Enumerable.Sum Enumerable.Sum Enumerable.Sum Enumerable.Sum Method

定義

計算數值序列的總和。Computes the sum of a sequence of numeric values.

多載

Sum(IEnumerable<Nullable<Int32>>) Sum(IEnumerable<Nullable<Int32>>) Sum(IEnumerable<Nullable<Int32>>) Sum(IEnumerable<Nullable<Int32>>)

計算可為 null 的序列的總和Int32值。Computes the sum of a sequence of nullable Int32 values.

Sum(IEnumerable<Nullable<Single>>) Sum(IEnumerable<Nullable<Single>>) Sum(IEnumerable<Nullable<Single>>) Sum(IEnumerable<Nullable<Single>>)

計算可為 null 的序列的總和Single值。Computes the sum of a sequence of nullable Single values.

Sum(IEnumerable<Nullable<Int64>>) Sum(IEnumerable<Nullable<Int64>>) Sum(IEnumerable<Nullable<Int64>>) Sum(IEnumerable<Nullable<Int64>>)

計算可為 null 的序列的總和Int64值。Computes the sum of a sequence of nullable Int64 values.

Sum(IEnumerable<Single>) Sum(IEnumerable<Single>) Sum(IEnumerable<Single>) Sum(IEnumerable<Single>)

計算序列的總和Single值。Computes the sum of a sequence of Single values.

Sum(IEnumerable<Nullable<Double>>) Sum(IEnumerable<Nullable<Double>>) Sum(IEnumerable<Nullable<Double>>) Sum(IEnumerable<Nullable<Double>>)

計算可為 null 的序列的總和Double值。Computes the sum of a sequence of nullable Double values.

Sum(IEnumerable<Int32>) Sum(IEnumerable<Int32>) Sum(IEnumerable<Int32>) Sum(IEnumerable<Int32>)

計算序列的總和Int32值。Computes the sum of a sequence of Int32 values.

Sum(IEnumerable<Int64>) Sum(IEnumerable<Int64>) Sum(IEnumerable<Int64>) Sum(IEnumerable<Int64>)

計算序列的總和Int64值。Computes the sum of a sequence of Int64 values.

Sum(IEnumerable<Double>) Sum(IEnumerable<Double>) Sum(IEnumerable<Double>) Sum(IEnumerable<Double>)

計算序列的總和Double值。Computes the sum of a sequence of Double values.

Sum(IEnumerable<Decimal>) Sum(IEnumerable<Decimal>) Sum(IEnumerable<Decimal>) Sum(IEnumerable<Decimal>)

計算序列的總和Decimal值。Computes the sum of a sequence of Decimal values.

Sum(IEnumerable<Nullable<Decimal>>) Sum(IEnumerable<Nullable<Decimal>>) Sum(IEnumerable<Nullable<Decimal>>) Sum(IEnumerable<Nullable<Decimal>>)

計算可為 null 的序列的總和Decimal值。Computes the sum of a sequence of nullable Decimal values.

Sum<TSource>(IEnumerable<TSource>, Func<TSource,Single>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Single>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Single>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Single>)

計算序列的總和Single叫用轉換函式的輸入序列的每個項目所取得的值。Computes the sum of the sequence of Single values that are obtained by invoking a transform function on each element of the input sequence.

Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Single>>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Single>>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Single>>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Single>>)

計算可為 null 的序列的總和Single叫用轉換函式的輸入序列的每個項目所取得的值。Computes the sum of the sequence of nullable Single values that are obtained by invoking a transform function on each element of the input sequence.

Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Int64>>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Int64>>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Int64>>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Int64>>)

計算可為 null 的序列的總和Int64叫用轉換函式的輸入序列的每個項目所取得的值。Computes the sum of the sequence of nullable Int64 values that are obtained by invoking a transform function on each element of the input sequence.

Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Int32>>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Int32>>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Int32>>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Int32>>)

計算可為 null 的序列的總和Int32叫用轉換函式的輸入序列的每個項目所取得的值。Computes the sum of the sequence of nullable Int32 values that are obtained by invoking a transform function on each element of the input sequence.

Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Double>>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Double>>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Double>>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Double>>)

計算可為 null 的序列的總和Double叫用轉換函式的輸入序列的每個項目所取得的值。Computes the sum of the sequence of nullable Double values that are obtained by invoking a transform function on each element of the input sequence.

Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Decimal>>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Decimal>>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Decimal>>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Decimal>>)

計算可為 null 的序列的總和Decimal叫用轉換函式的輸入序列的每個項目所取得的值。Computes the sum of the sequence of nullable Decimal values that are obtained by invoking a transform function on each element of the input sequence.

Sum<TSource>(IEnumerable<TSource>, Func<TSource,Int64>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Int64>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Int64>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Int64>)

計算序列的總和Int64叫用轉換函式的輸入序列的每個項目所取得的值。Computes the sum of the sequence of Int64 values that are obtained by invoking a transform function on each element of the input sequence.

Sum<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Int32>)

計算序列的總和Int32叫用轉換函式的輸入序列的每個項目所取得的值。Computes the sum of the sequence of Int32 values that are obtained by invoking a transform function on each element of the input sequence.

Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>)

計算序列的總和Double叫用轉換函式的輸入序列的每個項目所取得的值。Computes the sum of the sequence of Double values that are obtained by invoking a transform function on each element of the input sequence.

Sum<TSource>(IEnumerable<TSource>, Func<TSource,Decimal>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Decimal>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Decimal>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Decimal>)

計算序列的總和Decimal叫用轉換函式的輸入序列的每個項目所取得的值。Computes the sum of the sequence of Decimal values that are obtained by invoking a transform function on each element of the input sequence.

Sum(IEnumerable<Nullable<Int32>>) Sum(IEnumerable<Nullable<Int32>>) Sum(IEnumerable<Nullable<Int32>>) Sum(IEnumerable<Nullable<Int32>>)

計算可為 null 的序列的總和Int32值。Computes the sum of a sequence of nullable Int32 values.

public:
[System::Runtime::CompilerServices::Extension]
 static Nullable<int> Sum(System::Collections::Generic::IEnumerable<Nullable<int>> ^ source);
public static Nullable<int> Sum (this System.Collections.Generic.IEnumerable<Nullable<int>> source);
static member Sum : seq<Nullable<int>> -> Nullable<int>
<Extension()>
Public Function Sum (source As IEnumerable(Of Nullable(Of Integer))) As Nullable(Of Integer)

參數

source
IEnumerable<Nullable<Int32>>

可為 null 的序列Int32來計算總和的值。A sequence of nullable Int32 values to calculate the sum of.

傳回

序列中值的總和。The sum of the values in the sequence.

例外狀況

範例

下列程式碼範例示範如何使用Sum(IEnumerable<Nullable<Single>>)加總的一連串的值。The following code example demonstrates how to use Sum(IEnumerable<Nullable<Single>>) to sum the values of a sequence.

注意

這個程式碼範例會使用此多載方法的多載,這個多載不是本主題描述的特定多載。This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. 若要擴充範例以符合本主題內容,請以具有適當數值類型的項目取代來源序列的項目。To extend the example to this topic, substitute the elements of the source sequence with elements of the appropriate numerical type.

float?[] points = { null, 0, 92.83F, null, 100.0F, 37.46F, 81.1F };

float? sum = points.Sum();

Console.WriteLine("Total points earned: {0}", sum);

/*
 This code produces the following output:

 Total points earned: 311.39
*/
' Create an array of Nullable Single values.
Dim points() As Nullable(Of Single) =
{Nothing, 0, 92.83F, Nothing, 100.0F, 37.46F, 81.1F}

' Get the sum of values in the list.
Dim sum As Nullable(Of Single) = points.Sum()

' Display the output.
MsgBox("Total points earned: " & sum)

' This code produces the following output:
'
' Total points earned: 311.39

備註

這個方法會傳回零,如果source包含任何項目。This method returns zero if source contains no elements.

