is_fundamental Class

Tests if type is void or arithmetic.

Syntax

template <class Ty>
struct is_fundamental;

Parameters

Ty
The type to query.

Remarks

An instance of the type predicate holds true if the type Ty is a fundamental type, that is, void, an integral type, an floating point type, or a cv-qualified form of one of them, otherwise it holds false.

Example

// std__type_traits__is_fundamental.cpp
// compile with: /EHsc
#include <type_traits>
#include <iostream>

struct trivial
    {
    int val;
    };

int main()
    {
    std::cout << "is_fundamental<trivial> == " << std::boolalpha
        << std::is_fundamental<trivial>::value << std::endl;
    std::cout << "is_fundamental<int> == " << std::boolalpha
        << std::is_fundamental<int>::value << std::endl;
    std::cout << "is_fundamental<const float> == " << std::boolalpha
        << std::is_fundamental<const float>::value << std::endl;
    std::cout << "is_fundamental<void> == " << std::boolalpha
        << std::is_fundamental<void>::value << std::endl;

    return (0);
    }

is_fundamental<trivial> == false
is_fundamental<int> == true
is_fundamental<const float> == true
is_fundamental<void> == true

Requirements

Header: <type_traits>

Namespace: std

See also

<type_traits>
is_compound Class