How To Parse City, State, and Zip Code into Separate Values
Original product version: Microsoft Office Access 2003, Microsoft Office Access 2007, Access 2010
Original KB number: 168798
Summary
This article provides a procedure for parsing a single variable containing US City, State, and Zip Code information into three separate variables. The routine supports:
- Either 5- or 9-digit zip code.
- Multi-word state names (if preceded by a comma).
- Any number of intermediate spaces.
Examples of supported inputs:
New York, New York, 99999
New York, NY, 99999-9999
New York, NY 99999-9999
New York NY 99999
More information
WARNING: ANY USE BY YOU OF THE CODE/MACRO PROVIDED IN THIS ARTICLE IS AT YOUR OWN RISK. Microsoft provides this code/macro "as is" without warranty of any kind, either express or implied, including but not limited to the implied warranties of merchantability and/or fitness for a particular purpose.
NOTE: In the following sample code, an underscore (_) at the end of a line is used as a line-continuation character. For versions of BASIC that don't support line-continuation characters, remove the underscore from the end of the line and merge with the following line when re-creating this code.
Fields are parsed in the following order if no commas are found in the address: Zip Code, State, City If at least one comma is present, it is presumed to be between City and State, and the fields are parsed in a different order: City, State, Zip Code
Step-by-Step Example
Enter the following code:
Function CutLastWord (ByVal S As String, Remainder As String) _ As String ' CutLastWord: returns the last word in S. ' Remainder: returns the rest. ' ' Words are separated by spaces ' Dim I As Integer, P As Integer S = Trim$(S) P = 1 For I = Len(S) To 1 Step -1 If Mid$(S, I, 1) = " " Then P = I + 1 Exit For End If Next I If P = 1 Then CutLastWord = S Remainder = "" Else CutLastWord = Mid$(S, P) Remainder = Trim$(Left$(S, P - 1)) End If End Function Sub ParseCSZ (ByVal S As String, City As String, State As String, _ Zip As String) Dim P As Integer ' ' Check for comma after city name ' P = InStr(S, ",") If P > 0 Then City = Trim$(Left$(S, P - 1)) S = Trim$(Mid$(S, P + ' ' Check for comma after state ' P = InStr(S, ",") If P > 0 Then State = Trim$(Left$(S, P - 1)) Zip = Trim$(Mid$(S, P + 1)) Else ' No comma between state and zip Zip = CutLastWord(S, S) State = S End If Else ' No commas between city, state, or zip Zip = CutLastWord(S, S) State = CutLastWord(S, S) City = S End If ' ' Clean up any dangling commas ' If Right$(State, 1) = "," Then State = RTrim$(Left$(State, Len(State) - 1)) End If If Right$(City, 1) = "," Then City = RTrim$(Left$(City, Len(City) - 1)) End If End Sub
To test, create a form with four text boxes (txtAddress, txtCity, txtState, txtZip), and a command button. Add the following code:
Sub Command1_Click() Dim City As String, State As String, Zip As String ParseCSZ txtAddress, City, State, Zip txtCity = City txtState = State txtZip = Zip End Sub
Display the form, type an address into txtAddress, and click the command button. The other three fields should contain the parsed values.
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