Enumerable.Min 方法

定義

傳回值序列中的最小值。Returns the minimum value in a sequence of values.

多載

Min(IEnumerable<Nullable<Int64>>)

傳回可為 Null 之 Int64 值序列中的最小值。Returns the minimum value in a sequence of nullable Int64 values.

Min(IEnumerable<Nullable<Int32>>)

傳回可為 Null 之 Int32 值序列中的最小值。Returns the minimum value in a sequence of nullable Int32 values.

Min(IEnumerable<Single>)

傳回 Single 值序列中的最小值。Returns the minimum value in a sequence of Single values.

Min(IEnumerable<Nullable<Single>>)

傳回可為 Null 之 Single 值序列中的最小值。Returns the minimum value in a sequence of nullable Single values.

Min(IEnumerable<Nullable<Double>>)

傳回可為 Null 之 Double 值序列中的最小值。Returns the minimum value in a sequence of nullable Double values.

Min(IEnumerable<Double>)

傳回 Double 值序列中的最小值。Returns the minimum value in a sequence of Double values.

Min(IEnumerable<Int64>)

傳回 Int64 值序列中的最小值。Returns the minimum value in a sequence of Int64 values.

Min(IEnumerable<Int32>)

傳回 Int32 值序列中的最小值。Returns the minimum value in a sequence of Int32 values.

Min(IEnumerable<Nullable<Decimal>>)

傳回可為 Null 之 Decimal 值序列中的最小值。Returns the minimum value in a sequence of nullable Decimal values.

Min(IEnumerable<Decimal>)

傳回 Decimal 值序列中的最小值。Returns the minimum value in a sequence of Decimal values.

Min<TSource,TResult>(IEnumerable<TSource>, Func<TSource,TResult>)

在泛型序列的每個項目上叫用轉換函式,並傳回最小的結果值。Invokes a transform function on each element of a generic sequence and returns the minimum resulting value.

Min<TSource>(IEnumerable<TSource>, Func<TSource,Single>)

在序列的每個項目上叫用轉換函式,並傳回最小的 Single 值。Invokes a transform function on each element of a sequence and returns the minimum Single value.

Min<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Single>>)

在序列的每個項目上叫用轉換函式,並傳回最小的可為 Null 之 Single 值。Invokes a transform function on each element of a sequence and returns the minimum nullable Single value.

Min<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Int64>>)

在序列的每個項目上叫用轉換函式,並傳回最小的可為 Null 之 Int64 值。Invokes a transform function on each element of a sequence and returns the minimum nullable Int64 value.

Min<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Int32>>)

在序列的每個項目上叫用轉換函式,並傳回最小的可為 Null 之 Int32 值。Invokes a transform function on each element of a sequence and returns the minimum nullable Int32 value.

Min<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Double>>)

在序列的每個項目上叫用轉換函式,並傳回最小的可為 Null 之 Double 值。Invokes a transform function on each element of a sequence and returns the minimum nullable Double value.

Min<TSource>(IEnumerable<TSource>, Func<TSource,Int64>)

在序列的每個項目上叫用轉換函式,並傳回最小的 Int64 值。Invokes a transform function on each element of a sequence and returns the minimum Int64 value.

Min<TSource>(IEnumerable<TSource>, Func<TSource,Int32>)

在序列的每個項目上叫用轉換函式,並傳回最小的 Int32 值。Invokes a transform function on each element of a sequence and returns the minimum Int32 value.

Min<TSource>(IEnumerable<TSource>, Func<TSource,Double>)

在序列的每個項目上叫用轉換函式,並傳回最小的 Double 值。Invokes a transform function on each element of a sequence and returns the minimum Double value.

Min<TSource>(IEnumerable<TSource>, Func<TSource,Decimal>)

在序列的每個項目上叫用轉換函式,並傳回最小的 Decimal 值。Invokes a transform function on each element of a sequence and returns the minimum Decimal value.

Min<TSource>(IEnumerable<TSource>)

傳回泛型序列中的最小值。Returns the minimum value in a generic sequence.

Min<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Decimal>>)

在序列的每個項目上叫用轉換函式,並傳回最小的可為 Null 之 Decimal 值。Invokes a transform function on each element of a sequence and returns the minimum nullable Decimal value.

Min(IEnumerable<Nullable<Int64>>)

傳回可為 Null 之 Int64 值序列中的最小值。Returns the minimum value in a sequence of nullable Int64 values.

public:
[System::Runtime::CompilerServices::Extension]
 static Nullable<long> Min(System::Collections::Generic::IEnumerable<Nullable<long>> ^ source);
public static Nullable<long> Min (this System.Collections.Generic.IEnumerable<Nullable<long>> source);
static member Min : seq<Nullable<int64>> -> Nullable<int64>
<Extension()>
Public Function Min (source As IEnumerable(Of Nullable(Of Long))) As Nullable(Of Long)

參數

source
IEnumerable<Nullable<Int64>>

要判斷最小值之可為 Null 的 Int64 值序列。A sequence of nullable Int64 values to determine the minimum value of.

傳回

C# 中類型為 Nullable<Int64> 或 Visual Basic 中類型為 Nullable(Of Int64) 的值,其對應於序列中的最小值。A value of type Nullable<Int64> in C# or Nullable(Of Int64) in Visual Basic that corresponds to the minimum value in the sequence.

例外狀況

sourcenullsource is null.

範例

下列程式碼範例示範如何使用 Min(IEnumerable<Nullable<Int32>>) 來判斷序列中的最小值。The following code example demonstrates how to use Min(IEnumerable<Nullable<Int32>>) to determine the minimum value in a sequence.

注意

這個程式碼範例會使用此多載方法的多載,這個多載不是本主題描述的特定多載。This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. 若要擴充範例以符合本主題內容,請以具有適當數值類型的項目取代來源序列的項目。To extend the example to this topic, substitute the elements of the source sequence with elements of the appropriate numerical type.

int?[] grades = { 78, 92, null, 99, 37, 81 };

int? min = grades.Min();

Console.WriteLine("The lowest grade is {0}.", min);

/*
 This code produces the following output:

 The lowest grade is 37.
*/
Dim grades() As Nullable(Of Integer) = {78, 92, Nothing, 99, 37, 81}
Dim min As Nullable(Of Integer) = grades.Min()

' Display the output.
MsgBox("The lowest grade is " & min)

' This code produces the following output:
'
' The lowest grade is 37

備註

@No__t-0 方法會使用 IComparable<T>Int64 執行來比較值。The Min(IEnumerable<Nullable<Int64>>) method uses the Int64 implementation of IComparable<T> to compare values.

如果來源序列是空的或只包含 null 的值,則此函式會傳回 nullIf the source sequence is empty or contains only values that are null, this function returns null.

在 Visual Basic 查詢運算式語法中,@no__t 0 子句會轉譯為 Min 的調用。In Visual Basic query expression syntax, an Aggregate Into Min() clause translates to an invocation of Min.

另請參閱

Min(IEnumerable<Nullable<Int32>>)

傳回可為 Null 之 Int32 值序列中的最小值。Returns the minimum value in a sequence of nullable Int32 values.

public:
[System::Runtime::CompilerServices::Extension]
 static Nullable<int> Min(System::Collections::Generic::IEnumerable<Nullable<int>> ^ source);
public static Nullable<int> Min (this System.Collections.Generic.IEnumerable<Nullable<int>> source);
static member Min : seq<Nullable<int>> -> Nullable<int>
<Extension()>
Public Function Min (source As IEnumerable(Of Nullable(Of Integer))) As Nullable(Of Integer)

參數

source
IEnumerable<Nullable<Int32>>

要判斷最小值之可為 Null 的 Int32 值序列。A sequence of nullable Int32 values to determine the minimum value of.

傳回

C# 中類型為 Nullable<Int32> 或 Visual Basic 中類型為 Nullable(Of Int32) 的值,其對應於序列中的最小值。A value of type Nullable<Int32> in C# or Nullable(Of Int32) in Visual Basic that corresponds to the minimum value in the sequence.

例外狀況

sourcenullsource is null.

