Table.ContainsAny

Syntax

Table.ContainsAny(table as table, rows as list, optional equationCriteria as any) as logical

About

Indicates whether any the specified records in the list of records rows, appear as rows in the table. An optional parameter equationCriteria may be specified to control comparison between the rows of the table.

Example 1

Determine if the table ({[a = 1, b = 2], [a = 3, b = 4]}) contains the rows [a = 1, b = 2] or [a = 3, b = 5].

Table.ContainsAny(
    Table.FromRecords({
        [a = 1, b = 2],
        [a = 3, b = 4]
    }),
    {
        [a = 1, b = 2],
        [a = 3, b = 5]
    }
)

true

Example 2

Determine if the table ({[a = 1, b = 2], [a = 3, b = 4]}) contains the rows [a = 1, b = 3] or [a = 3, b = 5].

Table.ContainsAny(
    Table.FromRecords({
        [a = 1, b = 2],
        [a = 3, b = 4]
    }),
    {
        [a = 1, b = 3],
        [a = 3, b = 5]
    }
)

false

Example 3

Determine if the table (Table.FromRecords({[a = 1, b = 2], [a = 3, b = 4]})) contains the rows [a = 1, b = 3] or [a = 3, b = 5] comparing only the column [a].

Table.ContainsAny(
    Table.FromRecords({
        [a = 1, b = 2],
        [a = 3, b = 4]
    }),
    {
        [a = 1, b = 3],
        [a = 3, b = 5]
    },
    "a"
)

true