Share via

PartExtensionProvider.AddPartExtension(String, String) Method

  • Reference

Definition

Namespace:
DocumentFormat.OpenXml.Packaging
Assembly:
DocumentFormat.OpenXml.dll
Package:
DocumentFormat.OpenXml v2.10.0
Package:
DocumentFormat.OpenXml v2.10.1
Package:
DocumentFormat.OpenXml v2.11.0
Package:
DocumentFormat.OpenXml v2.11.1
Package:
DocumentFormat.OpenXml v2.11.2
Package:
DocumentFormat.OpenXml v2.11.3
Package:
DocumentFormat.OpenXml v2.12.0
Package:
DocumentFormat.OpenXml v2.12.1
Package:
DocumentFormat.OpenXml v2.12.2
Package:
DocumentFormat.OpenXml v2.12.3
Package:
DocumentFormat.OpenXml v2.13.0
Package:
DocumentFormat.OpenXml v2.13.1
Package:
DocumentFormat.OpenXml v2.14.0
Package:
DocumentFormat.OpenXml v2.15.0
Package:
DocumentFormat.OpenXml v2.16.0
Package:
DocumentFormat.OpenXml v2.17.1
Package:
DocumentFormat.OpenXml v2.18.0
Package:
DocumentFormat.OpenXml v2.19.0
Package:
DocumentFormat.OpenXml v2.20.0
Package:
DocumentFormat.OpenXml v2.7.1
Package:
DocumentFormat.OpenXml v2.7.2
Package:
DocumentFormat.OpenXml v2.8.0
Package:
DocumentFormat.OpenXml v2.8.1
Package:
DocumentFormat.OpenXml v2.9.0
Package:
DocumentFormat.OpenXml v2.9.1

Add a part extension for the specified content type.

public void AddPartExtension (string contentType, string partExtension);
member this.AddPartExtension : string * string -> unit
Public Sub AddPartExtension (contentType As String, partExtension As String)

Parameters

contentType
String

The content type.

partExtension
String

Part Extension (".xml") to be used for the part with the specified content type.

Applies to