範例

下列程式碼範例示範如何使用 Min(IEnumerable<Nullable<Int32>>) 來判斷序列中的最小值。The following code example demonstrates how to use Min(IEnumerable<Nullable<Int32>>) to determine the minimum value in a sequence.

int?[] grades = { 78, 92, null, 99, 37, 81 };

int? min = grades.Min();

Console.WriteLine("The lowest grade is {0}.", min);

/*
 This code produces the following output:

 The lowest grade is 37.
*/
Dim grades() As Nullable(Of Integer) = {78, 92, Nothing, 99, 37, 81}
Dim min As Nullable(Of Integer) = grades.Min()

' Display the output.
MsgBox("The lowest grade is " & min)

' This code produces the following output:
'
' The lowest grade is 37

備註

@No__t-0 方法會使用 IComparable<T>Int32 執行來比較值。The Min(IEnumerable<Nullable<Int32>>) method uses the Int32 implementation of IComparable<T> to compare values.

如果來源序列是空的或只包含 null 的值,則此函式會傳回 nullIf the source sequence is empty or contains only values that are null, this function returns null.

在 Visual Basic 查詢運算式語法中,@no__t 0 子句會轉譯為 Min 的調用。In Visual Basic query expression syntax, an Aggregate Into Min() clause translates to an invocation of Min.

另請參閱

Min(IEnumerable<Single>)

傳回 Single 值序列中的最小值。Returns the minimum value in a sequence of Single values.

public:
[System::Runtime::CompilerServices::Extension]
 static float Min(System::Collections::Generic::IEnumerable<float> ^ source);
public static float Min (this System.Collections.Generic.IEnumerable<float> source);
static member Min : seq<single> -> single
<Extension()>
Public Function Min (source As IEnumerable(Of Single)) As Single

參數

source
IEnumerable<Single>

要判斷最小值的 Single 值序列。A sequence of Single values to determine the minimum value of.

傳回

序列中的最小值。The minimum value in the sequence.

例外狀況

sourcenullsource is null.

source 沒有包含任何項目。source contains no elements.

範例

下列程式碼範例示範如何使用 Min(IEnumerable<Double>) 來判斷序列中的最小值。The following code example demonstrates how to use Min(IEnumerable<Double>) to determine the minimum value in a sequence.

注意

這個程式碼範例會使用此多載方法的多載,這個多載不是本主題描述的特定多載。This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. 若要擴充範例以符合本主題內容,請以具有適當數值類型的項目取代來源序列的項目。To extend the example to this topic, substitute the elements of the source sequence with elements of the appropriate numerical type.

double[] doubles = { 1.5E+104, 9E+103, -2E+103 };

double min = doubles.Min();

Console.WriteLine("The smallest number is {0}.", min);

/*
 This code produces the following output:

 The smallest number is -2E+103.
*/
' Create an array of double values.
Dim doubles() As Double = {1.5E+104, 9.0E+103, -2.0E+103}

' Determine the smallest number in the array.
Dim min As Double = doubles.Min()

' Display the result.
MsgBox("The smallest number is " & min)

' This code produces the following output:
'
' The smallest number is -2E+103

備註

@No__t-0 方法會使用 IComparable<T>Single 執行來比較值。The Min(IEnumerable<Single>) method uses the Single implementation of IComparable<T> to compare values.

在 Visual Basic 查詢運算式語法中,@no__t 0 子句會轉譯為 Min 的調用。In Visual Basic query expression syntax, an Aggregate Into Min() clause translates to an invocation of Min.

另請參閱

Min(IEnumerable<Nullable<Single>>)

傳回可為 Null 之 Single 值序列中的最小值。Returns the minimum value in a sequence of nullable Single values.

public:
[System::Runtime::CompilerServices::Extension]
 static Nullable<float> Min(System::Collections::Generic::IEnumerable<Nullable<float>> ^ source);
public static Nullable<float> Min (this System.Collections.Generic.IEnumerable<Nullable<float>> source);
static member Min : seq<Nullable<single>> -> Nullable<single>
<Extension()>
Public Function Min (source As IEnumerable(Of Nullable(Of Single))) As Nullable(Of Single)

參數

source
IEnumerable<Nullable<Single>>

要判斷最小值之可為 Null 的 Single 值序列。A sequence of nullable Single values to determine the minimum value of.

傳回

C# 中類型為 Nullable<Single> 或 Visual Basic 中類型為 Nullable(Of Single) 的值,其對應於序列中的最小值。A value of type Nullable<Single> in C# or Nullable(Of Single) in Visual Basic that corresponds to the minimum value in the sequence.

例外狀況

sourcenullsource is null.

範例

下列程式碼範例示範如何使用 Min(IEnumerable<Nullable<Int32>>) 來判斷序列中的最小值。The following code example demonstrates how to use Min(IEnumerable<Nullable<Int32>>) to determine the minimum value in a sequence.

注意

這個程式碼範例會使用此多載方法的多載,這個多載不是本主題描述的特定多載。This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. 若要擴充範例以符合本主題內容,請以具有適當數值類型的項目取代來源序列的項目。To extend the example to this topic, substitute the elements of the source sequence with elements of the appropriate numerical type.

int?[] grades = { 78, 92, null, 99, 37, 81 };

int? min = grades.Min();

Console.WriteLine("The lowest grade is {0}.", min);

/*
 This code produces the following output:

 The lowest grade is 37.
*/
Dim grades() As Nullable(Of Integer) = {78, 92, Nothing, 99, 37, 81}
Dim min As Nullable(Of Integer) = grades.Min()

' Display the output.
MsgBox("The lowest grade is " & min)

' This code produces the following output:
'
' The lowest grade is 37

備註

@No__t-0 方法會使用 IComparable<T>Single 執行來比較值。The Min(IEnumerable<Nullable<Single>>) method uses the Single implementation of IComparable<T> to compare values.

如果來源序列是空的或只包含 null 的值,則此函式會傳回 nullIf the source sequence is empty or contains only values that are null, this function returns null.

在 Visual Basic 查詢運算式語法中,@no__t 0 子句會轉譯為 Min 的調用。In Visual Basic query expression syntax, an Aggregate Into Min() clause translates to an invocation of Min.

另請參閱

Min(IEnumerable<Nullable<Double>>)

傳回可為 Null 之 Double 值序列中的最小值。Returns the minimum value in a sequence of nullable Double values.

public:
[System::Runtime::CompilerServices::Extension]
 static Nullable<double> Min(System::Collections::Generic::IEnumerable<Nullable<double>> ^ source);
public static Nullable<double> Min (this System.Collections.Generic.IEnumerable<Nullable<double>> source);
static member Min : seq<Nullable<double>> -> Nullable<double>
<Extension()>
Public Function Min (source As IEnumerable(Of Nullable(Of Double))) As Nullable(Of Double)

參數

source
IEnumerable<Nullable<Double>>

要判斷最小值之可為 Null 的 Double 值序列。A sequence of nullable Double values to determine the minimum value of.

傳回

C# 中類型為 Nullable<Double> 或 Visual Basic 中類型為 Nullable(Of Double) 的值,其對應於序列中的最小值。A value of type Nullable<Double> in C# or Nullable(Of Double) in Visual Basic that corresponds to the minimum value in the sequence.

例外狀況

sourcenullsource is null.

範例

下列程式碼範例示範如何使用 Min(IEnumerable<Nullable<Int32>>) 來判斷序列中的最小值。The following code example demonstrates how to use Min(IEnumerable<Nullable<Int32>>) to determine the minimum value in a sequence.

注意

這個程式碼範例會使用此多載方法的多載,這個多載不是本主題描述的特定多載。This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. 若要擴充範例以符合本主題內容,請以具有適當數值類型的項目取代來源序列的項目。To extend the example to this topic, substitute the elements of the source sequence with elements of the appropriate numerical type.

int?[] grades = { 78, 92, null, 99, 37, 81 };

int? min = grades.Min();

Console.WriteLine("The lowest grade is {0}.", min);

/*
 This code produces the following output:

 The lowest grade is 37.
*/
Dim grades() As Nullable(Of Integer) = {78, 92, Nothing, 99, 37, 81}
Dim min As Nullable(Of Integer) = grades.Min()

' Display the output.
MsgBox("The lowest grade is " & min)

' This code produces the following output:
'
' The lowest grade is 37

備註

@No__t-0 方法會使用 IComparable<T>Double 執行來比較值。The Min(IEnumerable<Nullable<Double>>) method uses the Double implementation of IComparable<T> to compare values.

如果來源序列是空的或只包含 null 的值,則此函式會傳回 nullIf the source sequence is empty or contains only values that are null, this function returns null.

在 Visual Basic 查詢運算式語法中,@no__t 0 子句會轉譯為 Min 的調用。In Visual Basic query expression syntax, an Aggregate Into Min() clause translates to an invocation of Min.

