file upload x509 python with custom filepath

Question

I am following the tutorial at: https://learn.microsoft.com/en-us/azure/iot-hub/file-upload-python#upload-a-file-from-a-device-app However, when I try to upload the file it always uploads with the filepath DEVICENAME/file.jpeg. What if I want to upload a file with a different filepath such as /Location/DEVICENAME/Date/file.jpeg. or what if I don't want to upload using the Device Name at all? so I just uploaded it with /Location/Date/file.jpeg. Looking at the documentation for BlobClient, if I change the blob_info["blobName"] filepath it leads to authentication problems. so how do I tackle this problem? Thank you for your time

Answer 1

Cabrejos, Jason J Greetings & Welcome to Microsoft Q&A forum!

I understand that you are trying to upload files to Azure Blob Storage.

when I try to upload the file it always uploads with the filepath DEVICENAME/file.jpeg

The documenation you are following uses the BlobClient class from the azure.storage.blob package to upload the file.

The BlobClient class has a upload_blob method that takes the blob_name parameter to specify the name of the blob. By default, the blob_name parameter is set to DEVICENAME/file.jpeg.

What if I want to upload a file with a different filepath such as /Location/DEVICENAME/Date/file.jpeg. or what if I don't want to upload using the Device Name at all?

To upload the file with a custom filepath, you can try to modify the blob_name parameter in the upload_blob method.

For example, to upload the file to /Location/DEVICENAME/Date/file.jpeg, the blob_name parameter should be set to Location/DEVICENAME/Date/file.jpeg. If you would like to upload the file without using the device name, you can set the blob_name parameter to the desired filepath.

For example, to upload the file to /Location/Date/file.jpeg, the blob_name parameter should be set to Location/Date/file.jpeg.

Looking at the documentation for BlobClient, if I change the blob_info["blobName"] filepath it leads to authentication problems.

It's important to note that the blob_info parameter is not used in the upload_blob method. Instead, the blob_name parameter is used to specify the name of the blob.

If you are still having authentication problems, you may need to check the Azure IoT Hub permissions and access rights.

You can refer to the Azure documentation on IoT Hub access control and Upload files with IoT Hub for more information.

Also, refer to Azure Blob storage client library v12 for Python for more information on using the BlobClient class to upload files.

Do let me know if that helps or have any other queries.

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Answer 2

Hi @Cabrejos, Jason J Greetings! Welcome to Microsoft Q&A forum. Thank you for posting this question here.

I am not sure if the BlobClinet class has the support for the use case you are looking for. I have tested the use case you are looking for using BlobServiceClient class which has some additional capabilities. Below is the code I have tested which creates the BlobServiceClient instance using the Azure Blob storage account connection string instead of the SAS URL.

from azure.storage.blob import BlobServiceClient
from azure.iot.device import IoTHubDeviceClient
import datetime
import os

# Connection string for the Azure Storage account
connection_string = "Storage Account Connection string"
device_connection_string = "<Replcae with device connection string>"

# Name of the container to upload the file to
container_name = "<Contianer name>"

# Path to the file to upload
file_path = r"<Path to your image>"



# Create a BlobServiceClient object using the connection string
blob_service_client = BlobServiceClient.from_connection_string(connection_string)

device_client = IoTHubDeviceClient.create_from_connection_string(device_connection_string)


# Create a ContainerClient object for the container
container_client = blob_service_client.get_container_client(container_name)

# Get the filename from the file path
filename = os.path.basename(file_path)

# Desired filepath for the uploaded file

current_date = datetime.datetime.now().strftime("%Y-%m-%d")
directory_path = "Location"
desired_filepath = f"{directory_path}/{current_date}/{filename}"

# Create a BlobClient object for the file
blob_client = container_client.get_blob_client(desired_filepath)

# Upload the file to the container
with open(file_path, "rb") as data:
    result = blob_client.upload_blob(data)

print(result)

storage_info = device_client.get_storage_info_for_blob(filename)

device_client.notify_blob_upload_status(storage_info["correlationId"], True, 200, "OK: {}".format(desired_filepath))

You can get the Connection string of your Azure storage account from Access Keys tab of your storage account. Please refer the below image for reference.

Make sure to pass a valid container_name in the above code. As you can see from the below image, the file gets saved in the path specified without the need of providing device name.

Hope this helps! Please let us know if you have any additional questions or need further clarification.

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If the response helped, please do click Accept Answer and Yes for the answer provided. Doing so would help other community members with similar issue identify the solution. I highly appreciate your contribution to the community.