Returns the rank of each row within the partition of a result set. The rank of a row is one plus the number of ranks that come before the row in question.
RANK ( ) OVER ( [ < partition_by_clause > ] < order_by_clause > )
- < partition_by_clause >
Divides the result set produced by the FROM clause into partitions to which the RANK function is applied. For the syntax of PARTITION BY, see OVER Clause (Transact-SQL).
- < order_by_clause >
Determines the order in which the RANK values are applied to the rows in a partition. For more information, see ORDER BY Clause (Transact-SQL). An integer cannot represent a column when the < order_by_clause > is used in a ranking function.
If two or more rows tie for a rank, each tied rows receives the same rank. For example, if the two top salespeople have the same SalesYTD value, they are both ranked one. The salesperson with the next highest SalesYTD is ranked number three, because there are two rows that are ranked higher. Therefore, the RANK function does not always return consecutive integers.
The sort order that is used for the whole query determines the order in which the rows appear in a result set.
The following example ranks the products in inventory according to their quantities. The rowset is partitioned by
LocationID and sorted by
Quantity. Notice that the
ORDER BY in the
OVER clause orders the
RANK and the
ORDER BY of the
SELECT statement orders the result set.
USE AdventureWorks; GO SELECT i.ProductID, p.Name, i.LocationID, i.Quantity ,RANK() OVER (PARTITION BY i.LocationID ORDER BY i.Quantity DESC) AS 'RANK' FROM Production.ProductInventory i INNER JOIN Production.Product p ON i.ProductID = p.ProductID ORDER BY p.Name; GO