RNGCryptoServiceProvider.GetBytes 方法

定义

重载

GetBytes(Byte[])

用经过加密的强随机值序列填充字节数组。Fills an array of bytes with a cryptographically strong sequence of random values.

GetBytes(Span<Byte>)

使用加密型强随机字节填充范围。Fills a span with cryptographically strong random bytes.

GetBytes(Byte[], Int32, Int32)

使用加密型强随机值序列填充指定字节数组(从指定索引处开始,填充指定字节数)。Fills the specified byte array with a cryptographically strong random sequence of values starting at a specified index for a specified number of bytes.

GetBytes(Byte[])

用经过加密的强随机值序列填充字节数组。Fills an array of bytes with a cryptographically strong sequence of random values.

public:
 override void GetBytes(cli::array <System::Byte> ^ data);
public override void GetBytes (byte[] data);
override this.GetBytes : byte[] -> unit
Public Overrides Sub GetBytes (data As Byte())

参数

data
Byte[]

用经过加密的强随机值序列填充的数组。The array to fill with a cryptographically strong sequence of random values.

例外

无法获取加密服务提供程序 (CSP)。The cryptographic service provider (CSP) cannot be acquired.

datanulldata is null.

示例

下面的代码示例演示如何创建具有 RNGCryptoServiceProvider 类的随机数字。The following code example shows how to create a random number with the RNGCryptoServiceProvider class.

//The following sample uses the Cryptography class to simulate the roll of a dice.

using namespace System;
using namespace System::IO;
using namespace System::Text;
using namespace System::Security::Cryptography;

ref class RNGCSP
{
public:
    // Main method.
    static void Main()
    {
        const int totalRolls = 25000;
        array<int>^ results = gcnew array<int>(6);

        // Roll the dice 25000 times and display
        // the results to the console.
        for (int x = 0; x < totalRolls; x++)
        {
            Byte roll = RollDice((Byte)results->Length);
            results[roll - 1]++;
        }
        for (int i = 0; i < results->Length; ++i)
        {
            Console::WriteLine("{0}: {1} ({2:p1})", i + 1, results[i], (double)results[i] / (double)totalRolls);
        }
    }

    // This method simulates a roll of the dice. The input parameter is the
    // number of sides of the dice.

    static Byte RollDice(Byte numberSides)
    {
        if (numberSides <= 0)
            throw gcnew ArgumentOutOfRangeException("numberSides");
        // Create a new instance of the RNGCryptoServiceProvider.
        RNGCryptoServiceProvider^ rngCsp = gcnew RNGCryptoServiceProvider();
        // Create a byte array to hold the random value.
        array<Byte>^ randomNumber = gcnew array<Byte>(1);
        do
        {
            // Fill the array with a random value.
            rngCsp->GetBytes(randomNumber);
        }
        while (!IsFairRoll(randomNumber[0], numberSides));
        // Return the random number mod the number
        // of sides.  The possible values are zero-
        // based, so we add one.
        return (Byte)((randomNumber[0] % numberSides) + 1);
    }

private:
    static bool IsFairRoll(Byte roll, Byte numSides)
    {
        // There are MaxValue / numSides full sets of numbers that can come up
        // in a single byte.  For instance, if we have a 6 sided die, there are
        // 42 full sets of 1-6 that come up.  The 43rd set is incomplete.
        int fullSetsOfValues = Byte::MaxValue / numSides;

        // If the roll is within this range of fair values, then we let it continue.
        // In the 6 sided die case, a roll between 0 and 251 is allowed.  (We use
        // < rather than <= since the = portion allows through an extra 0 value).
        // 252 through 255 would provide an extra 0, 1, 2, 3 so they are not fair
        // to use.
        return roll < numSides * fullSetsOfValues;
    }
};

int main()
{
    RNGCSP::Main();
}
//The following sample uses the Cryptography class to simulate the roll of a dice.

using System;
using System.IO;
using System.Text;
using System.Security.Cryptography;

class RNGCSP
{
    private static RNGCryptoServiceProvider rngCsp = new RNGCryptoServiceProvider();
    // Main method.
    public static void Main()
    {
        const int totalRolls = 25000;
        int[] results = new int[6];

        // Roll the dice 25000 times and display
        // the results to the console.
        for (int x = 0; x < totalRolls; x++)
        {
            byte roll = RollDice((byte)results.Length);
            results[roll - 1]++;
        }
        for (int i = 0; i < results.Length; ++i)
        {
            Console.WriteLine("{0}: {1} ({2:p1})", i + 1, results[i], (double)results[i] / (double)totalRolls);
        }
        rngCsp.Dispose();
        Console.ReadLine();
    }

    // This method simulates a roll of the dice. The input parameter is the
    // number of sides of the dice.

    public static byte RollDice(byte numberSides)
    {
        if (numberSides <= 0)
            throw new ArgumentOutOfRangeException("numberSides");

