10 == 0) Console.WriteLine();
}
// The example displays output like the following:
// First Series:
// 97 129 149 54 22 208 120 105 68 177
// 113 214 30 172 74 218 116 230 89 18
// 12 112 130 105 116 180 190 200 187 120
// 7 198 233 158 58 51 50 170 98 23
// 21 1 113 74 146 245 34 255 96 24
// 232 255 23 9 167 240 255 44 194 98
// 18 175 173 204 169 171 236 127 114 23
// 167 202 132 65 253 11 254 56 214 127
// 145 191 104 163 143 7 174 224 247 73
// 52 6 231 255 5 101 83 165 160 231
//
// Second Series:
// 97 129 149 54 22 208 120 105 68 177
// 113 214 30 172 74 218 116 230 89 18
// 12 112 130 105 116 180 190 200 187 120
// 7 198 233 158 58 51 50 170 98 23
// 21 1 113 74 146 245 34 255 96 24
// 232 255 23 9 167 240 255 44 194 98
// 18 175 173 204 169 171 236 127 114 23
// 167 202 132 65 253 11 254 56 214 127
// 145 191 104 163 143 7 174 224 247 73
// 52 6 231 255 5 101 83 165 160 231
Module modMain
Public Sub Main()
Dim bytes1(99), bytes2(99) As Byte
Dim rnd1 As New Random()
Dim rnd2 As New Random()
rnd1.NextBytes(bytes1)
rnd2.NextBytes(bytes2)
Console.WriteLine("First Series:")
For ctr As Integer = bytes1.GetLowerBound(0) to bytes1.GetUpperBound(0)
Console.Write("{0, 5}", bytes1(ctr))
If (ctr + 1) Mod 10 = 0 Then Console.WriteLine()
Next
Console.WriteLine()
Console.WriteLine("Second Series:")
For ctr As Integer = bytes2.GetLowerBound(0) to bytes2.GetUpperBound(0)
Console.Write("{0, 5}", bytes2(ctr))
If (ctr + 1) Mod 10 = 0 Then Console.WriteLine()
Next
End Sub
End Module
' The example displays output like the following:
' First Series:
' 97 129 149 54 22 208 120 105 68 177
' 113 214 30 172 74 218 116 230 89 18
' 12 112 130 105 116 180 190 200 187 120
' 7 198 233 158 58 51 50 170 98 23
' 21 1 113 74 146 245 34 255 96 24
' 232 255 23 9 167 240 255 44 194 98
' 18 175 173 204 169 171 236 127 114 23
' 167 202 132 65 253 11 254 56 214 127
' 145 191 104 163 143 7 174 224 247 73
' 52 6 231 255 5 101 83 165 160 231
'
' Second Series:
' 97 129 149 54 22 208 120 105 68 177
' 113 214 30 172 74 218 116 230 89 18
' 12 112 130 105 116 180 190 200 187 120
' 7 198 233 158 58 51 50 170 98 23
' 21 1 113 74 146 245 34 255 96 24
' 232 255 23 9 167 240 255 44 194 98
' 18 175 173 204 169 171 236 127 114 23
' 167 202 132 65 253 11 254 56 214 127
' 145 191 104 163 143 7 174 224 247 73
' 52 6 231 255 5 101 83 165 160 231
若要避免此问题，请创建单个 Random 对象，而不是多个对象。To avoid this problem, create a single Random object instead of multiple objects. 请注意，.NET Core 中的 Random 类没有此限制。Note that the Random class in .NET Core does not have this limitation.
避免多个实例化Avoiding multiple instantiations
在 .NET Framework 上，在紧凑循环中初始化两个随机数生成器，或在快速连续创建两个随机数生成器，它们可以生成相同的随机数序列。On the .NET Framework, initializing two random number generators in a tight loop or in rapid succession creates two random number generators that can produce identical sequences of random numbers. 在大多数情况下，这并不是开发人员的意图，可能会导致性能问题，因为实例化和初始化随机数生成器的过程相对较高。In most cases, this is not the developer's intent and can lead to performance issues, because instantiating and initializing a random number generator is a relatively expensive process.
若要提高性能，并避免无意中创建生成相同数值序列的单独随机数生成器，建议您创建一个 Random 对象，以便在一段时间内生成许多随机数，而不是创建新的 Random 对象以生成一个随机数。Both to improve performance and to avoid inadvertently creating separate random number generators that generate identical numeric sequences, we recommend that you create one Random object to generate many random numbers over time, instead of creating new Random objects to generate one random number.
但 Random 类不是线程安全的。However, the Random class isn't thread safe. 如果从多个线程调用 Random 方法，请遵循下一节中所述的准则。If you call Random methods from multiple threads, follow the guidelines discussed in the next section.
System.web 类和线程安全The System.Random class and thread safety
建议你创建单个 Random 实例来生成应用所需的所有随机数，而不是实例化单个 Random 对象。Instead of instantiating individual Random objects, we recommend that you create a single Random instance to generate all the random numbers needed by your app. 但 Random 对象不是线程安全的。However, Random objects are not thread safe. 如果你的应用程序从多个线程调用 Random 方法，则必须使用同步对象来确保每次只有一个线程可以访问随机数生成器。If your app calls Random methods from multiple threads, you must use a synchronization object to ensure that only one thread can access the random number generator at a time. 如果不确保以线程安全的方式访问 Random 对象，则调用返回随机数的方法将返回0。If you don't ensure that the Random object is accessed in a thread-safe way, calls to methods that return random numbers return 0.
下面的示例使用C# lock 语句和 Visual Basic SyncLock 语句来确保由11个线程在线程安全的方式下访问单个随机数生成器。The following example uses the C# lock Statement and the Visual Basic SyncLock statement to ensure that a single random number generator is accessed by 11 threads in a thread-safe manner. 每个线程都会生成2000000的随机数字，计算生成的随机数数并计算它们的总和，然后在完成执行后更新所有线程的总数。Each thread generates 2 million random numbers, counts the number of random numbers generated and calculates their sum, and then updates the totals for all threads when it finishes executing.
using namespace System;
using namespace System::Threading;
ref class Example
{
private:
[ThreadStatic] static double previous = 0.0;
[ThreadStatic] static int perThreadCtr = 0;
[ThreadStatic] static double perThreadTotal = 0.0;
static CancellationTokenSource^ source;
static CountdownEvent^ countdown;
static Object^ randLock;
static Object^ numericLock;
static Random^ rand;
double totalValue = 0.0;
int totalCount = 0;
public:
Example()
{
rand = gcnew Random();
randLock = gcnew Object();
numericLock = gcnew Object();
countdown = gcnew CountdownEvent(1);
source = gcnew CancellationTokenSource();
}
void Execute()
{
CancellationToken^ token = source->Token;
for (int threads = 1; threads <= 10; threads++)
{
Thread^ newThread = gcnew Thread(gcnew ParameterizedThreadStart(this, &Example::GetRandomNumbers));
newThread->Name = threads.ToString();
newThread->Start(token);
}
this->GetRandomNumbers(token);
countdown->Signal();
// Make sure all threads have finished.
countdown->Wait();
Console::WriteLine("\nTotal random numbers generated: {0:N0}", totalCount);
Console::WriteLine("Total sum of all random numbers: {0:N2}", totalValue);
Console::WriteLine("Random number mean: {0:N4}", totalValue/totalCount);
}
private:
void GetRandomNumbers(Object^ o)
{
CancellationToken^ token = (CancellationToken) o;
double result = 0.0;
countdown->AddCount(1);
try {
for (int ctr = 0; ctr < 2000000; ctr++)
{
// Make sure there's no corruption of Random.
token->ThrowIfCancellationRequested();
Monitor::Enter(randLock);
result = rand->NextDouble();
Monitor::Exit(randLock);
// Check for corruption of Random instance.
if ((result == previous) && result == 0) {
source->Cancel();
}
else {
previous = result;
}
perThreadCtr++;
perThreadTotal += result;
}
Console::WriteLine("Thread {0} finished execution.",
Thread::CurrentThread->Name);
Console::WriteLine("Random numbers generated: {0:N0}", perThreadCtr);
Console::WriteLine("Sum of random numbers: {0:N2}", perThreadTotal);
Console::WriteLine("Random number mean: {0:N4}\n", perThreadTotal/perThreadCtr);
// Update overall totals.
Monitor::Enter(numericLock);
totalCount += perThreadCtr;
totalValue += perThreadTotal;
Monitor::Exit(numericLock);
}
catch (OperationCanceledException^ e) {
Console::WriteLine("Corruption in Thread {1}", e->GetType()->Name,
Thread::CurrentThread->Name);
}
finally {
countdown->Signal();
}
}
};
void main()
{
Example^ ex = gcnew Example();
Thread::CurrentThread->Name = "Main";
ex->Execute();
}
// The example displays output like the following:
// Thread 6 finished execution.
// Random numbers generated: 2,000,000
// Sum of random numbers: 1,000,491.05
// Random number mean: 0.5002
//
// Thread 10 finished execution.
// Random numbers generated: 2,000,000
// Sum of random numbers: 999,329.64
// Random number mean: 0.4997
//
// Thread 4 finished execution.
// Random numbers generated: 2,000,000
// Sum of random numbers: 1,000,166.89
// Random number mean: 0.5001
//
// Thread 8 finished execution.
// Random numbers generated: 2,000,000
// Sum of random numbers: 999,628.37
// Random number mean: 0.4998
//
// Thread Main finished execution.
// Random numbers generated: 2,000,000
// Sum of random numbers: 999,920.89
// Random number mean: 0.5000
//
// Thread 3 finished execution.
// Random numbers generated: 2,000,000
// Sum of random numbers: 999,370.45
// Random number mean: 0.4997
//
// Thread 7 finished execution.
// Random numbers generated: 2,000,000
// Sum of random numbers: 999,330.92
// Random number mean: 0.4997
//
// Thread 9 finished execution.
// Random numbers generated: 2,000,000
// Sum of random numbers: 1,000,172.79
// Random number mean: 0.5001
//
// Thread 5 finished execution.
// Random numbers generated: 2,000,000
// Sum of random numbers: 1,000,079.43
// Random number mean: 0.5000
//
// Thread 1 finished execution.
// Random numbers generated: 2,000,000
// Sum of random numbers: 999,817.91
// Random number mean: 0.4999
//
// Thread 2 finished execution.
// Random numbers generated: 2,000,000
// Sum of random numbers: 999,930.63
// Random number mean: 0.5000
//
//
// Total random numbers generated: 22,000,000
// Total sum of all random numbers: 10,998,238.98
// Random number mean: 0.4999
using System;
using System.Threading;
public class Example
{
[ThreadStatic] static double previous = 0.0;
[ThreadStatic] static int perThreadCtr = 0;
[ThreadStatic] static double perThreadTotal = 0.0;
static CancellationTokenSource source;
static CountdownEvent countdown;
static Object randLock, numericLock;
static Random rand;
double totalValue = 0.0;
int totalCount = 0;
public Example()
{
rand = new Random();
randLock = new Object();
numericLock = new Object();
countdown = new CountdownEvent(1);
source = new CancellationTokenSource();
}
public static void Main()
{
Example ex = new Example();
Thread.CurrentThread.Name = "Main";
ex.Execute();
}
private void Execute()
{
CancellationToken token = source.Token;
for (int threads = 1; threads <= 10; threads++)
{
Thread newThread = new Thread(this.GetRandomNumbers);
newThread.Name = threads.ToString();
newThread.Start(token);
}
this.GetRandomNumbers(token);
countdown.Signal();
// Make sure all threads have finished.
countdown.Wait();
source.Dispose();
Console.WriteLine("\nTotal random numbers generated: {0:N0}", totalCount);
Console.WriteLine("Total sum of all random numbers: {0:N2}", totalValue);
Console.WriteLine("Random number mean: {0:N4}", totalValue/totalCount);
}
private void GetRandomNumbers(Object o)
{
CancellationToken token = (CancellationToken) o;
double result = 0.0;
countdown.AddCount(1);
try {
for (int ctr = 0; ctr < 2000000; ctr++)
{
// Make sure there's no corruption of Random.
token.ThrowIfCancellationRequested();
lock (randLock) {
result = rand.NextDouble();
}
// Check for corruption of Random instance.
if ((result == previous) && result == 0) {
source.Cancel();
}
else {
previous = result;
}
perThreadCtr++;
perThreadTotal += result;
}
Console.WriteLine("Thread {0} finished execution.",
Thread.CurrentThread.Name);
Console.WriteLine("Random numbers generated: {0:N0}", perThreadCtr);
Console.WriteLine("Sum of random numbers: {0:N2}", perThreadTotal);
Console.WriteLine("Random number mean: {0:N4}\n", perThreadTotal/perThreadCtr);
// Update overall totals.
lock (numericLock) {
totalCount += perThreadCtr;
totalValue += perThreadTotal;
}
}
catch (OperationCanceledException e) {
Console.WriteLine("Corruption in Thread {1}", e.GetType().Name, Thread.CurrentThread.Name);
}
finally {
countdown.Signal();
}
}
}
// The example displays output like the following:
// Thread 6 finished execution.
// Random numbers generated: 2,000,000
// Sum of random numbers: 1,000,491.05
// Random number mean: 0.5002
//
// Thread 10 finished execution.
// Random numbers generated: 2,000,000
// Sum of random numbers: 999,329.64
// Random number mean: 0.4997
//
// Thread 4 finished execution.
// Random numbers generated: 2,000,000
// Sum of random numbers: 1,000,166.89
// Random number mean: 0.5001
//
// Thread 8 finished execution.
// Random numbers generated: 2,000,000
// Sum of random numbers: 999,628.37
// Random number mean: 0.4998
//
// Thread Main finished execution.