結果不包含值nullThe result does not include values that are null.

在 Visual Basic 查詢運算式語法中,Aggregate Into Sum()子句會轉譯成的引動過程SumIn Visual Basic query expression syntax, an Aggregate Into Sum() clause translates to an invocation of Sum.

另請參閱

Sum(IEnumerable<Nullable<Single>>) Sum(IEnumerable<Nullable<Single>>) Sum(IEnumerable<Nullable<Single>>) Sum(IEnumerable<Nullable<Single>>)

計算可為 null 的序列的總和Single值。Computes the sum of a sequence of nullable Single values.

public:
[System::Runtime::CompilerServices::Extension]
 static Nullable<float> Sum(System::Collections::Generic::IEnumerable<Nullable<float>> ^ source);
public static Nullable<float> Sum (this System.Collections.Generic.IEnumerable<Nullable<float>> source);
static member Sum : seq<Nullable<single>> -> Nullable<single>
<Extension()>
Public Function Sum (source As IEnumerable(Of Nullable(Of Single))) As Nullable(Of Single)

參數

source
IEnumerable<Nullable<Single>>

可為 null 的序列Single來計算總和的值。A sequence of nullable Single values to calculate the sum of.

傳回

序列中值的總和。The sum of the values in the sequence.

例外狀況

範例

下列程式碼範例示範如何使用Sum(IEnumerable<Nullable<Single>>)加總的一連串的值。The following code example demonstrates how to use Sum(IEnumerable<Nullable<Single>>) to sum the values of a sequence.

float?[] points = { null, 0, 92.83F, null, 100.0F, 37.46F, 81.1F };

float? sum = points.Sum();

Console.WriteLine("Total points earned: {0}", sum);

/*
 This code produces the following output:

 Total points earned: 311.39
*/
' Create an array of Nullable Single values.
Dim points() As Nullable(Of Single) =
{Nothing, 0, 92.83F, Nothing, 100.0F, 37.46F, 81.1F}

' Get the sum of values in the list.
Dim sum As Nullable(Of Single) = points.Sum()

' Display the output.
MsgBox("Total points earned: " & sum)

' This code produces the following output:
'
' Total points earned: 311.39

備註

這個方法會傳回零,如果source包含任何項目。This method returns zero if source contains no elements.

結果不包含值nullThe result does not include values that are null.

在 Visual Basic 查詢運算式語法中,Aggregate Into Sum()子句會轉譯成的引動過程SumIn Visual Basic query expression syntax, an Aggregate Into Sum() clause translates to an invocation of Sum.

另請參閱

Sum(IEnumerable<Nullable<Int64>>) Sum(IEnumerable<Nullable<Int64>>) Sum(IEnumerable<Nullable<Int64>>) Sum(IEnumerable<Nullable<Int64>>)

計算可為 null 的序列的總和Int64值。Computes the sum of a sequence of nullable Int64 values.

public:
[System::Runtime::CompilerServices::Extension]
 static Nullable<long> Sum(System::Collections::Generic::IEnumerable<Nullable<long>> ^ source);
public static Nullable<long> Sum (this System.Collections.Generic.IEnumerable<Nullable<long>> source);
static member Sum : seq<Nullable<int64>> -> Nullable<int64>
<Extension()>
Public Function Sum (source As IEnumerable(Of Nullable(Of Long))) As Nullable(Of Long)

參數

source
IEnumerable<Nullable<Int64>>

可為 null 的序列Int64來計算總和的值。A sequence of nullable Int64 values to calculate the sum of.

傳回

序列中值的總和。The sum of the values in the sequence.

例外狀況

範例

下列程式碼範例示範如何使用Sum(IEnumerable<Nullable<Single>>)加總的一連串的值。The following code example demonstrates how to use Sum(IEnumerable<Nullable<Single>>) to sum the values of a sequence.

注意

這個程式碼範例會使用此多載方法的多載,這個多載不是本主題描述的特定多載。This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. 若要擴充範例以符合本主題內容,請以具有適當數值類型的項目取代來源序列的項目。To extend the example to this topic, substitute the elements of the source sequence with elements of the appropriate numerical type.

float?[] points = { null, 0, 92.83F, null, 100.0F, 37.46F, 81.1F };

float? sum = points.Sum();

Console.WriteLine("Total points earned: {0}", sum);

/*
 This code produces the following output:

 Total points earned: 311.39
*/
' Create an array of Nullable Single values.
Dim points() As Nullable(Of Single) =
{Nothing, 0, 92.83F, Nothing, 100.0F, 37.46F, 81.1F}

' Get the sum of values in the list.
Dim sum As Nullable(Of Single) = points.Sum()

' Display the output.
MsgBox("Total points earned: " & sum)

' This code produces the following output:
'
' Total points earned: 311.39

備註

這個方法會傳回零,如果source包含任何項目。This method returns zero if source contains no elements.

結果不包含值nullThe result does not include values that are null.

在 Visual Basic 查詢運算式語法中,Aggregate Into Sum()子句會轉譯成的引動過程SumIn Visual Basic query expression syntax, an Aggregate Into Sum() clause translates to an invocation of Sum.

另請參閱

Sum(IEnumerable<Single>) Sum(IEnumerable<Single>) Sum(IEnumerable<Single>) Sum(IEnumerable<Single>)

計算序列的總和Single值。Computes the sum of a sequence of Single values.

public:
[System::Runtime::CompilerServices::Extension]
 static float Sum(System::Collections::Generic::IEnumerable<float> ^ source);
public static float Sum (this System.Collections.Generic.IEnumerable<float> source);
static member Sum : seq<single> -> single
<Extension()>
Public Function Sum (source As IEnumerable(Of Single)) As Single

參數

source
IEnumerable<Single>

一連串的Single來計算總和的值。A sequence of Single values to calculate the sum of.

傳回

序列中值的總和。The sum of the values in the sequence.

例外狀況

範例

下列程式碼範例示範如何使用Sum(IEnumerable<Single>)加總的一連串的值。The following code example demonstrates how to use Sum(IEnumerable<Single>) to sum the values of a sequence.

List<float> numbers = new List<float> { 43.68F, 1.25F, 583.7F, 6.5F };

float sum = numbers.Sum();

Console.WriteLine("The sum of the numbers is {0}.", sum);

/*
 This code produces the following output:

 The sum of the numbers is 635.13.
*/
' Create a list of Single values.
Dim numbers As New List(Of Single)(New Single() _
                               {43.68F, 1.25F, 583.7F, 6.5F})

' Get the sum of values in the list.
Dim sum As Single = numbers.Sum()

' Display the output.
MsgBox("The sum of the numbers is " & sum)

' This code produces the following output:
'
' The sum of the numbers is 635.13

備註

這個方法會傳回零,如果source包含任何項目。This method returns zero if source contains no elements.

在 Visual Basic 查詢運算式語法中,Aggregate Into Sum()子句會轉譯成的引動過程SumIn Visual Basic query expression syntax, an Aggregate Into Sum() clause translates to an invocation of Sum.

另請參閱

Sum(IEnumerable<Nullable<Double>>) Sum(IEnumerable<Nullable<Double>>) Sum(IEnumerable<Nullable<Double>>) Sum(IEnumerable<Nullable<Double>>)

計算可為 null 的序列的總和Double值。Computes the sum of a sequence of nullable Double values.

public:
[System::Runtime::CompilerServices::Extension]
 static Nullable<double> Sum(System::Collections::Generic::IEnumerable<Nullable<double>> ^ source);
public static Nullable<double> Sum (this System.Collections.Generic.IEnumerable<Nullable<double>> source);
static member Sum : seq<Nullable<double>> -> Nullable<double>
<Extension()>
Public Function Sum (source As IEnumerable(Of Nullable(Of Double))) As Nullable(Of Double)

參數

source
IEnumerable<Nullable<Double>>

可為 null 的序列Double來計算總和的值。A sequence of nullable Double values to calculate the sum of.