另請參閱

Min(IEnumerable<Double>)

傳回 Double 值序列中的最小值。Returns the minimum value in a sequence of Double values.

public:
[System::Runtime::CompilerServices::Extension]
 static double Min(System::Collections::Generic::IEnumerable<double> ^ source);
public static double Min (this System.Collections.Generic.IEnumerable<double> source);
static member Min : seq<double> -> double
<Extension()>
Public Function Min (source As IEnumerable(Of Double)) As Double

參數

source
IEnumerable<Double>

要判斷最小值的 Double 值序列。A sequence of Double values to determine the minimum value of.

傳回

序列中的最小值。The minimum value in the sequence.

例外狀況

sourcenullsource is null.

source 沒有包含任何項目。source contains no elements.

範例

下列程式碼範例示範如何使用 Min(IEnumerable<Double>) 來判斷序列中的最小值。The following code example demonstrates how to use Min(IEnumerable<Double>) to determine the minimum value in a sequence.

double[] doubles = { 1.5E+104, 9E+103, -2E+103 };

double min = doubles.Min();

Console.WriteLine("The smallest number is {0}.", min);

/*
 This code produces the following output:

 The smallest number is -2E+103.
*/
' Create an array of double values.
Dim doubles() As Double = {1.5E+104, 9.0E+103, -2.0E+103}

' Determine the smallest number in the array.
Dim min As Double = doubles.Min()

' Display the result.
MsgBox("The smallest number is " & min)

' This code produces the following output:
'
' The smallest number is -2E+103

備註

@No__t-0 方法會使用 IComparable<T>Double 執行來比較值。The Min(IEnumerable<Double>) method uses the Double implementation of IComparable<T> to compare values.

在 Visual Basic 查詢運算式語法中,@no__t 0 子句會轉譯為 Min 的調用。In Visual Basic query expression syntax, an Aggregate Into Min() clause translates to an invocation of Min.

另請參閱

Min(IEnumerable<Int64>)

傳回 Int64 值序列中的最小值。Returns the minimum value in a sequence of Int64 values.

public:
[System::Runtime::CompilerServices::Extension]
 static long Min(System::Collections::Generic::IEnumerable<long> ^ source);
public static long Min (this System.Collections.Generic.IEnumerable<long> source);
static member Min : seq<int64> -> int64
<Extension()>
Public Function Min (source As IEnumerable(Of Long)) As Long

參數

source
IEnumerable<Int64>

要判斷最小值的 Int64 值序列。A sequence of Int64 values to determine the minimum value of.

傳回

序列中的最小值。The minimum value in the sequence.

例外狀況

sourcenullsource is null.

source 沒有包含任何項目。source contains no elements.

範例

下列程式碼範例示範如何使用 Min(IEnumerable<Double>) 來判斷序列中的最小值。The following code example demonstrates how to use Min(IEnumerable<Double>) to determine the minimum value in a sequence.

注意

這個程式碼範例會使用此多載方法的多載,這個多載不是本主題描述的特定多載。This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. 若要擴充範例以符合本主題內容,請以具有適當數值類型的項目取代來源序列的項目。To extend the example to this topic, substitute the elements of the source sequence with elements of the appropriate numerical type.

double[] doubles = { 1.5E+104, 9E+103, -2E+103 };

double min = doubles.Min();

Console.WriteLine("The smallest number is {0}.", min);

/*
 This code produces the following output:

 The smallest number is -2E+103.
*/
' Create an array of double values.
Dim doubles() As Double = {1.5E+104, 9.0E+103, -2.0E+103}

' Determine the smallest number in the array.
Dim min As Double = doubles.Min()

' Display the result.
MsgBox("The smallest number is " & min)

' This code produces the following output:
'
' The smallest number is -2E+103

備註

@No__t-0 方法會使用 IComparable<T>Int64 執行來比較值。The Min(IEnumerable<Int64>) method uses the Int64 implementation of IComparable<T> to compare values.

在 Visual Basic 查詢運算式語法中,@no__t 0 子句會轉譯為 Min 的調用。In Visual Basic query expression syntax, an Aggregate Into Min() clause translates to an invocation of Min.

另請參閱

Min(IEnumerable<Int32>)

傳回 Int32 值序列中的最小值。Returns the minimum value in a sequence of Int32 values.

public:
[System::Runtime::CompilerServices::Extension]
 static int Min(System::Collections::Generic::IEnumerable<int> ^ source);
public static int Min (this System.Collections.Generic.IEnumerable<int> source);
static member Min : seq<int> -> int
<Extension()>
Public Function Min (source As IEnumerable(Of Integer)) As Integer

參數

source
IEnumerable<Int32>

要判斷最小值的 Int32 值序列。A sequence of Int32 values to determine the minimum value of.

傳回

序列中的最小值。The minimum value in the sequence.

例外狀況

sourcenullsource is null.

source 沒有包含任何項目。source contains no elements.

範例

下列程式碼範例示範如何使用 Min(IEnumerable<Double>) 來判斷序列中的最小值。The following code example demonstrates how to use Min(IEnumerable<Double>) to determine the minimum value in a sequence.

注意

這個程式碼範例會使用此多載方法的多載,這個多載不是本主題描述的特定多載。This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. 若要擴充範例以符合本主題內容,請以具有適當數值類型的項目取代來源序列的項目。To extend the example to this topic, substitute the elements of the source sequence with elements of the appropriate numerical type.

double[] doubles = { 1.5E+104, 9E+103, -2E+103 };

double min = doubles.Min();

Console.WriteLine("The smallest number is {0}.", min);

/*
 This code produces the following output:

 The smallest number is -2E+103.
*/
' Create an array of double values.
Dim doubles() As Double = {1.5E+104, 9.0E+103, -2.0E+103}

' Determine the smallest number in the array.
Dim min As Double = doubles.Min()

' Display the result.
MsgBox("The smallest number is " & min)

' This code produces the following output:
'
' The smallest number is -2E+103

備註

@No__t-0 方法會使用 IComparable<T>Int32 執行來比較值。The Min(IEnumerable<Int32>) method uses the Int32 implementation of IComparable<T> to compare values.

在 Visual Basic 查詢運算式語法中,@no__t 0 子句會轉譯為 Min 的調用。In Visual Basic query expression syntax, an Aggregate Into Min() clause translates to an invocation of Min.

另請參閱

Min(IEnumerable<Nullable<Decimal>>)

傳回可為 Null 之 Decimal 值序列中的最小值。Returns the minimum value in a sequence of nullable Decimal values.

public:
[System::Runtime::CompilerServices::Extension]
 static Nullable<System::Decimal> Min(System::Collections::Generic::IEnumerable<Nullable<System::Decimal>> ^ source);
public static Nullable<decimal> Min (this System.Collections.Generic.IEnumerable<Nullable<decimal>> source);
static member Min : seq<Nullable<decimal>> -> Nullable<decimal>
<Extension()>
Public Function Min (source As IEnumerable(Of Nullable(Of Decimal))) As Nullable(Of Decimal)

參數

source
IEnumerable<Nullable<Decimal>>

要判斷最小值之可為 Null 的 Decimal 值序列。A sequence of nullable Decimal values to determine the minimum value of.

傳回

C# 中類型為 Nullable<Decimal> 或 Visual Basic 中類型為 Nullable(Of Decimal) 的值,其對應於序列中的最小值。A value of type Nullable<Decimal> in C# or Nullable(Of Decimal) in Visual Basic that corresponds to the minimum value in the sequence.

例外狀況

sourcenullsource is null.

範例

下列程式碼範例示範如何使用 Min(IEnumerable<Nullable<Int32>>) 來判斷序列中的最小值。The following code example demonstrates how to use Min(IEnumerable<Nullable<Int32>>) to determine the minimum value in a sequence.

注意

這個程式碼範例會使用此多載方法的多載,這個多載不是本主題描述的特定多載。This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. 若要擴充範例以符合本主題內容,請以具有適當數值類型的項目取代來源序列的項目。To extend the example to this topic, substitute the elements of the source sequence with elements of the appropriate numerical type.

int?[] grades = { 78, 92, null, 99, 37, 81 };

int? min = grades.Min();

Console.WriteLine("The lowest grade is {0}.", min);

/*
 This code produces the following output:

 The lowest grade is 37.
*/
Dim grades() As Nullable(Of Integer) = {78, 92, Nothing, 99, 37, 81}
Dim min As Nullable(Of Integer) = grades.Min()

' Display the output.
MsgBox("The lowest grade is " & min)

' This code produces the following output:
'
' The lowest grade is 37

備註

@No__t-0 方法會使用 IComparable<T>Decimal 執行來比較值。The Min(IEnumerable<Nullable<Decimal>>) method uses the Decimal implementation of IComparable<T> to compare values.

