Mid Statement

Replaces a specified number of characters in a String variable with characters from another string.

Syntax

Mid( _  
   ByRef Target As String, _  
   ByVal Start As Integer, _  
   Optional ByVal Length As Integer _  
) = StringExpression  

Parts

Target
Required. Name of the String variable to modify.

Start
Required. Integer expression. Character position in Target where the replacement of text begins. Start uses a one-based index.

Length
Optional. Integer expression. Number of characters to replace. If omitted, all of String is used.

StringExpression
Required. String expression that replaces part of Target.

Exceptions

Exception type Condition
ArgumentException Start <= 0 or Length < 0.

Remarks

The number of characters replaced is always less than or equal to the number of characters in Target.

Visual Basic has a Mid function and a Mid statement. These elements both operate on a specified number of characters in a string, but the Mid function returns the characters while the Mid statement replaces the characters. For more information, see Mid.

Note

The MidB statement of earlier versions of Visual Basic replaces a substring in bytes, rather than characters. It is used primarily for converting strings in double-byte character set (DBCS) applications. All Visual Basic strings are in Unicode, and MidB is no longer supported.

Example

This example uses the Mid statement to replace a specified number of characters in a string variable with characters from another string.

Dim TestString As String
' Initializes string.
TestString = "The dog jumps"
' Returns "The fox jumps".
Mid(TestString, 5, 3) = "fox"
' Returns "The cow jumps".
Mid(TestString, 5) = "cow"
' Returns "The cow jumpe".
Mid(TestString, 5) = "cow jumped over"
' Returns "The duc jumpe".
Mid(TestString, 5, 3) = "duck"

Requirements

Namespace: Microsoft.VisualBasic

Module: Strings

Assembly: Visual Basic Runtime Library (in Microsoft.VisualBasic.dll)

See Also

Mid
Strings
Introduction to Strings in Visual Basic