傳回

序列中值的總和。The sum of the values in the sequence.

例外狀況

範例

下列程式碼範例示範如何使用Sum(IEnumerable<Nullable<Single>>)加總的一連串的值。The following code example demonstrates how to use Sum(IEnumerable<Nullable<Single>>) to sum the values of a sequence.

注意

這個程式碼範例會使用此多載方法的多載,這個多載不是本主題描述的特定多載。This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. 若要擴充範例以符合本主題內容,請以具有適當數值類型的項目取代來源序列的項目。To extend the example to this topic, substitute the elements of the source sequence with elements of the appropriate numerical type.

float?[] points = { null, 0, 92.83F, null, 100.0F, 37.46F, 81.1F };

float? sum = points.Sum();

Console.WriteLine("Total points earned: {0}", sum);

/*
 This code produces the following output:

 Total points earned: 311.39
*/
' Create an array of Nullable Single values.
Dim points() As Nullable(Of Single) =
{Nothing, 0, 92.83F, Nothing, 100.0F, 37.46F, 81.1F}

' Get the sum of values in the list.
Dim sum As Nullable(Of Single) = points.Sum()

' Display the output.
MsgBox("Total points earned: " & sum)

' This code produces the following output:
'
' Total points earned: 311.39

備註

這個方法會傳回零,如果source包含任何項目。This method returns zero if source contains no elements.

結果不包含值nullThe result does not include values that are null.

在 Visual Basic 查詢運算式語法中,Aggregate Into Sum()子句會轉譯成的引動過程SumIn Visual Basic query expression syntax, an Aggregate Into Sum() clause translates to an invocation of Sum.

另請參閱

Sum(IEnumerable<Int32>) Sum(IEnumerable<Int32>) Sum(IEnumerable<Int32>) Sum(IEnumerable<Int32>)

計算序列的總和Int32值。Computes the sum of a sequence of Int32 values.

public:
[System::Runtime::CompilerServices::Extension]
 static int Sum(System::Collections::Generic::IEnumerable<int> ^ source);
public static int Sum (this System.Collections.Generic.IEnumerable<int> source);
static member Sum : seq<int> -> int
<Extension()>
Public Function Sum (source As IEnumerable(Of Integer)) As Integer

參數

source
IEnumerable<Int32>

一連串的Int32來計算總和的值。A sequence of Int32 values to calculate the sum of.

傳回

序列中值的總和。The sum of the values in the sequence.

例外狀況

範例

下列程式碼範例示範如何使用Sum(IEnumerable<Single>)加總的一連串的值。The following code example demonstrates how to use Sum(IEnumerable<Single>) to sum the values of a sequence.

注意

這個程式碼範例會使用此多載方法的多載,這個多載不是本主題描述的特定多載。This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. 若要擴充範例以符合本主題內容,請以具有適當數值類型的項目取代來源序列的項目。To extend the example to this topic, substitute the elements of the source sequence with elements of the appropriate numerical type.

List<float> numbers = new List<float> { 43.68F, 1.25F, 583.7F, 6.5F };

float sum = numbers.Sum();

Console.WriteLine("The sum of the numbers is {0}.", sum);

/*
 This code produces the following output:

 The sum of the numbers is 635.13.
*/
' Create a list of Single values.
Dim numbers As New List(Of Single)(New Single() _
                               {43.68F, 1.25F, 583.7F, 6.5F})

' Get the sum of values in the list.
Dim sum As Single = numbers.Sum()

' Display the output.
MsgBox("The sum of the numbers is " & sum)

' This code produces the following output:
'
' The sum of the numbers is 635.13

備註

這個方法會傳回零,如果source包含任何項目。This method returns zero if source contains no elements.

在 Visual Basic 查詢運算式語法中,Aggregate Into Sum()子句會轉譯成的引動過程SumIn Visual Basic query expression syntax, an Aggregate Into Sum() clause translates to an invocation of Sum.

另請參閱

Sum(IEnumerable<Int64>) Sum(IEnumerable<Int64>) Sum(IEnumerable<Int64>) Sum(IEnumerable<Int64>)

計算序列的總和Int64值。Computes the sum of a sequence of Int64 values.

public:
[System::Runtime::CompilerServices::Extension]
 static long Sum(System::Collections::Generic::IEnumerable<long> ^ source);
public static long Sum (this System.Collections.Generic.IEnumerable<long> source);
static member Sum : seq<int64> -> int64
<Extension()>
Public Function Sum (source As IEnumerable(Of Long)) As Long

參數

source
IEnumerable<Int64>

一連串的Int64來計算總和的值。A sequence of Int64 values to calculate the sum of.

傳回

序列中值的總和。The sum of the values in the sequence.

例外狀況

範例

下列程式碼範例示範如何使用Sum(IEnumerable<Single>)加總的一連串的值。The following code example demonstrates how to use Sum(IEnumerable<Single>) to sum the values of a sequence.

注意

這個程式碼範例會使用此多載方法的多載,這個多載不是本主題描述的特定多載。This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. 若要擴充範例以符合本主題內容,請以具有適當數值類型的項目取代來源序列的項目。To extend the example to this topic, substitute the elements of the source sequence with elements of the appropriate numerical type.

List<float> numbers = new List<float> { 43.68F, 1.25F, 583.7F, 6.5F };

float sum = numbers.Sum();

Console.WriteLine("The sum of the numbers is {0}.", sum);

/*
 This code produces the following output:

 The sum of the numbers is 635.13.
*/
' Create a list of Single values.
Dim numbers As New List(Of Single)(New Single() _
                               {43.68F, 1.25F, 583.7F, 6.5F})

' Get the sum of values in the list.
Dim sum As Single = numbers.Sum()

' Display the output.
MsgBox("The sum of the numbers is " & sum)

' This code produces the following output:
'
' The sum of the numbers is 635.13

備註

這個方法會傳回零,如果source包含任何項目。This method returns zero if source contains no elements.

在 Visual Basic 查詢運算式語法中,Aggregate Into Sum()子句會轉譯成的引動過程SumIn Visual Basic query expression syntax, an Aggregate Into Sum() clause translates to an invocation of Sum.

另請參閱

Sum(IEnumerable<Double>) Sum(IEnumerable<Double>) Sum(IEnumerable<Double>) Sum(IEnumerable<Double>)

計算序列的總和Double值。Computes the sum of a sequence of Double values.

public:
[System::Runtime::CompilerServices::Extension]
 static double Sum(System::Collections::Generic::IEnumerable<double> ^ source);
public static double Sum (this System.Collections.Generic.IEnumerable<double> source);
static member Sum : seq<double> -> double
<Extension()>
Public Function Sum (source As IEnumerable(Of Double)) As Double

參數

source
IEnumerable<Double>

一連串的Double來計算總和的值。A sequence of Double values to calculate the sum of.

傳回

序列中值的總和。The sum of the values in the sequence.

例外狀況

範例

下列程式碼範例示範如何使用Sum(IEnumerable<Single>)加總的一連串的值。The following code example demonstrates how to use Sum(IEnumerable<Single>) to sum the values of a sequence.

注意

這個程式碼範例會使用此多載方法的多載,這個多載不是本主題描述的特定多載。This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. 若要擴充範例以符合本主題內容,請以具有適當數值類型的項目取代來源序列的項目。To extend the example to this topic, substitute the elements of the source sequence with elements of the appropriate numerical type.

List<float> numbers = new List<float> { 43.68F, 1.25F, 583.7F, 6.5F };

float sum = numbers.Sum();

Console.WriteLine("The sum of the numbers is {0}.", sum);

/*
 This code produces the following output:

 The sum of the numbers is 635.13.
*/
' Create a list of Single values.
Dim numbers As New List(Of Single)(New Single() _
                               {43.68F, 1.25F, 583.7F, 6.5F})

' Get the sum of values in the list.
Dim sum As Single = numbers.Sum()

' Display the output.
MsgBox("The sum of the numbers is " & sum)

' This code produces the following output:
'
' The sum of the numbers is 635.13

備註

這個方法會傳回零,如果source包含任何項目。This method returns zero if source contains no elements.

