Compiler warning (level 2) C4146

unary minus operator applied to unsigned type, result still unsigned

Unsigned types can hold only non-negative values, so unary minus (negation) usually doesn't make sense when applied to an unsigned type. Both the operand and the result are non-negative.


When you express a negative integer literal, the - in front of the value is parsed as a unary negation operator. The compiler applies the operator after it parses the numeric value. If the numeric value fits in the range of an unsigned integer type, but not the corresponding signed integer type, the compiler interprets the value as unsigned. An unsigned value is unchanged by the unary negation operator.

This warning often occurs when you try to express the minimum int value, -2147483648, or the minimum long long value, -9223372036854775808. These values can't be written as -2147483648 or -9223372036854775808ll, respectively. That's because the compiler processes the expression in two stages: first, it parses the numeric value, then it applies the negation operator. For example, when the compiler parses -2147483648, it follows these steps:

  1. The number 2147483648 is evaluated. Because it's greater than the maximum int value of 2147483647, but still fits in an unsigned int, the type of 2147483648 is unsigned int.

  2. Unary minus is applied to the unsigned value, with an unsigned result, which also happens to be 2147483648.

The unsigned type of the result can cause unexpected behavior. If the result is used in a comparison, then an unsigned comparison might be used, for example, when the other operand is an int.

You can avoid C4146 by using INT_MIN or LLONG_MIN from <limits.h> or the C++ equivalent, <climits>. These values have signed types.


The following sample demonstrates the unexpected behavior that can happen when the compiler generates warning C4146:

// C4146.cpp
// compile with: /W2
#include <iostream>

void check(int i)
    if (i > -9223372036854775808ll)   // C4146
        std::cout << i << " is greater than the most negative long long int.\n";

int main()

In this example, the compiler considers -9223372036854775808ll unsigned even though the literal has an ll suffix and the negation operator is applied. To make the < comparison, the compiler silently promotes signed i to unsigned long long int. The expected second line, 1 is greater than the most negative long long int, isn't printed because ((unsigned long long int)1) > 9223372036854775808ull is false.

To fix the example, include <climits> and change -9223372036854775808ll to LLONG_MIN.

See also

Unary negation operator (-)