共用方式為


InOutArgument<T>.FromExpression 方法

定義

使用指定的 InOutArgument<T>,初始化並傳回建構的新 Activity<TResult>

public:
 static System::Activities::InOutArgument<T> ^ FromExpression(System::Activities::Activity<System::Activities::Location<T> ^> ^ expression);
public static System.Activities.InOutArgument<T> FromExpression (System.Activities.Activity<System.Activities.Location<T>> expression);
static member FromExpression : System.Activities.Activity<System.Activities.Location<'T>> -> System.Activities.InOutArgument<'T>
Public Shared Function FromExpression (expression As Activity(Of Location(Of T))) As InOutArgument(Of T)

參數

expression
Activity<Location<T>>

引數的值。

傳回

新引數。

適用於