Enumerable.Sum Enumerable.Sum Enumerable.Sum Enumerable.Sum Method

Definición

Calcula la suma de una secuencia de valores numéricos.Computes the sum of a sequence of numeric values.

Sobrecargas

Sum(IEnumerable<Nullable<Int32>>) Sum(IEnumerable<Nullable<Int32>>) Sum(IEnumerable<Nullable<Int32>>) Sum(IEnumerable<Nullable<Int32>>)

Calcula la suma de una secuencia de valores Int32 que aceptan valores NULL.Computes the sum of a sequence of nullable Int32 values.

Sum(IEnumerable<Nullable<Single>>) Sum(IEnumerable<Nullable<Single>>) Sum(IEnumerable<Nullable<Single>>) Sum(IEnumerable<Nullable<Single>>)

Calcula la suma de una secuencia de valores Single que aceptan valores NULL.Computes the sum of a sequence of nullable Single values.

Sum(IEnumerable<Nullable<Int64>>) Sum(IEnumerable<Nullable<Int64>>) Sum(IEnumerable<Nullable<Int64>>) Sum(IEnumerable<Nullable<Int64>>)

Calcula la suma de una secuencia de valores Int64 que aceptan valores NULL.Computes the sum of a sequence of nullable Int64 values.

Sum(IEnumerable<Single>) Sum(IEnumerable<Single>) Sum(IEnumerable<Single>) Sum(IEnumerable<Single>)

Calcula la suma de una secuencia de valores Single.Computes the sum of a sequence of Single values.

Sum(IEnumerable<Nullable<Double>>) Sum(IEnumerable<Nullable<Double>>) Sum(IEnumerable<Nullable<Double>>) Sum(IEnumerable<Nullable<Double>>)

Calcula la suma de una secuencia de valores Double que aceptan valores NULL.Computes the sum of a sequence of nullable Double values.

Sum(IEnumerable<Int32>) Sum(IEnumerable<Int32>) Sum(IEnumerable<Int32>) Sum(IEnumerable<Int32>)

Calcula la suma de una secuencia de valores Int32.Computes the sum of a sequence of Int32 values.

Sum(IEnumerable<Int64>) Sum(IEnumerable<Int64>) Sum(IEnumerable<Int64>) Sum(IEnumerable<Int64>)

Calcula la suma de una secuencia de valores Int64.Computes the sum of a sequence of Int64 values.

Sum(IEnumerable<Double>) Sum(IEnumerable<Double>) Sum(IEnumerable<Double>) Sum(IEnumerable<Double>)

Calcula la suma de una secuencia de valores Double.Computes the sum of a sequence of Double values.

Sum(IEnumerable<Decimal>) Sum(IEnumerable<Decimal>) Sum(IEnumerable<Decimal>) Sum(IEnumerable<Decimal>)

Calcula la suma de una secuencia de valores Decimal.Computes the sum of a sequence of Decimal values.

Sum(IEnumerable<Nullable<Decimal>>) Sum(IEnumerable<Nullable<Decimal>>) Sum(IEnumerable<Nullable<Decimal>>) Sum(IEnumerable<Nullable<Decimal>>)

Calcula la suma de una secuencia de valores Decimal que aceptan valores NULL.Computes the sum of a sequence of nullable Decimal values.

Sum<TSource>(IEnumerable<TSource>, Func<TSource,Single>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Single>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Single>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Single>)

Calcula la suma de una secuencia de valores Single que se obtiene al invocar una función de transformación en cada elemento de la secuencia de entrada.Computes the sum of the sequence of Single values that are obtained by invoking a transform function on each element of the input sequence.

Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Single>>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Single>>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Single>>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Single>>)

Calcula la suma de una secuencia de valores Single que aceptan valores NULL que se obtiene al invocar una función de transformación en cada elemento de la secuencia de entrada.Computes the sum of the sequence of nullable Single values that are obtained by invoking a transform function on each element of the input sequence.

Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Int64>>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Int64>>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Int64>>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Int64>>)

Calcula la suma de una secuencia de valores Int64 que aceptan valores NULL que se obtiene al invocar una función de transformación en cada elemento de la secuencia de entrada.Computes the sum of the sequence of nullable Int64 values that are obtained by invoking a transform function on each element of the input sequence.

Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Int32>>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Int32>>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Int32>>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Int32>>)

Calcula la suma de una secuencia de valores Int32 que aceptan valores NULL que se obtiene al invocar una función de transformación en cada elemento de la secuencia de entrada.Computes the sum of the sequence of nullable Int32 values that are obtained by invoking a transform function on each element of the input sequence.

Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Double>>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Double>>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Double>>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Double>>)

Calcula la suma de una secuencia de valores Double que aceptan valores NULL que se obtiene al invocar una función de transformación en cada elemento de la secuencia de entrada.Computes the sum of the sequence of nullable Double values that are obtained by invoking a transform function on each element of the input sequence.

Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Decimal>>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Decimal>>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Decimal>>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Decimal>>)

Calcula la suma de una secuencia de valores Decimal que aceptan valores NULL que se obtiene al invocar una función de transformación en cada elemento de la secuencia de entrada.Computes the sum of the sequence of nullable Decimal values that are obtained by invoking a transform function on each element of the input sequence.

Sum<TSource>(IEnumerable<TSource>, Func<TSource,Int64>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Int64>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Int64>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Int64>)

Calcula la suma de una secuencia de valores Int64 que se obtiene al invocar una función de transformación en cada elemento de la secuencia de entrada.Computes the sum of the sequence of Int64 values that are obtained by invoking a transform function on each element of the input sequence.

Sum<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Int32>)

Calcula la suma de una secuencia de valores Int32 que se obtiene al invocar una función de transformación en cada elemento de la secuencia de entrada.Computes the sum of the sequence of Int32 values that are obtained by invoking a transform function on each element of the input sequence.

Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>)

Calcula la suma de una secuencia de valores Double que se obtiene al invocar una función de transformación en cada elemento de la secuencia de entrada.Computes the sum of the sequence of Double values that are obtained by invoking a transform function on each element of the input sequence.

Sum<TSource>(IEnumerable<TSource>, Func<TSource,Decimal>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Decimal>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Decimal>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Decimal>)

Calcula la suma de una secuencia de valores Decimal que se obtiene al invocar una función de transformación en cada elemento de la secuencia de entrada.Computes the sum of the sequence of Decimal values that are obtained by invoking a transform function on each element of the input sequence.

Sum(IEnumerable<Nullable<Int32>>) Sum(IEnumerable<Nullable<Int32>>) Sum(IEnumerable<Nullable<Int32>>) Sum(IEnumerable<Nullable<Int32>>)

Calcula la suma de una secuencia de valores Int32 que aceptan valores NULL.Computes the sum of a sequence of nullable Int32 values.

public:
[System::Runtime::CompilerServices::Extension]
 static Nullable<int> Sum(System::Collections::Generic::IEnumerable<Nullable<int>> ^ source);
public static Nullable<int> Sum (this System.Collections.Generic.IEnumerable<Nullable<int>> source);
static member Sum : seq<Nullable<int>> -> Nullable<int>
<Extension()>
Public Function Sum (source As IEnumerable(Of Nullable(Of Integer))) As Nullable(Of Integer)

Parámetros

source
IEnumerable<Nullable<Int32>>

Secuencia de valores Int32 que aceptan valores NULL cuya suma se va a calcular.A sequence of nullable Int32 values to calculate the sum of.

Devoluciones

Suma de los valores de la secuencia.The sum of the values in the sequence.

Excepciones

Ejemplos

En el ejemplo de código siguiente se muestra cómo usar Sum(IEnumerable<Nullable<Single>>) que sume los valores de una secuencia.The following code example demonstrates how to use Sum(IEnumerable<Nullable<Single>>) to sum the values of a sequence.