// Random numbers generated: 2,000,000
// Sum of random numbers: 999,920.89
// Random number mean: 0.5000
//
// Thread 3 finished execution.
// Random numbers generated: 2,000,000
// Sum of random numbers: 999,370.45
// Random number mean: 0.4997
//
// Thread 7 finished execution.
// Random numbers generated: 2,000,000
// Sum of random numbers: 999,330.92
// Random number mean: 0.4997
//
// Thread 9 finished execution.
// Random numbers generated: 2,000,000
// Sum of random numbers: 1,000,172.79
// Random number mean: 0.5001
//
// Thread 5 finished execution.
// Random numbers generated: 2,000,000
// Sum of random numbers: 1,000,079.43
// Random number mean: 0.5000
//
// Thread 1 finished execution.
// Random numbers generated: 2,000,000
// Sum of random numbers: 999,817.91
// Random number mean: 0.4999
//
// Thread 2 finished execution.
// Random numbers generated: 2,000,000
// Sum of random numbers: 999,930.63
// Random number mean: 0.5000
//
//
// Total random numbers generated: 22,000,000
// Total sum of all random numbers: 10,998,238.98
// Random number mean: 0.4999
Imports System.Threading
Module Example
<ThreadStatic> Dim previous As Double = 0.0
<ThreadStatic> Dim perThreadCtr As Integer = 0
<ThreadStatic> Dim perThreadTotal As Double = 0.0
Dim source As New CancellationTokenSource()
Dim countdown As New CountdownEvent(1)
Dim randLock As New Object()
Dim numericLock As New Object()
Dim rand As New Random()
Dim totalValue As Double = 0.0
Dim totalCount As Integer = 0
Public Sub Main()
Thread.CurrentThread.Name = "Main"
Dim token As CancellationToken = source.Token
For threads As Integer = 1 To 10
Dim newThread As New Thread(AddressOf GetRandomNumbers)
newThread.Name = threads.ToString()
newThread.Start(token)
Next
GetRandomNumbers(token)
countdown.Signal()
' Make sure all threads have finished.
countdown.Wait()
Console.WriteLine()
Console.WriteLine("Total random numbers generated: {0:N0}", totalCount)
Console.WriteLine("Total sum of all random numbers: {0:N2}", totalValue)
Console.WriteLine("Random number mean: {0:N4}", totalValue/totalCount)
End Sub
Private Sub GetRandomNumbers(o As Object)
Dim token As CancellationToken = CType(o, CancellationToken)
Dim result As Double = 0.0
countdown.AddCount(1)
Try
For ctr As Integer = 1 To 2000000
' Make sure there's no corruption of Random.
token.ThrowIfCancellationRequested()
SyncLock randLock
result = rand.NextDouble()
End SyncLock
' Check for corruption of Random instance.
If result = previous AndAlso result = 0 Then
source.Cancel()
Else
previous = result
End If
perThreadCtr += 1
perThreadTotal += result
Next
Console.WriteLine("Thread {0} finished execution.",
Thread.CurrentThread.Name)
Console.WriteLine("Random numbers generated: {0:N0}", perThreadCtr)
Console.WriteLine("Sum of random numbers: {0:N2}", perThreadTotal)
Console.WriteLine("Random number mean: {0:N4}", perThreadTotal/perThreadCtr)
Console.WriteLine()
' Update overall totals.
SyncLock numericLock
totalCount += perThreadCtr
totalValue += perThreadTotal
End SyncLock
Catch e As OperationCanceledException
Console.WriteLine("Corruption in Thread {1}", e.GetType().Name, Thread.CurrentThread.Name)
Finally
countdown.Signal()
source.Dispose()
End Try
End Sub
End Module
' The example displays output like the following:
' Thread 6 finished execution.
' Random numbers generated: 2,000,000
' Sum of random numbers: 1,000,491.05
' Random number mean: 0.5002
'
' Thread 10 finished execution.
' Random numbers generated: 2,000,000
' Sum of random numbers: 999,329.64
' Random number mean: 0.4997
'
' Thread 4 finished execution.
' Random numbers generated: 2,000,000
' Sum of random numbers: 1,000,166.89
' Random number mean: 0.5001
'
' Thread 8 finished execution.
' Random numbers generated: 2,000,000
' Sum of random numbers: 999,628.37
' Random number mean: 0.4998
'
' Thread Main finished execution.
' Random numbers generated: 2,000,000
' Sum of random numbers: 999,920.89
' Random number mean: 0.5000
'
' Thread 3 finished execution.
' Random numbers generated: 2,000,000
' Sum of random numbers: 999,370.45
' Random number mean: 0.4997
'
' Thread 7 finished execution.
' Random numbers generated: 2,000,000
' Sum of random numbers: 999,330.92
' Random number mean: 0.4997
'
' Thread 9 finished execution.
' Random numbers generated: 2,000,000
' Sum of random numbers: 1,000,172.79
' Random number mean: 0.5001
'
' Thread 5 finished execution.
' Random numbers generated: 2,000,000
' Sum of random numbers: 1,000,079.43
' Random number mean: 0.5000
'
' Thread 1 finished execution.
' Random numbers generated: 2,000,000
' Sum of random numbers: 999,817.91
' Random number mean: 0.4999
'
' Thread 2 finished execution.
' Random numbers generated: 2,000,000
' Sum of random numbers: 999,930.63
' Random number mean: 0.5000
'
'
' Total random numbers generated: 22,000,000
' Total sum of all random numbers: 10,998,238.98
' Random number mean: 0.4999
该示例通过以下方式确保线程安全：The example ensures thread-safety in the following ways:
ThreadStaticAttribute 属性用于定义线程本地变量，这些变量跟踪每个线程生成的随机数总数及其总和。The ThreadStaticAttribute attribute is used to define thread-local variables that track the total number of random numbers generated and their sum for each thread.
锁（中C#的
lock语句和 Visual Basic 中的SyncLock语句）可保护对所有线程上生成的总数和所有随机数的总和的变量的访问。A lock (thelockstatement in C# and theSyncLockstatement in Visual Basic) protects access to the variables for the total count and sum of all random numbers generated on all threads.信号量（CountdownEvent 对象）用于确保在所有其他线程都完成执行之前，主线程将会阻塞。A semaphore (the CountdownEvent object) is used to ensure that the main thread blocks until all other threads complete execution.
该示例通过确定两次对随机数生成方法的连续调用是否返回0来检查随机数生成器是否已损坏。The example checks whether the random number generator has become corrupted by determining whether two consecutive calls to random number generation methods return 0. 如果检测到损坏，则该示例使用 CancellationTokenSource 对象发送所有线程都应被取消。If corruption is detected, the example uses the CancellationTokenSource object to signal that all threads should be canceled.
在生成每个随机数之前，每个线程都会检查 CancellationToken 对象的状态。Before generating each random number, each thread checks the state of the CancellationToken object. 如果请求取消，则该示例调用 CancellationToken.ThrowIfCancellationRequested 方法来取消线程。If cancellation is requested, the example calls the CancellationToken.ThrowIfCancellationRequested method to cancel the thread.
下面的示例与第一个示例相同，只不过它使用 Task 对象和 lambda 表达式，而不是 Thread 对象。The following example is identical to the first, except that it uses a Task object and a lambda expression instead of Thread objects.
using System;
using System.Collections.Generic;
using System.Threading;
using System.Threading.Tasks;
public class Example
{
static Object randLock, numericLock;
static Random rand;
static CancellationTokenSource source;
double totalValue = 0.0;
int totalCount = 0;
public Example()
{
rand = new Random();
randLock = new Object();
numericLock = new Object();
source = new CancellationTokenSource();
}
public static async Task Main()
{
Example ex = new Example();
Thread.CurrentThread.Name = "Main";
await ex.Execute();
}
private Task Execute()
{
List<Task> tasks = new List<Task>();
for (int ctr = 0; ctr <= 10; ctr++)
{
CancellationToken token = source.Token;
int taskNo = ctr;
tasks.Add(Task.Run( () =>
{
double previous = 0.0;
int taskCtr = 0;
double taskTotal = 0.0;
double result = 0.0;
for (int n = 0; n < 2000000; n++)
{
// Make sure there's no corruption of Random.
token.ThrowIfCancellationRequested();
lock (randLock) {
result = rand.NextDouble();
}
// Check for corruption of Random instance.
if ((result == previous) && result == 0) {
source.Cancel();
}
else {
previous = result;
}
taskCtr++;
taskTotal += result;
}
// Show result.
Console.WriteLine("Task {0} finished execution.", taskNo);
Console.WriteLine("Random numbers generated: {0:N0}", taskCtr);
Console.WriteLine("Sum of random numbers: {0:N2}", taskTotal);
Console.WriteLine("Random number mean: {0:N4}\n", taskTotal/taskCtr);
// Update overall totals.
lock (numericLock) {
totalCount += taskCtr;
totalValue += taskTotal;
}
},
token));
}
try {
await Task.WhenAll(tasks.ToArray());
Console.WriteLine("\nTotal random numbers generated: {0:N0}", totalCount);
Console.WriteLine("Total sum of all random numbers: {0:N2}", totalValue);
Console.WriteLine("Random number mean: {0:N4}", totalValue/totalCount);
}
catch (AggregateException e) {
foreach (Exception inner in e.InnerExceptions) {
TaskCanceledException canc = inner as TaskCanceledException;
if (canc != null)
Console.WriteLine("Task #{0} cancelled.", canc.Task.Id);
else
Console.WriteLine("Exception: {0}", inner.GetType().Name);
}
}
finally {
source.Dispose();
}
}
}
// The example displays output like the following:
// Task 1 finished execution.
// Random numbers generated: 2,000,000
// Sum of random numbers: 1,000,502.47
// Random number mean: 0.5003
//
// Task 0 finished execution.
// Random numbers generated: 2,000,000
// Sum of random numbers: 1,000,445.63
// Random number mean: 0.5002
//
// Task 2 finished execution.
// Random numbers generated: 2,000,000
// Sum of random numbers: 1,000,556.04
// Random number mean: 0.5003
//
// Task 3 finished execution.
// Random numbers generated: 2,000,000
// Sum of random numbers: 1,000,178.87
// Random number mean: 0.5001
//
// Task 4 finished execution.
// Random numbers generated: 2,000,000
// Sum of random numbers: 999,819.17
// Random number mean: 0.4999
//
// Task 5 finished execution.
// Random numbers generated: 2,000,000
// Sum of random numbers: 1,000,190.58
// Random number mean: 0.5001
//
// Task 6 finished execution.
// Random numbers generated: 2,000,000
// Sum of random numbers: 999,720.21
// Random number mean: 0.4999
//
// Task 7 finished execution.
// Random numbers generated: 2,000,000
// Sum of random numbers: 999,000.96
// Random number mean: 0.4995
//
// Task 8 finished execution.
// Random numbers generated: 2,000,000
// Sum of random numbers: 999,499.33
// Random number mean: 0.4997
//
// Task 9 finished execution.
// Random numbers generated: 2,000,000
// Sum of random numbers: 1,000,193.25
// Random number mean: 0.5001
//
// Task 10 finished execution.
// Random numbers generated: 2,000,000
// Sum of random numbers: 999,960.82
// Random number mean: 0.5000
//
//
// Total random numbers generated: 22,000,000
// Total sum of all random numbers: 11,000,067.33
// Random number mean: 0.5000
Imports System.Collections.Generic
Imports System.Threading
Imports System.Threading.Tasks
Module Example
Dim source As New CancellationTokenSource()
Dim randLock As New Object()
Dim numericLock As New Object()
Dim rand As New Random()
Dim totalValue As Double = 0.0
Dim totalCount As Integer = 0
Public Sub Main()
Dim tasks As New List(Of Task)()
For ctr As Integer = 1 To 10
Dim token As CancellationToken = source.Token
Dim taskNo As Integer = ctr
tasks.Add(Task.Run(
Sub()
Dim previous As Double = 0.0
Dim taskCtr As Integer = 0
Dim taskTotal As Double = 0.0
Dim result As Double = 0.0
For n As Integer = 1 To 2000000
' Make sure there's no corruption of Random.
token.ThrowIfCancellationRequested()
SyncLock randLock
result = rand.NextDouble()
End SyncLock
' Check for corruption of Random instance.
If result = previous AndAlso result = 0 Then
source.Cancel()
Else
previous = result
End If
taskCtr += 1
taskTotal += result
Next
' Show result.
Console.WriteLine("Task {0} finished execution.", taskNo)
Console.WriteLine("Random numbers generated: {0:N0}", taskCtr)
Console.WriteLine("Sum of random numbers: {0:N2}", taskTotal)
Console.WriteLine("Random number mean: {0:N4}", taskTotal/taskCtr)
Console.WriteLine()
' Update overall totals.
SyncLock numericLock
totalCount += taskCtr
totalValue += taskTotal
End SyncLock
End Sub, token))
Next
Try
Task.WaitAll(tasks.ToArray())
Console.WriteLine()
Console.WriteLine("Total random numbers generated: {0:N0}", totalCount)
Console.WriteLine("Total sum of all random numbers: {0:N2}", totalValue)
Console.WriteLine("Random number mean: {0:N4}", totalValue/totalCount)
Catch e As AggregateException
For Each inner As Exception In e.InnerExceptions
Dim canc As TaskCanceledException = TryCast(inner, TaskCanceledException)
If canc IsNot Nothing Then
Console.WriteLine("Task #{0} cancelled.", canc.Task.Id)
Else
Console.WriteLine("Exception: {0}", inner.GetType().Name)
End If
Next
Finally
source.Dispose()
End Try
End Sub
End Module
' The example displays output like the following:
' Task 1 finished execution.
' Random numbers generated: 2,000,000
' Sum of random numbers: 1,000,502.47
' Random number mean: 0.5003
'
' Task 0 finished execution.
