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BitArray.Xor(BitArray) Metoda

Definice

Provede bitové exkluzivní operace OR mezi prvky aktuálního BitArray objektu proti odpovídajícím prvkům v zadaném poli. Aktuální BitArray objekt bude upraven tak, aby ukládaly výsledek operace bitové exkluzivní operace OR.

public:
 System::Collections::BitArray ^ Xor(System::Collections::BitArray ^ value);
public System.Collections.BitArray Xor (System.Collections.BitArray value);
member this.Xor : System.Collections.BitArray -> System.Collections.BitArray
Public Function Xor (value As BitArray) As BitArray

Parametry

value
BitArray

Pole, se kterým se má provést bitové exkluzivní operace OR.

Návraty

Pole obsahující výsledek bitové operace OR, která je odkazem na aktuální BitArray objekt.

Výjimky

value je null.

value a aktuální BitArray nemají stejný počet prvků.

Příklady

Následující příklad kódu ukazuje, jak provést operaci XOR mezi dvěma BitArray objekty.

using namespace System;
using namespace System::Collections;
void PrintValues( IEnumerable^ myList, int myWidth );
int main()
{
   
   // Creates and initializes two BitArrays of the same size.
   BitArray^ myBA1 = gcnew BitArray( 4 );
   BitArray^ myBA2 = gcnew BitArray( 4 );
   myBA1[ 0 ] = false;
   myBA1[ 1 ] = false;
   myBA1[ 2 ] = true;
   myBA1[ 3 ] = true;
   myBA2[ 0 ] = false;
   myBA2[ 1 ] = true;
   myBA2[ 2 ] = false;
   myBA2[ 3 ] = true;
   
   // Performs a bitwise XOR operation between BitArray instances of the same size.
   Console::WriteLine( "Initial values" );
   Console::Write( "myBA1:" );
   PrintValues( myBA1, 8 );
   Console::Write( "myBA2:" );
   PrintValues( myBA2, 8 );
   Console::WriteLine();
   Console::WriteLine( "Result" );
   Console::Write( "XOR:" );
   PrintValues( myBA1->Xor( myBA2 ), 8 );
   Console::WriteLine();
   Console::WriteLine( "After XOR" );
   Console::Write( "myBA1:" );
   PrintValues( myBA1, 8 );
   Console::Write( "myBA2:" );
   PrintValues( myBA2, 8 );
   Console::WriteLine();
   
   // Performing XOR between BitArray instances of different sizes returns an exception.
   try
   {
      BitArray^ myBA3 = gcnew BitArray( 8 );
      myBA3[ 0 ] = false;
      myBA3[ 1 ] = false;
      myBA3[ 2 ] = false;
      myBA3[ 3 ] = false;
      myBA3[ 4 ] = true;
      myBA3[ 5 ] = true;
      myBA3[ 6 ] = true;
      myBA3[ 7 ] = true;
      myBA1->Xor( myBA3 );
   }
   catch ( Exception^ myException ) 
   {
      Console::WriteLine( "Exception: {0}", myException );
   }

}

void PrintValues( IEnumerable^ myList, int myWidth )
{
   int i = myWidth;
   IEnumerator^ myEnum = myList->GetEnumerator();
   while ( myEnum->MoveNext() )
   {
      Object^ obj = safe_cast<Object^>(myEnum->Current);
      if ( i <= 0 )
      {
         i = myWidth;
         Console::WriteLine();
      }

      i--;
      Console::Write( "{0,8}", obj );
   }

   Console::WriteLine();
}

/* 
 This code produces the following output.
 
 Initial values
 myBA1:   False   False    True    True
 myBA2:   False    True   False    True

 Result
 XOR:   False    True    True   False

 After XOR
 myBA1:   False    True    True   False
 myBA2:   False    True   False    True

 Exception: System.ArgumentException: Array lengths must be the same.
    at System.Collections.BitArray.Xor(BitArray value)
    at SamplesBitArray.Main()

 */
using System;
using System.Collections;
public class SamplesBitArray  {

   public static void Main()  {

      // Creates and initializes two BitArrays of the same size.
      BitArray myBA1 = new BitArray( 4 );
      BitArray myBA2 = new BitArray( 4 );
      myBA1[0] = myBA1[1] = false;
      myBA1[2] = myBA1[3] = true;
      myBA2[0] = myBA2[2] = false;
      myBA2[1] = myBA2[3] = true;