Nota

En este ejemplo de código se usa una sobrecarga de este método sobrecargado diferente de la carga específica que se describe en este tema.This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. Para ampliar el ejemplo a este tema, sustituye los elementos de la secuencia de origen por los elementos del tipo numérico adecuado.To extend the example to this topic, substitute the elements of the source sequence with elements of the appropriate numerical type.

float?[] points = { null, 0, 92.83F, null, 100.0F, 37.46F, 81.1F };

float? sum = points.Sum();

Console.WriteLine("Total points earned: {0}", sum);

/*
 This code produces the following output:

 Total points earned: 311.39
*/
' Create an array of Nullable Single values.
Dim points() As Nullable(Of Single) =
{Nothing, 0, 92.83F, Nothing, 100.0F, 37.46F, 81.1F}

' Get the sum of values in the list.
Dim sum As Nullable(Of Single) = points.Sum()

' Display the output.
MsgBox("Total points earned: " & sum)

' This code produces the following output:
'
' Total points earned: 311.39

Comentarios

Este método devuelve cero si source no contiene ningún elemento.This method returns zero if source contains no elements.

El resultado no incluyen valores que son null.The result does not include values that are null.

En la sintaxis de expresión de consulta de Visual Basic, un Aggregate Into Sum() cláusula se convierte en una invocación de Sum.In Visual Basic query expression syntax, an Aggregate Into Sum() clause translates to an invocation of Sum.

Consulte también:

Sum(IEnumerable<Nullable<Single>>) Sum(IEnumerable<Nullable<Single>>) Sum(IEnumerable<Nullable<Single>>) Sum(IEnumerable<Nullable<Single>>)

Calcula la suma de una secuencia de valores Single que aceptan valores NULL.Computes the sum of a sequence of nullable Single values.

public:
[System::Runtime::CompilerServices::Extension]
 static Nullable<float> Sum(System::Collections::Generic::IEnumerable<Nullable<float>> ^ source);
public static Nullable<float> Sum (this System.Collections.Generic.IEnumerable<Nullable<float>> source);
static member Sum : seq<Nullable<single>> -> Nullable<single>
<Extension()>
Public Function Sum (source As IEnumerable(Of Nullable(Of Single))) As Nullable(Of Single)

Parámetros

source
IEnumerable<Nullable<Single>>

Secuencia de valores Single que aceptan valores NULL cuya suma se va a calcular.A sequence of nullable Single values to calculate the sum of.

Devoluciones

Suma de los valores de la secuencia.The sum of the values in the sequence.

Excepciones

Ejemplos

En el ejemplo de código siguiente se muestra cómo usar Sum(IEnumerable<Nullable<Single>>) que sume los valores de una secuencia.The following code example demonstrates how to use Sum(IEnumerable<Nullable<Single>>) to sum the values of a sequence.

float?[] points = { null, 0, 92.83F, null, 100.0F, 37.46F, 81.1F };

float? sum = points.Sum();

Console.WriteLine("Total points earned: {0}", sum);

/*
 This code produces the following output:

 Total points earned: 311.39
*/
' Create an array of Nullable Single values.
Dim points() As Nullable(Of Single) =
{Nothing, 0, 92.83F, Nothing, 100.0F, 37.46F, 81.1F}

' Get the sum of values in the list.
Dim sum As Nullable(Of Single) = points.Sum()

' Display the output.
MsgBox("Total points earned: " & sum)

' This code produces the following output:
'
' Total points earned: 311.39

Comentarios

Este método devuelve cero si source no contiene ningún elemento.This method returns zero if source contains no elements.

El resultado no incluyen valores que son null.The result does not include values that are null.

En la sintaxis de expresión de consulta de Visual Basic, un Aggregate Into Sum() cláusula se convierte en una invocación de Sum.In Visual Basic query expression syntax, an Aggregate Into Sum() clause translates to an invocation of Sum.