如果來源序列是空的或只包含 null 的值,則此函式會傳回 nullIf the source sequence is empty or contains only values that are null, this function returns null.

在 Visual Basic 查詢運算式語法中,@no__t 0 子句會轉譯為 Min 的調用。In Visual Basic query expression syntax, an Aggregate Into Min() clause translates to an invocation of Min.

另請參閱

Min(IEnumerable<Decimal>)

傳回 Decimal 值序列中的最小值。Returns the minimum value in a sequence of Decimal values.

public:
[System::Runtime::CompilerServices::Extension]
 static System::Decimal Min(System::Collections::Generic::IEnumerable<System::Decimal> ^ source);
public static decimal Min (this System.Collections.Generic.IEnumerable<decimal> source);
static member Min : seq<decimal> -> decimal
<Extension()>
Public Function Min (source As IEnumerable(Of Decimal)) As Decimal

參數

source
IEnumerable<Decimal>

要判斷最小值的 Decimal 值序列。A sequence of Decimal values to determine the minimum value of.

傳回

序列中的最小值。The minimum value in the sequence.

例外狀況

sourcenullsource is null.

source 沒有包含任何項目。source contains no elements.

範例

下列程式碼範例示範如何使用 Min(IEnumerable<Double>) 來判斷序列中的最小值。The following code example demonstrates how to use Min(IEnumerable<Double>) to determine the minimum value in a sequence.

注意

這個程式碼範例會使用此多載方法的多載,這個多載不是本主題描述的特定多載。This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. 若要擴充範例以符合本主題內容,請以具有適當數值類型的項目取代來源序列的項目。To extend the example to this topic, substitute the elements of the source sequence with elements of the appropriate numerical type.

double[] doubles = { 1.5E+104, 9E+103, -2E+103 };

double min = doubles.Min();

Console.WriteLine("The smallest number is {0}.", min);

/*
 This code produces the following output:

 The smallest number is -2E+103.
*/
' Create an array of double values.
Dim doubles() As Double = {1.5E+104, 9.0E+103, -2.0E+103}

' Determine the smallest number in the array.
Dim min As Double = doubles.Min()

' Display the result.
MsgBox("The smallest number is " & min)

' This code produces the following output:
'
' The smallest number is -2E+103

備註

@No__t-0 方法會使用 IComparable<T>Decimal 執行來比較值。The Min(IEnumerable<Decimal>) method uses the Decimal implementation of IComparable<T> to compare values.

在 Visual Basic 查詢運算式語法中,@no__t 0 子句會轉譯為 Min 的調用。In Visual Basic query expression syntax, an Aggregate Into Min() clause translates to an invocation of Min.

另請參閱

Min<TSource,TResult>(IEnumerable<TSource>, Func<TSource,TResult>)

在泛型序列的每個項目上叫用轉換函式,並傳回最小的結果值。Invokes a transform function on each element of a generic sequence and returns the minimum resulting value.

public:
generic <typename TSource, typename TResult>
[System::Runtime::CompilerServices::Extension]
 static TResult Min(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, TResult> ^ selector);
public static TResult Min<TSource,TResult> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,TResult> selector);
static member Min : seq<'Source> * Func<'Source, 'Result> -> 'Result
<Extension()>
Public Function Min(Of TSource, TResult) (source As IEnumerable(Of TSource), selector As Func(Of TSource, TResult)) As TResult

類型參數

TSource

source 項目的類型。The type of the elements of source.

TResult

selector 所傳回值的型別。The type of the value returned by selector.

參數

source
IEnumerable<TSource>

要判斷最小值的值序列。A sequence of values to determine the minimum value of.

selector
Func<TSource,TResult>

要套用至每個項目的轉換函式。A transform function to apply to each element.

傳回

TResult

序列中的最小值。The minimum value in the sequence.

例外狀況

sourceselectornullsource or selector is null.

範例

下列程式碼範例示範如何使用 Min<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) 來判斷一系列預計值中的最小值。The following code example demonstrates how to use Min<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) to determine the minimum value in a sequence of projected values.

注意

這個程式碼範例會使用此多載方法的多載,這個多載不是本主題描述的特定多載。This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. 若要將此範例延伸到本主題中使用,請變更 selector 函式的主體。To extend the example to this topic, change the body of the selector function.

class Pet
{
    public string Name { get; set; }
    public int Age { get; set; }
}

public static void MinEx4()
{
    Pet[] pets = { new Pet { Name="Barley", Age=8 },
                   new Pet { Name="Boots", Age=4 },
                   new Pet { Name="Whiskers", Age=1 } };

    int min = pets.Min(pet => pet.Age);

    Console.WriteLine("The youngest animal is age {0}.", min);
}

/*
 This code produces the following output:

 The youngest animal is age 1.  
*/
Structure Pet
    Public Name As String
    Public Age As Integer
End Structure

Sub MinEx4()
    ' Create an array of Pet objects.
    Dim pets() As Pet = {New Pet With {.Name = "Barley", .Age = 8},
                     New Pet With {.Name = "Boots", .Age = 4},
                     New Pet With {.Name = "Whiskers", .Age = 1}}

    ' Find the youngest pet by passing a 
    ' lambda expression to the Min() method.
    Dim min As Integer = pets.Min(Function(pet) pet.Age)

    ' Display the result.
    MsgBox("The youngest pet is age " & min)
End Sub

' This code produces the following output:
'
' The youngest pet is age 1

備註

如果類型 TResult 會實 IComparable<T>,這個方法會使用該執行來比較值。If type TResult implements IComparable<T>, this method uses that implementation to compare values. 否則,如果類型 TResult 會執行 IComparable,則該實作為用來比較值。Otherwise, if type TResult implements IComparable, that implementation is used to compare values.

在 Visual Basic 查詢運算式語法中,@no__t 0 子句會轉譯為 Min 的調用。In Visual Basic query expression syntax, an Aggregate Into Min() clause translates to an invocation of Min.

另請參閱

Min<TSource>(IEnumerable<TSource>, Func<TSource,Single>)

在序列的每個項目上叫用轉換函式,並傳回最小的 Single 值。Invokes a transform function on each element of a sequence and returns the minimum Single value.

public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
 static float Min(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, float> ^ selector);
public static float Min<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,float> selector);
static member Min : seq<'Source> * Func<'Source, single> -> single
<Extension()>
Public Function Min(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Single)) As Single

類型參數

TSource

source 項目的類型。The type of the elements of source.

參數

source
IEnumerable<TSource>

要判斷最小值的值序列。A sequence of values to determine the minimum value of.

selector
Func<TSource,Single>

要套用至每個項目的轉換函式。A transform function to apply to each element.

傳回

序列中的最小值。The minimum value in the sequence.

例外狀況

sourceselectornullsource or selector is null.

source 沒有包含任何項目。source contains no elements.

範例

下列程式碼範例示範如何使用 Min<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) 來判斷一系列預計值中的最小值。The following code example demonstrates how to use Min<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) to determine the minimum value in a sequence of projected values.

注意

這個程式碼範例會使用此多載方法的多載,這個多載不是本主題描述的特定多載。This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. 若要將此範例延伸到本主題中使用,請變更 selector 函式的主體。To extend the example to this topic, change the body of the selector function.

class Pet
{
    public string Name { get; set; }
    public int Age { get; set; }
}

public static void MinEx4()
{
    Pet[] pets = { new Pet { Name="Barley", Age=8 },
                   new Pet { Name="Boots", Age=4 },
                   new Pet { Name="Whiskers", Age=1 } };

    int min = pets.Min(pet => pet.Age);

    Console.WriteLine("The youngest animal is age {0}.", min);
}

/*
 This code produces the following output:

 The youngest animal is age 1.  
*/
Structure Pet
    Public Name As String
    Public Age As Integer
End Structure

Sub MinEx4()
    ' Create an array of Pet objects.
    Dim pets() As Pet = {New Pet With {.Name = "Barley", .Age = 8},
                     New Pet With {.Name = "Boots", .Age = 4},
                     New Pet With {.Name = "Whiskers", .Age = 1}}

    ' Find the youngest pet by passing a 
    ' lambda expression to the Min() method.
    Dim min As Integer = pets.Min(Function(pet) pet.Age)

    ' Display the result.
    MsgBox("The youngest pet is age " & min)
End Sub

' This code produces the following output:
'
' The youngest pet is age 1

備註

@No__t-0 方法會使用 IComparable<T>Single 執行來比較值。The Min<TSource>(IEnumerable<TSource>, Func<TSource,Single>) method uses the Single implementation of IComparable<T> to compare values.