' Random numbers generated: 2,000,000
' Sum of random numbers: 1,000,445.63
' Random number mean: 0.5002
'
' Task 2 finished execution.
' Random numbers generated: 2,000,000
' Sum of random numbers: 1,000,556.04
' Random number mean: 0.5003
'
' Task 3 finished execution.
' Random numbers generated: 2,000,000
' Sum of random numbers: 1,000,178.87
' Random number mean: 0.5001
'
' Task 4 finished execution.
' Random numbers generated: 2,000,000
' Sum of random numbers: 999,819.17
' Random number mean: 0.4999
'
' Task 5 finished execution.
' Random numbers generated: 2,000,000
' Sum of random numbers: 1,000,190.58
' Random number mean: 0.5001
'
' Task 6 finished execution.
' Random numbers generated: 2,000,000
' Sum of random numbers: 999,720.21
' Random number mean: 0.4999
'
' Task 7 finished execution.
' Random numbers generated: 2,000,000
' Sum of random numbers: 999,000.96
' Random number mean: 0.4995
'
' Task 8 finished execution.
' Random numbers generated: 2,000,000
' Sum of random numbers: 999,499.33
' Random number mean: 0.4997
'
' Task 9 finished execution.
' Random numbers generated: 2,000,000
' Sum of random numbers: 1,000,193.25
' Random number mean: 0.5001
'
' Task 10 finished execution.
' Random numbers generated: 2,000,000
' Sum of random numbers: 999,960.82
' Random number mean: 0.5000
'
'
' Total random numbers generated: 22,000,000
' Total sum of all random numbers: 11,000,067.33
' Random number mean: 0.5000
它与第一个示例在以下方面有所不同：It differs from the first example in the following ways:
用于跟踪生成的随机数数量及其在每个任务中的总和的变量对于任务而言是本地的，因此无需使用 ThreadStaticAttribute 特性。The variables to keep track of the number of random numbers generated and their sum in each task are local to the task, so there is no need to use the ThreadStaticAttribute attribute.
静态 Task.WaitAll 方法用于确保主线程在所有任务完成之前未完成。The static Task.WaitAll method is used to ensure that the main thread doesn't complete before all tasks have finished. 不需要 CountdownEvent 的对象。There is no need for the CountdownEvent object.
任务取消导致的异常在 Task.WaitAll 方法中出现。The exception that results from task cancellation is surfaced in the Task.WaitAll method. 在上面的示例中，它由每个线程处理。In the previous example, it is handled by each thread.
生成不同类型的随机数Generating different types of random numbers
随机数生成器提供了一些方法，使您可以生成以下类型的随机数：The random number generator provides methods that let you generate the following kinds of random numbers:
一系列 Byte 值。A series of Byte values. 通过将初始化为要方法返回到 NextBytes 方法的元素数的数组，来确定字节值的数目。You determine the number of byte values by passing an array initialized to the number of elements you want the method to return to the NextBytes method. 下面的示例生成20个字节。The following example generates 20 bytes.
using namespace System; void main() { Random^ rnd = gcnew Random(); array<Byte>^ bytes = gcnew array<Byte>(20); rnd->NextBytes(bytes); for (int ctr = 1; ctr <= bytes->Length; ctr++) { Console::Write("{0,3} ", bytes[ctr - 1]); if (ctr % 10 == 0) Console::WriteLine(); } } // The example displays output like the following: // 141 48 189 66 134 212 211 71 161 56 // 181 166 220 133 9 252 222 57 62 62Random rnd = new Random(); Byte[] bytes = new Byte[20]; rnd.NextBytes(bytes); for (int ctr = 1; ctr <= bytes.Length; ctr++) { Console.Write("{0,3} ", bytes[ctr - 1]); if (ctr % 10 == 0) Console.WriteLine(); } // The example displays output like the following: // 141 48 189 66 134 212 211 71 161 56 // 181 166 220 133 9 252 222 57 62 62Module Example Public Sub Main() Dim rnd As New Random() Dim bytes(19) As Byte rnd.NextBytes(bytes) For ctr As Integer = 1 To bytes.Length Console.Write("{0,3} ", bytes(ctr - 1)) If ctr Mod 10 = 0 Then Console.WriteLine() Next End Sub End Module ' The example displays output like the following: ' 141 48 189 66 134 212 211 71 161 56 ' 181 166 220 133 9 252 222 57 62 62一个整数。A single integer. 您可以通过调用 Next() 方法来选择是否希望从0到最大值（Int32.MaxValue-1）的整数，或者通过调用 Next(Int32) 方法，从0到特定值之间的整数，或者通过调用 Next(Int32, Int32) 方法来选择值范围内的整数。You can choose whether you want an integer from 0 to a maximum value (Int32.MaxValue - 1) by calling the Next() method, an integer between 0 and a specific value by calling the Next(Int32) method, or an integer within a range of values by calling the Next(Int32, Int32) method. 在参数化重载中，指定的最大值是独占的;也就是说，生成的实际最大数目小于指定值。In the parameterized overloads, the specified maximum value is exclusive; that is, the actual maximum number generated is one less than the specified value.
下面的示例调用 Next(Int32, Int32) 方法，以便在-10 和10之间生成10个随机数。The following example calls the Next(Int32, Int32) method to generate 10 random numbers between -10 and 10. 请注意，方法的第二个参数指定方法返回的随机值的范围的上限。Note that the second argument to the method specifies the exclusive upper bound of the range of random values returned by the method. 换言之，该方法可以返回的最大整数是小于此值的整数。In other words, the largest integer that the method can return is one less than this value.
using namespace System; void main() { Random^ rnd = gcnew Random(); for (int ctr = 0; ctr < 10; ctr++) { Console::Write("{0,3} ", rnd->Next(-10, 11)); } } // The example displays output like the following: // 2 9 -3 2 4 -7 -3 -8 -8 5Random rnd = new Random(); for (int ctr = 0; ctr < 10; ctr++) { Console.Write("{0,3} ", rnd.Next(-10, 11)); } // The example displays output like the following: // 2 9 -3 2 4 -7 -3 -8 -8 5Module Example Public Sub Main() Dim rnd As New Random() For ctr As Integer = 0 To 9 Console.Write("{0,3} ", rnd.Next(-10, 11)) Next End Sub End Module ' The example displays output like the following: ' 2 9 -3 2 4 -7 -3 -8 -8 5通过调用 NextDouble 方法，从0.0 到小于1.0 的单个浮点值。A single floating-point value from 0.0 to less than 1.0 by calling the NextDouble method. 方法返回的随机数的上限上限为1，因此它的实际上限为0.99999999999999978。The exclusive upper bound of the random number returned by the method is 1, so its actual upper bound is 0.99999999999999978. 下面的示例生成10个随机浮点数。The following example generates 10 random floating-point numbers.
using namespace System; void main() { Random^ rnd = gcnew Random(); for (int ctr = 0; ctr < 10; ctr++) { Console::Write("{0,-19:R} ", rnd->NextDouble()); if ((ctr + 1) % 3 == 0) Console::WriteLine(); } } // The example displays output like the following: // 0.7911680553998649 0.0903414949264105 0.79776258291572455 // 0.615568345233597 0.652644504165577 0.84023809378977776 // 0.099662564741290441 0.91341467383942321 0.96018602045261581 // 0.74772306473354022Random rnd = new Random(); for (int ctr = 0; ctr < 10; ctr++) { Console.Write("{0,-19:R} ", rnd.NextDouble()); if ((ctr + 1) % 3 == 0) Console.WriteLine(); } // The example displays output like the following: // 0.7911680553998649 0.0903414949264105 0.79776258291572455 // 0.615568345233597 0.652644504165577 0.84023809378977776 // 0.099662564741290441 0.91341467383942321 0.96018602045261581 // 0.74772306473354022Module Example Public Sub Main() Dim rnd As New Random() For ctr As Integer = 0 To 9 Console.Write("{0,-19:R} ", rnd.NextDouble()) If (ctr + 1) Mod 3 = 0 Then Console.WriteLine() Next End Sub End Module ' The example displays output like the following: ' 0.7911680553998649 0.0903414949264105 0.79776258291572455 ' 0.615568345233597 0.652644504165577 0.84023809378977776 ' 0.099662564741290441 0.91341467383942321 0.96018602045261581 ' 0.74772306473354022
Important
Next(Int32, Int32) 方法允许您指定返回的随机数的范围。The Next(Int32, Int32) method allows you to specify the range of the returned random number. 但 maxValue 参数（指定上限返回的数字）是一个独占的，而不是包含的值。However, the maxValue parameter, which specifies the upper range returned number, is an exclusive, not an inclusive, value. 这意味着方法调用 Next(0, 100) 返回介于0到99之间的值，而不是介于0和100之间。This means that the method call Next(0, 100) returns a value between 0 and 99, and not between 0 and 100.
你还可以将此类任务用于如下所示的任务：生成随机的 Random 类、生成随机浮点值，范围为0到1以外的范围，生成随机的64位整数，并从数组或集合中随机检索唯一元素。You can also use the Random class for such tasks as generating random T:System.Boolean values, generating random floating point values with a range other than 0 to 1, generating random 64-bit integers, and randomly retrieving a unique element from an array or collection. 对于这些任务和其他常见任务，请参阅如何使用系统For these and other common tasks, see the How do you use System.Random to… 。section.
替换自己的算法Substituting your own algorithm
可以通过从 Random 类继承并提供随机数生成算法来实现自己的随机数生成器。You can implement your own random number generator by inheriting from the Random class and supplying your random number generation algorithm. 若要提供自己的算法，必须重写实现随机数生成算法的 Sample 方法。To supply your own algorithm, you must override the Sample method, which implements the random number generation algorithm. 还应覆盖 Next()、Next(Int32, Int32)和 NextBytes 方法，以确保它们调用重写的 Sample 方法。You should also override the Next(), Next(Int32, Int32), and NextBytes methods to ensure that they call your overridden Sample method. 不需要重写 Next(Int32) 和 NextDouble 方法。You don't have to override the Next(Int32) and NextDouble methods.
有关派生自 Random 类并修改其默认伪随机数生成器的示例，请参阅 Sample 参考页。For an example that derives from the Random class and modifies its default pseudo-random number generator, see the Sample reference page.
如何使用 "系统随机 ..."How do you use System.Random to…
以下部分讨论并为你可能想要在应用程序中使用随机数的一些方式提供示例代码。The following sections discuss and provide sample code for some of the ways you might want to use random numbers in your app.
检索相同的随机值序列Retrieve the same sequence of random values
有时，您想要在软件测试方案和游戏游戏中生成相同的随机数字序列。Sometimes you want to generate the same sequence of random numbers in software test scenarios and in game playing. 用相同的随机数序列进行测试，可以检测回归和确认 bug 修复。Testing with the same sequence of random numbers allows you to detect regressions and confirm bug fixes. 在游戏中使用相同的随机数字序列可重播以前的游戏。Using the same sequence of random number in games allows you to replay previous games.
您可以通过向 Random(Int32) 构造函数提供相同的种子值，生成相同的随机数字序列。You can generate the same sequence of random numbers by providing the same seed value to the Random(Int32) constructor. 种子值为伪随机数生成算法提供起始值。The seed value provides a starting value for the pseudo-random number generation algorithm. 下面的示例使用100100作为任意种子值来实例化 Random 的对象，显示20个随机浮点值，并保留种子值。The following example uses 100100 as an arbitrary seed value to instantiate the Random object, displays 20 random floating-point values, and persists the seed value. 然后，它将还原种子值，实例化新的随机数生成器，并显示相同的20个随机浮点值。It then restores the seed value, instantiates a new random number generator, and displays the same 20 random floating-point values. 请注意，如果在 .NET Framework 的不同版本上运行，则该示例可能生成不同的随机数字序列。Note that the example may produce different sequences of random numbers if run on different versions of the .NET Framework.