Consulte también:

Sum(IEnumerable<Nullable<Int64>>) Sum(IEnumerable<Nullable<Int64>>) Sum(IEnumerable<Nullable<Int64>>) Sum(IEnumerable<Nullable<Int64>>)

Calcula la suma de una secuencia de valores Int64 que aceptan valores NULL.Computes the sum of a sequence of nullable Int64 values.

public:
[System::Runtime::CompilerServices::Extension]
 static Nullable<long> Sum(System::Collections::Generic::IEnumerable<Nullable<long>> ^ source);
public static Nullable<long> Sum (this System.Collections.Generic.IEnumerable<Nullable<long>> source);
static member Sum : seq<Nullable<int64>> -> Nullable<int64>
<Extension()>
Public Function Sum (source As IEnumerable(Of Nullable(Of Long))) As Nullable(Of Long)

Parámetros

source
IEnumerable<Nullable<Int64>>

Secuencia de valores Int64 que aceptan valores NULL cuya suma se va a calcular.A sequence of nullable Int64 values to calculate the sum of.

Devoluciones

Suma de los valores de la secuencia.The sum of the values in the sequence.

Excepciones

Ejemplos

En el ejemplo de código siguiente se muestra cómo usar Sum(IEnumerable<Nullable<Single>>) que sume los valores de una secuencia.The following code example demonstrates how to use Sum(IEnumerable<Nullable<Single>>) to sum the values of a sequence.

Nota

En este ejemplo de código se usa una sobrecarga de este método sobrecargado diferente de la carga específica que se describe en este tema.This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. Para ampliar el ejemplo a este tema, sustituye los elementos de la secuencia de origen por los elementos del tipo numérico adecuado.To extend the example to this topic, substitute the elements of the source sequence with elements of the appropriate numerical type.

float?[] points = { null, 0, 92.83F, null, 100.0F, 37.46F, 81.1F };

float? sum = points.Sum();

Console.WriteLine("Total points earned: {0}", sum);

/*
 This code produces the following output:

 Total points earned: 311.39
*/
' Create an array of Nullable Single values.
Dim points() As Nullable(Of Single) =
{Nothing, 0, 92.83F, Nothing, 100.0F, 37.46F, 81.1F}

' Get the sum of values in the list.
Dim sum As Nullable(Of Single) = points.Sum()

' Display the output.
MsgBox("Total points earned: " & sum)

' This code produces the following output:
'
' Total points earned: 311.39

Comentarios

Este método devuelve cero si source no contiene ningún elemento.This method returns zero if source contains no elements.

El resultado no incluyen valores que son null.The result does not include values that are null.

En la sintaxis de expresión de consulta de Visual Basic, un Aggregate Into Sum() cláusula se convierte en una invocación de Sum.In Visual Basic query expression syntax, an Aggregate Into Sum() clause translates to an invocation of Sum.

Consulte también:

Sum(IEnumerable<Single>) Sum(IEnumerable<Single>) Sum(IEnumerable<Single>) Sum(IEnumerable<Single>)

Calcula la suma de una secuencia de valores Single.Computes the sum of a sequence of Single values.

public:
[System::Runtime::CompilerServices::Extension]
 static float Sum(System::Collections::Generic::IEnumerable<float> ^ source);
public static float Sum (this System.Collections.Generic.IEnumerable<float> source);
static member Sum : seq<single> -> single
<Extension()>
Public Function Sum (source As IEnumerable(Of Single)) As Single

Parámetros

source
IEnumerable<Single>

Secuencia de valores Single cuya suma se va a calcular.A sequence of Single values to calculate the sum of.

Devoluciones

Suma de los valores de la secuencia.The sum of the values in the sequence.

Excepciones

Ejemplos

En el ejemplo de código siguiente se muestra cómo usar Sum(IEnumerable<Single>) que sume los valores de una secuencia.The following code example demonstrates how to use Sum(IEnumerable<Single>) to sum the values of a sequence.

