String.LastIndexOf Method (String, Int32)
[ This article is for Windows Phone 8 developers. If you’re developing for Windows 10, see the latest documentation. ]
Reports the zero-based index position of the last occurrence of a specified string within this instance. The search starts at a specified character position and proceeds backward toward the beginning of the string.
Namespace: System
Assembly: mscorlib (in mscorlib.dll)
Syntax
Public Function LastIndexOf ( _
value As String, _
startIndex As Integer _
) As Integer
public int LastIndexOf(
string value,
int startIndex
)
Parameters
- value
Type: System..::.String
The string to seek.
- startIndex
Type: System..::.Int32
The search starting position. The search proceeds from startIndex toward the beginning of this instance.
Return Value
Type: System..::.Int32
The zero-based index position of value if that string is found, or -1 if it is not found or if the current instance equals String..::.Empty. If value is String..::.Empty, the return value is the smaller of startIndex and the last index position in this instance.
Exceptions
| Exception | Condition |
|---|---|
| ArgumentNullException | value is nullNothingnullptra null reference (Nothing in Visual Basic). |
| ArgumentOutOfRangeException | The current instance does not equal String..::.Empty, and startIndex is less than zero or greater than the length of the current instance. -or- The current instance equals String..::.Empty, and startIndex is greater than zero. |
Remarks
Index numbering starts from zero. That is, the first character in the string is at index zero and the last is at Length - 1.
The search begins at the startIndex character position of this instance and proceeds backward toward the beginning until either value is found or the first character position has been examined. For example, if startIndex is Length - 1, the method searches every character from the last character in the string to the beginning.
This method performs a word (case-sensitive and culture-sensitive) search using the current culture. The search begins at the startIndex character position of this instance and proceeds backward until either value is found or the first character position has been examined.
Examples
The following code example finds the index of all occurrences of a string in target string, working from the end of the target string to the start of the target string.
' Sample for String.LastIndexOf(String, Int32)
_
Class Example
Public Shared Sub Demo(ByVal outputBlock As System.Windows.Controls.TextBlock)
Dim br1 As String = "0----+----1----+----2----+----3----+----4----+----5----+----6----+-"
Dim br2 As String = "0123456789012345678901234567890123456789012345678901234567890123456"
Dim str As String = "Now is the time for all good men to come to the aid of their party."
Dim start As Integer
Dim at As Integer
'#3
start = str.Length - 1
outputBlock.Text += String.Format("All occurrences of 'he' from position {0} to 0.", start) & vbCrLf
outputBlock.Text += String.Format("{1}{0}{2}{0}{3}{0}", Environment.NewLine, br1, br2, str) & vbCrLf
outputBlock.Text &= "The string 'he' occurs at position(s): "
at = 0
While start > -1 And at > -1
at = str.LastIndexOf("he", start)
If at > -1 Then
outputBlock.Text += String.Format("{0} ", at)
start = at - 1
End If
End While
outputBlock.Text += String.Format("{0}{0}{0}", Environment.NewLine)
End Sub 'Main
End Class 'Sample
'
'This example produces the following results:
'All occurrences of 'he' from position 66 to 0.
'0----+----1----+----2----+----3----+----4----+----5----+----6----+-
'0123456789012345678901234567890123456789012345678901234567890123456
'Now is the time for all good men to come to the aid of their party.
'
'The string 'he' occurs at position(s): 56 45 8
'
'
// Sample for String.LastIndexOf(String, Int32)
using System;
class Example
{
public static void Demo(System.Windows.Controls.TextBlock outputBlock)
{
string br1 = "0----+----1----+----2----+----3----+----4----+----5----+----6----+-";
string br2 = "0123456789012345678901234567890123456789012345678901234567890123456";
string str = "Now is the time for all good men to come to the aid of their party.";
int start;
int at;
start = str.Length - 1;
outputBlock.Text += String.Format("All occurrences of 'he' from position {0} to 0.", start) + "\n";
outputBlock.Text += String.Format("{1}{0}{2}{0}{3}{0}", Environment.NewLine, br1, br2, str) + "\n";
outputBlock.Text += "The string 'he' occurs at position(s): ";
at = 0;
while ((start > -1) && (at > -1))
{
at = str.LastIndexOf("he", start);
if (at > -1)
{
outputBlock.Text += String.Format("{0} ", at);
start = at - 1;
}
}
outputBlock.Text += String.Format("{0}{0}{0}", Environment.NewLine);
}
}
/*
This example produces the following results:
All occurrences of 'he' from position 66 to 0.
0----+----1----+----2----+----3----+----4----+----5----+----6----+-
0123456789012345678901234567890123456789012345678901234567890123456
Now is the time for all good men to come to the aid of their party.
The string 'he' occurs at position(s): 56 45 8
*/
Version Information
Windows Phone OS
Supported in: 8.1, 8.0, 7.1, 7.0
Platforms
Windows Phone