在 Visual Basic 查詢運算式語法中,Aggregate Into Sum()子句會轉譯成的引動過程SumIn Visual Basic query expression syntax, an Aggregate Into Sum() clause translates to an invocation of Sum.

另請參閱

Sum(IEnumerable<Decimal>) Sum(IEnumerable<Decimal>) Sum(IEnumerable<Decimal>) Sum(IEnumerable<Decimal>)

計算序列的總和Decimal值。Computes the sum of a sequence of Decimal values.

public:
[System::Runtime::CompilerServices::Extension]
 static System::Decimal Sum(System::Collections::Generic::IEnumerable<System::Decimal> ^ source);
public static decimal Sum (this System.Collections.Generic.IEnumerable<decimal> source);
static member Sum : seq<decimal> -> decimal
<Extension()>
Public Function Sum (source As IEnumerable(Of Decimal)) As Decimal

參數

source
IEnumerable<Decimal>

一連串的Decimal來計算總和的值。A sequence of Decimal values to calculate the sum of.

傳回

序列中值的總和。The sum of the values in the sequence.

例外狀況

範例

下列程式碼範例示範如何使用Sum(IEnumerable<Single>)加總的一連串的值。The following code example demonstrates how to use Sum(IEnumerable<Single>) to sum the values of a sequence.

注意

這個程式碼範例會使用此多載方法的多載,這個多載不是本主題描述的特定多載。This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. 若要擴充範例以符合本主題內容,請以具有適當數值類型的項目取代來源序列的項目。To extend the example to this topic, substitute the elements of the source sequence with elements of the appropriate numerical type.

List<float> numbers = new List<float> { 43.68F, 1.25F, 583.7F, 6.5F };

float sum = numbers.Sum();

Console.WriteLine("The sum of the numbers is {0}.", sum);

/*
 This code produces the following output:

 The sum of the numbers is 635.13.
*/
' Create a list of Single values.
Dim numbers As New List(Of Single)(New Single() _
                               {43.68F, 1.25F, 583.7F, 6.5F})

' Get the sum of values in the list.
Dim sum As Single = numbers.Sum()

' Display the output.
MsgBox("The sum of the numbers is " & sum)

' This code produces the following output:
'
' The sum of the numbers is 635.13

備註

Sum(IEnumerable<Decimal>)方法會傳回零,如果source包含任何項目。The Sum(IEnumerable<Decimal>) method returns zero if source contains no elements.

在 Visual Basic 查詢運算式語法中,Aggregate Into Sum()子句會轉譯成的引動過程SumIn Visual Basic query expression syntax, an Aggregate Into Sum() clause translates to an invocation of Sum.

另請參閱

Sum(IEnumerable<Nullable<Decimal>>) Sum(IEnumerable<Nullable<Decimal>>) Sum(IEnumerable<Nullable<Decimal>>) Sum(IEnumerable<Nullable<Decimal>>)

計算可為 null 的序列的總和Decimal值。Computes the sum of a sequence of nullable Decimal values.

public:
[System::Runtime::CompilerServices::Extension]
 static Nullable<System::Decimal> Sum(System::Collections::Generic::IEnumerable<Nullable<System::Decimal>> ^ source);
public static Nullable<decimal> Sum (this System.Collections.Generic.IEnumerable<Nullable<decimal>> source);
static member Sum : seq<Nullable<decimal>> -> Nullable<decimal>
<Extension()>
Public Function Sum (source As IEnumerable(Of Nullable(Of Decimal))) As Nullable(Of Decimal)

參數

source
IEnumerable<Nullable<Decimal>>

可為 null 的序列Decimal來計算總和的值。A sequence of nullable Decimal values to calculate the sum of.

傳回

序列中值的總和。The sum of the values in the sequence.

例外狀況

範例

下列程式碼範例示範如何使用Sum(IEnumerable<Nullable<Single>>)加總的一連串的值。The following code example demonstrates how to use Sum(IEnumerable<Nullable<Single>>) to sum the values of a sequence.

注意

這個程式碼範例會使用此多載方法的多載,這個多載不是本主題描述的特定多載。This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. 若要擴充範例以符合本主題內容,請以具有適當數值類型的項目取代來源序列的項目。To extend the example to this topic, substitute the elements of the source sequence with elements of the appropriate numerical type.

float?[] points = { null, 0, 92.83F, null, 100.0F, 37.46F, 81.1F };

float? sum = points.Sum();

Console.WriteLine("Total points earned: {0}", sum);

/*
 This code produces the following output:

 Total points earned: 311.39
*/
' Create an array of Nullable Single values.
Dim points() As Nullable(Of Single) =
{Nothing, 0, 92.83F, Nothing, 100.0F, 37.46F, 81.1F}

' Get the sum of values in the list.
Dim sum As Nullable(Of Single) = points.Sum()

' Display the output.
MsgBox("Total points earned: " & sum)

' This code produces the following output:
'
' Total points earned: 311.39

備註

這個方法會傳回零,如果source包含任何項目。This method returns zero if source contains no elements.

結果不包含值的nullThe result doesnot include values that are null.

在 Visual Basic 查詢運算式語法中,Aggregate Into Sum()子句會轉譯成的引動過程SumIn Visual Basic query expression syntax, an Aggregate Into Sum() clause translates to an invocation of Sum.

另請參閱

Sum<TSource>(IEnumerable<TSource>, Func<TSource,Single>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Single>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Single>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Single>)

計算序列的總和Single叫用轉換函式的輸入序列的每個項目所取得的值。Computes the sum of the sequence of Single values that are obtained by invoking a transform function on each element of the input sequence.

public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
 static float Sum(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, float> ^ selector);
public static float Sum<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,float> selector);
static member Sum : seq<'Source> * Func<'Source, single> -> single
<Extension()>
Public Function Sum(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Single)) As Single

類型參數

TSource

source 項目的類型。The type of the elements of source.

參數

source
IEnumerable<TSource>

用來計算總和的值序列。A sequence of values that are used to calculate a sum.

selector
Func<TSource,Single>

要套用至每個項目的轉換函式。A transform function to apply to each element.

傳回

預計值的總和。The sum of the projected values.

例外狀況

sourceselectornullsource or selector is null.

範例

下列程式碼範例示範如何使用Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>)加總的預計的值的序列。The following code example demonstrates how to use Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) to sum the projected values of a sequence.

注意

這個程式碼範例會使用此多載方法的多載,這個多載不是本主題描述的特定多載。This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. 若要將此範例延伸到本主題中使用,請變更 selector 函式的主體。To extend the example to this topic, change the body of the selector function.

class Package
{
    public string Company { get; set; }
    public double Weight { get; set; }
}

public static void SumEx1()
{
    List<Package> packages =
        new List<Package> 
            { new Package { Company = "Coho Vineyard", Weight = 25.2 },
              new Package { Company = "Lucerne Publishing", Weight = 18.7 },
              new Package { Company = "Wingtip Toys", Weight = 6.0 },
              new Package { Company = "Adventure Works", Weight = 33.8 } };

    double totalWeight = packages.Sum(pkg => pkg.Weight);

    Console.WriteLine("The total weight of the packages is: {0}", totalWeight);
}

/*
 This code produces the following output:

 The total weight of the packages is: 83.7
*/
Structure Package
    Public Company As String
    Public Weight As Double
End Structure

Sub SumEx1()
    ' Create a list of Package values.
    Dim packages As New List(Of Package)(New Package() _
     {New Package With {.Company = "Coho Vineyard", .Weight = 25.2},
      New Package With {.Company = "Lucerne Publishing", .Weight = 18.7},
      New Package With {.Company = "Wingtip Toys", .Weight = 6.0},
      New Package With {.Company = "Adventure Works", .Weight = 33.8}})

    ' Sum the values from each item's Weight property.
    Dim totalWeight As Double = packages.Sum(Function(pkg) _
                                             pkg.Weight)

    ' Display the result.
    MsgBox("The total weight of the packages is: " & totalWeight)
End Sub

' This code produces the following output:
'
' The total weight of the packages is: 83.7

備註

Sum<TSource>(IEnumerable<TSource>, Func<TSource,Single>)方法會傳回零,如果source包含任何項目。The Sum<TSource>(IEnumerable<TSource>, Func<TSource,Single>) method returns zero if source contains no elements.