List<float> numbers = new List<float> { 43.68F, 1.25F, 583.7F, 6.5F };

float sum = numbers.Sum();

Console.WriteLine("The sum of the numbers is {0}.", sum);

/*
 This code produces the following output:

 The sum of the numbers is 635.13.
*/
' Create a list of Single values.
Dim numbers As New List(Of Single)(New Single() _
                               {43.68F, 1.25F, 583.7F, 6.5F})

' Get the sum of values in the list.
Dim sum As Single = numbers.Sum()

' Display the output.
MsgBox("The sum of the numbers is " & sum)

' This code produces the following output:
'
' The sum of the numbers is 635.13

Comentarios

Este método devuelve cero si source no contiene ningún elemento.This method returns zero if source contains no elements.

En la sintaxis de expresión de consulta de Visual Basic, un Aggregate Into Sum() cláusula se convierte en una invocación de Sum.In Visual Basic query expression syntax, an Aggregate Into Sum() clause translates to an invocation of Sum.

Consulte también:

Sum(IEnumerable<Nullable<Double>>) Sum(IEnumerable<Nullable<Double>>) Sum(IEnumerable<Nullable<Double>>) Sum(IEnumerable<Nullable<Double>>)

Calcula la suma de una secuencia de valores Double que aceptan valores NULL.Computes the sum of a sequence of nullable Double values.

public:
[System::Runtime::CompilerServices::Extension]
 static Nullable<double> Sum(System::Collections::Generic::IEnumerable<Nullable<double>> ^ source);
public static Nullable<double> Sum (this System.Collections.Generic.IEnumerable<Nullable<double>> source);
static member Sum : seq<Nullable<double>> -> Nullable<double>
<Extension()>
Public Function Sum (source As IEnumerable(Of Nullable(Of Double))) As Nullable(Of Double)

Parámetros

source
IEnumerable<Nullable<Double>>

Secuencia de valores Double que aceptan valores NULL cuya suma se va a calcular.A sequence of nullable Double values to calculate the sum of.

Devoluciones

Suma de los valores de la secuencia.The sum of the values in the sequence.

Excepciones

Ejemplos

En el ejemplo de código siguiente se muestra cómo usar Sum(IEnumerable<Nullable<Single>>) que sume los valores de una secuencia.The following code example demonstrates how to use Sum(IEnumerable<Nullable<Single>>) to sum the values of a sequence.

Nota

En este ejemplo de código se usa una sobrecarga de este método sobrecargado diferente de la carga específica que se describe en este tema.This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. Para ampliar el ejemplo a este tema, sustituye los elementos de la secuencia de origen por los elementos del tipo numérico adecuado.To extend the example to this topic, substitute the elements of the source sequence with elements of the appropriate numerical type.

float?[] points = { null, 0, 92.83F, null, 100.0F, 37.46F, 81.1F };

float? sum = points.Sum();

Console.WriteLine("Total points earned: {0}", sum);

/*
 This code produces the following output:

 Total points earned: 311.39
*/
' Create an array of Nullable Single values.
Dim points() As Nullable(Of Single) =
{Nothing, 0, 92.83F, Nothing, 100.0F, 37.46F, 81.1F}

' Get the sum of values in the list.
Dim sum As Nullable(Of Single) = points.Sum()

' Display the output.
MsgBox("Total points earned: " & sum)

' This code produces the following output:
'
' Total points earned: 311.39

Comentarios

Este método devuelve cero si source no contiene ningún elemento.This method returns zero if source contains no elements.

El resultado no incluyen valores que son null.The result does not include values that are null.

En la sintaxis de expresión de consulta de Visual Basic, un Aggregate Into Sum() cláusula se convierte en una invocación de Sum.In Visual Basic query expression syntax, an Aggregate Into Sum() clause translates to an invocation of Sum.

Consulte también:

Sum(IEnumerable<Int32>) Sum(IEnumerable<Int32>) Sum(IEnumerable<Int32>) Sum(IEnumerable<Int32>)

Calcula la suma de una secuencia de valores Int32.Computes the sum of a sequence of Int32 values.

public:
[System::Runtime::CompilerServices::Extension]
 static int Sum(System::Collections::Generic::IEnumerable<int> ^ source);
public static int Sum (this System.Collections.Generic.IEnumerable<int> source);
static member Sum : seq<int> -> int
<Extension()>
Public Function Sum (source As IEnumerable(Of Integer)) As Integer

Parámetros

source
IEnumerable<Int32>

Secuencia de valores Int32 cuya suma se va a calcular.A sequence of Int32 values to calculate the sum of.

