Enumerable.Max Método

public:
[System::Runtime::CompilerServices::Extension]
 static Nullable<float> Max(System::Collections::Generic::IEnumerable<Nullable<float>> ^ source);

public static float? Max (this System.Collections.Generic.IEnumerable<Nullable<float>> source);

static member Max : seq<Nullable<single>> -> Nullable<single>

<Extension()>
Public Function Max (source As IEnumerable(Of Nullable(Of Single))) As Nullable(Of Single)

Parámetros

Devoluciones

Nullable<Single>

Valor de tipo Nullable<Single> en C# o Nullable(Of Single) en Visual Basic que corresponde al valor máximo de la secuencia.A value of type Nullable<Single> in C# or Nullable(Of Single) in Visual Basic that corresponds to the maximum value in the sequence.

Excepciones

Ejemplos

En el ejemplo de código siguiente se muestra cómo utilizar Max(IEnumerable<Nullable<Double>>) para determinar el valor máximo de una secuencia.The following code example demonstrates how to use Max(IEnumerable<Nullable<Double>>) to determine the maximum value in a sequence.

double?[] doubles = { null, 1.5E+104, 9E+103, -2E+103 };

double? max = doubles.Max();

Console.WriteLine("The largest number is {0}.", max);

/*
 This code produces the following output:

 The largest number is 1.5E+104.
*/

' Create an array of Nullable Double values.
Dim doubles() As Nullable(Of Double) =
{Nothing, 1.5E+104, 9.0E+103, -2.0E+103}

' Determine the maximum value in the array.
Dim max As Nullable(Of Double) = doubles.Max()

' Display the result.
Console.WriteLine($"The largest number is {max}")

' This code produces the following output:
'
' The largest number is 1.5E+104

Comentarios

El Max(IEnumerable<Nullable<Single>>) método utiliza la Single implementación de IComparable<T> para comparar los valores.The Max(IEnumerable<Nullable<Single>>) method uses the Single implementation of IComparable<T> to compare values.

Si la secuencia de origen está vacía o contiene solo valores que son null , esta función devuelve null .If the source sequence is empty or contains only values that are null, this function returns null.

En Visual Basic sintaxis de expresiones de consulta, una Aggregate Into Max() cláusula se convierte en una invocación de Max .In Visual Basic query expression syntax, an Aggregate Into Max() clause translates to an invocation of Max.

Consulte también

• Aggregate (Cláusula, Visual Basic)Aggregate Clause (Visual Basic)

public:
[System::Runtime::CompilerServices::Extension]
 static int Max(System::Collections::Generic::IEnumerable<int> ^ source);

public static int Max (this System.Collections.Generic.IEnumerable<int> source);

static member Max : seq<int> -> int

<Extension()>
Public Function Max (source As IEnumerable(Of Integer)) As Integer

Parámetros

Devoluciones

Int32

El valor máximo de la secuencia.The maximum value in the sequence.

Excepciones

Ejemplos

En el ejemplo de código siguiente se muestra cómo utilizar Max(IEnumerable<Int64>) para determinar el valor máximo de una secuencia.The following code example demonstrates how to use Max(IEnumerable<Int64>) to determine the maximum value in a sequence.

List<long> longs = new List<long> { 4294967296L, 466855135L, 81125L };

long max = longs.Max();

Console.WriteLine("The largest number is {0}.", max);

/*
 This code produces the following output:

 The largest number is 4294967296.
*/

' Create a list of Long values.
Dim longs As New List(Of Long)(New Long() _
                           {4294967296L, 466855135L, 81125L})

' Get the maximum value in the list.
Dim max As Long = longs.Max()

' Display the result.
Console.WriteLine($"The largest number is {max}")

' This code produces the following output:
'
' The largest number is 4294967296

Comentarios

El Max(IEnumerable<Int32>) método utiliza la Int32 implementación de IComparable<T> para comparar los valores.The Max(IEnumerable<Int32>) method uses the Int32 implementation of IComparable<T> to compare values.

En Visual Basic sintaxis de expresiones de consulta, una Aggregate Into Max() cláusula se convierte en una invocación de Max .In Visual Basic query expression syntax, an Aggregate Into Max() clause translates to an invocation of Max.

Consulte también

• Aggregate (Cláusula, Visual Basic)Aggregate Clause (Visual Basic)

public:
[System::Runtime::CompilerServices::Extension]
 static Nullable<long> Max(System::Collections::Generic::IEnumerable<Nullable<long>> ^ source);

public static long? Max (this System.Collections.Generic.IEnumerable<Nullable<long>> source);

static member Max : seq<Nullable<int64>> -> Nullable<int64>

<Extension()>
Public Function Max (source As IEnumerable(Of Nullable(Of Long))) As Nullable(Of Long)

Parámetros

Devoluciones

Nullable<Int64>

Valor de tipo Nullable<Int64> en C# o Nullable(Of Int64) en Visual Basic que corresponde al valor máximo de la secuencia.A value of type Nullable<Int64> in C# or Nullable(Of Int64) in Visual Basic that corresponds to the maximum value in the sequence.

Excepciones

Ejemplos

En el ejemplo de código siguiente se muestra cómo utilizar Max(IEnumerable<Nullable<Double>>) para determinar el valor máximo de una secuencia.The following code example demonstrates how to use Max(IEnumerable<Nullable<Double>>) to determine the maximum value in a sequence.

double?[] doubles = { null, 1.5E+104, 9E+103, -2E+103 };

double? max = doubles.Max();

Console.WriteLine("The largest number is {0}.", max);

/*
 This code produces the following output:

 The largest number is 1.5E+104.
*/

' Create an array of Nullable Double values.
Dim doubles() As Nullable(Of Double) =
{Nothing, 1.5E+104, 9.0E+103, -2.0E+103}

' Determine the maximum value in the array.
Dim max As Nullable(Of Double) = doubles.Max()

' Display the result.
Console.WriteLine($"The largest number is {max}")

' This code produces the following output:
'
' The largest number is 1.5E+104

Comentarios

El Max(IEnumerable<Nullable<Int64>>) método utiliza la Int64 implementación de IComparable<T> para comparar los valores.The Max(IEnumerable<Nullable<Int64>>) method uses the Int64 implementation of IComparable<T> to compare values.

Si la secuencia de origen está vacía o contiene solo valores que son null , esta función devuelve null .If the source sequence is empty or contains only values that are null, this function returns null.

En Visual Basic sintaxis de expresiones de consulta, una Aggregate Into Max() cláusula se convierte en una invocación de Max .In Visual Basic query expression syntax, an Aggregate Into Max() clause translates to an invocation of Max.

Consulte también

• Aggregate (Cláusula, Visual Basic)Aggregate Clause (Visual Basic)

public:
[System::Runtime::CompilerServices::Extension]
 static float Max(System::Collections::Generic::IEnumerable<float> ^ source);

public static float Max (this System.Collections.Generic.IEnumerable<float> source);

static member Max : seq<single> -> single

<Extension()>
Public Function Max (source As IEnumerable(Of Single)) As Single

Parámetros

Devoluciones

Single

El valor máximo de la secuencia.The maximum value in the sequence.