如果您提供函數 selector,將 source 的成員投射至數數值型別,特別是 Single,您可以將此方法套用至任意值的序列。You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Single.

在 Visual Basic 查詢運算式語法中,@no__t 0 子句會轉譯為 Min 的調用。In Visual Basic query expression syntax, an Aggregate Into Min() clause translates to an invocation of Min.

另請參閱

Min<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Single>>)

在序列的每個項目上叫用轉換函式,並傳回最小的可為 Null 之 Single 值。Invokes a transform function on each element of a sequence and returns the minimum nullable Single value.

public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
 static Nullable<float> Min(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, Nullable<float>> ^ selector);
public static Nullable<float> Min<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,Nullable<float>> selector);
static member Min : seq<'Source> * Func<'Source, Nullable<single>> -> Nullable<single>
<Extension()>
Public Function Min(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Nullable(Of Single))) As Nullable(Of Single)

類型參數

TSource

source 項目的類型。The type of the elements of source.

參數

source
IEnumerable<TSource>

要判斷最小值的值序列。A sequence of values to determine the minimum value of.

selector
Func<TSource,Nullable<Single>>

要套用至每個項目的轉換函式。A transform function to apply to each element.

傳回

C# 中類型為 Nullable<Single> 或 Visual Basic 中類型為 Nullable(Of Single) 的值,其對應於序列中的最小值。The value of type Nullable<Single> in C# or Nullable(Of Single) in Visual Basic that corresponds to the minimum value in the sequence.

例外狀況

sourceselectornullsource or selector is null.

範例

下列程式碼範例示範如何使用 Min<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) 來判斷一系列預計值中的最小值。The following code example demonstrates how to use Min<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) to determine the minimum value in a sequence of projected values.

注意

這個程式碼範例會使用此多載方法的多載,這個多載不是本主題描述的特定多載。This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. 若要將此範例延伸到本主題中使用,請變更 selector 函式的主體。To extend the example to this topic, change the body of the selector function.

class Pet
{
    public string Name { get; set; }
    public int Age { get; set; }
}

public static void MinEx4()
{
    Pet[] pets = { new Pet { Name="Barley", Age=8 },
                   new Pet { Name="Boots", Age=4 },
                   new Pet { Name="Whiskers", Age=1 } };

    int min = pets.Min(pet => pet.Age);

    Console.WriteLine("The youngest animal is age {0}.", min);
}

/*
 This code produces the following output:

 The youngest animal is age 1.  
*/
Structure Pet
    Public Name As String
    Public Age As Integer
End Structure

Sub MinEx4()
    ' Create an array of Pet objects.
    Dim pets() As Pet = {New Pet With {.Name = "Barley", .Age = 8},
                     New Pet With {.Name = "Boots", .Age = 4},
                     New Pet With {.Name = "Whiskers", .Age = 1}}

    ' Find the youngest pet by passing a 
    ' lambda expression to the Min() method.
    Dim min As Integer = pets.Min(Function(pet) pet.Age)

    ' Display the result.
    MsgBox("The youngest pet is age " & min)
End Sub

' This code produces the following output:
'
' The youngest pet is age 1

備註

@No__t-0 方法會使用 IComparable<T>Single 執行來比較值。The Min<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Single>>) method uses the Single implementation of IComparable<T> to compare values.

如果您提供函式 selector,將 source 的成員投射至數數值型別,特別是 @no__t 在C# Visual Basic 中的 Nullable<Single>,則可以將此方法套用至任意值的序列。You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Nullable<Single> in C# or Nullable(Of Single) in Visual Basic.

在 Visual Basic 查詢運算式語法中,@no__t 0 子句會轉譯為 Min 的調用。In Visual Basic query expression syntax, an Aggregate Into Min() clause translates to an invocation of Min.

另請參閱

Min<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Int64>>)

在序列的每個項目上叫用轉換函式,並傳回最小的可為 Null 之 Int64 值。Invokes a transform function on each element of a sequence and returns the minimum nullable Int64 value.

public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
 static Nullable<long> Min(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, Nullable<long>> ^ selector);
public static Nullable<long> Min<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,Nullable<long>> selector);
static member Min : seq<'Source> * Func<'Source, Nullable<int64>> -> Nullable<int64>
<Extension()>
Public Function Min(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Nullable(Of Long))) As Nullable(Of Long)

類型參數

TSource

source 項目的類型。The type of the elements of source.

參數

source
IEnumerable<TSource>

要判斷最小值的值序列。A sequence of values to determine the minimum value of.

selector
Func<TSource,Nullable<Int64>>

要套用至每個項目的轉換函式。A transform function to apply to each element.

傳回

C# 中類型為 Nullable<Int64> 或 Visual Basic 中類型為 Nullable(Of Int64) 的值,其對應於序列中的最小值。The value of type Nullable<Int64> in C# or Nullable(Of Int64) in Visual Basic that corresponds to the minimum value in the sequence.

例外狀況

sourceselectornullsource or selector is null.

範例

下列程式碼範例示範如何使用 Min<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) 來判斷一系列預計值中的最小值。The following code example demonstrates how to use Min<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) to determine the minimum value in a sequence of projected values.

注意

這個程式碼範例會使用此多載方法的多載,這個多載不是本主題描述的特定多載。This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. 若要將此範例延伸到本主題中使用,請變更 selector 函式的主體。To extend the example to this topic, change the body of the selector function.

class Pet
{
    public string Name { get; set; }
    public int Age { get; set; }
}

public static void MinEx4()
{
    Pet[] pets = { new Pet { Name="Barley", Age=8 },
                   new Pet { Name="Boots", Age=4 },
                   new Pet { Name="Whiskers", Age=1 } };

    int min = pets.Min(pet => pet.Age);

    Console.WriteLine("The youngest animal is age {0}.", min);
}

/*
 This code produces the following output:

 The youngest animal is age 1.  
*/
Structure Pet
    Public Name As String
    Public Age As Integer
End Structure

Sub MinEx4()
    ' Create an array of Pet objects.
    Dim pets() As Pet = {New Pet With {.Name = "Barley", .Age = 8},
                     New Pet With {.Name = "Boots", .Age = 4},
                     New Pet With {.Name = "Whiskers", .Age = 1}}

    ' Find the youngest pet by passing a 
    ' lambda expression to the Min() method.
    Dim min As Integer = pets.Min(Function(pet) pet.Age)

    ' Display the result.
    MsgBox("The youngest pet is age " & min)
End Sub

' This code produces the following output:
'
' The youngest pet is age 1

備註

@No__t-0 方法會使用 IComparable<T>Int64 執行來比較值。The Min<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Int64>>) method uses the Int64 implementation of IComparable<T> to compare values.

如果您提供函式 selector,將 source 的成員投射至數數值型別,特別是 @no__t 在C# Visual Basic 中的 Nullable<Int64>,則可以將此方法套用至任意值的序列。You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Nullable<Int64> in C# or Nullable(Of Int64) in Visual Basic.

在 Visual Basic 查詢運算式語法中,@no__t 0 子句會轉譯為 Min 的調用。In Visual Basic query expression syntax, an Aggregate Into Min() clause translates to an invocation of Min.

另請參閱

Min<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Int32>>)

在序列的每個項目上叫用轉換函式,並傳回最小的可為 Null 之 Int32 值。Invokes a transform function on each element of a sequence and returns the minimum nullable Int32 value.

public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
 static Nullable<int> Min(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, Nullable<int>> ^ selector);
public static Nullable<int> Min<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,Nullable<int>> selector);
static member Min : seq<'Source> * Func<'Source, Nullable<int>> -> Nullable<int>
<Extension()>
Public Function Min(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Nullable(Of Integer))) As Nullable(Of Integer)

類型參數

TSource

source 項目的類型。The type of the elements of source.

參數

source
IEnumerable<TSource>

要判斷最小值的值序列。A sequence of values to determine the minimum value of.

selector
Func<TSource,Nullable<Int32>>

要套用至每個項目的轉換函式。A transform function to apply to each element.

傳回

C# 中類型為 Nullable<Int32> 或 Visual Basic 中類型為 Nullable(Of Int32) 的值,其對應於序列中的最小值。The value of type Nullable<Int32> in C# or Nullable(Of Int32) in Visual Basic that corresponds to the minimum value in the sequence.

例外狀況

sourceselectornullsource or selector is null.