您可以將這個方法套用至一連串的任意值,如果您提供函式, selector,,專案的成員source成數值類型,特別是SingleYou can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Single.

在 Visual Basic 查詢運算式語法中,Aggregate Into Sum()子句會轉譯成的引動過程SumIn Visual Basic query expression syntax, an Aggregate Into Sum() clause translates to an invocation of Sum.

另請參閱

Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Single>>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Single>>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Single>>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Single>>)

計算可為 null 的序列的總和Single叫用轉換函式的輸入序列的每個項目所取得的值。Computes the sum of the sequence of nullable Single values that are obtained by invoking a transform function on each element of the input sequence.

public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
 static Nullable<float> Sum(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, Nullable<float>> ^ selector);
public static Nullable<float> Sum<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,Nullable<float>> selector);
static member Sum : seq<'Source> * Func<'Source, Nullable<single>> -> Nullable<single>
<Extension()>
Public Function Sum(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Nullable(Of Single))) As Nullable(Of Single)

類型參數

TSource

source 項目的類型。The type of the elements of source.

參數

source
IEnumerable<TSource>

用來計算總和的值序列。A sequence of values that are used to calculate a sum.

selector
Func<TSource,Nullable<Single>>

要套用至每個項目的轉換函式。A transform function to apply to each element.

傳回

預計值的總和。The sum of the projected values.

例外狀況

sourceselectornullsource or selector is null.

範例

下列程式碼範例示範如何使用Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>)加總的預計的值的序列。The following code example demonstrates how to use Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) to sum the projected values of a sequence.

注意

這個程式碼範例會使用此多載方法的多載,這個多載不是本主題描述的特定多載。This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. 若要將此範例延伸到本主題中使用,請變更 selector 函式的主體。To extend the example to this topic, change the body of the selector function.

class Package
{
    public string Company { get; set; }
    public double Weight { get; set; }
}

public static void SumEx1()
{
    List<Package> packages =
        new List<Package> 
            { new Package { Company = "Coho Vineyard", Weight = 25.2 },
              new Package { Company = "Lucerne Publishing", Weight = 18.7 },
              new Package { Company = "Wingtip Toys", Weight = 6.0 },
              new Package { Company = "Adventure Works", Weight = 33.8 } };

    double totalWeight = packages.Sum(pkg => pkg.Weight);

    Console.WriteLine("The total weight of the packages is: {0}", totalWeight);
}

/*
 This code produces the following output:

 The total weight of the packages is: 83.7
*/
Structure Package
    Public Company As String
    Public Weight As Double
End Structure

Sub SumEx1()
    ' Create a list of Package values.
    Dim packages As New List(Of Package)(New Package() _
     {New Package With {.Company = "Coho Vineyard", .Weight = 25.2},
      New Package With {.Company = "Lucerne Publishing", .Weight = 18.7},
      New Package With {.Company = "Wingtip Toys", .Weight = 6.0},
      New Package With {.Company = "Adventure Works", .Weight = 33.8}})

    ' Sum the values from each item's Weight property.
    Dim totalWeight As Double = packages.Sum(Function(pkg) _
                                             pkg.Weight)

    ' Display the result.
    MsgBox("The total weight of the packages is: " & totalWeight)
End Sub

' This code produces the following output:
'
' The total weight of the packages is: 83.7

備註

這個方法會傳回零,如果source包含任何項目。This method returns zero if source contains no elements.

結果不包含值nullThe result does not include values that are null.

您可以將這個方法套用至一連串的任意值,如果您提供函式, selector,,專案的成員source成數值類型,特別Nullable<Single>在 C# 或Nullable(Of Single)Visual Basic 中。You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Nullable<Single> in C# or Nullable(Of Single) in Visual Basic.

在 Visual Basic 查詢運算式語法中,Aggregate Into Sum()子句會轉譯成的引動過程SumIn Visual Basic query expression syntax, an Aggregate Into Sum() clause translates to an invocation of Sum.

另請參閱

Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Int64>>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Int64>>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Int64>>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Int64>>)

計算可為 null 的序列的總和Int64叫用轉換函式的輸入序列的每個項目所取得的值。Computes the sum of the sequence of nullable Int64 values that are obtained by invoking a transform function on each element of the input sequence.

public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
 static Nullable<long> Sum(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, Nullable<long>> ^ selector);
public static Nullable<long> Sum<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,Nullable<long>> selector);
static member Sum : seq<'Source> * Func<'Source, Nullable<int64>> -> Nullable<int64>
<Extension()>
Public Function Sum(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Nullable(Of Long))) As Nullable(Of Long)

類型參數

TSource

source 項目的類型。The type of the elements of source.

參數

source
IEnumerable<TSource>

用來計算總和的值序列。A sequence of values that are used to calculate a sum.

selector
Func<TSource,Nullable<Int64>>

要套用至每個項目的轉換函式。A transform function to apply to each element.

傳回

預計值的總和。The sum of the projected values.

例外狀況

sourceselectornullsource or selector is null.

範例

下列程式碼範例示範如何使用Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>)加總的預計的值的序列。The following code example demonstrates how to use Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) to sum the projected values of a sequence.

注意

這個程式碼範例會使用此多載方法的多載,這個多載不是本主題描述的特定多載。This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. 若要將此範例延伸到本主題中使用,請變更 selector 函式的主體。To extend the example to this topic, change the body of the selector function.

class Package
{
    public string Company { get; set; }
    public double Weight { get; set; }
}

public static void SumEx1()
{
    List<Package> packages =
        new List<Package> 
            { new Package { Company = "Coho Vineyard", Weight = 25.2 },
              new Package { Company = "Lucerne Publishing", Weight = 18.7 },
              new Package { Company = "Wingtip Toys", Weight = 6.0 },
              new Package { Company = "Adventure Works", Weight = 33.8 } };

    double totalWeight = packages.Sum(pkg => pkg.Weight);

    Console.WriteLine("The total weight of the packages is: {0}", totalWeight);
}

/*
 This code produces the following output:

 The total weight of the packages is: 83.7
*/
Structure Package
    Public Company As String
    Public Weight As Double
End Structure

Sub SumEx1()
    ' Create a list of Package values.
    Dim packages As New List(Of Package)(New Package() _
     {New Package With {.Company = "Coho Vineyard", .Weight = 25.2},
      New Package With {.Company = "Lucerne Publishing", .Weight = 18.7},
      New Package With {.Company = "Wingtip Toys", .Weight = 6.0},
      New Package With {.Company = "Adventure Works", .Weight = 33.8}})

    ' Sum the values from each item's Weight property.
    Dim totalWeight As Double = packages.Sum(Function(pkg) _
                                             pkg.Weight)

    ' Display the result.
    MsgBox("The total weight of the packages is: " & totalWeight)
End Sub

' This code produces the following output:
'
' The total weight of the packages is: 83.7

備註

這個方法會傳回零,如果source包含任何項目。This method returns zero if source contains no elements.

結果不包含值nullThe result does not include values that are null.

您可以將這個方法套用至一連串的任意值,如果您提供函式, selector,,專案的成員source成數值類型,特別Nullable<Int64>在 C# 或Nullable(Of Int64)Visual Basic 中You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Nullable<Int64> in C# or Nullable(Of Int64) in Visual Basic

在 Visual Basic 查詢運算式語法中,Aggregate Into Sum()子句會轉譯成的引動過程SumIn Visual Basic query expression syntax, an Aggregate Into Sum() clause translates to an invocation of Sum.

