VirtualPathProvider.OpenFile(String) 方法

定义

从虚拟文件返回一个流。Returns a stream from a virtual file.

public:
 static System::IO::Stream ^ OpenFile(System::String ^ virtualPath);
public static System.IO.Stream OpenFile (string virtualPath);
static member OpenFile : string -> System.IO.Stream
Public Shared Function OpenFile (virtualPath As String) As Stream

参数

virtualPath
String

虚拟文件的路径。The path to the virtual file.

返回

Stream

所指定虚拟文件或资源的只读 Stream 对象。A read-only Stream object for the specified virtual file or resource.

注解

OpenFile 方法是一种便捷方法,使你可以从虚拟文件获取流,而无需创建 VirtualPathProvider 实例。The OpenFile method is a convenience method that enables you to get a stream from a virtual file without creating a VirtualPathProvider instance.

适用于