Excepciones

Ejemplos

En el ejemplo de código siguiente se muestra cómo utilizar Max(IEnumerable<Int64>) para determinar el valor máximo de una secuencia.The following code example demonstrates how to use Max(IEnumerable<Int64>) to determine the maximum value in a sequence.

List<long> longs = new List<long> { 4294967296L, 466855135L, 81125L };

long max = longs.Max();

Console.WriteLine("The largest number is {0}.", max);

/*
 This code produces the following output:

 The largest number is 4294967296.
*/

' Create a list of Long values.
Dim longs As New List(Of Long)(New Long() _
                           {4294967296L, 466855135L, 81125L})

' Get the maximum value in the list.
Dim max As Long = longs.Max()

' Display the result.
Console.WriteLine($"The largest number is {max}")

' This code produces the following output:
'
' The largest number is 4294967296

Comentarios

El Max(IEnumerable<Single>) método utiliza la Single implementación de IComparable<T> para comparar los valores.The Max(IEnumerable<Single>) method uses the Single implementation of IComparable<T> to compare values.

En Visual Basic sintaxis de expresiones de consulta, una Aggregate Into Max() cláusula se convierte en una invocación de Max .In Visual Basic query expression syntax, an Aggregate Into Max() clause translates to an invocation of Max.

Consulte también

• Aggregate (Cláusula, Visual Basic)Aggregate Clause (Visual Basic)

public:
[System::Runtime::CompilerServices::Extension]
 static Nullable<int> Max(System::Collections::Generic::IEnumerable<Nullable<int>> ^ source);

public static int? Max (this System.Collections.Generic.IEnumerable<Nullable<int>> source);

static member Max : seq<Nullable<int>> -> Nullable<int>

<Extension()>
Public Function Max (source As IEnumerable(Of Nullable(Of Integer))) As Nullable(Of Integer)

Parámetros

Devoluciones

Nullable<Int32>

Valor de tipo Nullable<Int32> en C# o Nullable(Of Int32) en Visual Basic que corresponde al valor máximo de la secuencia.A value of type Nullable<Int32> in C# or Nullable(Of Int32) in Visual Basic that corresponds to the maximum value in the sequence.

Excepciones

Ejemplos

En el ejemplo de código siguiente se muestra cómo utilizar Max(IEnumerable<Nullable<Double>>) para determinar el valor máximo de una secuencia.The following code example demonstrates how to use Max(IEnumerable<Nullable<Double>>) to determine the maximum value in a sequence.

double?[] doubles = { null, 1.5E+104, 9E+103, -2E+103 };

double? max = doubles.Max();

Console.WriteLine("The largest number is {0}.", max);

/*
 This code produces the following output:

 The largest number is 1.5E+104.
*/

' Create an array of Nullable Double values.
Dim doubles() As Nullable(Of Double) =
{Nothing, 1.5E+104, 9.0E+103, -2.0E+103}

' Determine the maximum value in the array.
Dim max As Nullable(Of Double) = doubles.Max()

' Display the result.
Console.WriteLine($"The largest number is {max}")

' This code produces the following output:
'
' The largest number is 1.5E+104

Comentarios

El Max(IEnumerable<Nullable<Int32>>) método utiliza la Int32 implementación de IComparable<T> para comparar los valores.The Max(IEnumerable<Nullable<Int32>>) method uses the Int32 implementation of IComparable<T> to compare values.

Si la secuencia de origen está vacía o contiene solo valores que son null , esta función devuelve null .If the source sequence is empty or contains only values that are null, this function returns null.

En Visual Basic sintaxis de expresiones de consulta, una Aggregate Into Max() cláusula se convierte en una invocación de Max .In Visual Basic query expression syntax, an Aggregate Into Max() clause translates to an invocation of Max.

Consulte también

• Aggregate (Cláusula, Visual Basic)Aggregate Clause (Visual Basic)

public:
[System::Runtime::CompilerServices::Extension]
 static System::Decimal Max(System::Collections::Generic::IEnumerable<System::Decimal> ^ source);

public static decimal Max (this System.Collections.Generic.IEnumerable<decimal> source);

static member Max : seq<decimal> -> decimal

<Extension()>
Public Function Max (source As IEnumerable(Of Decimal)) As Decimal

Parámetros

Devoluciones

Decimal

El valor máximo de la secuencia.The maximum value in the sequence.

Excepciones

Ejemplos

En el ejemplo de código siguiente se muestra cómo utilizar Max(IEnumerable<Int64>) para determinar el valor máximo de una secuencia.The following code example demonstrates how to use Max(IEnumerable<Int64>) to determine the maximum value in a sequence.

List<long> longs = new List<long> { 4294967296L, 466855135L, 81125L };

long max = longs.Max();

Console.WriteLine("The largest number is {0}.", max);

/*
 This code produces the following output:

 The largest number is 4294967296.
*/

' Create a list of Long values.
Dim longs As New List(Of Long)(New Long() _
                           {4294967296L, 466855135L, 81125L})

' Get the maximum value in the list.
Dim max As Long = longs.Max()

' Display the result.
Console.WriteLine($"The largest number is {max}")

' This code produces the following output:
'
' The largest number is 4294967296

Comentarios

El Max(IEnumerable<Decimal>) método utiliza la Decimal implementación de IComparable<T> para comparar los valores.The Max(IEnumerable<Decimal>) method uses the Decimal implementation of IComparable<T> to compare values.

En Visual Basic sintaxis de expresiones de consulta, una Aggregate Into Max() cláusula se convierte en una invocación de Max .In Visual Basic query expression syntax, an Aggregate Into Max() clause translates to an invocation of Max.

Consulte también

• Aggregate (Cláusula, Visual Basic)Aggregate Clause (Visual Basic)

public:
[System::Runtime::CompilerServices::Extension]
 static Nullable<System::Decimal> Max(System::Collections::Generic::IEnumerable<Nullable<System::Decimal>> ^ source);

public static decimal? Max (this System.Collections.Generic.IEnumerable<Nullable<decimal>> source);

static member Max : seq<Nullable<decimal>> -> Nullable<decimal>

<Extension()>
Public Function Max (source As IEnumerable(Of Nullable(Of Decimal))) As Nullable(Of Decimal)

Parámetros

Devoluciones

Nullable<Decimal>

Valor de tipo Nullable<Decimal> en C# o Nullable(Of Decimal) en Visual Basic que corresponde al valor máximo de la secuencia.A value of type Nullable<Decimal> in C# or Nullable(Of Decimal) in Visual Basic that corresponds to the maximum value in the sequence.

Excepciones

Ejemplos

En el ejemplo de código siguiente se muestra cómo utilizar Max(IEnumerable<Nullable<Double>>) para determinar el valor máximo de una secuencia.The following code example demonstrates how to use Max(IEnumerable<Nullable<Double>>) to determine the maximum value in a sequence.

double?[] doubles = { null, 1.5E+104, 9E+103, -2E+103 };

double? max = doubles.Max();

Console.WriteLine("The largest number is {0}.", max);

/*
 This code produces the following output:

 The largest number is 1.5E+104.
*/

' Create an array of Nullable Double values.
Dim doubles() As Nullable(Of Double) =
{Nothing, 1.5E+104, 9.0E+103, -2.0E+103}

' Determine the maximum value in the array.
Dim max As Nullable(Of Double) = doubles.Max()

' Display the result.
Console.WriteLine($"The largest number is {max}")

' This code produces the following output:
'
' The largest number is 1.5E+104

Comentarios

El Max(IEnumerable<Nullable<Decimal>>) método utiliza la Decimal implementación de IComparable<T> para comparar los valores.The Max(IEnumerable<Nullable<Decimal>>) method uses the Decimal implementation of IComparable<T> to compare values.

