FontDialog.ShowColor FontDialog.ShowColor FontDialog.ShowColor FontDialog.ShowColor Property


Gets or sets a value indicating whether the dialog box displays the color choice.

 property bool ShowColor { bool get(); void set(bool value); };
public bool ShowColor { get; set; }
member this.ShowColor : bool with get, set
Public Property ShowColor As Boolean

Property Value

true if the dialog box displays the color choice; otherwise, false. The default value is false.


The following code example uses ShowDialog to display a FontDialog. This code requires that a Form has already been created with a TextBox and button placed on it. It also requires that the fontDialog1 has been created. The Font contains the size information but not the color information.

   void button1_Click( Object^ /*sender*/, System::EventArgs^ /*e*/ )
      fontDialog1->ShowColor = true;

      fontDialog1->Font = textBox1->Font;
      fontDialog1->Color = textBox1->ForeColor;

      if ( fontDialog1->ShowDialog() != ::DialogResult::Cancel )
         textBox1->Font = fontDialog1->Font;
         textBox1->ForeColor = fontDialog1->Color;
private void button1_Click(object sender, System.EventArgs e)
    fontDialog1.ShowColor = true;

    fontDialog1.Font = textBox1.Font;
    fontDialog1.Color = textBox1.ForeColor;

    if(fontDialog1.ShowDialog() != DialogResult.Cancel )
       textBox1.Font = fontDialog1.Font ;
       textBox1.ForeColor = fontDialog1.Color;
Private Sub button1_Click(sender As Object, e As System.EventArgs)
    fontDialog1.ShowColor = True

    fontDialog1.Font = textBox1.Font
    fontDialog1.Color = textBox1.ForeColor

    If fontDialog1.ShowDialog() <> DialogResult.Cancel Then
        textBox1.Font = fontDialog1.Font
        textBox1.ForeColor = fontDialog1.Color
    End If
End Sub 'button1_Click

Applies to

See also