      // Performs a bitwise XOR operation between BitArray instances of the same size.
      Console.WriteLine( "Initial values" );
      Console.Write( "myBA1:" );
      PrintValues( myBA1, 8 );
      Console.Write( "myBA2:" );
      PrintValues( myBA2, 8 );
      Console.WriteLine();

      Console.WriteLine( "Result" );
      Console.Write( "XOR:" );
      PrintValues( myBA1.Xor( myBA2 ), 8 );
      Console.WriteLine();

      Console.WriteLine( "After XOR" );
      Console.Write( "myBA1:" );
      PrintValues( myBA1, 8 );
      Console.Write( "myBA2:" );
      PrintValues( myBA2, 8 );
      Console.WriteLine();

      // Performing XOR between BitArray instances of different sizes returns an exception.
      try  {
         BitArray myBA3 = new BitArray( 8 );
         myBA3[0] = myBA3[1] = myBA3[2] = myBA3[3] = false;
         myBA3[4] = myBA3[5] = myBA3[6] = myBA3[7] = true;
         myBA1.Xor( myBA3 );
      } catch ( Exception myException )  {
         Console.WriteLine("Exception: " + myException.ToString());
      }
   }

   public static void PrintValues( IEnumerable myList, int myWidth )  {
      int i = myWidth;
      foreach ( Object obj in myList ) {
         if ( i <= 0 )  {
            i = myWidth;
            Console.WriteLine();
         }
         i--;
         Console.Write( "{0,8}", obj );
      }
      Console.WriteLine();
   }
}


/*
This code produces the following output.

Initial values
myBA1:   False   False    True    True
myBA2:   False    True   False    True

Result
XOR:   False    True    True   False

After XOR
myBA1:   False    True    True   False
myBA2:   False    True   False    True

Exception: System.ArgumentException: Array lengths must be the same.
   at System.Collections.BitArray.Xor(BitArray value)
   at SamplesBitArray.Main()

*/
Imports System.Collections

Public Class SamplesBitArray    
    
    Public Shared Sub Main()
        
        ' Creates and initializes two BitArrays of the same size.
        Dim myBA1 As New BitArray(4)
        Dim myBA2 As New BitArray(4)
        myBA1(0) = False
        myBA1(1) = False
        myBA1(2) = True
        myBA1(3) = True
        myBA2(0) = False
        myBA2(2) = False
        myBA2(1) = True
        myBA2(3) = True
        
        ' Performs a bitwise XOR operation between BitArray instances of the same size.
        Console.WriteLine("Initial values")
        Console.Write("myBA1:")
        PrintValues(myBA1, 8)
        Console.Write("myBA2:")
        PrintValues(myBA2, 8)
        Console.WriteLine()
        
        Console.WriteLine("Result")
        Console.Write("XOR:")
        PrintValues(myBA1.Xor(myBA2), 8)
        Console.WriteLine()
        
        Console.WriteLine("After XOR")
        Console.Write("myBA1:")
        PrintValues(myBA1, 8)
        Console.Write("myBA2:")
        PrintValues(myBA2, 8)
        Console.WriteLine()
        
        ' Performing XOR between BitArray instances of different sizes returns an exception.
        Try
            Dim myBA3 As New BitArray(8)
            myBA3(0) = False
            myBA3(1) = False
            myBA3(2) = False
            myBA3(3) = False
            myBA3(4) = True
            myBA3(5) = True
            myBA3(6) = True
            myBA3(7) = True
            myBA1.Xor(myBA3)
        Catch myException As Exception
            Console.WriteLine("Exception: " + myException.ToString())
        End Try
    End Sub
    
    Public Shared Sub PrintValues(myList As IEnumerable, myWidth As Integer)
        Dim i As Integer = myWidth
        Dim obj As [Object]
        For Each obj In  myList
            If i <= 0 Then
                i = myWidth
                Console.WriteLine()
            End If
            i -= 1
            Console.Write("{0,8}", obj)
        Next obj
        Console.WriteLine()
    End Sub

End Class


' This code produces the following output.
' 
' Initial values
' myBA1:   False   False    True    True
' myBA2:   False    True   False    True
' 
' Result
' XOR:   False    True    True   False
' 
' After XOR
' myBA1:   False    True    True   False
' myBA2:   False    True   False    True
' 
' Exception: System.ArgumentException: Array lengths must be the same.
'    at System.Collections.BitArray.Xor(BitArray value)
'    at SamplesBitArray.Main()

Poznámky

Bitové exkluzivní operace OR vrátí true , pokud je trueprávě jeden operand , a vrátí, false pokud oba operandy mají stejnou logickou hodnotu.

Tato metoda je O(n) operace, kde n je Count.

Platí pro