範例

下列程式碼範例示範如何使用 Min<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) 來判斷一系列預計值中的最小值。The following code example demonstrates how to use Min<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) to determine the minimum value in a sequence of projected values.

注意

這個程式碼範例會使用此多載方法的多載,這個多載不是本主題描述的特定多載。This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. 若要將此範例延伸到本主題中使用,請變更 selector 函式的主體。To extend the example to this topic, change the body of the selector function.

class Pet
{
    public string Name { get; set; }
    public int Age { get; set; }
}

public static void MinEx4()
{
    Pet[] pets = { new Pet { Name="Barley", Age=8 },
                   new Pet { Name="Boots", Age=4 },
                   new Pet { Name="Whiskers", Age=1 } };

    int min = pets.Min(pet => pet.Age);

    Console.WriteLine("The youngest animal is age {0}.", min);
}

/*
 This code produces the following output:

 The youngest animal is age 1.  
*/
Structure Pet
    Public Name As String
    Public Age As Integer
End Structure

Sub MinEx4()
    ' Create an array of Pet objects.
    Dim pets() As Pet = {New Pet With {.Name = "Barley", .Age = 8},
                     New Pet With {.Name = "Boots", .Age = 4},
                     New Pet With {.Name = "Whiskers", .Age = 1}}

    ' Find the youngest pet by passing a 
    ' lambda expression to the Min() method.
    Dim min As Integer = pets.Min(Function(pet) pet.Age)

    ' Display the result.
    MsgBox("The youngest pet is age " & min)
End Sub

' This code produces the following output:
'
' The youngest pet is age 1

備註

@No__t-0 方法會使用 IComparable<T>Int32 執行來比較值。The Min<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Int32>>) method uses the Int32 implementation of IComparable<T> to compare values.

如果您提供函式 selector,將來源的成員投射至數數值型別(特別是 @no__t 在C# Visual Basic 中的 Nullable<Int32>),則可以將此方法套用至任意值的序列。You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Nullable<Int32> in C# or Nullable(Of Int32) in Visual Basic.

在 Visual Basic 查詢運算式語法中,@no__t 0 子句會轉譯為 Min 的調用。In Visual Basic query expression syntax, an Aggregate Into Min() clause translates to an invocation of Min.

另請參閱

Min<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Double>>)

在序列的每個項目上叫用轉換函式,並傳回最小的可為 Null 之 Double 值。Invokes a transform function on each element of a sequence and returns the minimum nullable Double value.

public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
 static Nullable<double> Min(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, Nullable<double>> ^ selector);
public static Nullable<double> Min<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,Nullable<double>> selector);
static member Min : seq<'Source> * Func<'Source, Nullable<double>> -> Nullable<double>
<Extension()>
Public Function Min(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Nullable(Of Double))) As Nullable(Of Double)

類型參數

TSource

source 項目的類型。The type of the elements of source.

參數

source
IEnumerable<TSource>

要判斷最小值的值序列。A sequence of values to determine the minimum value of.

selector
Func<TSource,Nullable<Double>>

要套用至每個項目的轉換函式。A transform function to apply to each element.

傳回

C# 中類型為 Nullable<Double> 或 Visual Basic 中類型為 Nullable(Of Double) 的值,其對應於序列中的最小值。The value of type Nullable<Double> in C# or Nullable(Of Double) in Visual Basic that corresponds to the minimum value in the sequence.

例外狀況

sourceselectornullsource or selector is null.

範例

下列程式碼範例示範如何使用 Min<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) 來判斷一系列預計值中的最小值。The following code example demonstrates how to use Min<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) to determine the minimum value in a sequence of projected values.

注意

這個程式碼範例會使用此多載方法的多載,這個多載不是本主題描述的特定多載。This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. 若要將此範例延伸到本主題中使用,請變更 selector 函式的主體。To extend the example to this topic, change the body of the selector function.

class Pet
{
    public string Name { get; set; }
    public int Age { get; set; }
}

public static void MinEx4()
{
    Pet[] pets = { new Pet { Name="Barley", Age=8 },
                   new Pet { Name="Boots", Age=4 },
                   new Pet { Name="Whiskers", Age=1 } };

    int min = pets.Min(pet => pet.Age);

    Console.WriteLine("The youngest animal is age {0}.", min);
}

/*
 This code produces the following output:

 The youngest animal is age 1.  
*/
Structure Pet
    Public Name As String
    Public Age As Integer
End Structure

Sub MinEx4()
    ' Create an array of Pet objects.
    Dim pets() As Pet = {New Pet With {.Name = "Barley", .Age = 8},
                     New Pet With {.Name = "Boots", .Age = 4},
                     New Pet With {.Name = "Whiskers", .Age = 1}}

    ' Find the youngest pet by passing a 
    ' lambda expression to the Min() method.
    Dim min As Integer = pets.Min(Function(pet) pet.Age)

    ' Display the result.
    MsgBox("The youngest pet is age " & min)
End Sub

' This code produces the following output:
'
' The youngest pet is age 1

備註

@No__t-0 方法會使用 IComparable<T>Double 執行來比較值。The Min<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Double>>) method uses the Double implementation of IComparable<T> to compare values.

如果您提供函式 selector,將 source 的成員投射至數數值型別,特別是 @no__t 在C# Visual Basic 中的 Nullable<Double>,則可以將此方法套用至任意值的序列。You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Nullable<Double> in C# or Nullable(Of Double) in Visual Basic.

在 Visual Basic 查詢運算式語法中,@no__t 0 子句會轉譯為 Min 的調用。In Visual Basic query expression syntax, an Aggregate Into Min() clause translates to an invocation of Min.

另請參閱

Min<TSource>(IEnumerable<TSource>, Func<TSource,Int64>)

在序列的每個項目上叫用轉換函式,並傳回最小的 Int64 值。Invokes a transform function on each element of a sequence and returns the minimum Int64 value.

public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
 static long Min(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, long> ^ selector);
public static long Min<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,long> selector);
static member Min : seq<'Source> * Func<'Source, int64> -> int64
<Extension()>
Public Function Min(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Long)) As Long

類型參數

TSource

source 項目的類型。The type of the elements of source.

參數

source
IEnumerable<TSource>

要判斷最小值的值序列。A sequence of values to determine the minimum value of.

selector
Func<TSource,Int64>

要套用至每個項目的轉換函式。A transform function to apply to each element.

傳回

序列中的最小值。The minimum value in the sequence.

例外狀況

sourceselectornullsource or selector is null.

source 沒有包含任何項目。source contains no elements.

範例

下列程式碼範例示範如何使用 Min<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) 來判斷一系列預計值中的最小值。The following code example demonstrates how to use Min<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) to determine the minimum value in a sequence of projected values.

注意

這個程式碼範例會使用此多載方法的多載,這個多載不是本主題描述的特定多載。This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. 若要將此範例延伸到本主題中使用,請變更 selector 函式的主體。To extend the example to this topic, change the body of the selector function.

class Pet
{
    public string Name { get; set; }
    public int Age { get; set; }
}

public static void MinEx4()
{
    Pet[] pets = { new Pet { Name="Barley", Age=8 },
                   new Pet { Name="Boots", Age=4 },
                   new Pet { Name="Whiskers", Age=1 } };

    int min = pets.Min(pet => pet.Age);

    Console.WriteLine("The youngest animal is age {0}.", min);
}

/*
 This code produces the following output:

 The youngest animal is age 1.  
*/
Structure Pet
    Public Name As String
    Public Age As Integer
End Structure

Sub MinEx4()
    ' Create an array of Pet objects.
    Dim pets() As Pet = {New Pet With {.Name = "Barley", .Age = 8},
                     New Pet With {.Name = "Boots", .Age = 4},
                     New Pet With {.Name = "Whiskers", .Age = 1}}

    ' Find the youngest pet by passing a 
    ' lambda expression to the Min() method.
    Dim min As Integer = pets.Min(Function(pet) pet.Age)

    ' Display the result.
    MsgBox("The youngest pet is age " & min)
End Sub

' This code produces the following output:
'
' The youngest pet is age 1

備註

@No__t-0 方法會使用 IComparable<T>Int64 執行來比較值。The Min<TSource>(IEnumerable<TSource>, Func<TSource,Int64>) method uses the Int64 implementation of IComparable<T> to compare values.

如果您提供函數 selector,將 source 的成員投射至數數值型別,特別是 Int64,您可以將此方法套用至任意值的序列。You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Int64.