using System;
using System.IO;
public class Example
{
public static void Main()
{
int seed = 100100;
ShowRandomNumbers(seed);
Console.WriteLine();
PersistSeed(seed);
DisplayNewRandomNumbers();
}
private static void ShowRandomNumbers(int seed)
{
Random rnd = new Random(seed);
for (int ctr = 0; ctr <= 20; ctr++)
Console.WriteLine(rnd.NextDouble());
}
private static void PersistSeed(int seed)
{
FileStream fs = new FileStream(@".\seed.dat", FileMode.Create);
BinaryWriter bin = new BinaryWriter(fs);
bin.Write(seed);
bin.Close();
}
private static void DisplayNewRandomNumbers()
{
FileStream fs = new FileStream(@".\seed.dat", FileMode.Open);
BinaryReader bin = new BinaryReader(fs);
int seed = bin.ReadInt32();
bin.Close();
Random rnd = new Random(seed);
for (int ctr = 0; ctr <= 20; ctr++)
Console.WriteLine(rnd.NextDouble());
}
}
// The example displays output like the following:
// 0.500193602172748
// 0.0209461245783354
// 0.465869495396442
// 0.195512794514891
// 0.928583675496552
// 0.729333720509584
// 0.381455668891527
// 0.0508996467343064
// 0.019261200921266
// 0.258578445417145
// 0.0177532266908107
// 0.983277184415272
// 0.483650274334313
// 0.0219647376900375
// 0.165910115077118
// 0.572085966622497
// 0.805291457942357
// 0.927985211335116
// 0.4228545699375
// 0.523320379910674
// 0.157783938645285
//
// 0.500193602172748
// 0.0209461245783354
// 0.465869495396442
// 0.195512794514891
// 0.928583675496552
// 0.729333720509584
// 0.381455668891527
// 0.0508996467343064
// 0.019261200921266
// 0.258578445417145
// 0.0177532266908107
// 0.983277184415272
// 0.483650274334313
// 0.0219647376900375
// 0.165910115077118
// 0.572085966622497
// 0.805291457942357
// 0.927985211335116
// 0.4228545699375
// 0.523320379910674
// 0.157783938645285
using namespace System;
using namespace System::IO;
ref class RandomMethods
{
internal:
static void ShowRandomNumbers(int seed)
{
Random^ rnd = gcnew Random(seed);
for (int ctr = 0; ctr <= 20; ctr++)
Console::WriteLine(rnd->NextDouble());
}
static void PersistSeed(int seed)
{
FileStream^ fs = gcnew FileStream(".\\seed.dat", FileMode::Create);
BinaryWriter^ bin = gcnew BinaryWriter(fs);
bin->Write(seed);
bin->Close();
}
static void DisplayNewRandomNumbers()
{
FileStream^ fs = gcnew FileStream(".\\seed.dat", FileMode::Open);
BinaryReader^ bin = gcnew BinaryReader(fs);
int seed = bin->ReadInt32();
bin->Close();
Random^ rnd = gcnew Random(seed);
for (int ctr = 0; ctr <= 20; ctr++)
Console::WriteLine(rnd->NextDouble());
}
};
void main()
{
int seed = 100100;
RandomMethods::ShowRandomNumbers(seed);
Console::WriteLine();
RandomMethods::PersistSeed(seed);
RandomMethods::DisplayNewRandomNumbers();
}
// The example displays output like the following:
// 0.500193602172748
// 0.0209461245783354
// 0.465869495396442
// 0.195512794514891
// 0.928583675496552
// 0.729333720509584
// 0.381455668891527
// 0.0508996467343064
// 0.019261200921266
// 0.258578445417145
// 0.0177532266908107
// 0.983277184415272
// 0.483650274334313
// 0.0219647376900375
// 0.165910115077118
// 0.572085966622497
// 0.805291457942357
// 0.927985211335116
// 0.4228545699375
// 0.523320379910674
// 0.157783938645285
//
// 0.500193602172748
// 0.0209461245783354
// 0.465869495396442
// 0.195512794514891
// 0.928583675496552
// 0.729333720509584
// 0.381455668891527
// 0.0508996467343064
// 0.019261200921266
// 0.258578445417145
// 0.0177532266908107
// 0.983277184415272
// 0.483650274334313
// 0.0219647376900375
// 0.165910115077118
// 0.572085966622497
// 0.805291457942357
// 0.927985211335116
// 0.4228545699375
// 0.523320379910674
// 0.157783938645285
Imports System.IO
Module Example
Public Sub Main()
Dim seed As Integer = 100100
ShowRandomNumbers(seed)
Console.WriteLine()
PersistSeed(seed)
DisplayNewRandomNumbers()
End Sub
Private Sub ShowRandomNumbers(seed As Integer)
Dim rnd As New Random(seed)
For ctr As Integer = 0 To 20
Console.WriteLine(rnd.NextDouble())
Next
End Sub
Private Sub PersistSeed(seed As Integer)
Dim fs As New FileStream(".\seed.dat", FileMode.Create)
Dim bin As New BinaryWriter(fs)
bin.Write(seed)
bin.Close()
End Sub
Private Sub DisplayNewRandomNumbers()
Dim fs As New FileStream(".\seed.dat", FileMode.Open)
Dim bin As New BinaryReader(fs)
Dim seed As Integer = bin.ReadInt32()
bin.Close()
Dim rnd As New Random(seed)
For ctr As Integer = 0 To 20
Console.WriteLine(rnd.NextDouble())
Next
End Sub
End Module
' The example displays output like the following:
' 0.500193602172748
' 0.0209461245783354
' 0.465869495396442
' 0.195512794514891
' 0.928583675496552
' 0.729333720509584
' 0.381455668891527
' 0.0508996467343064
' 0.019261200921266
' 0.258578445417145
' 0.0177532266908107
' 0.983277184415272
' 0.483650274334313
' 0.0219647376900375
' 0.165910115077118
' 0.572085966622497
' 0.805291457942357
' 0.927985211335116
' 0.4228545699375
' 0.523320379910674
' 0.157783938645285
'
' 0.500193602172748
' 0.0209461245783354
' 0.465869495396442
' 0.195512794514891
' 0.928583675496552
' 0.729333720509584
' 0.381455668891527
' 0.0508996467343064
' 0.019261200921266
' 0.258578445417145
' 0.0177532266908107
' 0.983277184415272
' 0.483650274334313
' 0.0219647376900375
' 0.165910115077118
' 0.572085966622497
' 0.805291457942357
' 0.927985211335116
' 0.4228545699375
' 0.523320379910674
' 0.157783938645285
检索随机数的唯一序列Retrieve unique sequences of random numbers
向 Random 类的实例提供不同的种子值会导致每个随机数生成器生成不同的值序列。Providing different seed values to instances of the Random class causes each random number generator to produce a different sequence of values. 可以通过调用 Random(Int32) 构造函数或通过调用 Random() 构造函数隐式地提供种子值。You can provide a seed value either explicitly by calling the Random(Int32) constructor, or implicitly by calling the Random() constructor. 大多数开发人员调用使用系统时钟的无参数构造函数。Most developers call the parameterless constructor, which uses the system clock. 下面的示例使用此方法实例化两个 Random 实例。The following example uses this approach to instantiate two Random instances. 每个实例都显示一系列10个随机整数。Each instance displays a series of 10 random integers.
using namespace System;
using namespace System::Threading;
void main()
{
Console::WriteLine("Instantiating two random number generators...");
Random^ rnd1 = gcnew Random();
Thread::Sleep(2000);
Random^ rnd2 = gcnew Random();
Console::WriteLine("\nThe first random number generator:");
for (int ctr = 1; ctr <= 10; ctr++)
Console::WriteLine(" {0}", rnd1->Next());
Console::WriteLine("\nThe second random number generator:");
for (int ctr = 1; ctr <= 10; ctr++)
Console::WriteLine(" {0}", rnd2->Next());
}
// The example displays output like the following:
// Instantiating two random number generators...
//
// The first random number generator:
// 643164361
// 1606571630
// 1725607587
// 2138048432
// 496874898
// 1969147632
// 2034533749
// 1840964542
// 412380298
// 47518930
//
// The second random number generator:
// 1251659083
// 1514185439
// 1465798544
// 517841554
// 1821920222
// 195154223
// 1538948391
// 1548375095
// 546062716
// 897797880
using System;
using System.Threading;
public class Example
{
public static void Main()
{
Console.WriteLine("Instantiating two random number generators...");
Random rnd1 = new Random();
Thread.Sleep(2000);
Random rnd2 = new Random();
Console.WriteLine("\nThe first random number generator:");
for (int ctr = 1; ctr <= 10; ctr++)
Console.WriteLine(" {0}", rnd1.Next());
Console.WriteLine("\nThe second random number generator:");
for (int ctr = 1; ctr <= 10; ctr++)
Console.WriteLine(" {0}", rnd2.Next());
}
}
// The example displays output like the following:
// Instantiating two random number generators...
//
// The first random number generator:
// 643164361
// 1606571630
// 1725607587
// 2138048432
// 496874898
// 1969147632
// 2034533749
// 1840964542
// 412380298
// 47518930
//
// The second random number generator:
// 1251659083
// 1514185439
// 1465798544
// 517841554
// 1821920222
// 195154223
// 1538948391
// 1548375095
// 546062716
// 897797880
Imports System.Threading
Module Example
Public Sub Main()
Console.WriteLine("Instantiating two random number generators...")
Dim rnd1 As New Random()
Thread.Sleep(2000)
Dim rnd2 As New Random()
Console.WriteLine()
Console.WriteLine("The first random number generator:")
For ctr As Integer = 1 To 10
Console.WriteLine(" {0}", rnd1.Next())
Next
Console.WriteLine()
Console.WriteLine("The second random number generator:")
For ctr As Integer = 1 To 10
Console.WriteLine(" {0}", rnd2.Next())
Next
End Sub
End Module
' The example displays output like the following:
' Instantiating two random number generators...
'
' The first random number generator:
' 643164361
' 1606571630
' 1725607587
' 2138048432
' 496874898
' 1969147632
' 2034533749
' 1840964542
' 412380298
' 47518930
'
' The second random number generator:
' 1251659083
' 1514185439
' 1465798544
' 517841554
' 1821920222
' 195154223
' 1538948391
' 1548375095
' 546062716
' 897797880
但是，由于其有限的解决方法，系统时钟不会检测到大约15毫秒的时间差异。However, because of its finite resolution, the system clock doesn't detect time differences that are less than approximately 15 milliseconds. 因此，如果你的代码调用 .NET Framework 上的 Random() 重载以便连续实例化两个 Random 对象，则可能会无意中提供具有相同种子值的对象。Therefore, if your code calls the Random() overload on the .NET Framework to instantiate two Random objects in succession, you might inadvertently be providing the objects with identical seed values. （.NET Core 中的 Random 类没有此限制。）若要在上面的示例中查看此示例，请注释掉 Thread.Sleep 方法调用，然后再次编译并运行该示例。(The Random class in .NET Core does not have this limitation.) To see this in the previous example, comment out the Thread.Sleep method call, and compile and run the example again.
为了防止发生这种情况，我们建议您实例化单个 Random 对象，而不是多个对象。To prevent this from happening, we recommend that you instantiate a single Random object rather than multiple ones. 但是，由于 Random 不是线程安全的，因此，如果从多个线程访问 Random 实例，则必须使用某个同步设备;有关详细信息，请参阅本主题前面的随机类和线程安全。However, since Random isn't thread safe, you must use some synchronization device if you access a Random instance from multiple threads; for more information, see The Random class and thread safety earlier in this topic. 另外，还可以使用延迟机制，如上一示例中使用的 Sleep 方法，以确保实例化的时间间隔超过15毫秒。Alternately, you can use a delay mechanism, such as the Sleep method used in the previous example, to ensure that the instantiations occur more than 15 millisecond apart.
检索指定范围内的整数Retrieve integers in a specified range
您可以通过调用 Next(Int32, Int32) 方法来检索指定范围内的整数，这允许您指定要随机数生成器返回的数字的下限和上限。You can retrieve integers in a specified range by calling the Next(Int32, Int32) method, which lets you specify both the lower and the upper bound of the numbers you'd like the random number generator to return. 上限是专用的，而不是包含的值。The upper bound is an exclusive, not an inclusive, value. 也就是说，它不包含在由方法返回的值范围内。That is, it isn't included in the range of values returned by the method. 下面的示例使用此方法生成介于-10 和10之间的随机整数。The following example uses this method to generate random integers between -10 and 10. 请注意，它指定11，它比所需的值大一，作为方法调用中 maxValue 参数的值。Note that it specifies 11, which is one greater than the desired value, as the value of the maxValue argument in the method call.
using namespace System;
void main()
{
Random^ rnd = gcnew Random();
for (int ctr = 1; ctr <= 15; ctr++) {
Console::Write("{0,3} ", rnd->Next(-10, 11));
if(ctr % 5 == 0) Console::WriteLine();
}
}
// The example displays output like the following:
// -2 -5 -1 -2 10
// -3 6 -4 -8 3
// -7 10 5 -2 4
Random rnd = new Random();
for (int ctr = 1; ctr <= 15; ctr++) {
Console.Write("{0,3} ", rnd.Next(-10, 11));
if(ctr % 5 == 0) Console.WriteLine();
}
// The example displays output like the following:
// -2 -5 -1 -2 10
// -3 6 -4 -8 3
// -7 10 5 -2 4
Module Example
Public Sub Main()
Dim rnd As New Random()
For ctr As Integer = 1 To 15
Console.Write("{0,3} ", rnd.Next(-10, 11))
If ctr Mod 5 = 0 Then Console.WriteLine()
Next
End Sub
End Module
' The example displays output like the following:
' -2 -5 -1 -2 10
' -3 6 -4 -8 3
' -7 10 5 -2 4
检索指定位数的整数Retrieve integers with a specified number of digits
可以调用 Next(Int32, Int32) 方法来检索具有指定位数的数字。You can call the Next(Int32, Int32) method to retrieve numbers with a specified number of digits. 例如，若要检索具有四位数的数字（即从1000到9999的数字），请调用 Next(Int32, Int32) 方法，其 minValue 值为1000，maxValue 值为10000，如下面的示例所示。For example, to retrieve numbers with four digits (that is, numbers that range from 1000 to 9999), you call the Next(Int32, Int32) method with a minValue value of 1000 and a maxValue value of 10000, as the following example shows.
using namespace System;
void main()
{
Random^ rnd = gcnew Random();
for (int ctr = 1; ctr <= 50; ctr++) {
Console::Write("{0,3} ", rnd->Next(1000, 10000));
if(ctr % 10 == 0) Console::WriteLine();
}
}
// The example displays output like the following:
// 9570 8979 5770 1606 3818 4735 8495 7196 7070 2313
// 5279 6577 5104 5734 4227 3373 7376 6007 8193 5540
// 7558 3934 3819 7392 1113 7191 6947 4963 9179 7907
// 3391 6667 7269 1838 7317 1981 5154 7377 3297 5320
// 9869 8694 2684 4949 2999 3019 2357 5211 9604 2593
Random rnd = new Random();
for (int ctr = 1; ctr <= 50; ctr++) {
Console.Write("{0,3} ", rnd.Next(1000, 10000));
if(ctr % 10 == 0) Console.WriteLine();
}
// The example displays output like the following:
// 9570 8979 5770 1606 3818 4735 8495 7196 7070 2313
// 5279 6577 5104 5734 4227 3373 7376 6007 8193 5540
// 7558 3934 3819 7392 1113 7191 6947 4963 9179 7907
// 3391 6667 7269 1838 7317 1981 5154 7377 3297 5320
// 9869 8694 2684 4949 2999 3019 2357 5211 9604 2593
Module Example
Public Sub Main()
Dim rnd As New Random()
For ctr As Integer = 1 To 50
Console.Write("{0,3} ", rnd.Next(1000, 10000))
If ctr Mod 10 = 0 Then Console.WriteLine()
Next
End Sub
End Module
' The example displays output like the following:
' 9570 8979 5770 1606 3818 4735 8495 7196 7070 2313
' 5279 6577 5104 5734 4227 3373 7376 6007 8193 5540
' 7558 3934 3819 7392 1113 7191 6947 4963 9179 7907
' 3391 6667 7269 1838 7317 1981 5154 7377 3297 5320
' 9869 8694 2684 4949 2999 3019 2357 5211 9604 2593
检索指定范围内的浮点值Retrieve floating-point values in a specified range
NextDouble 方法返回介于0和1之间的随机浮点值。The NextDouble method returns random floating-point values that range from 0 to less than 1. 但是，您通常需要在其他某个范围内生成随机值。However, you'll often want to generate random values in some other range.
