VirtualPathProvider.OpenFile(String) 方法
定义
从虚拟文件返回一个流。Returns a stream from a virtual file.
public:
static System::IO::Stream ^ OpenFile(System::String ^ virtualPath);
public static System.IO.Stream OpenFile (string virtualPath);
static member OpenFile : string -> System.IO.Stream
Public Shared Function OpenFile (virtualPath As String) As Stream
参数
- virtualPath
- String
虚拟文件的路径。The path to the virtual file.
返回
所指定虚拟文件或资源的只读 Stream 对象。A read-only Stream object for the specified virtual file or resource.
注解
此 OpenFile 方法是一种便捷方法,使你可以从虚拟文件获取流,而无需创建 VirtualPathProvider 实例。The OpenFile method is a convenience method that enables you to get a stream from a virtual file without creating a VirtualPathProvider instance.