另請參閱

Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Int32>>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Int32>>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Int32>>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Int32>>)

計算可為 null 的序列的總和Int32叫用轉換函式的輸入序列的每個項目所取得的值。Computes the sum of the sequence of nullable Int32 values that are obtained by invoking a transform function on each element of the input sequence.

public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
 static Nullable<int> Sum(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, Nullable<int>> ^ selector);
public static Nullable<int> Sum<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,Nullable<int>> selector);
static member Sum : seq<'Source> * Func<'Source, Nullable<int>> -> Nullable<int>
<Extension()>
Public Function Sum(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Nullable(Of Integer))) As Nullable(Of Integer)

類型參數

TSource

source 項目的類型。The type of the elements of source.

參數

source
IEnumerable<TSource>

用來計算總和的值序列。A sequence of values that are used to calculate a sum.

selector
Func<TSource,Nullable<Int32>>

要套用至每個項目的轉換函式。A transform function to apply to each element.

傳回

預計值的總和。The sum of the projected values.

例外狀況

sourceselectornullsource or selector is null.

範例

下列程式碼範例示範如何使用Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>)加總的預計的值的序列。The following code example demonstrates how to use Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) to sum the projected values of a sequence.

注意

這個程式碼範例會使用此多載方法的多載,這個多載不是本主題描述的特定多載。This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. 若要將此範例延伸到本主題中使用,請變更 selector 函式的主體。To extend the example to this topic, change the body of the selector function.

class Package
{
    public string Company { get; set; }
    public double Weight { get; set; }
}

public static void SumEx1()
{
    List<Package> packages =
        new List<Package> 
            { new Package { Company = "Coho Vineyard", Weight = 25.2 },
              new Package { Company = "Lucerne Publishing", Weight = 18.7 },
              new Package { Company = "Wingtip Toys", Weight = 6.0 },
              new Package { Company = "Adventure Works", Weight = 33.8 } };

    double totalWeight = packages.Sum(pkg => pkg.Weight);

    Console.WriteLine("The total weight of the packages is: {0}", totalWeight);
}

/*
 This code produces the following output:

 The total weight of the packages is: 83.7
*/
Structure Package
    Public Company As String
    Public Weight As Double
End Structure

Sub SumEx1()
    ' Create a list of Package values.
    Dim packages As New List(Of Package)(New Package() _
     {New Package With {.Company = "Coho Vineyard", .Weight = 25.2},
      New Package With {.Company = "Lucerne Publishing", .Weight = 18.7},
      New Package With {.Company = "Wingtip Toys", .Weight = 6.0},
      New Package With {.Company = "Adventure Works", .Weight = 33.8}})

    ' Sum the values from each item's Weight property.
    Dim totalWeight As Double = packages.Sum(Function(pkg) _
                                             pkg.Weight)

    ' Display the result.
    MsgBox("The total weight of the packages is: " & totalWeight)
End Sub

' This code produces the following output:
'
' The total weight of the packages is: 83.7

備註

這個方法會傳回零,如果source包含任何項目。This method returns zero if source contains no elements.

結果不包含值nullThe result does not include values that are null.

您可以將這個方法套用至一連串的任意值,如果您提供函式, selector,,專案的成員source成數值類型,特別Nullable<Int32>在 C# 或Nullable(Of Int32)Visual Basic 中。You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Nullable<Int32> in C# or Nullable(Of Int32) in Visual Basic.

在 Visual Basic 查詢運算式語法中,Aggregate Into Sum()子句會轉譯成的引動過程SumIn Visual Basic query expression syntax, an Aggregate Into Sum() clause translates to an invocation of Sum.

另請參閱

Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Double>>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Double>>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Double>>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Double>>)

計算可為 null 的序列的總和Double叫用轉換函式的輸入序列的每個項目所取得的值。Computes the sum of the sequence of nullable Double values that are obtained by invoking a transform function on each element of the input sequence.

public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
 static Nullable<double> Sum(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, Nullable<double>> ^ selector);
public static Nullable<double> Sum<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,Nullable<double>> selector);
static member Sum : seq<'Source> * Func<'Source, Nullable<double>> -> Nullable<double>
<Extension()>
Public Function Sum(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Nullable(Of Double))) As Nullable(Of Double)

類型參數

TSource

source 項目的類型。The type of the elements of source.

參數

source
IEnumerable<TSource>

用來計算總和的值序列。A sequence of values that are used to calculate a sum.

selector
Func<TSource,Nullable<Double>>

要套用至每個項目的轉換函式。A transform function to apply to each element.

傳回

預計值的總和。The sum of the projected values.

例外狀況

sourceselectornullsource or selector is null.

範例

下列程式碼範例示範如何使用Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>)加總的預計的值的序列。The following code example demonstrates how to use Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) to sum the projected values of a sequence.

注意

這個程式碼範例會使用此多載方法的多載,這個多載不是本主題描述的特定多載。This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. 若要將此範例延伸到本主題中使用,請變更 selector 函式的主體。To extend the example to this topic, change the body of the selector function.

class Package
{
    public string Company { get; set; }
    public double Weight { get; set; }
}

public static void SumEx1()
{
    List<Package> packages =
        new List<Package> 
            { new Package { Company = "Coho Vineyard", Weight = 25.2 },
              new Package { Company = "Lucerne Publishing", Weight = 18.7 },
              new Package { Company = "Wingtip Toys", Weight = 6.0 },
              new Package { Company = "Adventure Works", Weight = 33.8 } };

    double totalWeight = packages.Sum(pkg => pkg.Weight);

    Console.WriteLine("The total weight of the packages is: {0}", totalWeight);
}

/*
 This code produces the following output:

 The total weight of the packages is: 83.7
*/
Structure Package
    Public Company As String
    Public Weight As Double
End Structure

Sub SumEx1()
    ' Create a list of Package values.
    Dim packages As New List(Of Package)(New Package() _
     {New Package With {.Company = "Coho Vineyard", .Weight = 25.2},
      New Package With {.Company = "Lucerne Publishing", .Weight = 18.7},
      New Package With {.Company = "Wingtip Toys", .Weight = 6.0},
      New Package With {.Company = "Adventure Works", .Weight = 33.8}})

    ' Sum the values from each item's Weight property.
    Dim totalWeight As Double = packages.Sum(Function(pkg) _
                                             pkg.Weight)

    ' Display the result.
    MsgBox("The total weight of the packages is: " & totalWeight)
End Sub

' This code produces the following output:
'
' The total weight of the packages is: 83.7

備註

這個方法會傳回零,如果source包含任何項目。This method returns zero if source contains no elements.

結果不包含值nullThe result does not include values that are null.

您可以將這個方法套用至一連串的任意值,如果您提供函式, selector,,專案的成員source成數值類型,特別Nullable<Double>在 C# 或Nullable(Of Double)Visual Basic 中。You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Nullable<Double> in C# or Nullable(Of Double) in Visual Basic.

在 Visual Basic 查詢運算式語法中,Aggregate Into Sum()子句會轉譯成的引動過程SumIn Visual Basic query expression syntax, an Aggregate Into Sum() clause translates to an invocation of Sum.

另請參閱

Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Decimal>>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Decimal>>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Decimal>>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Decimal>>)

計算可為 null 的序列的總和Decimal叫用轉換函式的輸入序列的每個項目所取得的值。Computes the sum of the sequence of nullable Decimal values that are obtained by invoking a transform function on each element of the input sequence.

public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
 static Nullable<System::Decimal> Sum(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, Nullable<System::Decimal>> ^ selector);
public static Nullable<decimal> Sum<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,Nullable<decimal>> selector);
static member Sum : seq<'Source> * Func<'Source, Nullable<decimal>> -> Nullable<decimal>
<Extension()>
Public Function Sum(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Nullable(Of Decimal))) As Nullable(Of Decimal)

類型參數

TSource

source 項目的類型。The type of the elements of source.