Devoluciones

Suma de los valores de la secuencia.The sum of the values in the sequence.

Excepciones

Ejemplos

En el ejemplo de código siguiente se muestra cómo usar Sum(IEnumerable<Single>) que sume los valores de una secuencia.The following code example demonstrates how to use Sum(IEnumerable<Single>) to sum the values of a sequence.

Nota

En este ejemplo de código se usa una sobrecarga de este método sobrecargado diferente de la carga específica que se describe en este tema.This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. Para ampliar el ejemplo a este tema, sustituye los elementos de la secuencia de origen por los elementos del tipo numérico adecuado.To extend the example to this topic, substitute the elements of the source sequence with elements of the appropriate numerical type.

List<float> numbers = new List<float> { 43.68F, 1.25F, 583.7F, 6.5F };

float sum = numbers.Sum();

Console.WriteLine("The sum of the numbers is {0}.", sum);

/*
 This code produces the following output:

 The sum of the numbers is 635.13.
*/
' Create a list of Single values.
Dim numbers As New List(Of Single)(New Single() _
                               {43.68F, 1.25F, 583.7F, 6.5F})

' Get the sum of values in the list.
Dim sum As Single = numbers.Sum()

' Display the output.
MsgBox("The sum of the numbers is " & sum)

' This code produces the following output:
'
' The sum of the numbers is 635.13

Comentarios

Este método devuelve cero si source no contiene ningún elemento.This method returns zero if source contains no elements.

En la sintaxis de expresión de consulta de Visual Basic, un Aggregate Into Sum() cláusula se convierte en una invocación de Sum.In Visual Basic query expression syntax, an Aggregate Into Sum() clause translates to an invocation of Sum.

Consulte también:

Sum(IEnumerable<Int64>) Sum(IEnumerable<Int64>) Sum(IEnumerable<Int64>) Sum(IEnumerable<Int64>)

Calcula la suma de una secuencia de valores Int64.Computes the sum of a sequence of Int64 values.

public:
[System::Runtime::CompilerServices::Extension]
 static long Sum(System::Collections::Generic::IEnumerable<long> ^ source);
public static long Sum (this System.Collections.Generic.IEnumerable<long> source);
static member Sum : seq<int64> -> int64
<Extension()>
Public Function Sum (source As IEnumerable(Of Long)) As Long

Parámetros

source
IEnumerable<Int64>

Secuencia de valores Int64 cuya suma se va a calcular.A sequence of Int64 values to calculate the sum of.

Devoluciones

Suma de los valores de la secuencia.The sum of the values in the sequence.

Excepciones

Ejemplos

En el ejemplo de código siguiente se muestra cómo usar Sum(IEnumerable<Single>) que sume los valores de una secuencia.The following code example demonstrates how to use Sum(IEnumerable<Single>) to sum the values of a sequence.

Nota

En este ejemplo de código se usa una sobrecarga de este método sobrecargado diferente de la carga específica que se describe en este tema.This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. Para ampliar el ejemplo a este tema, sustituye los elementos de la secuencia de origen por los elementos del tipo numérico adecuado.To extend the example to this topic, substitute the elements of the source sequence with elements of the appropriate numerical type.

List<float> numbers = new List<float> { 43.68F, 1.25F, 583.7F, 6.5F };

float sum = numbers.Sum();

Console.WriteLine("The sum of the numbers is {0}.", sum);

/*
 This code produces the following output:

 The sum of the numbers is 635.13.
*/
' Create a list of Single values.
Dim numbers As New List(Of Single)(New Single() _
                               {43.68F, 1.25F, 583.7F, 6.5F})

' Get the sum of values in the list.
Dim sum As Single = numbers.Sum()

' Display the output.
MsgBox("The sum of the numbers is " & sum)

' This code produces the following output:
'
' The sum of the numbers is 635.13

Comentarios

Este método devuelve cero si source no contiene ningún elemento.This method returns zero if source contains no elements.

