Uri.GetLeftPart(UriPartial) 方法

定义

获取 Uri 实例的指定部分。Gets the specified portion of a Uri instance.

public:
 System::String ^ GetLeftPart(UriPartial part);
public string GetLeftPart (UriPartial part);
member this.GetLeftPart : UriPartial -> string
Public Function GetLeftPart (part As UriPartial) As String

参数

part
UriPartial

枚举值之一,指定要返回的 URI 部分的结尾。One of the enumeration values that specifies the end of the URI portion to return.

返回

String

Uri 实例的指定部分。The specified portion of the Uri instance.

例外

当前 Uri 实例不是绝对实例。The current Uri instance is not an absolute instance.

指定的 part 无效。The specified part is not valid.

示例

下面的示例创建一个 Uri 实例,并将路径写入控制台。The following example creates a Uri instance and writes the path to the console.

// Create Uri
Uri^ uriAddress = gcnew Uri( "http://www.contoso.com/index.htm#search" );
Console::WriteLine( uriAddress->Fragment );
Console::WriteLine( "Uri {0} the default port ", uriAddress->IsDefaultPort ? (String^)"uses" : "does not use" );

Console::WriteLine( "The path of this Uri is {0}", uriAddress->GetLeftPart( UriPartial::Path ) );
Console::WriteLine( "Hash code {0}", uriAddress->GetHashCode() );
// The example displays output similar to the following:
//        #search
//        Uri uses the default port
//        The path of this Uri is http://www.contoso.com/index.htm
//        Hash code -988419291
// Create Uri
Uri uriAddress = new Uri("http://www.contoso.com/index.htm#search");
Console.WriteLine(uriAddress.Fragment);
Console.WriteLine("Uri {0} the default port ", uriAddress.IsDefaultPort ? "uses" : "does not use");

Console.WriteLine("The path of this Uri is {0}", uriAddress.GetLeftPart(UriPartial.Path));
Console.WriteLine("Hash code {0}", uriAddress.GetHashCode());
// The example displays output similar to the following:
//        #search
//        Uri uses the default port
//        The path of this Uri is http://www.contoso.com/index.htm
//        Hash code -988419291
' Create Uri
Dim uriAddress As New Uri("http://www.contoso.com/index.htm#search")
Console.WriteLine(uriAddress.Fragment)
Console.WriteLine("Uri {0} the default port ", If(uriAddress.IsDefaultPort, "uses", "does not use")) 

Console.WriteLine("The path of this Uri is {0}", uriAddress.GetLeftPart(UriPartial.Path))
Console.WriteLine("Hash code {0}", uriAddress.GetHashCode())
' The example displays output similar to the following:
'        #search
'        Uri uses the default port
'        The path of this Uri is http://www.contoso.com/index.htm
'        Hash code -988419291

注解

The <xref:System.Uri.GetLeftPart%2A> method returns a string containing the leftmost portion of the URI string, ending with the portion specified by part.

GetLeftPart 在以下情况下包括分隔符:GetLeftPart includes delimiters in the following cases:

  • Scheme 包含方案分隔符。Scheme includes the scheme delimiter.

  • Authority 不包括路径分隔符。Authority does not include the path delimiter.

  • Path 在原始 URI 中包括查询或片段分隔符之前的所有分隔符。Path includes any delimiters in the original URI up to the query or fragment delimiter.

  • Query 包括 Path 、查询及其分隔符。Query includes the Path, plus the query and its delimiter.

下面的示例演示了如何 GetLeftPart 使用 SchemeAuthorityPath 或调用的 URI 和结果 QueryThe following examples show a URI and the results of calling GetLeftPart with Scheme, Authority, Path, or Query.

URIURI 方案Scheme 颁发机构Authority 路径Path 查询Query
http://www.contoso.com/index.htm?date=today http:// http://www.contoso.com http://www.contoso.com/index.htm http://www.contoso.com/index.htm?date=today
http://www.contoso.com/index.htm#main http:// http://www.contoso.com http://www.contoso.com/index.htm http://www.contoso.com/index.htm
mailto:user@contoso.com?subject=uri mailto: mailto:user@contoso.com mailto:user@contoso.com?subject=uri <none>
nntp://news.contoso.com/123456@contoso.com nntp:// nntp://news.contoso.com nntp://news.contoso.com/123456@contoso.com nntp://news.contoso.com/123456@contoso.com
news:123456@contoso.com news: news:123456@contoso.com news:123456@contoso.com <none>
file://server/filename.ext file:// file://server file://server/filename.ext file://server/filename.ext

适用于