如果所需的最小值和最大值之间的间隔为1，则可以将所需起始间隔和0之间的差值添加到 NextDouble 方法返回的数字。If the interval between the minimum and maximum desired values is 1, you can add the difference between the desired starting interval and 0 to the number returned by the NextDouble method. 下面的示例将生成10个介于-1 和0之间的随机数。The following example does this to generate 10 random numbers between -1 and 0.
using namespace System;
void main()
{
Random^ rnd = gcnew Random();
for (int ctr = 1; ctr <= 10; ctr++)
Console::WriteLine(rnd->NextDouble() - 1);
}
// The example displays output like the following:
// -0.930412760437658
// -0.164699016215605
// -0.9851692803135
// -0.43468508843085
// -0.177202483255976
// -0.776813320245972
// -0.0713201854710096
// -0.0912875561468711
// -0.540621722368813
// -0.232211863730201
Random rnd = new Random();
for (int ctr = 1; ctr <= 10; ctr++)
Console.WriteLine(rnd.NextDouble() - 1);
// The example displays output like the following:
// -0.930412760437658
// -0.164699016215605
// -0.9851692803135
// -0.43468508843085
// -0.177202483255976
// -0.776813320245972
// -0.0713201854710096
// -0.0912875561468711
// -0.540621722368813
// -0.232211863730201
Module Example
Public Sub Main()
Dim rnd As New Random()
For ctr As Integer = 1 To 10
Console.WriteLine(rnd.NextDouble() - 1)
Next
End Sub
End Module
' The example displays output like the following:
' -0.930412760437658
' -0.164699016215605
' -0.9851692803135
' -0.43468508843085
' -0.177202483255976
' -0.776813320245972
' -0.0713201854710096
' -0.0912875561468711
' -0.540621722368813
' -0.232211863730201
若要生成其下限为0但上限大于1的随机浮点数（或者在负数的情况下，其下限小于-1 且上限为0），则将该随机数乘以非零界限。To generate random floating-point numbers whose lower bound is 0 but upper bound is greater than 1 (or, in the case of negative numbers, whose lower bound is less than -1 and upper bound is 0), multiply the random number by the non-zero bound. 下面的示例将生成20000000随机浮点数，范围为0到 Int64.MaxValue。The following example does this to generate 20 million random floating-point numbers that range from 0 to Int64.MaxValue. 中的还显示方法所生成的随机值的分布。In also displays the distribution of the random values generated by the method.
using namespace System;
void main()
{
const Int64 ONE_TENTH = 922337203685477581;
Random^ rnd = gcnew Random();
double number;
array<int>^ count = gcnew array<int>(10);
// Generate 20 million integer values between.
for (int ctr = 1; ctr <= 20000000; ctr++) {
number = rnd->NextDouble() * Int64::MaxValue;
// Categorize random numbers into 10 groups.
int value = (int) (number / ONE_TENTH);
count[value]++;
}
// Display breakdown by range.
Console::WriteLine("{0,28} {1,32} {2,7}\n", "Range", "Count", "Pct.");
for (int ctr = 0; ctr <= 9; ctr++)
Console::WriteLine("{0,25:N0}-{1,25:N0} {2,8:N0} {3,7:P2}", ctr * ONE_TENTH,
ctr < 9 ? ctr * ONE_TENTH + ONE_TENTH - 1 : Int64::MaxValue,
count[ctr], count[ctr]/20000000.0);
}
// The example displays output like the following:
// Range Count Pct.
//
// 0- 922,337,203,685,477,580 1,996,148 9.98 %
// 922,337,203,685,477,581-1,844,674,407,370,955,161 2,000,293 10.00 %
// 1,844,674,407,370,955,162-2,767,011,611,056,432,742 2,000,094 10.00 %
// 2,767,011,611,056,432,743-3,689,348,814,741,910,323 2,000,159 10.00 %
// 3,689,348,814,741,910,324-4,611,686,018,427,387,904 1,999,552 10.00 %
// 4,611,686,018,427,387,905-5,534,023,222,112,865,485 1,998,248 9.99 %
// 5,534,023,222,112,865,486-6,456,360,425,798,343,066 2,000,696 10.00 %
// 6,456,360,425,798,343,067-7,378,697,629,483,820,647 2,001,637 10.01 %
// 7,378,697,629,483,820,648-8,301,034,833,169,298,228 2,002,870 10.01 %
// 8,301,034,833,169,298,229-9,223,372,036,854,775,807 2,000,303 10.00 %
const long ONE_TENTH = 922337203685477581;
Random rnd = new Random();
double number;
int[] count = new int[10];
// Generate 20 million integer values between.
for (int ctr = 1; ctr <= 20000000; ctr++) {
number = rnd.NextDouble() * Int64.MaxValue;
// Categorize random numbers into 10 groups.
count[(int) (number / ONE_TENTH)]++;
}
// Display breakdown by range.
Console.WriteLine("{0,28} {1,32} {2,7}\n", "Range", "Count", "Pct.");
for (int ctr = 0; ctr <= 9; ctr++)
Console.WriteLine("{0,25:N0}-{1,25:N0} {2,8:N0} {3,7:P2}", ctr * ONE_TENTH,
ctr < 9 ? ctr * ONE_TENTH + ONE_TENTH - 1 : Int64.MaxValue,
count[ctr], count[ctr]/20000000.0);
// The example displays output like the following:
// Range Count Pct.
//
// 0- 922,337,203,685,477,580 1,996,148 9.98 %
// 922,337,203,685,477,581-1,844,674,407,370,955,161 2,000,293 10.00 %
// 1,844,674,407,370,955,162-2,767,011,611,056,432,742 2,000,094 10.00 %
// 2,767,011,611,056,432,743-3,689,348,814,741,910,323 2,000,159 10.00 %
// 3,689,348,814,741,910,324-4,611,686,018,427,387,904 1,999,552 10.00 %
// 4,611,686,018,427,387,905-5,534,023,222,112,865,485 1,998,248 9.99 %
// 5,534,023,222,112,865,486-6,456,360,425,798,343,066 2,000,696 10.00 %
// 6,456,360,425,798,343,067-7,378,697,629,483,820,647 2,001,637 10.01 %
// 7,378,697,629,483,820,648-8,301,034,833,169,298,228 2,002,870 10.01 %
// 8,301,034,833,169,298,229-9,223,372,036,854,775,807 2,000,303 10.00 %
Module Example
Public Sub Main()
Const ONE_TENTH As Long = 922337203685477581
Dim rnd As New Random()
Dim number As Long
Dim count(9) As Integer
' Generate 20 million integer values.
For ctr As Integer = 1 To 20000000
number = CLng(rnd.NextDouble() * Int64.MaxValue)
' Categorize random numbers.
count(CInt(number \ ONE_TENTH)) += 1
Next
' Display breakdown by range.
Console.WriteLine("{0,28} {1,32} {2,7}", "Range", "Count", "Pct.")
Console.WriteLine()
For ctr As Integer = 0 To 9
Console.WriteLine("{0,25:N0}-{1,25:N0} {2,8:N0} {3,7:P2}", ctr * ONE_TENTH,
If(ctr < 9, ctr * ONE_TENTH + ONE_TENTH - 1, Int64.MaxValue),
count(ctr), count(ctr)/20000000)
Next
End Sub
End Module
' The example displays output like the following:
' Range Count Pct.
'
' 0- 922,337,203,685,477,580 1,996,148 9.98 %
' 922,337,203,685,477,581-1,844,674,407,370,955,161 2,000,293 10.00 %
' 1,844,674,407,370,955,162-2,767,011,611,056,432,742 2,000,094 10.00 %
' 2,767,011,611,056,432,743-3,689,348,814,741,910,323 2,000,159 10.00 %
' 3,689,348,814,741,910,324-4,611,686,018,427,387,904 1,999,552 10.00 %
' 4,611,686,018,427,387,905-5,534,023,222,112,865,485 1,998,248 9.99 %
' 5,534,023,222,112,865,486-6,456,360,425,798,343,066 2,000,696 10.00 %
' 6,456,360,425,798,343,067-7,378,697,629,483,820,647 2,001,637 10.01 %
' 7,378,697,629,483,820,648-8,301,034,833,169,298,228 2,002,870 10.01 %
' 8,301,034,833,169,298,229-9,223,372,036,854,775,807 2,000,303 10.00 %
若要在两个任意值之间生成随机浮点数，如 Next(Int32, Int32) 方法对整数执行运算，请使用以下公式：To generate random floating-point numbers between two arbitrary values, like the Next(Int32, Int32) method does for integers, use the following formula:
Random.NextDouble() * (maxValue - minValue) + minValue
下面的示例生成1000000到11.0 范围10.0 内的随机数字，并显示其分布。The following example generates 1 million random numbers that range from 10.0 to 11.0, and displays their distribution.
using namespace System;
void main()
{
Random^ rnd = gcnew Random();
int lowerBound = 10;
int upperBound = 11;
array<int>^ range = gcnew array<int>(10);
for (int ctr = 1; ctr <= 1000000; ctr++) {
Double value = rnd->NextDouble() * (upperBound - lowerBound) + lowerBound;
range[(int) Math::Truncate((value - lowerBound) * 10)]++;
}
for (int ctr = 0; ctr <= 9; ctr++) {
Double lowerRange = 10 + ctr * .1;
Console::WriteLine("{0:N1} to {1:N1}: {2,8:N0} ({3,7:P2})",
lowerRange, lowerRange + .1, range[ctr],
range[ctr] / 1000000.0);
}
}
// The example displays output like the following:
// 10.0 to 10.1: 99,929 ( 9.99 %)
// 10.1 to 10.2: 100,189 (10.02 %)
// 10.2 to 10.3: 99,384 ( 9.94 %)
// 10.3 to 10.4: 100,240 (10.02 %)
// 10.4 to 10.5: 99,397 ( 9.94 %)
// 10.5 to 10.6: 100,580 (10.06 %)
// 10.6 to 10.7: 100,293 (10.03 %)
// 10.7 to 10.8: 100,135 (10.01 %)
// 10.8 to 10.9: 99,905 ( 9.99 %)
// 10.9 to 11.0: 99,948 ( 9.99 %)
Random rnd = new Random();
int lowerBound = 10;
int upperBound = 11;
int[] range = new int[10];
for (int ctr = 1; ctr <= 1000000; ctr++) {
Double value = rnd.NextDouble() * (upperBound - lowerBound) + lowerBound;
range[(int) Math.Truncate((value - lowerBound) * 10)]++;
}
for (int ctr = 0; ctr <= 9; ctr++) {
Double lowerRange = 10 + ctr * .1;
Console.WriteLine("{0:N1} to {1:N1}: {2,8:N0} ({3,7:P2})",
lowerRange, lowerRange + .1, range[ctr],
range[ctr] / 1000000.0);
}
// The example displays output like the following:
// 10.0 to 10.1: 99,929 ( 9.99 %)
// 10.1 to 10.2: 100,189 (10.02 %)
// 10.2 to 10.3: 99,384 ( 9.94 %)
// 10.3 to 10.4: 100,240 (10.02 %)
// 10.4 to 10.5: 99,397 ( 9.94 %)
// 10.5 to 10.6: 100,580 (10.06 %)
// 10.6 to 10.7: 100,293 (10.03 %)
// 10.7 to 10.8: 100,135 (10.01 %)
// 10.8 to 10.9: 99,905 ( 9.99 %)
// 10.9 to 11.0: 99,948 ( 9.99 %)
Module Example
Public Sub Main()
Dim rnd As New Random()
Dim lowerBound As Integer = 10
Dim upperBound As Integer = 11
Dim range(9) As Integer
For ctr As Integer = 1 To 1000000
Dim value As Double = rnd.NextDouble() * (upperBound - lowerBound) + lowerBound
range(CInt(Math.Truncate((value - lowerBound) * 10))) += 1
Next
For ctr As Integer = 0 To 9
Dim lowerRange As Double = 10 + ctr * .1
Console.WriteLine("{0:N1} to {1:N1}: {2,8:N0} ({3,7:P2})",
lowerRange, lowerRange + .1, range(ctr),
range(ctr) / 1000000.0)
Next
End Sub
End Module
' The example displays output like the following:
' 10.0 to 10.1: 99,929 ( 9.99 %)
' 10.1 to 10.2: 100,189 (10.02 %)
' 10.2 to 10.3: 99,384 ( 9.94 %)
' 10.3 to 10.4: 100,240 (10.02 %)
' 10.4 to 10.5: 99,397 ( 9.94 %)
' 10.5 to 10.6: 100,580 (10.06 %)
' 10.6 to 10.7: 100,293 (10.03 %)
' 10.7 to 10.8: 100,135 (10.01 %)
' 10.8 to 10.9: 99,905 ( 9.99 %)
' 10.9 to 11.0: 99,948 ( 9.99 %)
生成随机布尔值Generate random Boolean values
Random 类不提供生成 Boolean 值的方法。The Random class doesn't provide methods that generate Boolean values. 但是，您可以定义自己的类或方法来执行此操作。However, you can define your own class or method to do that. 下面的示例定义了一个使用单个方法 NextBoolean``BooleanGenerator的类。The following example defines a class, BooleanGenerator, with a single method, NextBoolean. BooleanGenerator 类将 Random 对象存储为私有变量。The BooleanGenerator class stores a Random object as a private variable. NextBoolean 方法调用 Random.Next(Int32, Int32) 方法并将结果传递给 Convert.ToBoolean(Int32) 方法。The NextBoolean method calls the Random.Next(Int32, Int32) method and passes the result to the Convert.ToBoolean(Int32) method. 请注意，使用2作为参数来指定随机数的上限。Note that 2 is used as the argument to specify the upper bound of the random number. 由于这是一个独占值，因此该方法调用返回0或1。Since this is an exclusive value, the method call returns either 0 or 1.
using namespace System;
public ref class BooleanGenerator
{
private:
Random^ rnd;
public:
BooleanGenerator()
{
rnd = gcnew Random();
}
bool NextBoolean()
{
return Convert::ToBoolean(rnd->Next(0, 2));
}
};
void main()
{
// Instantiate the Boolean generator.