參數

source
IEnumerable<TSource>

用來計算總和的值序列。A sequence of values that are used to calculate a sum.

selector
Func<TSource,Nullable<Decimal>>

要套用至每個項目的轉換函式。A transform function to apply to each element.

傳回

預計值的總和。The sum of the projected values.

例外狀況

sourceselectornullsource or selector is null.

範例

下列程式碼範例示範如何使用Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>)加總的預計的值的序列。The following code example demonstrates how to use Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) to sum the projected values of a sequence.

注意

這個程式碼範例會使用此多載方法的多載,這個多載不是本主題描述的特定多載。This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. 若要將此範例延伸到本主題中使用,請變更 selector 函式的主體。To extend the example to this topic, change the body of the selector function.

class Package
{
    public string Company { get; set; }
    public double Weight { get; set; }
}

public static void SumEx1()
{
    List<Package> packages =
        new List<Package> 
            { new Package { Company = "Coho Vineyard", Weight = 25.2 },
              new Package { Company = "Lucerne Publishing", Weight = 18.7 },
              new Package { Company = "Wingtip Toys", Weight = 6.0 },
              new Package { Company = "Adventure Works", Weight = 33.8 } };

    double totalWeight = packages.Sum(pkg => pkg.Weight);

    Console.WriteLine("The total weight of the packages is: {0}", totalWeight);
}

/*
 This code produces the following output:

 The total weight of the packages is: 83.7
*/
Structure Package
    Public Company As String
    Public Weight As Double
End Structure

Sub SumEx1()
    ' Create a list of Package values.
    Dim packages As New List(Of Package)(New Package() _
     {New Package With {.Company = "Coho Vineyard", .Weight = 25.2},
      New Package With {.Company = "Lucerne Publishing", .Weight = 18.7},
      New Package With {.Company = "Wingtip Toys", .Weight = 6.0},
      New Package With {.Company = "Adventure Works", .Weight = 33.8}})

    ' Sum the values from each item's Weight property.
    Dim totalWeight As Double = packages.Sum(Function(pkg) _
                                             pkg.Weight)

    ' Display the result.
    MsgBox("The total weight of the packages is: " & totalWeight)
End Sub

' This code produces the following output:
'
' The total weight of the packages is: 83.7

備註

這個方法會傳回零,如果source包含任何項目。This method returns zero if source contains no elements.

結果不會不會包含值nullThe result does not included values that are null.

您可以將這個方法套用至一連串的任意值,如果您提供函式, selector,,專案的成員source成數值類型,特別Nullable<Decimal>在 C# 或Nullable(Of Decimal)Visual Basic 中。You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Nullable<Decimal> in C# or Nullable(Of Decimal) in Visual Basic.

在 Visual Basic 查詢運算式語法中,Aggregate Into Sum()子句會轉譯成的引動過程SumIn Visual Basic query expression syntax, an Aggregate Into Sum() clause translates to an invocation of Sum.

另請參閱

Sum<TSource>(IEnumerable<TSource>, Func<TSource,Int64>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Int64>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Int64>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Int64>)

計算序列的總和Int64叫用轉換函式的輸入序列的每個項目所取得的值。Computes the sum of the sequence of Int64 values that are obtained by invoking a transform function on each element of the input sequence.

public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
 static long Sum(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, long> ^ selector);
public static long Sum<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,long> selector);
static member Sum : seq<'Source> * Func<'Source, int64> -> int64
<Extension()>
Public Function Sum(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Long)) As Long

類型參數

TSource

source 項目的類型。The type of the elements of source.

參數

source
IEnumerable<TSource>

用來計算總和的值序列。A sequence of values that are used to calculate a sum.

selector
Func<TSource,Int64>

要套用至每個項目的轉換函式。A transform function to apply to each element.

傳回

預計值的總和。The sum of the projected values.

例外狀況

sourceselectornullsource or selector is null.

範例

下列程式碼範例示範如何使用Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>)加總的預計的值的序列。The following code example demonstrates how to use Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) to sum the projected values of a sequence.

注意

這個程式碼範例會使用此多載方法的多載,這個多載不是本主題描述的特定多載。This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. 若要將此範例延伸到本主題中使用,請變更 selector 函式的主體。To extend the example to this topic, change the body of the selector function.

class Package
{
    public string Company { get; set; }
    public double Weight { get; set; }
}

public static void SumEx1()
{
    List<Package> packages =
        new List<Package> 
            { new Package { Company = "Coho Vineyard", Weight = 25.2 },
              new Package { Company = "Lucerne Publishing", Weight = 18.7 },
              new Package { Company = "Wingtip Toys", Weight = 6.0 },
              new Package { Company = "Adventure Works", Weight = 33.8 } };

    double totalWeight = packages.Sum(pkg => pkg.Weight);

    Console.WriteLine("The total weight of the packages is: {0}", totalWeight);
}

/*
 This code produces the following output:

 The total weight of the packages is: 83.7
*/
Structure Package
    Public Company As String
    Public Weight As Double
End Structure

Sub SumEx1()
    ' Create a list of Package values.
    Dim packages As New List(Of Package)(New Package() _
     {New Package With {.Company = "Coho Vineyard", .Weight = 25.2},
      New Package With {.Company = "Lucerne Publishing", .Weight = 18.7},
      New Package With {.Company = "Wingtip Toys", .Weight = 6.0},
      New Package With {.Company = "Adventure Works", .Weight = 33.8}})

    ' Sum the values from each item's Weight property.
    Dim totalWeight As Double = packages.Sum(Function(pkg) _
                                             pkg.Weight)

    ' Display the result.
    MsgBox("The total weight of the packages is: " & totalWeight)
End Sub

' This code produces the following output:
'
' The total weight of the packages is: 83.7

備註

這個方法會傳回零,如果source包含任何項目。This method returns zero if source contains no elements.

您可以將這個方法套用至一連串的任意值,如果您提供函式, selector,,專案的成員source成數值類型,特別是Int64You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Int64.

在 Visual Basic 查詢運算式語法中,Aggregate Into Sum()子句會轉譯成的引動過程SumIn Visual Basic query expression syntax, an Aggregate Into Sum() clause translates to an invocation of Sum.

另請參閱

Sum<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Int32>)

計算序列的總和Int32叫用轉換函式的輸入序列的每個項目所取得的值。Computes the sum of the sequence of Int32 values that are obtained by invoking a transform function on each element of the input sequence.

public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
 static int Sum(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, int> ^ selector);
public static int Sum<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,int> selector);
static member Sum : seq<'Source> * Func<'Source, int> -> int
<Extension()>
Public Function Sum(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Integer)) As Integer

類型參數

TSource

source 項目的類型。The type of the elements of source.

參數

source
IEnumerable<TSource>

用來計算總和的值序列。A sequence of values that are used to calculate a sum.

selector
Func<TSource,Int32>

要套用至每個項目的轉換函式。A transform function to apply to each element.

傳回

預計值的總和。The sum of the projected values.

例外狀況

sourceselectornullsource or selector is null.

範例

下列程式碼範例示範如何使用Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>)加總的預計的值的序列。The following code example demonstrates how to use Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) to sum the projected values of a sequence.