Si la secuencia de origen está vacía o contiene solo valores que son null , esta función devuelve null .If the source sequence is empty or contains only values that are null, this function returns null.

En Visual Basic sintaxis de expresiones de consulta, una Aggregate Into Max() cláusula se convierte en una invocación de Max .In Visual Basic query expression syntax, an Aggregate Into Max() clause translates to an invocation of Max.

Consulte también

• Aggregate (Cláusula, Visual Basic)Aggregate Clause (Visual Basic)

public:
[System::Runtime::CompilerServices::Extension]
 static long Max(System::Collections::Generic::IEnumerable<long> ^ source);

public static long Max (this System.Collections.Generic.IEnumerable<long> source);

static member Max : seq<int64> -> int64

<Extension()>
Public Function Max (source As IEnumerable(Of Long)) As Long

Parámetros

Devoluciones

Int64

El valor máximo de la secuencia.The maximum value in the sequence.

Excepciones

Ejemplos

En el ejemplo de código siguiente se muestra cómo utilizar Max(IEnumerable<Int64>) para determinar el valor máximo de una secuencia.The following code example demonstrates how to use Max(IEnumerable<Int64>) to determine the maximum value in a sequence.

List<long> longs = new List<long> { 4294967296L, 466855135L, 81125L };

long max = longs.Max();

Console.WriteLine("The largest number is {0}.", max);

/*
 This code produces the following output:

 The largest number is 4294967296.
*/

' Create a list of Long values.
Dim longs As New List(Of Long)(New Long() _
                           {4294967296L, 466855135L, 81125L})

' Get the maximum value in the list.
Dim max As Long = longs.Max()

' Display the result.
Console.WriteLine($"The largest number is {max}")

' This code produces the following output:
'
' The largest number is 4294967296

Comentarios

El Max(IEnumerable<Int64>) método utiliza la Int64 implementación de IComparable<T> para comparar los valores.The Max(IEnumerable<Int64>) method uses the Int64 implementation of IComparable<T> to compare values.

En Visual Basic sintaxis de expresiones de consulta, una Aggregate Into Max() cláusula se convierte en una invocación de Max .In Visual Basic query expression syntax, an Aggregate Into Max() clause translates to an invocation of Max.

Consulte también

• Aggregate (Cláusula, Visual Basic)Aggregate Clause (Visual Basic)

public:
[System::Runtime::CompilerServices::Extension]
 static double Max(System::Collections::Generic::IEnumerable<double> ^ source);

public static double Max (this System.Collections.Generic.IEnumerable<double> source);

static member Max : seq<double> -> double

<Extension()>
Public Function Max (source As IEnumerable(Of Double)) As Double

Parámetros

Devoluciones

Double

El valor máximo de la secuencia.The maximum value in the sequence.

Excepciones

Ejemplos

En el ejemplo de código siguiente se muestra cómo utilizar Max(IEnumerable<Int64>) para determinar el valor máximo de una secuencia.The following code example demonstrates how to use Max(IEnumerable<Int64>) to determine the maximum value in a sequence.

List<long> longs = new List<long> { 4294967296L, 466855135L, 81125L };

long max = longs.Max();

Console.WriteLine("The largest number is {0}.", max);

/*
 This code produces the following output:

 The largest number is 4294967296.
*/

' Create a list of Long values.
Dim longs As New List(Of Long)(New Long() _
                           {4294967296L, 466855135L, 81125L})

' Get the maximum value in the list.
Dim max As Long = longs.Max()

' Display the result.
Console.WriteLine($"The largest number is {max}")

' This code produces the following output:
'
' The largest number is 4294967296

Comentarios

El Max(IEnumerable<Double>) método utiliza la Double implementación de IComparable<T> para comparar los valores.The Max(IEnumerable<Double>) method uses the Double implementation of IComparable<T> to compare values.

En Visual Basic sintaxis de expresiones de consulta, una Aggregate Into Max() cláusula se convierte en una invocación de Max .In Visual Basic query expression syntax, an Aggregate Into Max() clause translates to an invocation of Max.

Consulte también

• Aggregate (Cláusula, Visual Basic)Aggregate Clause (Visual Basic)

public:
[System::Runtime::CompilerServices::Extension]
 static Nullable<double> Max(System::Collections::Generic::IEnumerable<Nullable<double>> ^ source);

public static double? Max (this System.Collections.Generic.IEnumerable<Nullable<double>> source);

static member Max : seq<Nullable<double>> -> Nullable<double>

<Extension()>
Public Function Max (source As IEnumerable(Of Nullable(Of Double))) As Nullable(Of Double)

Parámetros

Devoluciones

Nullable<Double>

Valor de tipo Nullable<Double> en C# o Nullable(Of Double) en Visual Basic que corresponde al valor máximo de la secuencia.A value of type Nullable<Double> in C# or Nullable(Of Double) in Visual Basic that corresponds to the maximum value in the sequence.

Excepciones

Ejemplos

En el ejemplo de código siguiente se muestra cómo utilizar Max(IEnumerable<Nullable<Double>>) para determinar el valor máximo de una secuencia.The following code example demonstrates how to use Max(IEnumerable<Nullable<Double>>) to determine the maximum value in a sequence.

double?[] doubles = { null, 1.5E+104, 9E+103, -2E+103 };

double? max = doubles.Max();

Console.WriteLine("The largest number is {0}.", max);

/*
 This code produces the following output:

 The largest number is 1.5E+104.
*/

' Create an array of Nullable Double values.
Dim doubles() As Nullable(Of Double) =
{Nothing, 1.5E+104, 9.0E+103, -2.0E+103}

' Determine the maximum value in the array.
Dim max As Nullable(Of Double) = doubles.Max()

' Display the result.
Console.WriteLine($"The largest number is {max}")

' This code produces the following output:
'
' The largest number is 1.5E+104

Comentarios

El Max(IEnumerable<Nullable<Double>>) método utiliza la Double implementación de IComparable<T> para comparar los valores.The Max(IEnumerable<Nullable<Double>>) method uses the Double implementation of IComparable<T> to compare values.

Si la secuencia de origen está vacía o contiene solo valores que son null , esta función devuelve null .If the source sequence is empty or contains only values that are null, this function returns null.

En Visual Basic sintaxis de expresiones de consulta, una Aggregate Into Max() cláusula se convierte en una invocación de Max .In Visual Basic query expression syntax, an Aggregate Into Max() clause translates to an invocation of Max.

Consulte también

• Aggregate (Cláusula, Visual Basic)Aggregate Clause (Visual Basic)

public:
generic <typename TSource, typename TResult>
[System::Runtime::CompilerServices::Extension]
 static TResult Max(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, TResult> ^ selector);

public static TResult Max<TSource,TResult> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,TResult> selector);

public static TResult Max<TSource,TResult> (this System.Collections.Generic.IEnumerable<TSource>? source, Func<TSource,TResult>? selector);

static member Max : seq<'Source> * Func<'Source, 'Result> -> 'Result

<Extension()>
Public Function Max(Of TSource, TResult) (source As IEnumerable(Of TSource), selector As Func(Of TSource, TResult)) As TResult

Parámetros de tipo

Parámetros

Devoluciones

TResult

El valor máximo de la secuencia.The maximum value in the sequence.

Excepciones

Ejemplos

En el ejemplo de código siguiente se muestra cómo utilizar Max<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) para determinar el valor máximo de una secuencia de valores proyectados.The following code example demonstrates how to use Max<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) to determine the maximum value in a sequence of projected values.

class Pet
{
    public string Name { get; set; }
    public int Age { get; set; }
}

public static void MaxEx4()
{
    Pet[] pets = { new Pet { Name="Barley", Age=8 },
                   new Pet { Name="Boots", Age=4 },
                   new Pet { Name="Whiskers", Age=1 } };

    int max = pets.Max(pet => pet.Age + pet.Name.Length);

    Console.WriteLine(
        "The maximum pet age plus name length is {0}.",
        max);
}

/*
 This code produces the following output:

 The maximum pet age plus name length is 14.
*/

Structure Pet
    Public Name As String
    Public Age As Integer
End Structure

Sub MaxEx4()
    ' Create an array of Pet objects.
    Dim pets() As Pet = {New Pet With {.Name = "Barley", .Age = 8},
                     New Pet With {.Name = "Boots", .Age = 4},
                     New Pet With {.Name = "Whiskers", .Age = 1}}

    ' Determine the "maximum" pet by passing a
    ' lambda expression to Max() that sums the pet's age
    ' and name length.
    Dim max As Integer = pets.Max(Function(pet) _
                                  pet.Age + pet.Name.Length)

    ' Display the result.
    Console.WriteLine($"The maximum pet age plus name length is {max}")
End Sub

' This code produces the following output:
'
' The maximum pet age plus name length is 14

Comentarios

Si TResult el tipo implementa IComparable<T> , este método utiliza esa implementación para comparar los valores.If type TResult implements IComparable<T>, this method uses that implementation to compare values. De lo contrario, si el tipo TResult implementa IComparable , esa implementación se utiliza para comparar los valores.Otherwise, if type TResult implements IComparable, that implementation is used to compare values.

En Visual Basic sintaxis de expresiones de consulta, una Aggregate Into Max() cláusula se convierte en una invocación de Max .In Visual Basic query expression syntax, an Aggregate Into Max() clause translates to an invocation of Max.

Consulte también

• Aggregate (Cláusula, Visual Basic)Aggregate Clause (Visual Basic)

public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
 static float Max(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, float> ^ selector);

public static float Max<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,float> selector);

static member Max : seq<'Source> * Func<'Source, single> -> single

<Extension()>
Public Function Max(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Single)) As Single

Parámetros de tipo

Parámetros

Devoluciones

Single

El valor máximo de la secuencia.The maximum value in the sequence.

Excepciones

Ejemplos

En el ejemplo de código siguiente se muestra cómo utilizar Max<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) para determinar el valor máximo de una secuencia de valores proyectados.The following code example demonstrates how to use Max<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) to determine the maximum value in a sequence of projected values.

class Pet
{
    public string Name { get; set; }
    public int Age { get; set; }
}

public static void MaxEx4()
{
    Pet[] pets = { new Pet { Name="Barley", Age=8 },
                   new Pet { Name="Boots", Age=4 },
                   new Pet { Name="Whiskers", Age=1 } };

    int max = pets.Max(pet => pet.Age + pet.Name.Length);

    Console.WriteLine(
        "The maximum pet age plus name length is {0}.",
        max);
}

/*
 This code produces the following output:

 The maximum pet age plus name length is 14.
*/

Structure Pet
    Public Name As String
    Public Age As Integer
End Structure

Sub MaxEx4()
    ' Create an array of Pet objects.
    Dim pets() As Pet = {New Pet With {.Name = "Barley", .Age = 8},
                     New Pet With {.Name = "Boots", .Age = 4},
                     New Pet With {.Name = "Whiskers", .Age = 1}}

    ' Determine the "maximum" pet by passing a
    ' lambda expression to Max() that sums the pet's age
    ' and name length.
    Dim max As Integer = pets.Max(Function(pet) _
                                  pet.Age + pet.Name.Length)

    ' Display the result.
    Console.WriteLine($"The maximum pet age plus name length is {max}")
End Sub

' This code produces the following output:
'
' The maximum pet age plus name length is 14

Comentarios

El Max<TSource>(IEnumerable<TSource>, Func<TSource,Single>) método utiliza la Single implementación de IComparable<T> para comparar los valores.The Max<TSource>(IEnumerable<TSource>, Func<TSource,Single>) method uses the Single implementation of IComparable<T> to compare values.

Este método se puede aplicar a una secuencia de valores arbitrarios si se proporciona una función, selector , que proyecta los miembros de source en un tipo numérico, en concreto Single .You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Single.

En Visual Basic sintaxis de expresiones de consulta, una Aggregate Into Max() cláusula se convierte en una invocación de Max .In Visual Basic query expression syntax, an Aggregate Into Max() clause translates to an invocation of Max.

Consulte también

• Aggregate (Cláusula, Visual Basic)Aggregate Clause (Visual Basic)

public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
 static Nullable<float> Max(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, Nullable<float>> ^ selector);

public static float? Max<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,Nullable<float>> selector);

static member Max : seq<'Source> * Func<'Source, Nullable<single>> -> Nullable<single>

<Extension()>
Public Function Max(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Nullable(Of Single))) As Nullable(Of Single)

Parámetros de tipo

Parámetros

Devoluciones

Nullable<Single>

Valor de tipo Nullable<Single> en C# o Nullable(Of Single) en Visual Basic que corresponde al valor máximo de la secuencia.The value of type Nullable<Single> in C# or Nullable(Of Single) in Visual Basic that corresponds to the maximum value in the sequence.

Excepciones

Ejemplos

En el ejemplo de código siguiente se muestra cómo utilizar Max<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) para determinar el valor máximo de una secuencia de valores proyectados.The following code example demonstrates how to use Max<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) to determine the maximum value in a sequence of projected values.

class Pet
{
    public string Name { get; set; }
    public int Age { get; set; }
}

public static void MaxEx4()
{
    Pet[] pets = { new Pet { Name="Barley", Age=8 },
                   new Pet { Name="Boots", Age=4 },
                   new Pet { Name="Whiskers", Age=1 } };

    int max = pets.Max(pet => pet.Age + pet.Name.Length);

    Console.WriteLine(
        "The maximum pet age plus name length is {0}.",
        max);
}

/*
 This code produces the following output:

 The maximum pet age plus name length is 14.
*/

Structure Pet
    Public Name As String
    Public Age As Integer
End Structure

Sub MaxEx4()
    ' Create an array of Pet objects.
    Dim pets() As Pet = {New Pet With {.Name = "Barley", .Age = 8},
                     New Pet With {.Name = "Boots", .Age = 4},
                     New Pet With {.Name = "Whiskers", .Age = 1}}

    ' Determine the "maximum" pet by passing a
    ' lambda expression to Max() that sums the pet's age
    ' and name length.
    Dim max As Integer = pets.Max(Function(pet) _
                                  pet.Age + pet.Name.Length)

    ' Display the result.
    Console.WriteLine($"The maximum pet age plus name length is {max}")
End Sub

' This code produces the following output:
'
' The maximum pet age plus name length is 14

Comentarios

El Max<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Single>>) método utiliza la Single implementación de IComparable<T> para comparar los valores.The Max<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Single>>) method uses the Single implementation of IComparable<T> to compare values.