En la sintaxis de expresión de consulta de Visual Basic, un Aggregate Into Sum() cláusula se convierte en una invocación de Sum.In Visual Basic query expression syntax, an Aggregate Into Sum() clause translates to an invocation of Sum.

Consulte también:

Sum(IEnumerable<Double>) Sum(IEnumerable<Double>) Sum(IEnumerable<Double>) Sum(IEnumerable<Double>)

Calcula la suma de una secuencia de valores Double.Computes the sum of a sequence of Double values.

public:
[System::Runtime::CompilerServices::Extension]
 static double Sum(System::Collections::Generic::IEnumerable<double> ^ source);
public static double Sum (this System.Collections.Generic.IEnumerable<double> source);
static member Sum : seq<double> -> double
<Extension()>
Public Function Sum (source As IEnumerable(Of Double)) As Double

Parámetros

source
IEnumerable<Double>

Secuencia de valores Double cuya suma se va a calcular.A sequence of Double values to calculate the sum of.

Devoluciones

Suma de los valores de la secuencia.The sum of the values in the sequence.

Excepciones

Ejemplos

En el ejemplo de código siguiente se muestra cómo usar Sum(IEnumerable<Single>) que sume los valores de una secuencia.The following code example demonstrates how to use Sum(IEnumerable<Single>) to sum the values of a sequence.

Nota

En este ejemplo de código se usa una sobrecarga de este método sobrecargado diferente de la carga específica que se describe en este tema.This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. Para ampliar el ejemplo a este tema, sustituye los elementos de la secuencia de origen por los elementos del tipo numérico adecuado.To extend the example to this topic, substitute the elements of the source sequence with elements of the appropriate numerical type.

List<float> numbers = new List<float> { 43.68F, 1.25F, 583.7F, 6.5F };

float sum = numbers.Sum();

Console.WriteLine("The sum of the numbers is {0}.", sum);

/*
 This code produces the following output:

 The sum of the numbers is 635.13.
*/
' Create a list of Single values.
Dim numbers As New List(Of Single)(New Single() _
                               {43.68F, 1.25F, 583.7F, 6.5F})

' Get the sum of values in the list.
Dim sum As Single = numbers.Sum()

' Display the output.
MsgBox("The sum of the numbers is " & sum)

' This code produces the following output:
'
' The sum of the numbers is 635.13

Comentarios

Este método devuelve cero si source no contiene ningún elemento.This method returns zero if source contains no elements.

En la sintaxis de expresión de consulta de Visual Basic, un Aggregate Into Sum() cláusula se convierte en una invocación de Sum.In Visual Basic query expression syntax, an Aggregate Into Sum() clause translates to an invocation of Sum.

Consulte también:

Sum(IEnumerable<Decimal>) Sum(IEnumerable<Decimal>) Sum(IEnumerable<Decimal>) Sum(IEnumerable<Decimal>)

Calcula la suma de una secuencia de valores Decimal.Computes the sum of a sequence of Decimal values.

public:
[System::Runtime::CompilerServices::Extension]
 static System::Decimal Sum(System::Collections::Generic::IEnumerable<System::Decimal> ^ source);
public static decimal Sum (this System.Collections.Generic.IEnumerable<decimal> source);
static member Sum : seq<decimal> -> decimal
<Extension()>
Public Function Sum (source As IEnumerable(Of Decimal)) As Decimal

Parámetros

source
IEnumerable<Decimal>

Secuencia de valores Decimal cuya suma se va a calcular.A sequence of Decimal values to calculate the sum of.

Devoluciones

Suma de los valores de la secuencia.The sum of the values in the sequence.

Excepciones

Ejemplos

En el ejemplo de código siguiente se muestra cómo usar Sum(IEnumerable<Single>) que sume los valores de una secuencia.The following code example demonstrates how to use Sum(IEnumerable<Single>) to sum the values of a sequence.