注意

這個程式碼範例會使用此多載方法的多載,這個多載不是本主題描述的特定多載。This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. 若要將此範例延伸到本主題中使用,請變更 selector 函式的主體。To extend the example to this topic, change the body of the selector function.

class Package
{
    public string Company { get; set; }
    public double Weight { get; set; }
}

public static void SumEx1()
{
    List<Package> packages =
        new List<Package> 
            { new Package { Company = "Coho Vineyard", Weight = 25.2 },
              new Package { Company = "Lucerne Publishing", Weight = 18.7 },
              new Package { Company = "Wingtip Toys", Weight = 6.0 },
              new Package { Company = "Adventure Works", Weight = 33.8 } };

    double totalWeight = packages.Sum(pkg => pkg.Weight);

    Console.WriteLine("The total weight of the packages is: {0}", totalWeight);
}

/*
 This code produces the following output:

 The total weight of the packages is: 83.7
*/
Structure Package
    Public Company As String
    Public Weight As Double
End Structure

Sub SumEx1()
    ' Create a list of Package values.
    Dim packages As New List(Of Package)(New Package() _
     {New Package With {.Company = "Coho Vineyard", .Weight = 25.2},
      New Package With {.Company = "Lucerne Publishing", .Weight = 18.7},
      New Package With {.Company = "Wingtip Toys", .Weight = 6.0},
      New Package With {.Company = "Adventure Works", .Weight = 33.8}})

    ' Sum the values from each item's Weight property.
    Dim totalWeight As Double = packages.Sum(Function(pkg) _
                                             pkg.Weight)

    ' Display the result.
    MsgBox("The total weight of the packages is: " & totalWeight)
End Sub

' This code produces the following output:
'
' The total weight of the packages is: 83.7

備註

這個方法會傳回零,如果source包含任何項目。This method returns zero if source contains no elements.

您可以將這個方法套用至一連串的任意值,如果您提供函式, selector,,專案的成員source成數值類型,特別是Int32You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Int32.

在 Visual Basic 查詢運算式語法中,Aggregate Into Sum()子句會轉譯成的引動過程SumIn Visual Basic query expression syntax, an Aggregate Into Sum() clause translates to an invocation of Sum.

另請參閱

Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>)

計算序列的總和Double叫用轉換函式的輸入序列的每個項目所取得的值。Computes the sum of the sequence of Double values that are obtained by invoking a transform function on each element of the input sequence.

public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
 static double Sum(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, double> ^ selector);
public static double Sum<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,double> selector);
static member Sum : seq<'Source> * Func<'Source, double> -> double
<Extension()>
Public Function Sum(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Double)) As Double

類型參數

TSource

source 項目的類型。The type of the elements of source.

參數

source
IEnumerable<TSource>

用來計算總和的值序列。A sequence of values that are used to calculate a sum.

selector
Func<TSource,Double>

要套用至每個項目的轉換函式。A transform function to apply to each element.

傳回

預計值的總和。The sum of the projected values.

例外狀況

sourceselectornullsource or selector is null.

範例

下列程式碼範例示範如何使用Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>)加總的預計的值的序列。The following code example demonstrates how to use Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) to sum the projected values of a sequence.

class Package
{
    public string Company { get; set; }
    public double Weight { get; set; }
}

public static void SumEx1()
{
    List<Package> packages =
        new List<Package> 
            { new Package { Company = "Coho Vineyard", Weight = 25.2 },
              new Package { Company = "Lucerne Publishing", Weight = 18.7 },
              new Package { Company = "Wingtip Toys", Weight = 6.0 },
              new Package { Company = "Adventure Works", Weight = 33.8 } };

    double totalWeight = packages.Sum(pkg => pkg.Weight);

    Console.WriteLine("The total weight of the packages is: {0}", totalWeight);
}

/*
 This code produces the following output:

 The total weight of the packages is: 83.7
*/
Structure Package
    Public Company As String
    Public Weight As Double
End Structure

Sub SumEx1()
    ' Create a list of Package values.
    Dim packages As New List(Of Package)(New Package() _
     {New Package With {.Company = "Coho Vineyard", .Weight = 25.2},
      New Package With {.Company = "Lucerne Publishing", .Weight = 18.7},
      New Package With {.Company = "Wingtip Toys", .Weight = 6.0},
      New Package With {.Company = "Adventure Works", .Weight = 33.8}})

    ' Sum the values from each item's Weight property.
    Dim totalWeight As Double = packages.Sum(Function(pkg) _
                                             pkg.Weight)

    ' Display the result.
    MsgBox("The total weight of the packages is: " & totalWeight)
End Sub

' This code produces the following output:
'
' The total weight of the packages is: 83.7

備註

這個方法會傳回零,如果source包含任何項目。This method returns zero if source contains no elements.

您可以將這個方法套用至一連串的任意值,如果您提供函式, selector,,專案的成員source成數值類型,特別是DoubleYou can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Double.

在 Visual Basic 查詢運算式語法中,Aggregate Into Sum()子句會轉譯成的引動過程SumIn Visual Basic query expression syntax, an Aggregate Into Sum() clause translates to an invocation of Sum.

另請參閱

Sum<TSource>(IEnumerable<TSource>, Func<TSource,Decimal>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Decimal>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Decimal>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Decimal>)

計算序列的總和Decimal叫用轉換函式的輸入序列的每個項目所取得的值。Computes the sum of the sequence of Decimal values that are obtained by invoking a transform function on each element of the input sequence.

public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
 static System::Decimal Sum(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, System::Decimal> ^ selector);
public static decimal Sum<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,decimal> selector);
static member Sum : seq<'Source> * Func<'Source, decimal> -> decimal
<Extension()>
Public Function Sum(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Decimal)) As Decimal

類型參數

TSource

source 項目的類型。The type of the elements of source.

參數

source
IEnumerable<TSource>

用來計算總和的值序列。A sequence of values that are used to calculate a sum.

selector
Func<TSource,Decimal>

要套用至每個項目的轉換函式。A transform function to apply to each element.

傳回

預計值的總和。The sum of the projected values.

例外狀況

sourceselectornullsource or selector is null.

範例

下列程式碼範例示範如何使用Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>)加總的預計的值的序列。The following code example demonstrates how to use Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) to sum the projected values of a sequence.

注意

這個程式碼範例會使用此多載方法的多載,這個多載不是本主題描述的特定多載。This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. 若要將此範例延伸到本主題中使用,請變更 selector 函式的主體。To extend the example to this topic, change the body of the selector function.

class Package
{
    public string Company { get; set; }
    public double Weight { get; set; }
}

public static void SumEx1()
{
    List<Package> packages =
        new List<Package> 
            { new Package { Company = "Coho Vineyard", Weight = 25.2 },
              new Package { Company = "Lucerne Publishing", Weight = 18.7 },
              new Package { Company = "Wingtip Toys", Weight = 6.0 },
              new Package { Company = "Adventure Works", Weight = 33.8 } };

    double totalWeight = packages.Sum(pkg => pkg.Weight);

    Console.WriteLine("The total weight of the packages is: {0}", totalWeight);
}

/*
 This code produces the following output:

 The total weight of the packages is: 83.7
*/
Structure Package
    Public Company As String
    Public Weight As Double
End Structure

Sub SumEx1()
    ' Create a list of Package values.
    Dim packages As New List(Of Package)(New Package() _
     {New Package With {.Company = "Coho Vineyard", .Weight = 25.2},
      New Package With {.Company = "Lucerne Publishing", .Weight = 18.7},
      New Package With {.Company = "Wingtip Toys", .Weight = 6.0},
      New Package With {.Company = "Adventure Works", .Weight = 33.8}})

    ' Sum the values from each item's Weight property.
    Dim totalWeight As Double = packages.Sum(Function(pkg) _
                                             pkg.Weight)

    ' Display the result.
    MsgBox("The total weight of the packages is: " & totalWeight)
End Sub

' This code produces the following output:
'
' The total weight of the packages is: 83.7

備註

這個方法會傳回零,如果source包含任何項目。This method returns zero if source contains no elements.

您可以將這個方法套用至一連串的任意值,如果您提供函式, selector,,專案的成員source成數值類型,特別是DecimalYou can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Decimal.

在 Visual Basic 查詢運算式語法中,Aggregate Into Sum()子句會轉譯成的引動過程SumIn Visual Basic query expression syntax, an Aggregate Into Sum() clause translates to an invocation of Sum.

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