在 Visual Basic 查詢運算式語法中,@no__t 0 子句會轉譯為 Min 的調用。In Visual Basic query expression syntax, an Aggregate Into Min() clause translates to an invocation of Min.

另請參閱

Min<TSource>(IEnumerable<TSource>, Func<TSource,Int32>)

在序列的每個項目上叫用轉換函式,並傳回最小的 Int32 值。Invokes a transform function on each element of a sequence and returns the minimum Int32 value.

public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
 static int Min(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, int> ^ selector);
public static int Min<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,int> selector);
static member Min : seq<'Source> * Func<'Source, int> -> int
<Extension()>
Public Function Min(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Integer)) As Integer

類型參數

TSource

source 項目的類型。The type of the elements of source.

參數

source
IEnumerable<TSource>

要判斷最小值的值序列。A sequence of values to determine the minimum value of.

selector
Func<TSource,Int32>

要套用至每個項目的轉換函式。A transform function to apply to each element.

傳回

序列中的最小值。The minimum value in the sequence.

例外狀況

sourceselectornullsource or selector is null.

source 沒有包含任何項目。source contains no elements.

範例

下列程式碼範例示範如何使用 Min<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) 來判斷一系列預計值中的最小值。The following code example demonstrates how to use Min<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) to determine the minimum value in a sequence of projected values.

class Pet
{
    public string Name { get; set; }
    public int Age { get; set; }
}

public static void MinEx4()
{
    Pet[] pets = { new Pet { Name="Barley", Age=8 },
                   new Pet { Name="Boots", Age=4 },
                   new Pet { Name="Whiskers", Age=1 } };

    int min = pets.Min(pet => pet.Age);

    Console.WriteLine("The youngest animal is age {0}.", min);
}

/*
 This code produces the following output:

 The youngest animal is age 1.  
*/
Structure Pet
    Public Name As String
    Public Age As Integer
End Structure

Sub MinEx4()
    ' Create an array of Pet objects.
    Dim pets() As Pet = {New Pet With {.Name = "Barley", .Age = 8},
                     New Pet With {.Name = "Boots", .Age = 4},
                     New Pet With {.Name = "Whiskers", .Age = 1}}

    ' Find the youngest pet by passing a 
    ' lambda expression to the Min() method.
    Dim min As Integer = pets.Min(Function(pet) pet.Age)

    ' Display the result.
    MsgBox("The youngest pet is age " & min)
End Sub

' This code produces the following output:
'
' The youngest pet is age 1

備註

@No__t-0 方法會使用 IComparable<T>Int32 執行來比較值。The Min<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) method uses the Int32 implementation of IComparable<T> to compare values.

如果您提供函數 selector,將 source 的成員投射至數數值型別,特別是 Int32,您可以將此方法套用至任意值的序列。You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Int32.

在 Visual Basic 查詢運算式語法中,@no__t 0 子句會轉譯為 Min 的調用。In Visual Basic query expression syntax, an Aggregate Into Min() clause translates to an invocation of Min.

另請參閱

Min<TSource>(IEnumerable<TSource>, Func<TSource,Double>)

在序列的每個項目上叫用轉換函式,並傳回最小的 Double 值。Invokes a transform function on each element of a sequence and returns the minimum Double value.

public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
 static double Min(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, double> ^ selector);
public static double Min<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,double> selector);
static member Min : seq<'Source> * Func<'Source, double> -> double
<Extension()>
Public Function Min(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Double)) As Double

類型參數

TSource

source 項目的類型。The type of the elements of source.

參數

source
IEnumerable<TSource>

要判斷最小值的值序列。A sequence of values to determine the minimum value of.

selector
Func<TSource,Double>

要套用至每個項目的轉換函式。A transform function to apply to each element.

傳回

序列中的最小值。The minimum value in the sequence.

例外狀況

sourceselectornullsource or selector is null.

source 沒有包含任何項目。source contains no elements.

範例

下列程式碼範例示範如何使用 Min<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) 來判斷一系列預計值中的最小值。The following code example demonstrates how to use Min<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) to determine the minimum value in a sequence of projected values.

注意

這個程式碼範例會使用此多載方法的多載,這個多載不是本主題描述的特定多載。This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. 若要將此範例延伸到本主題中使用,請變更 selector 函式的主體。To extend the example to this topic, change the body of the selector function.

class Pet
{
    public string Name { get; set; }
    public int Age { get; set; }
}

public static void MinEx4()
{
    Pet[] pets = { new Pet { Name="Barley", Age=8 },
                   new Pet { Name="Boots", Age=4 },
                   new Pet { Name="Whiskers", Age=1 } };

    int min = pets.Min(pet => pet.Age);

    Console.WriteLine("The youngest animal is age {0}.", min);
}

/*
 This code produces the following output:

 The youngest animal is age 1.  
*/
Structure Pet
    Public Name As String
    Public Age As Integer
End Structure

Sub MinEx4()
    ' Create an array of Pet objects.
    Dim pets() As Pet = {New Pet With {.Name = "Barley", .Age = 8},
                     New Pet With {.Name = "Boots", .Age = 4},
                     New Pet With {.Name = "Whiskers", .Age = 1}}

    ' Find the youngest pet by passing a 
    ' lambda expression to the Min() method.
    Dim min As Integer = pets.Min(Function(pet) pet.Age)

    ' Display the result.
    MsgBox("The youngest pet is age " & min)
End Sub

' This code produces the following output:
'
' The youngest pet is age 1

備註

@No__t-0 方法會使用 IComparable<T>Double 執行來比較值。The Min<TSource>(IEnumerable<TSource>, Func<TSource,Double>) method uses the Double implementation of IComparable<T> to compare values.

如果您提供函數 selector,將 source 的成員投射至數數值型別,特別是 Double,您可以將此方法套用至任意值的序列。You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Double.

在 Visual Basic 查詢運算式語法中,@no__t 0 子句會轉譯為 Min 的調用。In Visual Basic query expression syntax, an Aggregate Into Min() clause translates to an invocation of Min.

另請參閱

Min<TSource>(IEnumerable<TSource>, Func<TSource,Decimal>)

在序列的每個項目上叫用轉換函式,並傳回最小的 Decimal 值。Invokes a transform function on each element of a sequence and returns the minimum Decimal value.

public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
 static System::Decimal Min(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, System::Decimal> ^ selector);
public static decimal Min<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,decimal> selector);
static member Min : seq<'Source> * Func<'Source, decimal> -> decimal
<Extension()>
Public Function Min(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Decimal)) As Decimal

類型參數

TSource

source 項目的類型。The type of the elements of source.

參數

source
IEnumerable<TSource>

要判斷最小值的值序列。A sequence of values to determine the minimum value of.

selector
Func<TSource,Decimal>

要套用至每個項目的轉換函式。A transform function to apply to each element.

傳回

序列中的最小值。The minimum value in the sequence.

例外狀況

sourceselectornullsource or selector is null.

source 沒有包含任何項目。source contains no elements.

範例

下列程式碼範例示範如何使用 Min<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) 來判斷一系列預計值中的最小值。The following code example demonstrates how to use Min<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) to determine the minimum value in a sequence of projected values.

注意

這個程式碼範例會使用此多載方法的多載,這個多載不是本主題描述的特定多載。This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. 若要將此範例延伸到本主題中使用,請變更 selector 函式的主體。To extend the example to this topic, change the body of the selector function.

class Pet
{
    public string Name { get; set; }
    public int Age { get; set; }
}

public static void MinEx4()
{
    Pet[] pets = { new Pet { Name="Barley", Age=8 },
                   new Pet { Name="Boots", Age=4 },
                   new Pet { Name="Whiskers", Age=1 } };

    int min = pets.Min(pet => pet.Age);

    Console.WriteLine("The youngest animal is age {0}.", min);
}

/*
 This code produces the following output:

 The youngest animal is age 1.  
*/
Structure Pet
    Public Name As String
    Public Age As Integer
End Structure

Sub MinEx4()
    ' Create an array of Pet objects.
    Dim pets() As Pet = {New Pet With {.Name = "Barley", .Age = 8},
                     New Pet With {.Name = "Boots", .Age = 4},
                     New Pet With {.Name = "Whiskers", .Age = 1}}

    ' Find the youngest pet by passing a 
    ' lambda expression to the Min() method.
    Dim min As Integer = pets.Min(Function(pet) pet.Age)

    ' Display the result.
    MsgBox("The youngest pet is age " & min)
End Sub

' This code produces the following output:
'
' The youngest pet is age 1

備註

@No__t-0 方法會使用 IComparable<T>Decimal 執行來比較值。The Min<TSource>(IEnumerable<TSource>, Func<TSource,Decimal>) method uses the Decimal implementation of IComparable<T> to compare values.

