Uri.UriSchemeHttp Uri.UriSchemeHttp Uri.UriSchemeHttp Uri.UriSchemeHttp Field

Definition

Gibt an, dass auf den URI über HTTP (Hypertext Transfer Protocol) zugegriffen wird.Specifies that the URI is accessed through the Hypertext Transfer Protocol (HTTP). Dieses Feld ist schreibgeschützt.This field is read-only.

public: static initonly System::String ^ UriSchemeHttp;
public static readonly string UriSchemeHttp;
 staticval mutable UriSchemeHttp : string
Public Shared ReadOnly UriSchemeHttp As String 

Feldwert

Beispiele

Im folgenden Beispiel wird eine Uri -Instanz erstellt, und es wird UriSchemeHttpbestimmt, ob das Schema ist.The following example creates a Uri instance and determines whether the scheme is UriSchemeHttp.

Uri^ address1 = gcnew Uri( "http://www.contoso.com/index.htm#search" );
Console::WriteLine( "address 1 {0} a valid scheme name",
   Uri::CheckSchemeName( address1->Scheme ) ? (String^)" has" : " does not have" );
if ( address1->Scheme == Uri::UriSchemeHttp )
{
   Console::WriteLine( "Uri is HTTP type" );
}

Console::WriteLine( address1->HostNameType );
Uri address1 = new Uri("http://www.contoso.com/index.htm#search");
Console.WriteLine("address 1 {0} a valid scheme name",
      Uri.CheckSchemeName(address1.Scheme) ? " has" : " does not have");

if (address1.Scheme == Uri.UriSchemeHttp)
    Console.WriteLine("Uri is HTTP type");
      
Console.WriteLine(address1.HostNameType);
Dim address1 As New Uri("http://www.contoso.com/index.htm#search")
Console.WriteLine("address 1 {0} a valid scheme name", IIf(Uri.CheckSchemeName(address1.Scheme), " has", " does not have")) 'TODO: For performance reasons this should be changed to nested IF statements

If address1.Scheme = Uri.UriSchemeHttp Then
    Console.WriteLine("Uri is HTTP type")
End If 
Console.WriteLine(address1.HostNameType)

Gilt für: