_rotr8, _rotr16

Microsoft Specific

Rotate the input values to the right to the least significant bit (LSB) by a specified number of bit positions.

unsigned char _rotr8( 
   unsigned char value, 
   unsigned char shift 
unsigned short _rotr16( 
   unsigned short value, 
   unsigned char shift 


  • [in] value
    The value to rotate.

  • [in] shift
    The number of bits to rotate.

Return Value

The rotated value.





x86, IPF, x64


x86, IPF, x64

Header file <intrin.h>


Unlike a right-shift operation, when executing a right rotation, the low order bits that fall off the low end are moved into the high order bit positions.


// rotr.cpp
#include <stdio.h>
#include <intrin.h>

#pragma intrinsic(_rotr8, _rotr16)

int main()
    unsigned char c = 'A', c1, c2;

    for (int i = 0; i < 8; i++)
       printf_s("Rotating 0x%x right by %d bits gives 0x%x\n", c,
                i, _rotr8(c, i));

    unsigned short s = 0x12;
    int nBit = 10;

    printf_s("Rotating unsigned short 0x%x right by %d bits "
             "gives 0x%x\n",
            s, nBit, _rotr16(s, nBit));
Rotating 0x41 right by 0 bits gives 0x41
Rotating 0x41 right by 1 bits gives 0xa0
Rotating 0x41 right by 2 bits gives 0x50
Rotating 0x41 right by 3 bits gives 0x28
Rotating 0x41 right by 4 bits gives 0x14
Rotating 0x41 right by 5 bits gives 0xa
Rotating 0x41 right by 6 bits gives 0x5
Rotating 0x41 right by 7 bits gives 0x82
Rotating unsigned short 0x12 right by 10 bits gives 0x480

See Also


_rotl8, _rotl16

Compiler Intrinsics