BooleanGenerator^ boolGen = gcnew BooleanGenerator();
int totalTrue = 0, totalFalse = 0;
// Generate 1,0000 random Booleans, and keep a running total.
for (int ctr = 0; ctr < 1000000; ctr++) {
bool value = boolGen->NextBoolean();
if (value)
totalTrue++;
else
totalFalse++;
}
Console::WriteLine("Number of true values: {0,7:N0} ({1:P3})",
totalTrue,
((double) totalTrue)/(totalTrue + totalFalse));
Console::WriteLine("Number of false values: {0,7:N0} ({1:P3})",
totalFalse,
((double) totalFalse)/(totalTrue + totalFalse));
}
// The example displays output like the following:
// Number of true values: 500,004 (50.000 %)
// Number of false values: 499,996 (50.000 %)
using System;
public class Example
{
public static void Main()
{
// Instantiate the Boolean generator.
BooleanGenerator boolGen = new BooleanGenerator();
int totalTrue = 0, totalFalse = 0;
// Generate 1,0000 random Booleans, and keep a running total.
for (int ctr = 0; ctr < 1000000; ctr++) {
bool value = boolGen.NextBoolean();
if (value)
totalTrue++;
else
totalFalse++;
}
Console.WriteLine("Number of true values: {0,7:N0} ({1:P3})",
totalTrue,
((double) totalTrue)/(totalTrue + totalFalse));
Console.WriteLine("Number of false values: {0,7:N0} ({1:P3})",
totalFalse,
((double) totalFalse)/(totalTrue + totalFalse));
}
}
public class BooleanGenerator
{
Random rnd;
public BooleanGenerator()
{
rnd = new Random();
}
public bool NextBoolean()
{
return Convert.ToBoolean(rnd.Next(0, 2));
}
}
// The example displays output like the following:
// Number of true values: 500,004 (50.000 %)
// Number of false values: 499,996 (50.000 %)
Module Example
Public Sub Main()
' Instantiate the Boolean generator.
Dim boolGen As New BooleanGenerator()
Dim totalTrue, totalFalse As Integer
' Generate 1,0000 random Booleans, and keep a running total.
For ctr As Integer = 0 To 9999999
Dim value As Boolean = boolGen.NextBoolean()
If value Then
totalTrue += 1
Else
totalFalse += 1
End If
Next
Console.WriteLine("Number of true values: {0,7:N0} ({1:P3})",
totalTrue,
totalTrue/(totalTrue + totalFalse))
Console.WriteLine("Number of false values: {0,7:N0} ({1:P3})",
totalFalse,
totalFalse/(totalTrue + totalFalse))
End Sub
End Module
Public Class BooleanGenerator
Dim rnd As Random
Public Sub New()
rnd = New Random()
End Sub
Public Function NextBoolean() As Boolean
Return Convert.ToBoolean(rnd.Next(0, 2))
End Function
End Class
' The example displays the following output:
' Number of true values: 500,004 (50.000 %)
' Number of false values: 499,996 (50.000 %)
该示例只是定义了一个方法，而不是创建一个单独的类来生成随机 Boolean 值。Instead of creating a separate class to generate random Boolean values, the example could simply have defined a single method. 但是，在这种情况下，应将 Random 对象定义为类级变量，以避免在每个方法调用中实例化新的 Random 实例。In that case, however, the Random object should have been defined as a class-level variable to avoid instantiating a new Random instance in each method call. 在 Visual Basic 中，随机实例可以定义为 NextBoolean 方法中的静态变量。In Visual Basic, the Random instance can be defined as a Static variable in the NextBoolean method. 下面的示例提供了一个实现。The following example provides an implementation.
using namespace System;
ref class Example
{
private:
static Random^ rnd = gcnew Random();
public:
static void Execute()
{
int totalTrue = 0, totalFalse = 0;
// Generate 1,0000 random Booleans, and keep a running total.
for (int ctr = 0; ctr < 1000000; ctr++) {
bool value = NextBoolean();
if (value)
totalTrue++;
else
totalFalse++;
}
Console::WriteLine("Number of true values: {0,7:N0} ({1:P3})",
totalTrue,
((double) totalTrue)/(totalTrue + totalFalse));
Console::WriteLine("Number of false values: {0,7:N0} ({1:P3})",
totalFalse,
((double) totalFalse)/(totalTrue + totalFalse));
}
static bool NextBoolean()
{
return Convert::ToBoolean(rnd->Next(0, 2));
}
};
void main()
{
Example::Execute();
}
// The example displays output like the following:
// Number of true values: 499,777 (49.978 %)
// Number of false values: 500,223 (50.022 %)
Random rnd = new Random();
int totalTrue = 0, totalFalse = 0;
// Generate 1,000,000 random Booleans, and keep a running total.
for (int ctr = 0; ctr < 1000000; ctr++) {
bool value = NextBoolean();
if (value)
totalTrue++;
else
totalFalse++;
}
Console.WriteLine("Number of true values: {0,7:N0} ({1:P3})",
totalTrue,
((double) totalTrue)/(totalTrue + totalFalse));
Console.WriteLine("Number of false values: {0,7:N0} ({1:P3})",
totalFalse,
((double) totalFalse)/(totalTrue + totalFalse));
bool NextBoolean()
{
return Convert.ToBoolean(rnd.Next(0, 2));
}
// The example displays output like the following:
// Number of true values: 499,777 (49.978 %)
// Number of false values: 500,223 (50.022 %)
Module Example
Public Sub Main()
Dim totalTrue, totalFalse As Integer
' Generate 1,0000 random Booleans, and keep a running total.
For ctr As Integer = 0 To 9999999
Dim value As Boolean = NextBoolean()
If value Then
totalTrue += 1
Else
totalFalse += 1
End If
Next
Console.WriteLine("Number of true values: {0,7:N0} ({1:P3})",
totalTrue,
totalTrue/(totalTrue + totalFalse))
Console.WriteLine("Number of false values: {0,7:N0} ({1:P3})",
totalFalse,
totalFalse/(totalTrue + totalFalse))
End Sub
Public Function NextBoolean() As Boolean
Static rnd As New Random()
Return Convert.ToBoolean(rnd.Next(0, 2))
End Function
End Module
' The example displays the following output:
' Number of true values: 499,777 (49.978 %)
' Number of false values: 500,223 (50.022 %)
生成随机的64位整数Generate random 64-bit integers
Next 方法的重载将返回32位整数。The overloads of the Next method return 32-bit integers. 但是，在某些情况下，可能需要使用64位整数。However, in some cases, you might want to work with 64-bit integers. 可按如下方式操作：You can do this as follows:
调用 NextDouble 方法以检索双精度浮点值。Call the NextDouble method to retrieve a double-precision floating point value.
通过 Int64.MaxValue将该值相乘。Multiply that value by Int64.MaxValue.
下面的示例使用此方法生成20000000个随机长整数，并将它们分类为10个等组。The following example uses this technique to generate 20 million random long integers and categorizes them in 10 equal groups. 然后，它通过将每个组中的数字从0计算到 Int64.MaxValue来计算随机数的分布。It then evaluates the distribution of the random numbers by counting the number in each group from 0 to Int64.MaxValue. 如示例中的输出所示，在长整数的范围内，数值的分布将更多或更少。As the output from the example shows, the numbers are distributed more or less equally through the range of a long integer.
using namespace System;
void main()
{
const Int64 ONE_TENTH = 922337203685477581;
Random^ rnd = gcnew Random();
Int64 number;
array<int>^ count = gcnew array<int>(10);
// Generate 20 million long integers.
for (int ctr = 1; ctr <= 20000000; ctr++) {
number = (Int64) (rnd->NextDouble() * Int64::MaxValue);
// Categorize random numbers.
count[(int) (number / ONE_TENTH)]++;
}
// Display breakdown by range.
Console::WriteLine("{0,28} {1,32} {2,7}\n", "Range", "Count", "Pct.");
for (int ctr = 0; ctr <= 9; ctr++)
Console::WriteLine("{0,25:N0}-{1,25:N0} {2,8:N0} {3,7:P2}", ctr * ONE_TENTH,
ctr < 9 ? ctr * ONE_TENTH + ONE_TENTH - 1 : Int64::MaxValue,
count[ctr], count[ctr]/20000000.0);
}
// The example displays output like the following:
// Range Count Pct.
//
// 0- 922,337,203,685,477,580 1,996,148 9.98 %
// 922,337,203,685,477,581-1,844,674,407,370,955,161 2,000,293 10.00 %
// 1,844,674,407,370,955,162-2,767,011,611,056,432,742 2,000,094 10.00 %
// 2,767,011,611,056,432,743-3,689,348,814,741,910,323 2,000,159 10.00 %
// 3,689,348,814,741,910,324-4,611,686,018,427,387,904 1,999,552 10.00 %
// 4,611,686,018,427,387,905-5,534,023,222,112,865,485 1,998,248 9.99 %
// 5,534,023,222,112,865,486-6,456,360,425,798,343,066 2,000,696 10.00 %
// 6,456,360,425,798,343,067-7,378,697,629,483,820,647 2,001,637 10.01 %
// 7,378,697,629,483,820,648-8,301,034,833,169,298,228 2,002,870 10.01 %
// 8,301,034,833,169,298,229-9,223,372,036,854,775,807 2,000,303 10.00 %
const long ONE_TENTH = 922337203685477581;
Random rnd = new Random();
long number;
int[] count = new int[10];
// Generate 20 million long integers.
for (int ctr = 1; ctr <= 20000000; ctr++) {
number = (long) (rnd.NextDouble() * Int64.MaxValue);
// Categorize random numbers.
count[(int) (number / ONE_TENTH)]++;
}
// Display breakdown by range.
Console.WriteLine("{0,28} {1,32} {2,7}\n", "Range", "Count", "Pct.");
for (int ctr = 0; ctr <= 9; ctr++)
Console.WriteLine("{0,25:N0}-{1,25:N0} {2,8:N0} {3,7:P2}", ctr * ONE_TENTH,
ctr < 9 ? ctr * ONE_TENTH + ONE_TENTH - 1 : Int64.MaxValue,
count[ctr], count[ctr]/20000000.0);
// The example displays output like the following:
// Range Count Pct.
//
// 0- 922,337,203,685,477,580 1,996,148 9.98 %
// 922,337,203,685,477,581-1,844,674,407,370,955,161 2,000,293 10.00 %
// 1,844,674,407,370,955,162-2,767,011,611,056,432,742 2,000,094 10.00 %
// 2,767,011,611,056,432,743-3,689,348,814,741,910,323 2,000,159 10.00 %
// 3,689,348,814,741,910,324-4,611,686,018,427,387,904 1,999,552 10.00 %
// 4,611,686,018,427,387,905-5,534,023,222,112,865,485 1,998,248 9.99 %
// 5,534,023,222,112,865,486-6,456,360,425,798,343,066 2,000,696 10.00 %
// 6,456,360,425,798,343,067-7,378,697,629,483,820,647 2,001,637 10.01 %
// 7,378,697,629,483,820,648-8,301,034,833,169,298,228 2,002,870 10.01 %
// 8,301,034,833,169,298,229-9,223,372,036,854,775,807 2,000,303 10.00 %
Module Example
Public Sub Main()
Const ONE_TENTH As Long = 922337203685477581
Dim rnd As New Random()
Dim number As Long
Dim count(9) As Integer
' Generate 20 million long integers.
For ctr As Integer = 1 To 20000000
number = CLng(rnd.NextDouble() * Int64.MaxValue)
' Categorize random numbers.
count(CInt(number \ ONE_TENTH)) += 1
Next
' Display breakdown by range.
Console.WriteLine("{0,28} {1,32} {2,7}", "Range", "Count", "Pct.")
Console.WriteLine()
For ctr As Integer = 0 To 9
Console.WriteLine("{0,25:N0}-{1,25:N0} {2,8:N0} {3,7:P2}", ctr * ONE_TENTH,
If(ctr < 9, ctr * ONE_TENTH + ONE_TENTH - 1, Int64.MaxValue),
count(ctr), count(ctr)/20000000)
Next
End Sub
End Module
' The example displays output like the following:
' Range Count Pct.
