How to deserialize an object using XmlSerializer

When you deserialize an object, the transport format determines whether you will create a stream or file object. After the transport format is determined, you can call the Serialize or Deserialize methods, as required.

To deserialize an object

  1. Construct a XmlSerializer using the type of the object to deserialize.

  2. Call the Deserialize method to produce a replica of the object. When deserializing, you must cast the returned object to the type of the original, as shown in the following example, which deserializes the object from a file (although it could also be deserialized from a stream).

    ' Construct an instance of the XmlSerializer with the type
    ' of object that is being deserialized.
    Dim mySerializer As New XmlSerializer(GetType(MySerializableClass))
    ' To read the file, create a FileStream.
    Dim myFileStream As New FileStream("myFileName.xml", FileMode.Open)
    ' Call the Deserialize method and cast to the object type.
    Dim myObject = CType( _
    mySerializer.Deserialize(myFileStream), MySerializableClass)
    
    // Construct an instance of the XmlSerializer with the type
    // of object that is being deserialized.
    var mySerializer = new XmlSerializer(typeof(MySerializableClass));
    // To read the file, create a FileStream.
    var myFileStream = new FileStream("myFileName.xml", FileMode.Open);
    // Call the Deserialize method and cast to the object type.
    var myObject = (MySerializableClass) mySerializer.Deserialize(myFileStream)
    

See also