Este método se puede aplicar a una secuencia de valores arbitrarios si se proporciona una función, selector , que proyecta los miembros de source en un tipo numérico, específicamente Nullable<Single> en C# o Nullable(Of Single) en Visual Basic.You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Nullable<Single> in C# or Nullable(Of Single) in Visual Basic.

En Visual Basic sintaxis de expresiones de consulta, una Aggregate Into Max() cláusula se convierte en una invocación de Max .In Visual Basic query expression syntax, an Aggregate Into Max() clause translates to an invocation of Max.

Consulte también

• Aggregate (Cláusula, Visual Basic)Aggregate Clause (Visual Basic)

public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
 static Nullable<long> Max(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, Nullable<long>> ^ selector);

public static long? Max<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,Nullable<long>> selector);

static member Max : seq<'Source> * Func<'Source, Nullable<int64>> -> Nullable<int64>

<Extension()>
Public Function Max(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Nullable(Of Long))) As Nullable(Of Long)

Parámetros de tipo

Parámetros

Devoluciones

Nullable<Int64>

Valor de tipo Nullable<Int64> en C# o Nullable(Of Int64) en Visual Basic que corresponde al valor máximo de la secuencia.The value of type Nullable<Int64> in C# or Nullable(Of Int64) in Visual Basic that corresponds to the maximum value in the sequence.

Excepciones

Ejemplos

En el ejemplo de código siguiente se muestra cómo utilizar Max<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) para determinar el valor máximo de una secuencia de valores proyectados.The following code example demonstrates how to use Max<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) to determine the maximum value in a sequence of projected values.

class Pet
{
    public string Name { get; set; }
    public int Age { get; set; }
}

public static void MaxEx4()
{
    Pet[] pets = { new Pet { Name="Barley", Age=8 },
                   new Pet { Name="Boots", Age=4 },
                   new Pet { Name="Whiskers", Age=1 } };

    int max = pets.Max(pet => pet.Age + pet.Name.Length);

    Console.WriteLine(
        "The maximum pet age plus name length is {0}.",
        max);
}

/*
 This code produces the following output:

 The maximum pet age plus name length is 14.
*/

Structure Pet
    Public Name As String
    Public Age As Integer
End Structure

Sub MaxEx4()
    ' Create an array of Pet objects.
    Dim pets() As Pet = {New Pet With {.Name = "Barley", .Age = 8},
                     New Pet With {.Name = "Boots", .Age = 4},
                     New Pet With {.Name = "Whiskers", .Age = 1}}

    ' Determine the "maximum" pet by passing a
    ' lambda expression to Max() that sums the pet's age
    ' and name length.
    Dim max As Integer = pets.Max(Function(pet) _
                                  pet.Age + pet.Name.Length)

    ' Display the result.
    Console.WriteLine($"The maximum pet age plus name length is {max}")
End Sub

' This code produces the following output:
'
' The maximum pet age plus name length is 14

Comentarios

El Max<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Int64>>) método utiliza la Int64 implementación de IComparable<T> para comparar los valores.The Max<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Int64>>) method uses the Int64 implementation of IComparable<T> to compare values.

Este método se puede aplicar a una secuencia de valores arbitrarios si se proporciona una función, selector , que proyecta los miembros de source en un tipo numérico, específicamente Nullable<Int64> en C# o Nullable(Of Int64) en Visual Basic.You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Nullable<Int64> in C# or Nullable(Of Int64) in Visual Basic.

En Visual Basic sintaxis de expresiones de consulta, una Aggregate Into Max() cláusula se convierte en una invocación de Max .In Visual Basic query expression syntax, an Aggregate Into Max() clause translates to an invocation of Max.

Consulte también

• Aggregate (Cláusula, Visual Basic)Aggregate Clause (Visual Basic)

public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
 static Nullable<int> Max(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, Nullable<int>> ^ selector);

public static int? Max<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,Nullable<int>> selector);

static member Max : seq<'Source> * Func<'Source, Nullable<int>> -> Nullable<int>

<Extension()>
Public Function Max(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Nullable(Of Integer))) As Nullable(Of Integer)

Parámetros de tipo

Parámetros

Devoluciones

Nullable<Int32>

Valor de tipo Nullable<Int32> en C# o Nullable(Of Int32) en Visual Basic que corresponde al valor máximo de la secuencia.The value of type Nullable<Int32> in C# or Nullable(Of Int32) in Visual Basic that corresponds to the maximum value in the sequence.

Excepciones

Ejemplos

En el ejemplo de código siguiente se muestra cómo utilizar Max<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) para determinar el valor máximo de una secuencia de valores proyectados.The following code example demonstrates how to use Max<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) to determine the maximum value in a sequence of projected values.

class Pet
{
    public string Name { get; set; }
    public int Age { get; set; }
}

public static void MaxEx4()
{
    Pet[] pets = { new Pet { Name="Barley", Age=8 },
                   new Pet { Name="Boots", Age=4 },
                   new Pet { Name="Whiskers", Age=1 } };

    int max = pets.Max(pet => pet.Age + pet.Name.Length);

    Console.WriteLine(
        "The maximum pet age plus name length is {0}.",
        max);
}

/*
 This code produces the following output:

 The maximum pet age plus name length is 14.
*/

Structure Pet
    Public Name As String
    Public Age As Integer
End Structure

Sub MaxEx4()
    ' Create an array of Pet objects.
    Dim pets() As Pet = {New Pet With {.Name = "Barley", .Age = 8},
                     New Pet With {.Name = "Boots", .Age = 4},
                     New Pet With {.Name = "Whiskers", .Age = 1}}

    ' Determine the "maximum" pet by passing a
    ' lambda expression to Max() that sums the pet's age
    ' and name length.
    Dim max As Integer = pets.Max(Function(pet) _
                                  pet.Age + pet.Name.Length)

    ' Display the result.
    Console.WriteLine($"The maximum pet age plus name length is {max}")
End Sub

' This code produces the following output:
'
' The maximum pet age plus name length is 14

Comentarios

El Max<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Int32>>) método utiliza la Int32 implementación de IComparable<T> para comparar los valores.The Max<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Int32>>) method uses the Int32 implementation of IComparable<T> to compare values.

Este método se puede aplicar a una secuencia de valores arbitrarios si se proporciona una función, selector , que proyecta los miembros de source en un tipo numérico, específicamente Nullable<Int32> en C# o Nullable(Of Int32) en Visual Basic.You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Nullable<Int32> in C# or Nullable(Of Int32) in Visual Basic.

En Visual Basic sintaxis de expresiones de consulta, una Aggregate Into Max() cláusula se convierte en una invocación de Max .In Visual Basic query expression syntax, an Aggregate Into Max() clause translates to an invocation of Max.