'
' 0- 922,337,203,685,477,580 1,996,148 9.98 %
' 922,337,203,685,477,581-1,844,674,407,370,955,161 2,000,293 10.00 %
' 1,844,674,407,370,955,162-2,767,011,611,056,432,742 2,000,094 10.00 %
' 2,767,011,611,056,432,743-3,689,348,814,741,910,323 2,000,159 10.00 %
' 3,689,348,814,741,910,324-4,611,686,018,427,387,904 1,999,552 10.00 %
' 4,611,686,018,427,387,905-5,534,023,222,112,865,485 1,998,248 9.99 %
' 5,534,023,222,112,865,486-6,456,360,425,798,343,066 2,000,696 10.00 %
' 6,456,360,425,798,343,067-7,378,697,629,483,820,647 2,001,637 10.01 %
' 7,378,697,629,483,820,648-8,301,034,833,169,298,228 2,002,870 10.01 %
' 8,301,034,833,169,298,229-9,223,372,036,854,775,807 2,000,303 10.00 %
使用位操作的一种替代方法不会生成真正的随机数字。An alternative technique that uses bit manipulation does not generate truly random numbers. 此方法调用 Next() 来生成两个整数，按32位左移一位，并将它们 Or 在一起。This technique calls Next() to generate two integers, left-shifts one by 32 bits, and ORs them together. 此方法有两个限制：This technique has two limitations:
因为位31是符号位，所以生成的长整型值的值始终为0。Because bit 31 is the sign bit, the value in bit 31 of the resulting long integer is always 0. 为此，可以生成一个随机0或1，左移第31位，并将其与原始随机长整数 Or。This can be addressed by generating a random 0 or 1, left-shifting it 31 bits, and ORing it with the original random long integer.
更严肃，因为 Next() 返回的值将为0，所以如果范围为 0x0-0x00000000FFFFFFFF 的任何随机数，都将有很多。More seriously, because the probability that the value returned by Next() will be 0, there will be few if any random numbers in the range 0x0-0x00000000FFFFFFFF.
检索指定范围内的字节Retrieve bytes in a specified range
利用 Next 方法的重载，可以指定随机数的范围，但 NextBytes 方法不能。The overloads of the Next method allow you to specify the range of random numbers, but the NextBytes method does not. 下面的示例实现一个 NextBytes 方法，该方法允许你指定返回的字节范围。The following example implements a NextBytes method that lets you specify the range of the returned bytes. 它定义派生自 Random 的 Random2 类，并重载其 NextBytes 方法。It defines a Random2 class that derives from Random and overloads its NextBytes method.
using namespace System;
ref class Random2 : Random
{
public:
Random2()
{}
Random2(int seed) : Random(seed)
{}
void NextBytes(array<Byte>^ bytes, Byte minValue, Byte maxValue)
{
for (int ctr = bytes->GetLowerBound(0); ctr <= bytes->GetUpperBound(0); ctr++)
bytes[ctr] = (Byte) Next(minValue, maxValue);
}
};
void main()
{
Random2^ rnd = gcnew Random2();
array<Byte>^ bytes = gcnew array<Byte>(10000);
array<int>^ total = gcnew array<int>(101);
rnd->NextBytes(bytes, 0, 101);
// Calculate how many of each value we have.
for each (Byte value in bytes)
total[value]++;
// Display the results.
for (int ctr = 0; ctr < total->Length; ctr++) {
Console::Write("{0,3}: {1,-3} ", ctr, total[ctr]);
if ((ctr + 1) % 5 == 0) Console::WriteLine();
}
}
// The example displays output like the following:
// 0: 115 1: 119 2: 92 3: 98 4: 92
// 5: 102 6: 103 7: 84 8: 93 9: 116
// 10: 91 11: 98 12: 106 13: 91 14: 92
// 15: 101 16: 100 17: 96 18: 97 19: 100
// 20: 101 21: 106 22: 112 23: 82 24: 85
// 25: 102 26: 107 27: 98 28: 106 29: 102
// 30: 109 31: 108 32: 94 33: 101 34: 107
// 35: 101 36: 86 37: 100 38: 101 39: 102
// 40: 113 41: 95 42: 96 43: 89 44: 99
// 45: 81 46: 89 47: 105 48: 100 49: 85
// 50: 103 51: 103 52: 93 53: 89 54: 91
// 55: 97 56: 105 57: 97 58: 110 59: 86
// 60: 116 61: 94 62: 117 63: 98 64: 110
// 65: 93 66: 102 67: 100 68: 105 69: 83
// 70: 81 71: 97 72: 85 73: 70 74: 98
// 75: 100 76: 110 77: 114 78: 83 79: 90
// 80: 96 81: 112 82: 102 83: 102 84: 99
// 85: 81 86: 100 87: 93 88: 99 89: 118
// 90: 95 91: 124 92: 108 93: 96 94: 104
// 95: 106 96: 99 97: 99 98: 92 99: 99
// 100: 108
using System;
public class Example
{
public static void Main()
{
Random2 rnd = new Random2();
Byte[] bytes = new Byte[10000];
int[] total = new int[101];
rnd.NextBytes(bytes, 0, 101);
// Calculate how many of each value we have.
foreach (var value in bytes)
total[value]++;
// Display the results.
for (int ctr = 0; ctr < total.Length; ctr++) {
Console.Write("{0,3}: {1,-3} ", ctr, total[ctr]);
if ((ctr + 1) % 5 == 0) Console.WriteLine();
}
}
}
public class Random2 : Random
{
public Random2() : base()
{}
public Random2(int seed) : base(seed)
{}
public void NextBytes(byte[] bytes, byte minValue, byte maxValue)
{
for (int ctr = bytes.GetLowerBound(0); ctr <= bytes.GetUpperBound(0); ctr++)
bytes[ctr] = (byte) Next(minValue, maxValue);
}
}
// The example displays output like the following:
// 0: 115 1: 119 2: 92 3: 98 4: 92
// 5: 102 6: 103 7: 84 8: 93 9: 116
// 10: 91 11: 98 12: 106 13: 91 14: 92
// 15: 101 16: 100 17: 96 18: 97 19: 100
// 20: 101 21: 106 22: 112 23: 82 24: 85
// 25: 102 26: 107 27: 98 28: 106 29: 102
// 30: 109 31: 108 32: 94 33: 101 34: 107
// 35: 101 36: 86 37: 100 38: 101 39: 102
// 40: 113 41: 95 42: 96 43: 89 44: 99
// 45: 81 46: 89 47: 105 48: 100 49: 85
// 50: 103 51: 103 52: 93 53: 89 54: 91
// 55: 97 56: 105 57: 97 58: 110 59: 86
// 60: 116 61: 94 62: 117 63: 98 64: 110
// 65: 93 66: 102 67: 100 68: 105 69: 83
// 70: 81 71: 97 72: 85 73: 70 74: 98
// 75: 100 76: 110 77: 114 78: 83 79: 90
// 80: 96 81: 112 82: 102 83: 102 84: 99
// 85: 81 86: 100 87: 93 88: 99 89: 118
// 90: 95 91: 124 92: 108 93: 96 94: 104
// 95: 106 96: 99 97: 99 98: 92 99: 99
// 100: 108
Module Example
Public Sub Main()
Dim rnd As New Random2()
Dim bytes(9999) As Byte
Dim total(100) As Integer
rnd.NextBytes(bytes, 0, 101)
' Calculate how many of each value we have.
For Each value In bytes
total(value) += 1
Next
' Display the results.
For ctr As Integer = 0 To total.Length - 1
Console.Write("{0,3}: {1,-3} ", ctr, total(ctr))
If (ctr + 1) Mod 5 = 0 Then Console.WriteLine()
Next
End Sub
End Module
Public Class Random2 : Inherits Random
Public Sub New()
MyBase.New()
End Sub
Public Sub New(seed As Integer)
MyBase.New(seed)
End Sub
Public Overloads Sub NextBytes(bytes() As Byte,
minValue As Byte, maxValue As Byte)
For ctr As Integer = bytes.GetLowerbound(0) To bytes.GetUpperBound(0)
bytes(ctr) = CByte(MyBase.Next(minValue, maxValue))
Next
End Sub
End Class
' The example displays output like the following:
' 0: 115 1: 119 2: 92 3: 98 4: 92
' 5: 102 6: 103 7: 84 8: 93 9: 116
' 10: 91 11: 98 12: 106 13: 91 14: 92
' 15: 101 16: 100 17: 96 18: 97 19: 100
' 20: 101 21: 106 22: 112 23: 82 24: 85
' 25: 102 26: 107 27: 98 28: 106 29: 102
' 30: 109 31: 108 32: 94 33: 101 34: 107
' 35: 101 36: 86 37: 100 38: 101 39: 102
' 40: 113 41: 95 42: 96 43: 89 44: 99
' 45: 81 46: 89 47: 105 48: 100 49: 85
' 50: 103 51: 103 52: 93 53: 89 54: 91
' 55: 97 56: 105 57: 97 58: 110 59: 86
' 60: 116 61: 94 62: 117 63: 98 64: 110
' 65: 93 66: 102 67: 100 68: 105 69: 83
' 70: 81 71: 97 72: 85 73: 70 74: 98
' 75: 100 76: 110 77: 114 78: 83 79: 90
' 80: 96 81: 112 82: 102 83: 102 84: 99
' 85: 81 86: 100 87: 93 88: 99 89: 118
' 90: 95 91: 124 92: 108 93: 96 94: 104
' 95: 106 96: 99 97: 99 98: 92 99: 99
' 100: 108
NextBytes(Byte[], Byte, Byte) 方法包装对 Next(Int32, Int32) 方法的调用，并指定最小值和一个大于我们希望在字节数组中返回的最大值（在本例中为0和101）。The NextBytes(Byte[], Byte, Byte) method wraps a call to the Next(Int32, Int32) method and specifies the minimum value and one greater than the maximum value (in this case, 0 and 101) that we want returned in the byte array. 由于我们确信 Next 方法返回的整数值在 Byte 数据类型的范围内，因此可以安全地将它们强制转换（在中C#）或将它们从整数转换（在 Visual Basic 中）。Because we are sure that the integer values returned by the Next method are within the range of the Byte data type, we can safely cast them (in C#) or convert them (in Visual Basic) from integers to bytes.
随机检索数组或集合中的元素Retrieve an element from an array or collection at random
随机数字通常用作索引来检索数组或集合中的值。Random numbers often serve as indexes to retrieve values from arrays or collections. 若要检索随机索引值，可以调用 Next(Int32, Int32) 方法，并使用数组的下限作为其 minValue 参数的值，并将该数组的下限作为其 maxValue 参数的值。To retrieve a random index value, you can call the Next(Int32, Int32) method, and use the lower bound of the array as the value of its minValue argument and one greater than the upper bound of the array as the value of its maxValue argument. 对于从零开始的数组，这等效于其 Length 属性，或大于 Array.GetUpperBound 方法返回的值的数组。For a zero-based array, this is equivalent to its Length property, or one greater than the value returned by the Array.GetUpperBound method. 下面的示例从城市数组中随机检索美国中的城市名称。The following example randomly retrieves the name of a city in the United States from an array of cities.
using namespace System;
void main()
{
array<String^>^ cities = { "Atlanta", "Boston", "Chicago", "Detroit",
"Fort Wayne", "Greensboro", "Honolulu", "Indianapolis",
"Jersey City", "Kansas City", "Los Angeles",
"Milwaukee", "New York", "Omaha", "Philadelphia",
"Raleigh", "San Francisco", "Tulsa", "Washington" };
Random^ rnd = gcnew Random();
int index = rnd->Next(0, cities->Length);
Console::WriteLine("Today's city of the day: {0}",
cities[index]);
}
// The example displays output like the following:
// Today's city of the day: Honolulu
String[] cities = { "Atlanta", "Boston", "Chicago", "Detroit",
"Fort Wayne", "Greensboro", "Honolulu", "Indianapolis",
"Jersey City", "Kansas City", "Los Angeles",
"Milwaukee", "New York", "Omaha", "Philadelphia",
"Raleigh", "San Francisco", "Tulsa", "Washington" };
Random rnd = new Random();
int index = rnd.Next(0, cities.Length);
Console.WriteLine("Today's city of the day: {0}",
cities[index]);
// The example displays output like the following:
// Today's city of the day: Honolulu
Module Example
Public Sub Main()
Dim cities() As String = { "Atlanta", "Boston", "Chicago", "Detroit",
"Fort Wayne", "Greensboro", "Honolulu", "Indianapolis",
"Jersey City", "Kansas City", "Los Angeles",
"Milwaukee", "New York", "Omaha", "Philadelphia",
"Raleigh", "San Francisco", "Tulsa", "Washington" }
Dim rnd As New Random()
Dim index As Integer = rnd.Next(0, cities.Length)
Console.WriteLine("Today's city of the day: {0}",
cities(index))
End Sub
End Module
' The example displays output like the following:
' Today's city of the day: Honolulu
从数组或集合中检索唯一元素Retrieve a unique element from an array or collection
随机数生成器始终可以返回重复值。A random number generator can always return duplicate values. 当数字范围变小或生成的值的数目变大时，重复的概率会增大。As the range of numbers becomes smaller or the number of values generated becomes larger, the probability of duplicates grows. 如果随机值必须是唯一的，则会生成更多的数字来补偿重复项，从而导致性能日趋下降。If random values must be unique, more numbers are generated to compensate for duplicates, resulting in increasingly poor performance.
可以通过多种方法来处理这种情况。There are a number of techniques to handle this scenario. 一种常见的解决方法是创建包含要检索的值的数组或集合，以及包含随机浮点数的并行数组。One common solution is to create an array or collection that contains the values to be retrieved, and a parallel array that contains random floating-point numbers. 第二个数组是在第一个数组创建时用随机数字填充的，而 Array.Sort(Array, Array) 方法用于使用并行数组中的值对第一个数组进行排序。The second array is populated with random numbers at the time the first array is created, and the Array.Sort(Array, Array) method is used to sort the first array by using the values in the parallel array.
