Database.Defaults Property

Represents a collection of Default objects. Each Default object represents a default defined on the database.

Namespace:  Microsoft.SqlServer.Management.Smo
Assembly:  Microsoft.SqlServer.Smo (in Microsoft.SqlServer.Smo.dll)

Syntax

'Declaration
<SfcObjectAttribute(SfcContainerRelationship.ObjectContainer, SfcContainerCardinality.ZeroToAny,  _
    GetType(Default))> _
Public ReadOnly Property Defaults As DefaultCollection
    Get
'Usage
Dim instance As Database
Dim value As DefaultCollection

value = instance.Defaults
[SfcObjectAttribute(SfcContainerRelationship.ObjectContainer, SfcContainerCardinality.ZeroToAny, 
    typeof(Default))]
public DefaultCollection Defaults { get; }
[SfcObjectAttribute(SfcContainerRelationship::ObjectContainer, SfcContainerCardinality::ZeroToAny, 
    typeof(Default))]
public:
property DefaultCollection^ Defaults {
    DefaultCollection^ get ();
}
[<SfcObjectAttribute(SfcContainerRelationship.ObjectContainer, SfcContainerCardinality.ZeroToAny, 
    typeof(Default))>]
member Defaults : DefaultCollection
function get Defaults () : DefaultCollection

Property Value

Type: Microsoft.SqlServer.Management.Smo.DefaultCollection
A DefaultCollection object that represents all the defaults defined on the database.

Remarks

Specific defaults can be referenced by using this collection by specifying the name of the default. To add a new default to the collection, call the default constructor Default.

Examples

'Connect to the local, default instance of SQL Server.
Dim srv As Server
srv = New Server

'Reference the AdventureWorks2008R2 database.
Dim db As Database
db = srv.Databases("AdventureWorks2008R2")

'Display all the log files in the database.
Dim lf As LogFile
For Each lf In db.LogFiles
   Console.WriteLine(lf.Name)
Next

PowerShell

$srv = new-Object Microsoft.SqlServer.Management.Smo.Server("(local)")
$db = New-Object Microsoft.SqlServer.Management.Smo.Database
$db = $srv.Databases.Item("AdventureWorks2008R2")

Foreach ($lf in $db.LogFiles)
{
   Write-Host $lf.Name
}