Consulte también

• Aggregate (Cláusula, Visual Basic)Aggregate Clause (Visual Basic)

public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
 static Nullable<double> Max(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, Nullable<double>> ^ selector);

public static double? Max<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,Nullable<double>> selector);

static member Max : seq<'Source> * Func<'Source, Nullable<double>> -> Nullable<double>

<Extension()>
Public Function Max(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Nullable(Of Double))) As Nullable(Of Double)

Parámetros de tipo

Parámetros

Devoluciones

Nullable<Double>

Valor de tipo Nullable<Double> en C# o Nullable(Of Double) en Visual Basic que corresponde al valor máximo de la secuencia.The value of type Nullable<Double> in C# or Nullable(Of Double) in Visual Basic that corresponds to the maximum value in the sequence.

Excepciones

Ejemplos

En el ejemplo de código siguiente se muestra cómo utilizar Max<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) para determinar el valor máximo de una secuencia de valores proyectados.The following code example demonstrates how to use Max<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) to determine the maximum value in a sequence of projected values.

class Pet
{
    public string Name { get; set; }
    public int Age { get; set; }
}

public static void MaxEx4()
{
    Pet[] pets = { new Pet { Name="Barley", Age=8 },
                   new Pet { Name="Boots", Age=4 },
                   new Pet { Name="Whiskers", Age=1 } };

    int max = pets.Max(pet => pet.Age + pet.Name.Length);

    Console.WriteLine(
        "The maximum pet age plus name length is {0}.",
        max);
}

/*
 This code produces the following output:

 The maximum pet age plus name length is 14.
*/

Structure Pet
    Public Name As String
    Public Age As Integer
End Structure

Sub MaxEx4()
    ' Create an array of Pet objects.
    Dim pets() As Pet = {New Pet With {.Name = "Barley", .Age = 8},
                     New Pet With {.Name = "Boots", .Age = 4},
                     New Pet With {.Name = "Whiskers", .Age = 1}}

    ' Determine the "maximum" pet by passing a
    ' lambda expression to Max() that sums the pet's age
    ' and name length.
    Dim max As Integer = pets.Max(Function(pet) _
                                  pet.Age + pet.Name.Length)

    ' Display the result.
    Console.WriteLine($"The maximum pet age plus name length is {max}")
End Sub

' This code produces the following output:
'
' The maximum pet age plus name length is 14

Comentarios

El Max<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Double>>) método utiliza la Double implementación de IComparable<T> para comparar los valores.The Max<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Double>>) method uses the Double implementation of IComparable<T> to compare values.

Este método se puede aplicar a una secuencia de valores arbitrarios si se proporciona una función, selector , que proyecta los miembros de source en un tipo numérico, específicamente Nullable<Double> en C# o Nullable(Of Double) en Visual Basic.You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Nullable<Double> in C# or Nullable(Of Double) in Visual Basic.

En Visual Basic sintaxis de expresiones de consulta, una Aggregate Into Max() cláusula se convierte en una invocación de Max .In Visual Basic query expression syntax, an Aggregate Into Max() clause translates to an invocation of Max.

Consulte también

• Aggregate (Cláusula, Visual Basic)Aggregate Clause (Visual Basic)

public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
 static long Max(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, long> ^ selector);

public static long Max<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,long> selector);

static member Max : seq<'Source> * Func<'Source, int64> -> int64

<Extension()>
Public Function Max(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Long)) As Long

Parámetros de tipo

Parámetros

Devoluciones

Int64

El valor máximo de la secuencia.The maximum value in the sequence.

Excepciones

Ejemplos

En el ejemplo de código siguiente se muestra cómo utilizar Max<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) para determinar el valor máximo de una secuencia de valores proyectados.The following code example demonstrates how to use Max<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) to determine the maximum value in a sequence of projected values.

class Pet
{
    public string Name { get; set; }
    public int Age { get; set; }
}

public static void MaxEx4()
{
    Pet[] pets = { new Pet { Name="Barley", Age=8 },
                   new Pet { Name="Boots", Age=4 },
                   new Pet { Name="Whiskers", Age=1 } };

    int max = pets.Max(pet => pet.Age + pet.Name.Length);

    Console.WriteLine(
        "The maximum pet age plus name length is {0}.",
        max);
}

/*
 This code produces the following output:

 The maximum pet age plus name length is 14.
*/

Structure Pet
    Public Name As String
    Public Age As Integer
End Structure

Sub MaxEx4()
    ' Create an array of Pet objects.
    Dim pets() As Pet = {New Pet With {.Name = "Barley", .Age = 8},
                     New Pet With {.Name = "Boots", .Age = 4},
                     New Pet With {.Name = "Whiskers", .Age = 1}}

    ' Determine the "maximum" pet by passing a
    ' lambda expression to Max() that sums the pet's age
    ' and name length.
    Dim max As Integer = pets.Max(Function(pet) _
                                  pet.Age + pet.Name.Length)

    ' Display the result.
    Console.WriteLine($"The maximum pet age plus name length is {max}")
End Sub

' This code produces the following output:
'
' The maximum pet age plus name length is 14

Comentarios

El Max<TSource>(IEnumerable<TSource>, Func<TSource,Int64>) método utiliza la Int64 implementación de IComparable<T> para comparar los valores.The Max<TSource>(IEnumerable<TSource>, Func<TSource,Int64>) method uses the Int64 implementation of IComparable<T> to compare values.

Este método se puede aplicar a una secuencia de valores arbitrarios si se proporciona una función, selector , que proyecta los miembros de source en un tipo numérico, en concreto Int64 .You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Int64.

En Visual Basic sintaxis de expresiones de consulta, una Aggregate Into Max() cláusula se convierte en una invocación de Max .In Visual Basic query expression syntax, an Aggregate Into Max() clause translates to an invocation of Max.

Consulte también

• Aggregate (Cláusula, Visual Basic)Aggregate Clause (Visual Basic)

public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
 static int Max(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, int> ^ selector);

public static int Max<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,int> selector);

static member Max : seq<'Source> * Func<'Source, int> -> int

<Extension()>
Public Function Max(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Integer)) As Integer

Parámetros de tipo

Parámetros

Devoluciones

Int32

El valor máximo de la secuencia.The maximum value in the sequence.

Excepciones

Ejemplos

En el ejemplo de código siguiente se muestra cómo utilizar Max<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) para determinar el valor máximo de una secuencia de valores proyectados.The following code example demonstrates how to use Max<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) to determine the maximum value in a sequence of projected values.

class Pet
{
    public string Name { get; set; }
    public int Age { get; set; }
}

public static void MaxEx4()
{
    Pet[] pets = { new Pet { Name="Barley", Age=8 },
                   new Pet { Name="Boots", Age=4 },
                   new Pet { Name="Whiskers", Age=1 } };

    int max = pets.Max(pet => pet.Age + pet.Name.Length);

    Console.WriteLine(
        "The maximum pet age plus name length is {0}.",
        max);
}

/*
 This code produces the following output:

 The maximum pet age plus name length is 14.
*/

Structure Pet
    Public Name As String
    Public Age As Integer
End Structure

Sub MaxEx4()
    ' Create an array of Pet objects.
    Dim pets() As Pet = {New Pet With {.Name = "Barley", .Age = 8},
                     New Pet With {.Name = "Boots", .Age = 4},
                     New Pet With {.Name = "Whiskers", .Age = 1}}

    ' Determine the "maximum" pet by passing a
    ' lambda expression to Max() that sums the pet's age
    ' and name length.
    Dim max As Integer = pets.Max(Function(pet) _
                                  pet.Age + pet.Name.Length)

    ' Display the result.
    Console.WriteLine($"The maximum pet age plus name length is {max}")
End Sub

' This code produces the following output:
'
' The maximum pet age plus name length is 14

Comentarios

El Max<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) método utiliza la Int32 implementación de IComparable<T> para comparar los valores.The Max<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) method uses the Int32 implementation of IComparable<T> to compare values.

