Double.IsNegativeInfinity(Double) 方法

定義

傳回值,指出指定的數字是否計算結果為負的無限大。Returns a value indicating whether the specified number evaluates to negative infinity.

public:
 static bool IsNegativeInfinity(double d);
public static bool IsNegativeInfinity (double d);
static member IsNegativeInfinity : double -> bool
Public Shared Function IsNegativeInfinity (d As Double) As Boolean

參數

d
Double

雙精確度浮點數。A double-precision floating-point number.

傳回

如果 d 計算結果為 NegativeInfinity,則為 true;否則為 falsetrue if d evaluates to NegativeInfinity; otherwise, false.

範例

下列程式碼範例說明如何使用 IsNegativeInfinityThe following code example illustrates the use of IsNegativeInfinity:

// This will return S"true".
Console::WriteLine( "IsNegativeInfinity(-5.0 / 0) == {0}.", Double::IsNegativeInfinity(  -5.0 / zero ) ? (String^)"true" : "false" );
// This will return "true".
Console.WriteLine("IsNegativeInfinity(-5.0 / 0) == {0}.", Double.IsNegativeInfinity(-5.0 / 0) ? "true" : "false");
' This will return "True".
Console.Write("IsNegativeInfinity(-5.0 / 0) = ")
If Double.IsNegativeInfinity(-5 / 0) Then
    Console.WriteLine("True.")
Else
    Console.WriteLine("False.")
End If
if ( d > Double::MaxValue )
{
   Console::WriteLine( "Your number is bigger than a double." );
}
if (d > Double.MaxValue) 
   Console.WriteLine("Your number is bigger than a double.");
If D > Double.MaxValue Then
    Console.WriteLine("Your number is bigger than a double.")
End If
// This will equal Infinity.
Console::WriteLine( "10.0 minus NegativeInfinity equals {0}.", (10.0 - Double::NegativeInfinity) );
// This will equal Infinity.
Console.WriteLine("10.0 minus NegativeInfinity equals {0}.", (10.0 - Double.NegativeInfinity).ToString());
' This will equal Infinity.
Console.WriteLine("10.0 minus NegativeInfinity equals " + (10 - Double.NegativeInfinity).ToString() + ".")

備註

浮點運算會傳回 NegativeInfinity 以發出溢位條件。Floating-point operations return NegativeInfinity to signal an overflow condition.

適用於

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