如果您提供函數 selector,將 source 的成員投射至數數值型別,特別是 Decimal,您可以將此方法套用至任意值的序列。You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Decimal.

在 Visual Basic 查詢運算式語法中,@no__t 0 子句會轉譯為 Min 的調用。In Visual Basic query expression syntax, an Aggregate Into Min() clause translates to an invocation of Min.

另請參閱

Min<TSource>(IEnumerable<TSource>)

傳回泛型序列中的最小值。Returns the minimum value in a generic sequence.

public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
 static TSource Min(System::Collections::Generic::IEnumerable<TSource> ^ source);
public static TSource Min<TSource> (this System.Collections.Generic.IEnumerable<TSource> source);
static member Min : seq<'Source> -> 'Source
<Extension()>
Public Function Min(Of TSource) (source As IEnumerable(Of TSource)) As TSource

類型參數

TSource

source 項目的類型。The type of the elements of source.

參數

source
IEnumerable<TSource>

要判斷最小值的值序列。A sequence of values to determine the minimum value of.

傳回

TSource

序列中的最小值。The minimum value in the sequence.

例外狀況

sourcenullsource is null.

source 中沒有任何物件實作 IComparableIComparable<T> 介面。No object in source implements the IComparable or IComparable<T> interface.

範例

下列程式碼範例示範如何使用 Min<TSource>(IEnumerable<TSource>) 來判斷一系列 IComparable<T> 物件中的最小值。The following code example demonstrates how to use Min<TSource>(IEnumerable<TSource>) to determine the minimum value in a sequence of IComparable<T> objects.

/// <summary>
/// This class implements IComparable in order to 
/// be able to compare different Pet objects.
/// </summary>
class Pet : IComparable<Pet>
{
    public string Name { get; set; }
    public int Age { get; set; }

    /// <summary>
    /// Compares this Pet's age to another Pet's age.
    /// </summary>
    /// <param name="other">The Pet to compare this Pet to.</param>
    /// <returns>-1 if this Pet's age is smaller, 
    /// 0 if the Pets' ages are equal, or 
    /// 1 if this Pet's age is greater.</returns>
    int IComparable<Pet>.CompareTo(Pet other)
    {
        if (other.Age > this.Age)
            return -1;
        else if (other.Age == this.Age)
            return 0;
        else
            return 1;
    }
}

public static void MinEx3()
{
    Pet[] pets = { new Pet { Name="Barley", Age=8 },
                   new Pet { Name="Boots", Age=4 },
                   new Pet { Name="Whiskers", Age=1 } };

    Pet min = pets.Min();

    Console.WriteLine(
        "The 'minimum' animal is {0}.",
        min.Name);
}

/*
 This code produces the following output:

 The 'minimum' animal is Whiskers.
*/
' This class implements IComparable 
' and has a custom 'CompareTo' implementation.
Class Pet
    Implements IComparable(Of Pet)

    Public Name As String
    Public Age As Integer

    ''' <summary>
    ''' Compares this Pet's age to another Pet's age.
    ''' </summary>
    ''' <param name="other">The Pet to compare this Pet to.</param>
    ''' <returns>-1 if this Pet's age is smaller,
    ''' 0 if the Pets' ages are equal,
    ''' or 1 if this Pet's age is greater.</returns>
    Function CompareTo(ByVal other As Pet) As Integer _
    Implements IComparable(Of Pet).CompareTo

        If (other.Age > Me.Age) Then
            Return -1
        ElseIf (other.Age = Me.Age) Then
            Return 0
        Else
            Return 1
        End If
    End Function
End Class

Sub MinEx3()
    ' Create an array of Pet objects.
    Dim pets() As Pet = {New Pet With {.Name = "Barley", .Age = 8},
                     New Pet With {.Name = "Boots", .Age = 4},
                     New Pet With {.Name = "Whiskers", .Age = 1}}

    ' Determine the "minimum" pet in the array,
    ' according to the custom CompareTo() implementation.
    Dim min As Pet = pets.Min()

    ' Display the result.
    MsgBox("The 'minimum' pet is " & min.Name)
End Sub

' This code produces the following output:
'
' The 'minimum' pet is Whiskers

備註

如果類型 TSource 會實 IComparable<T>,這個方法會使用該執行來比較值。If type TSource implements IComparable<T>, this method uses that implementation to compare values. 否則,如果類型 TSource 會執行 IComparable,則該實作為用來比較值。Otherwise, if type TSource implements IComparable, that implementation is used to compare values.

如果 TSource 是參考型別,而來源序列是空的或只包含 null 的值,則此函式會傳回 nullIf TSource is a reference type and the source sequence is empty or contains only values that are null, this function returns null.

在 Visual Basic 查詢運算式語法中,@no__t 0 子句會轉譯為 Min 的調用。In Visual Basic query expression syntax, an Aggregate Into Min() clause translates to an invocation of Min.

另請參閱

Min<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Decimal>>)

在序列的每個項目上叫用轉換函式,並傳回最小的可為 Null 之 Decimal 值。Invokes a transform function on each element of a sequence and returns the minimum nullable Decimal value.

public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
 static Nullable<System::Decimal> Min(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, Nullable<System::Decimal>> ^ selector);
public static Nullable<decimal> Min<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,Nullable<decimal>> selector);
static member Min : seq<'Source> * Func<'Source, Nullable<decimal>> -> Nullable<decimal>
<Extension()>
Public Function Min(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Nullable(Of Decimal))) As Nullable(Of Decimal)

類型參數

TSource

source 項目的類型。The type of the elements of source.

參數

source
IEnumerable<TSource>

要判斷最小值的值序列。A sequence of values to determine the minimum value of.

selector
Func<TSource,Nullable<Decimal>>

要套用至每個項目的轉換函式。A transform function to apply to each element.

傳回

C# 中類型為 Nullable<Decimal> 或 Visual Basic 中類型為 Nullable(Of Decimal) 的值,其對應於序列中的最小值。The value of type Nullable<Decimal> in C# or Nullable(Of Decimal) in Visual Basic that corresponds to the minimum value in the sequence.

例外狀況

sourceselectornullsource or selector is null.

範例

下列程式碼範例示範如何使用 Min<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) 來判斷一系列預計值中的最小值。The following code example demonstrates how to use Min<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) to determine the minimum value in a sequence of projected values.

注意

這個程式碼範例會使用此多載方法的多載,這個多載不是本主題描述的特定多載。This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. 若要將此範例延伸到本主題中使用,請變更 selector 函式的主體。To extend the example to this topic, change the body of the selector function.

class Pet
{
    public string Name { get; set; }
    public int Age { get; set; }
}

public static void MinEx4()
{
    Pet[] pets = { new Pet { Name="Barley", Age=8 },
                   new Pet { Name="Boots", Age=4 },
                   new Pet { Name="Whiskers", Age=1 } };

    int min = pets.Min(pet => pet.Age);

    Console.WriteLine("The youngest animal is age {0}.", min);
}

/*
 This code produces the following output:

 The youngest animal is age 1.  
*/
Structure Pet
    Public Name As String
    Public Age As Integer
End Structure

Sub MinEx4()
    ' Create an array of Pet objects.
    Dim pets() As Pet = {New Pet With {.Name = "Barley", .Age = 8},
                     New Pet With {.Name = "Boots", .Age = 4},
                     New Pet With {.Name = "Whiskers", .Age = 1}}

    ' Find the youngest pet by passing a 
    ' lambda expression to the Min() method.
    Dim min As Integer = pets.Min(Function(pet) pet.Age)

    ' Display the result.
    MsgBox("The youngest pet is age " & min)
End Sub

' This code produces the following output:
'
' The youngest pet is age 1

備註

@No__t-0 方法會使用 IComparable<T>Decimal 執行來比較值。The Min<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Decimal>>) method uses the Decimal implementation of IComparable<T> to compare values.

如果您提供函式 selector,將 source 的成員投射至數數值型別,特別是 @no__t 在C# Visual Basic 中的 Nullable<Decimal>,則可以將此方法套用至任意值的序列。You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Nullable<Decimal> in C# or Nullable(Of Decimal) in Visual Basic.

在 Visual Basic 查詢運算式語法中,@no__t 0 子句會轉譯為 Min 的調用。In Visual Basic query expression syntax, an Aggregate Into Min() clause translates to an invocation of Min.

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