Este método se puede aplicar a una secuencia de valores arbitrarios si se proporciona una función, selector , que proyecta los miembros de source en un tipo numérico, en concreto Int32 .You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Int32.

En Visual Basic sintaxis de expresiones de consulta, una Aggregate Into Max() cláusula se convierte en una invocación de Max .In Visual Basic query expression syntax, an Aggregate Into Max() clause translates to an invocation of Max.

Consulte también

• Aggregate (Cláusula, Visual Basic)Aggregate Clause (Visual Basic)

public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
 static double Max(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, double> ^ selector);

public static double Max<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,double> selector);

static member Max : seq<'Source> * Func<'Source, double> -> double

<Extension()>
Public Function Max(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Double)) As Double

Parámetros de tipo

Parámetros

Devoluciones

Double

El valor máximo de la secuencia.The maximum value in the sequence.

Excepciones

Ejemplos

En el ejemplo de código siguiente se muestra cómo utilizar Max<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) para determinar el valor máximo de una secuencia de valores proyectados.The following code example demonstrates how to use Max<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) to determine the maximum value in a sequence of projected values.

class Pet
{
    public string Name { get; set; }
    public int Age { get; set; }
}

public static void MaxEx4()
{
    Pet[] pets = { new Pet { Name="Barley", Age=8 },
                   new Pet { Name="Boots", Age=4 },
                   new Pet { Name="Whiskers", Age=1 } };

    int max = pets.Max(pet => pet.Age + pet.Name.Length);

    Console.WriteLine(
        "The maximum pet age plus name length is {0}.",
        max);
}

/*
 This code produces the following output:

 The maximum pet age plus name length is 14.
*/

Structure Pet
    Public Name As String
    Public Age As Integer
End Structure

Sub MaxEx4()
    ' Create an array of Pet objects.
    Dim pets() As Pet = {New Pet With {.Name = "Barley", .Age = 8},
                     New Pet With {.Name = "Boots", .Age = 4},
                     New Pet With {.Name = "Whiskers", .Age = 1}}

    ' Determine the "maximum" pet by passing a
    ' lambda expression to Max() that sums the pet's age
    ' and name length.
    Dim max As Integer = pets.Max(Function(pet) _
                                  pet.Age + pet.Name.Length)

    ' Display the result.
    Console.WriteLine($"The maximum pet age plus name length is {max}")
End Sub

' This code produces the following output:
'
' The maximum pet age plus name length is 14

Comentarios

El Max<TSource>(IEnumerable<TSource>, Func<TSource,Double>) método utiliza la Double implementación de IComparable<T> para comparar los valores.The Max<TSource>(IEnumerable<TSource>, Func<TSource,Double>) method uses the Double implementation of IComparable<T> to compare values.

Este método se puede aplicar a una secuencia de valores arbitrarios si se proporciona una función, selector , que proyecta los miembros de source en un tipo numérico, en concreto Double .You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Double.

En Visual Basic sintaxis de expresiones de consulta, una Aggregate Into Max() cláusula se convierte en una invocación de Max .In Visual Basic query expression syntax, an Aggregate Into Max() clause translates to an invocation of Max.

Consulte también

• Aggregate (Cláusula, Visual Basic)Aggregate Clause (Visual Basic)

public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
 static System::Decimal Max(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, System::Decimal> ^ selector);

public static decimal Max<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,decimal> selector);

static member Max : seq<'Source> * Func<'Source, decimal> -> decimal

<Extension()>
Public Function Max(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Decimal)) As Decimal

Parámetros de tipo

Parámetros

Devoluciones

Decimal

El valor máximo de la secuencia.The maximum value in the sequence.

Excepciones

Ejemplos

En el ejemplo de código siguiente se muestra cómo utilizar Max<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) para determinar el valor máximo de una secuencia de valores proyectados.The following code example demonstrates how to use Max<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) to determine the maximum value in a sequence of projected values.

class Pet
{
    public string Name { get; set; }
    public int Age { get; set; }
}

public static void MaxEx4()
{
    Pet[] pets = { new Pet { Name="Barley", Age=8 },
                   new Pet { Name="Boots", Age=4 },
                   new Pet { Name="Whiskers", Age=1 } };

    int max = pets.Max(pet => pet.Age + pet.Name.Length);

    Console.WriteLine(
        "The maximum pet age plus name length is {0}.",
        max);
}

/*
 This code produces the following output:

 The maximum pet age plus name length is 14.
*/

Structure Pet
    Public Name As String
    Public Age As Integer
End Structure

Sub MaxEx4()
    ' Create an array of Pet objects.
    Dim pets() As Pet = {New Pet With {.Name = "Barley", .Age = 8},
                     New Pet With {.Name = "Boots", .Age = 4},
                     New Pet With {.Name = "Whiskers", .Age = 1}}

    ' Determine the "maximum" pet by passing a
    ' lambda expression to Max() that sums the pet's age
    ' and name length.
    Dim max As Integer = pets.Max(Function(pet) _
                                  pet.Age + pet.Name.Length)

    ' Display the result.
    Console.WriteLine($"The maximum pet age plus name length is {max}")
End Sub

' This code produces the following output:
'
' The maximum pet age plus name length is 14

Comentarios

El Max<TSource>(IEnumerable<TSource>, Func<TSource,Decimal>) método utiliza la Decimal implementación de IComparable<T> para comparar los valores.The Max<TSource>(IEnumerable<TSource>, Func<TSource,Decimal>) method uses the Decimal implementation of IComparable<T> to compare values.

Este método se puede aplicar a una secuencia de valores arbitrarios si se proporciona una función, selector , que proyecta los miembros de source en un tipo numérico, en concreto Decimal .You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Decimal.

En Visual Basic sintaxis de expresiones de consulta, una Aggregate Into Max() cláusula se convierte en una invocación de Max .In Visual Basic query expression syntax, an Aggregate Into Max() clause translates to an invocation of Max.

Consulte también

• Aggregate (Cláusula, Visual Basic)Aggregate Clause (Visual Basic)

public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
 static TSource Max(System::Collections::Generic::IEnumerable<TSource> ^ source);

public static TSource Max<TSource> (this System.Collections.Generic.IEnumerable<TSource> source);

public static TSource Max<TSource> (this System.Collections.Generic.IEnumerable<TSource>? source);

static member Max : seq<'Source> -> 'Source

<Extension()>
Public Function Max(Of TSource) (source As IEnumerable(Of TSource)) As TSource

Parámetros de tipo

Parámetros

Devoluciones

TSource

El valor máximo de la secuencia.The maximum value in the sequence.

