OpenXmlPartRootXElementExtensions.GetXElement(OpenXmlPart) Method

Definition

Namespace:

DocumentFormat.OpenXml.Packaging

Assembly:

DocumentFormat.OpenXml.Linq.dll

Package:

DocumentFormat.OpenXml.Linq v3.0.1

Gets an XElement representation of the part.

public static System.Xml.Linq.XElement? GetXElement (this DocumentFormat.OpenXml.Packaging.OpenXmlPart part);

static member GetXElement : DocumentFormat.OpenXml.Packaging.OpenXmlPart -> System.Xml.Linq.XElement

<Extension()>
Public Function GetXElement (part As OpenXmlPart) As XElement

Parameters

part

OpenXmlPart

The part to get the contents of.

Returns

XElement

An XElement.

Remarks

Calling this method has same effect as calling part.GetXDocument().Root.

When called with a given OpenXmlPart for the first time after having opened the containing OpenXmlPackage or saved the strongly-typed OpenXmlPartRootElement to the OpenXmlPart, deserializes, caches, and returns the outer XML of an already loaded OpenXmlPartRootElement or the content of the OpenXmlPart as an XElement. In the following calls, directly returns the cached XElement.

See also

• GetXDocument(OpenXmlPart)
• SetXElement(OpenXmlPart, XElement)
• SaveXElement(OpenXmlPart)