# STWithin (geometry Data Type)

Returns 1 if a geometry instance is completely within another geometry instance; otherwise, returns 0.

## Syntax

```
.STWithin ( other_geometry )
```

## Arguments

- other_geometry

Is another geometry instance to compare against the instance on which STWithin() is invoked.

## Return Types

SQL Server return type: bit

CLR return type: SqlBoolean

## Remarks

This method always returns null if the spatial reference IDs (SRIDs) of the geometry instances do not match.

## Examples

The following example uses STWithin() to test two geometry instances to see if the first instance is completely within the second instance.

```
DECLARE @g geometry;
DECLARE @h geometry;
SET @g = geometry::STGeomFromText('POLYGON((0 0, 2 0, 2 2, 0 2, 0 0))', 0);
SET @h = geometry::STGeomFromText('POLYGON((1 1, 3 1, 3 3, 1 3, 1 1))', 0);
SELECT @g.STWithin(@h);
```

## See Also