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Enumerable.ToList<TSource>(IEnumerable<TSource>) 方法

定義

IEnumerable<T> 建立 List<T>

public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
 static System::Collections::Generic::List<TSource> ^ ToList(System::Collections::Generic::IEnumerable<TSource> ^ source);
public static System.Collections.Generic.List<TSource> ToList<TSource> (this System.Collections.Generic.IEnumerable<TSource> source);
static member ToList : seq<'Source> -> System.Collections.Generic.List<'Source>
<Extension()>
Public Function ToList(Of TSource) (source As IEnumerable(Of TSource)) As List(Of TSource)

類型參數

TSource

source 項目的類型。

參數

source
IEnumerable<TSource>

用來建立 IEnumerable<T> 的來源 List<T>

傳回

List<TSource>

List<T>,包含輸入序列中的項目。

例外狀況

sourcenull

範例

下列程式代碼範例示範如何使用 ToList 來強制立即查詢評估,並傳回 List<T> 包含查詢結果的 。

string[] fruits = { "apple", "passionfruit", "banana", "mango",
                      "orange", "blueberry", "grape", "strawberry" };

List<int> lengths = fruits.Select(fruit => fruit.Length).ToList();

foreach (int length in lengths)
{
    Console.WriteLine(length);
}

/*
 This code produces the following output:

 5
 12
 6
 5
 6
 9
 5
 10
*/
' Create an array of strings.
Dim fruits() As String =
{"apple", "passionfruit", "banana", "mango",
 "orange", "blueberry", "grape", "strawberry"}

' Project the length of each string and
' put the length values into a List object.
Dim lengths As List(Of Integer) =
fruits _
.Select(Function(fruit) fruit.Length) _
.ToList()

' Display the results.
Dim output As New System.Text.StringBuilder
For Each length As Integer In lengths
    output.AppendLine(length)
Next
Console.WriteLine(output.ToString())

' This code produces the following output:
'
' 5
' 12
' 6
' 5
' 6
' 9
' 5
' 10

備註

方法 ToList<TSource>(IEnumerable<TSource>) 會強制立即查詢評估,並傳回 List<T> 包含查詢結果的 。 您可以將這個方法附加至查詢,以取得查詢結果的快取複本。

ToArray 具有類似的行為,但會傳回數位列,而不是 List<T>

適用於