例如，如果您正在开发纸牌游戏，则需要确保每张卡片仅使用一次。For example, if you're developing a Solitaire game, you want to ensure that each card is used only once. 您可以创建可用于对卡片组进行排序的随机数字的并行数组，而不是生成用于检索卡并跟踪该卡是否已被处理的随机数。Instead of generating random numbers to retrieve a card and tracking whether that card has already been dealt, you can create a parallel array of random numbers that can be used to sort the deck. 对卡片组进行排序后，你的应用程序可以维护一个指针来指示卡片上下一张卡片的索引。Once the deck is sorted, your app can maintain a pointer to indicate the index of the next card on the deck.
下面的示例阐释了这种方法。The following example illustrates this approach. 它定义了一个 Card 类，该类表示一个纸牌，并使用一类 Dealer 类来处理有序的卡片。It defines a Card class that represents a playing card and a Dealer class that deals a deck of shuffled cards. Dealer 类构造函数填充了两个数组：一个 deck 数组，该类具有类范围并表示了卡片组中的所有卡片;和一个本地 order 数组，其元素数与 deck 数组的元素数相同，并使用随机生成的 Double 值进行填充。The Dealer class constructor populates two arrays: a deck array that has class scope and that represents all the cards in the deck; and a local order array that has the same number of elements as the deck array and is populated with randomly generated Double values. 然后调用 Array.Sort(Array, Array) 方法，根据 order 数组中的值对 deck 数组进行排序。The Array.Sort(Array, Array) method is then called to sort the deck array based on the values in the order array.
using namespace System;
public enum class Suit { Hearts, Diamonds, Spades, Clubs };
public enum class FaceValue { Ace = 1, Two, Three, Four, Five, Six,
Seven, Eight, Nine, Ten, Jack, Queen,
King };
// A class that represents an individual card in a playing deck.
ref class Card
{
public:
Suit Suit;
FaceValue FaceValue;
String^ ToString() override
{
return String::Format("{0:F} of {1:F}", this->FaceValue, this->Suit);
}
};
ref class Dealer
{
private:
Random^ rnd;
// A deck of cards, without Jokers.
array<Card^>^ deck = gcnew array<Card^>(52);
// Parallel array for sorting cards.
array<Double>^ order = gcnew array<Double>(52);
// A pointer to the next card to deal.
int ptr = 0;
// A flag to indicate the deck is used.
bool mustReshuffle = false;
public:
Dealer()
{
rnd = gcnew Random();
// Initialize the deck.
int deckCtr = 0;
for each (auto suit in Enum::GetValues(Suit::typeid)) {
for each (FaceValue faceValue in Enum::GetValues(FaceValue::typeid)) {
Card^ card = gcnew Card();
card->Suit = (Suit) suit;
card->FaceValue = (FaceValue) faceValue;
deck[deckCtr] = card;
deckCtr++;
}
}
for (int ctr = 0; ctr < order->Length; ctr++)
order[ctr] = rnd->NextDouble();
Array::Sort(order, deck);
}
array<Card^>^ Deal(int numberToDeal)
{
if (mustReshuffle) {
Console::WriteLine("There are no cards left in the deck");
return nullptr;
}
array<Card^>^ cardsDealt = gcnew array<Card^>(numberToDeal);
for (int ctr = 0; ctr < numberToDeal; ctr++) {
cardsDealt[ctr] = deck[ptr];
ptr++;
if (ptr == deck->Length)
mustReshuffle = true;
if (mustReshuffle & ctr < numberToDeal - 1) {
Console::WriteLine("Can only deal the {0} cards remaining on the deck.",
ctr + 1);
return cardsDealt;
}
}
return cardsDealt;
}
};
void ShowCards(array<Card^>^ cards)
{
for each (Card^ card in cards)
if (card != nullptr)
Console::WriteLine("{0} of {1}", card->FaceValue, card->Suit);
};
void main()
{
Dealer^ dealer = gcnew Dealer();
ShowCards(dealer->Deal(20));
}
// The example displays output like the following:
// Six of Diamonds
// King of Clubs
// Eight of Clubs
// Seven of Clubs
// Queen of Clubs
// King of Hearts
// Three of Spades
// Ace of Clubs
// Four of Hearts
// Three of Diamonds
// Nine of Diamonds
// Two of Hearts
// Ace of Hearts
// Three of Hearts
// Four of Spades
// Eight of Hearts
// Queen of Diamonds
// Two of Clubs
// Four of Diamonds
// Jack of Hearts
using System;
// A class that represents an individual card in a playing deck.
public class Card
{
public Suit Suit;
public FaceValue FaceValue;
public override String ToString()
{
return String.Format("{0:F} of {1:F}", this.FaceValue, this.Suit);
}
}
public enum Suit { Hearts, Diamonds, Spades, Clubs };
public enum FaceValue { Ace = 1, Two, Three, Four, Five, Six,
Seven, Eight, Nine, Ten, Jack, Queen,
King };
public class Dealer
{
Random rnd;
// A deck of cards, without Jokers.
Card[] deck = new Card[52];
// Parallel array for sorting cards.
Double[] order = new Double[52];
// A pointer to the next card to deal.
int ptr = 0;
// A flag to indicate the deck is used.
bool mustReshuffle = false;
public Dealer()
{
rnd = new Random();
// Initialize the deck.
int deckCtr = 0;
foreach (var suit in Enum.GetValues(typeof(Suit))) {
foreach (var faceValue in Enum.GetValues(typeof(FaceValue))) {
Card card = new Card();
card.Suit = (Suit) suit;
card.FaceValue = (FaceValue) faceValue;
deck[deckCtr] = card;
deckCtr++;
}
}
for (int ctr = 0; ctr < order.Length; ctr++)
order[ctr] = rnd.NextDouble();
Array.Sort(order, deck);
}
public Card[] Deal(int numberToDeal)
{
if (mustReshuffle) {
Console.WriteLine("There are no cards left in the deck");
return null;
}
Card[] cardsDealt = new Card[numberToDeal];
for (int ctr = 0; ctr < numberToDeal; ctr++) {
cardsDealt[ctr] = deck[ptr];
ptr++;
if (ptr == deck.Length)
mustReshuffle = true;
if (mustReshuffle & ctr < numberToDeal - 1) {
Console.WriteLine("Can only deal the {0} cards remaining on the deck.",
ctr + 1);
return cardsDealt;
}
}
return cardsDealt;
}
}
public class Example
{
public static void Main()
{
Dealer dealer = new Dealer();
ShowCards(dealer.Deal(20));
}
private static void ShowCards(Card[] cards)
{
foreach (var card in cards)
if (card != null)
Console.WriteLine("{0} of {1}", card.FaceValue, card.Suit);
}
}
// The example displays output like the following:
// Six of Diamonds
// King of Clubs
// Eight of Clubs
// Seven of Clubs
// Queen of Clubs
// King of Hearts
// Three of Spades
// Ace of Clubs
// Four of Hearts
// Three of Diamonds
// Nine of Diamonds
// Two of Hearts
// Ace of Hearts
// Three of Hearts
// Four of Spades
// Eight of Hearts
// Queen of Diamonds
// Two of Clubs
// Four of Diamonds
// Jack of Hearts
' A class that represents an individual card in a playing deck.
Public Class Card
Public Suit As Suit
Public FaceValue As FaceValue
Public Overrides Function ToString() As String
Return String.Format("{0:F} of {1:F}", Me.FaceValue, Me.Suit)
End Function
End Class
Public Enum Suit As Integer
Hearts = 0
Diamonds = 1
Spades = 2
Clubs = 3
End Enum
Public Enum FaceValue As Integer
Ace = 1
Two = 2
Three = 3
Four = 4
Five = 5
Six = 6
Seven = 7
Eight = 8
Nine = 9
Ten = 10
Jack = 11
Queen = 12
King = 13
End Enum
Public Class Dealer
Dim rnd As Random
' A deck of cards, without Jokers.
Dim deck(51) As Card
' Parallel array for sorting cards.
Dim order(51) As Double
' A pointer to the next card to deal.
Dim ptr As Integer = 0
' A flag to indicate the deck is used.
Dim mustReshuffle As Boolean
Public Sub New()
rnd = New Random()
' Initialize the deck.
Dim deckCtr As Integer = 0
For Each Suit In [Enum].GetValues(GetType(Suit))
For Each faceValue In [Enum].GetValues(GetType(FaceValue))
Dim card As New Card()
card.Suit = CType(Suit, Suit)
card.FaceValue = CType(faceValue, FaceValue)
deck(deckCtr) = card
deckCtr += 1
Next
Next
For ctr As Integer = 0 To order.Length - 1
order(ctr) = rnd.NextDouble()
Next
Array.Sort(order, deck)
End Sub
Public Function Deal(numberToDeal As Integer) As Card()
If mustReshuffle Then
Console.WriteLine("There are no cards left in the deck")
Return Nothing
End If
Dim cardsDealt(numberToDeal - 1) As Card
For ctr As Integer = 0 To numberToDeal - 1
cardsDealt(ctr) = deck(ptr)
ptr += 1
If ptr = deck.Length Then
mustReshuffle = True
End If
If mustReshuffle And ctr < numberToDeal - 1
Console.WriteLine("Can only deal the {0} cards remaining on the deck.",
ctr + 1)
Return cardsDealt
End If
Next
Return cardsDealt
End Function
End Class
Public Module Example
Public Sub Main()
Dim dealer As New Dealer()
ShowCards(dealer.Deal(20))
End Sub
Private Sub ShowCards(cards() As Card)
For Each card In cards
If card IsNot Nothing Then _
Console.WriteLine("{0} of {1}", card.FaceValue, card.Suit)
Next
End Sub
End Module
' The example displays output like the following:
' Six of Diamonds
' King of Clubs
' Eight of Clubs
' Seven of Clubs
' Queen of Clubs
' King of Hearts
' Three of Spades
' Ace of Clubs
' Four of Hearts
' Three of Diamonds
' Nine of Diamonds
' Two of Hearts
' Ace of Hearts
' Three of Hearts
' Four of Spades
' Eight of Hearts
' Queen of Diamonds
' Two of Clubs
' Four of Diamonds
' Jack of Hearts
Notes to Inheritors
在 .NET Framework 1.0 和1.1 中，从 Random 派生的类的最小实现需要重写 Sample() 方法，以定义新的或修改的算法来生成随机数。In the .NET Framework 1.0 and 1.1, a minimum implementation of a class derived from Random required overriding the Sample() method to define a new or modified algorithm for generating random numbers. 然后，派生类可以依赖于 Next()、Next(Int32)、Next(Int32, Int32)、NextBytes(Byte[])和 NextDouble() 方法的基类实现来调用 Sample() 方法的派生类实现。The derived class could then rely on the base class implementation of the Next(), Next(Int32), Next(Int32, Int32), NextBytes(Byte[]), and NextDouble() methods to call the derived class implementation of the Sample() method.
在 .NET Framework 2.0 及更高版本中，Next()、Next(Int32, Int32)和 NextBytes(Byte[]) 方法的行为已更改，因此这些方法不一定调用 Sample() 方法的派生类实现。In the .NET Framework 2.0 and later, the behavior of the Next(), Next(Int32, Int32), and NextBytes(Byte[]) methods have changed so that these methods do not necessarily call the derived class implementation of the Sample() method. 因此，派生自面向 .NET Framework 2.0 及更高版本的 Random 的类也应重写这三个方法。As a result, classes derived from Random that target the .NET Framework 2.0 and later should also override these three methods.
Notes to Callers
不保证 Random 类中随机数生成器的实现在 .NET Framework 的主要版本中保持不变。The implementation of the random number generator in the Random class isn't guaranteed to remain the same across major versions of the .NET Framework. 因此，不应假定同一种子会导致在不同版本的 .NET Framework 中产生相同的伪随机序列。As a result, you shouldn't assume that the same seed will result in the same pseudo-random sequence in different versions of the .NET Framework.
Constructors
| Random() |
使用默认种子值初始化 Random 类的新实例。Initializes a new instance of the Random class using a default seed value. |
| Random(Int32) |
使用指定的种子值初始化 Random 类的新实例。Initializes a new instance of the Random class, using the specified seed value. |
Methods
| Equals(Object) |
确定指定的对象是否等于当前对象。Determines whether the specified object is equal to the current object. (Inherited from Object) |
| GetHashCode() |
作为默认哈希函数。Serves as the default hash function. (Inherited from Object) |
| GetType() |
获取当前实例的 Type。Gets the Type of the current instance. (Inherited from Object) |
| MemberwiseClone() |
创建当前 Object 的浅表副本。Creates a shallow copy of the current Object. (Inherited from Object) |
| Next() |
返回一个非负随机整数。Returns a non-negative random integer. |
| Next(Int32) |
返回一个小于所指定最大值的非负随机整数。Returns a non-negative random integer that is less than the specified maximum. |
| Next(Int32, Int32) |
返回在指定范围内的任意整数。Returns a random integer that is within a specified range. |
| NextBytes(Byte[]) |
用随机数填充指定字节数组的元素。Fills the elements of a specified array of bytes with random numbers. |
| NextBytes(Span<Byte>) |
用随机数填充指定字节范围的元素。Fills the elements of a specified span of bytes with random numbers. |
| NextDouble() |
返回一个大于或等于 0.0 且小于 1.0 的随机浮点数。Returns a random floating-point number that is greater than or equal to 0.0, and less than 1.0. |
| Sample() |
返回一个介于 0.0 和 1.0 之间的随机浮点数。Returns a random floating-point number between 0.0 and 1.0. |
| ToString() |
返回表示当前对象的字符串。Returns a string that represents the current object. (Inherited from Object) |