        // Create a byte array to hold the random value.
        byte[] randomNumber = new byte[1];
        do
        {
            // Fill the array with a random value.
            rngCsp.GetBytes(randomNumber);
        }
        while (!IsFairRoll(randomNumber[0], numberSides));
        // Return the random number mod the number
        // of sides.  The possible values are zero-
        // based, so we add one.
        return (byte)((randomNumber[0] % numberSides) + 1);
    }

    private static bool IsFairRoll(byte roll, byte numSides)
    {
        // There are MaxValue / numSides full sets of numbers that can come up
        // in a single byte.  For instance, if we have a 6 sided die, there are
        // 42 full sets of 1-6 that come up.  The 43rd set is incomplete.
        int fullSetsOfValues = Byte.MaxValue / numSides;

        // If the roll is within this range of fair values, then we let it continue.
        // In the 6 sided die case, a roll between 0 and 251 is allowed.  (We use
        // < rather than <= since the = portion allows through an extra 0 value).
        // 252 through 255 would provide an extra 0, 1, 2, 3 so they are not fair
        // to use.
        return roll < numSides * fullSetsOfValues;
    }
}
'The following sample uses the Cryptography class to simulate the roll of a dice.
Imports System.IO
Imports System.Text
Imports System.Security.Cryptography



Class RNGCSP
    Private Shared rngCsp As New RNGCryptoServiceProvider()
    ' Main method.
    Public Shared Sub Main()
        Const totalRolls As Integer = 25000
        Dim results(5) As Integer

        ' Roll the dice 25000 times and display
        ' the results to the console.
        Dim x As Integer
        For x = 0 To totalRolls
            Dim roll As Byte = RollDice(System.Convert.ToByte(results.Length))
            results((roll - 1)) += 1
        Next x
        Dim i As Integer

        While i < results.Length
            Console.WriteLine("{0}: {1} ({2:p1})", i + 1, results(i), System.Convert.ToDouble(results(i)) / System.Convert.ToDouble(totalRolls))
            i += 1
        End While
        rngCsp.Dispose()
        Console.ReadLine()
    End Sub


    ' This method simulates a roll of the dice. The input parameter is the
    ' number of sides of the dice.
    Public Shared Function RollDice(ByVal numberSides As Byte) As Byte
        If numberSides <= 0 Then
            Throw New ArgumentOutOfRangeException("NumSides")
        End If 
        ' Create a byte array to hold the random value.
        Dim randomNumber(0) As Byte
        Do
            ' Fill the array with a random value.
            rngCsp.GetBytes(randomNumber)
        Loop While Not IsFairRoll(randomNumber(0), numberSides)
        ' Return the random number mod the number
        ' of sides.  The possible values are zero-
        ' based, so we add one.
        Return System.Convert.ToByte(randomNumber(0) Mod numberSides + 1)

    End Function


    Private Shared Function IsFairRoll(ByVal roll As Byte, ByVal numSides As Byte) As Boolean
        ' There are MaxValue / numSides full sets of numbers that can come up
        ' in a single byte.  For instance, if we have a 6 sided die, there are
        ' 42 full sets of 1-6 that come up.  The 43rd set is incomplete.
        Dim fullSetsOfValues As Integer = [Byte].MaxValue / numSides

        ' If the roll is within this range of fair values, then we let it continue.
        ' In the 6 sided die case, a roll between 0 and 251 is allowed.  (We use
        ' < rather than <= since the = portion allows through an extra 0 value).
        ' 252 through 255 would provide an extra 0, 1, 2, 3 so they are not fair
        ' to use.
        Return roll < numSides * fullSetsOfValues

    End Function 'IsFairRoll
End Class

注解

字节数组的长度决定了生成多少个经过加密的强随机字节。The length of the byte array determines how many cryptographically strong random bytes are produced.

此方法是线程安全的。This method is thread safe.

另请参阅

GetBytes(Span<Byte>)

使用加密型强随机字节填充范围。Fills a span with cryptographically strong random bytes.

public:
 override void GetBytes(Span<System::Byte> data);
public override void GetBytes (Span<byte> data);
override this.GetBytes : Span<byte> -> unit
Public Overrides Sub GetBytes (data As Span(Of Byte))

参数

data
Span<Byte>

要用加密型强随机字节填充的范围。The span to fill with cryptographically strong random bytes.

GetBytes(Byte[], Int32, Int32)

使用加密型强随机值序列填充指定字节数组(从指定索引处开始,填充指定字节数)。Fills the specified byte array with a cryptographically strong random sequence of values starting at a specified index for a specified number of bytes.

public:
 override void GetBytes(cli::array <System::Byte> ^ data, int offset, int count);
public override void GetBytes (byte[] data, int offset, int count);
override this.GetBytes : byte[] * int * int -> unit
Public Overrides Sub GetBytes (data As Byte(), offset As Integer, count As Integer)

参数

data
Byte[]

要用加密型强随机字节填充的数组。The array to fill with cryptographically strong random bytes.

offset
Int32

开始填充操作的数组的索引。The index of the array to start the fill operation.

count
Int32

要填充的字节数。The number of bytes to fill.

例外

datanulldata is null.

offsetcount 小于 0。offset or count is less than 0.

offset 加上 count 超过 data 的长度。offset plus count exceeds the length of data.

适用于