Excepciones

Ejemplos

En el ejemplo de código siguiente se muestra cómo utilizar Max<TSource>(IEnumerable<TSource>) para determinar el valor máximo de una secuencia de IComparable<T> objetos.The following code example demonstrates how to use Max<TSource>(IEnumerable<TSource>) to determine the maximum value in a sequence of IComparable<T> objects.

/// <summary>
/// This class implements IComparable to be able to
/// compare one Pet to another Pet.
/// </summary>
class Pet : IComparable<Pet>
{
    public string Name { get; set; }
    public int Age { get; set; }

    /// <summary>
    /// Compares this Pet to another Pet by
    /// summing each Pet's age and name length.
    /// </summary>
    /// <param name="other">The Pet to compare this Pet to.</param>
    /// <returns>-1 if this Pet is 'less' than the other Pet,
    /// 0 if they are equal,
    /// or 1 if this Pet is 'greater' than the other Pet.</returns>
    int IComparable<Pet>.CompareTo(Pet other)
    {
        int sumOther = other.Age + other.Name.Length;
        int sumThis = this.Age + this.Name.Length;

        if (sumOther > sumThis)
            return -1;
        else if (sumOther == sumThis)
            return 0;
        else
            return 1;
    }
}

public static void MaxEx3()
{
    Pet[] pets = { new Pet { Name="Barley", Age=8 },
                   new Pet { Name="Boots", Age=4 },
                   new Pet { Name="Whiskers", Age=1 } };

    Pet max = pets.Max();

    Console.WriteLine(
        "The 'maximum' animal is {0}.",
        max.Name);
}

/*
 This code produces the following output:

 The 'maximum' animal is Barley.
*/

' This class implements IComparable 
' and has a custom 'CompareTo' implementation.
Class Pet
    Implements IComparable(Of Pet)

    Public Name As String
    Public Age As Integer

    ''' <summary>
    ''' Compares Pet objects by the sum of their age and name length.
    ''' </summary>
    ''' <param name="other">The Pet to compare this Pet to.</param>
    ''' <returns>-1 if this Pet's sum is 'less' than the other Pet,
    ''' 0 if they are equal,
    ''' or 1 if this Pet's sum is 'greater' than the other Pet.</returns>
    Function CompareTo(ByVal other As Pet) As Integer _
    Implements IComparable(Of Pet).CompareTo

        If (other.Age + other.Name.Length > Me.Age + Me.Name.Length) Then
            Return -1
        ElseIf (other.Age + other.Name.Length = Me.Age + Me.Name.Length) Then
            Return 0
        Else
            Return 1
        End If
    End Function
End Class

Sub MaxEx3()
    ' Create an array of Pet objects.
    Dim pets() As Pet = {New Pet With {.Name = "Barley", .Age = 8},
                     New Pet With {.Name = "Boots", .Age = 4},
                     New Pet With {.Name = "Whiskers", .Age = 1}}

    ' Find the "maximum" pet according to the 
    ' custom CompareTo() implementation.
    Dim max As Pet = pets.Max()

    ' Display the result.
    Console.WriteLine($"The 'maximum' animal is {max.Name}")
End Sub

' This code produces the following output:
'
' The 'maximum' animal is Barley

Comentarios

Si TSource el tipo implementa IComparable<T> , el Max<TSource>(IEnumerable<TSource>) método utiliza esa implementación para comparar los valores.If type TSource implements IComparable<T>, the Max<TSource>(IEnumerable<TSource>) method uses that implementation to compare values. De lo contrario, si el tipo TSource implementa IComparable , esa implementación se utiliza para comparar los valores.Otherwise, if type TSource implements IComparable, that implementation is used to compare values.

Si TSource es un tipo de referencia y la secuencia de origen está vacía o contiene solo valores que son null , este método devuelve null .If TSource is a reference type and the source sequence is empty or contains only values that are null, this method returns null.

En Visual Basic sintaxis de expresiones de consulta, una Aggregate Into Max() cláusula se convierte en una invocación de Max .In Visual Basic query expression syntax, an Aggregate Into Max() clause translates to an invocation of Max.

Consulte también

• Aggregate (Cláusula, Visual Basic)Aggregate Clause (Visual Basic)

public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
 static Nullable<System::Decimal> Max(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, Nullable<System::Decimal>> ^ selector);

public static decimal? Max<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,Nullable<decimal>> selector);

static member Max : seq<'Source> * Func<'Source, Nullable<decimal>> -> Nullable<decimal>

<Extension()>
Public Function Max(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Nullable(Of Decimal))) As Nullable(Of Decimal)

Parámetros de tipo

Parámetros

Devoluciones

Nullable<Decimal>

Valor de tipo Nullable<Decimal> en C# o Nullable(Of Decimal) en Visual Basic que corresponde al valor máximo de la secuencia.The value of type Nullable<Decimal> in C# or Nullable(Of Decimal) in Visual Basic that corresponds to the maximum value in the sequence.

Excepciones

Ejemplos

En el ejemplo de código siguiente se muestra cómo utilizar Max<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) para determinar el valor máximo de una secuencia de valores proyectados.The following code example demonstrates how to use Max<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) to determine the maximum value in a sequence of projected values.

class Pet
{
    public string Name { get; set; }
    public int Age { get; set; }
}

public static void MaxEx4()
{
    Pet[] pets = { new Pet { Name="Barley", Age=8 },
                   new Pet { Name="Boots", Age=4 },
                   new Pet { Name="Whiskers", Age=1 } };

    int max = pets.Max(pet => pet.Age + pet.Name.Length);

    Console.WriteLine(
        "The maximum pet age plus name length is {0}.",
        max);
}

/*
 This code produces the following output:

 The maximum pet age plus name length is 14.
*/

Structure Pet
    Public Name As String
    Public Age As Integer
End Structure

Sub MaxEx4()
    ' Create an array of Pet objects.
    Dim pets() As Pet = {New Pet With {.Name = "Barley", .Age = 8},
                     New Pet With {.Name = "Boots", .Age = 4},
                     New Pet With {.Name = "Whiskers", .Age = 1}}

    ' Determine the "maximum" pet by passing a
    ' lambda expression to Max() that sums the pet's age
    ' and name length.
    Dim max As Integer = pets.Max(Function(pet) _
                                  pet.Age + pet.Name.Length)

    ' Display the result.
    Console.WriteLine($"The maximum pet age plus name length is {max}")
End Sub

' This code produces the following output:
'
' The maximum pet age plus name length is 14

Comentarios

El Max<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Decimal>>) método utiliza la Decimal implementación de IComparable<T> para comparar los valores.The Max<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Decimal>>) method uses the Decimal implementation of IComparable<T> to compare values.

Este método se puede aplicar a una secuencia de valores arbitrarios si se proporciona una función, selector , que proyecta los miembros de source en un tipo numérico, específicamente Nullable<Decimal> en C# o Nullable(Of Decimal) en Visual Basic.You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Nullable<Decimal> in C# or Nullable(Of Decimal) in Visual Basic.

En Visual Basic sintaxis de expresiones de consulta, una Aggregate Into Max() cláusula se convierte en una invocación de Max .In Visual Basic query expression syntax, an Aggregate Into Max() clause translates to an invocation of Max.

Consulte también

• Aggregate (Cláusula, Visual Basic)Aggregate Clause (Visual Basic)