_memccpy

Article
06/05/2017

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The latest version of this topic can be found at _memccpy.

Copies characters from a buffer.

Syntax

  
      void *_memccpy(  
   void *dest,  
   const void *src,  
   int c,  
   size_t count   
);

Parameters

dest
Pointer to the destination.

src
Pointer to the source.

c
Last character to copy.

count
Number of characters.

Return Value

If the character c is copied, _memccpy returns a pointer to the char in dest that immediately follows the character. If c is not copied, it returns NULL.

Remarks

The _memccpy function copies 0 or more characters of src to dest, halting when the character c has been copied or when count characters have been copied, whichever comes first.

Security Note Make sure that the destination buffer is the same size or larger than the source buffer. For more information, see Avoiding Buffer Overruns.

Requirements

Routine	Required header
`_memccpy`	<memory.h> or <string.h>

For more compatibility information, see Compatibility in the Introduction.

Libraries

All versions of the C run-time libraries.

Example

// crt_memccpy.c  
  
#include <memory.h>  
#include <stdio.h>  
#include <string.h>  
  
char string1[60] = "The quick brown dog jumps over the lazy fox";  
  
int main( void )  
{  
   char buffer[61];  
   char *pdest;  
  
   printf( "Function: _memccpy 60 characters or to character 's'\n" );  
   printf( "Source: %s\n", string1 );  
   pdest = _memccpy( buffer, string1, 's', 60 );  
   *pdest = '\0';  
   printf( "Result: %s\n", buffer );  
   printf( "Length: %d characters\n", strlen( buffer ) );  
}

Output

Function: _memccpy 60 characters or to character 's'  
Source: The quick brown dog jumps over the lazy fox  
Result: The quick brown dog jumps  
Length: 25 characters