Nota

En este ejemplo de código se usa una sobrecarga de este método sobrecargado diferente de la carga específica que se describe en este tema.This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. Para ampliar el ejemplo a este tema, sustituye los elementos de la secuencia de origen por los elementos del tipo numérico adecuado.To extend the example to this topic, substitute the elements of the source sequence with elements of the appropriate numerical type.

List<float> numbers = new List<float> { 43.68F, 1.25F, 583.7F, 6.5F };

float sum = numbers.Sum();

Console.WriteLine("The sum of the numbers is {0}.", sum);

/*
 This code produces the following output:

 The sum of the numbers is 635.13.
*/
' Create a list of Single values.
Dim numbers As New List(Of Single)(New Single() _
                               {43.68F, 1.25F, 583.7F, 6.5F})

' Get the sum of values in the list.
Dim sum As Single = numbers.Sum()

' Display the output.
MsgBox("The sum of the numbers is " & sum)

' This code produces the following output:
'
' The sum of the numbers is 635.13

Comentarios

El Sum(IEnumerable<Decimal>) método devuelve cero si source no contiene ningún elemento.The Sum(IEnumerable<Decimal>) method returns zero if source contains no elements.

En la sintaxis de expresión de consulta de Visual Basic, un Aggregate Into Sum() cláusula se convierte en una invocación de Sum.In Visual Basic query expression syntax, an Aggregate Into Sum() clause translates to an invocation of Sum.

Consulte también:

Sum(IEnumerable<Nullable<Decimal>>) Sum(IEnumerable<Nullable<Decimal>>) Sum(IEnumerable<Nullable<Decimal>>) Sum(IEnumerable<Nullable<Decimal>>)

Calcula la suma de una secuencia de valores Decimal que aceptan valores NULL.Computes the sum of a sequence of nullable Decimal values.

public:
[System::Runtime::CompilerServices::Extension]
 static Nullable<System::Decimal> Sum(System::Collections::Generic::IEnumerable<Nullable<System::Decimal>> ^ source);
public static Nullable<decimal> Sum (this System.Collections.Generic.IEnumerable<Nullable<decimal>> source);
static member Sum : seq<Nullable<decimal>> -> Nullable<decimal>
<Extension()>
Public Function Sum (source As IEnumerable(Of Nullable(Of Decimal))) As Nullable(Of Decimal)

Parámetros

source
IEnumerable<Nullable<Decimal>>

Secuencia de valores Decimal que aceptan valores NULL cuya suma se va a calcular.A sequence of nullable Decimal values to calculate the sum of.

Devoluciones

Suma de los valores de la secuencia.The sum of the values in the sequence.

Excepciones

Ejemplos

En el ejemplo de código siguiente se muestra cómo usar Sum(IEnumerable<Nullable<Single>>) que sume los valores de una secuencia.The following code example demonstrates how to use Sum(IEnumerable<Nullable<Single>>) to sum the values of a sequence.

Nota

En este ejemplo de código se usa una sobrecarga de este método sobrecargado diferente de la carga específica que se describe en este tema.This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. Para ampliar el ejemplo a este tema, sustituye los elementos de la secuencia de origen por los elementos del tipo numérico adecuado.To extend the example to this topic, substitute the elements of the source sequence with elements of the appropriate numerical type.

float?[] points = { null, 0, 92.83F, null, 100.0F, 37.46F, 81.1F };

float? sum = points.Sum();

Console.WriteLine("Total points earned: {0}", sum);

/*
 This code produces the following output:

 Total points earned: 311.39
*/
' Create an array of Nullable Single values.
Dim points() As Nullable(Of Single) =
{Nothing, 0, 92.83F, Nothing, 100.0F, 37.46F, 81.1F}

' Get the sum of values in the list.
Dim sum As Nullable(Of Single) = points.Sum()

' Display the output.
MsgBox("Total points earned: " & sum)

' This code produces the following output:
'
' Total points earned: 311.39

Comentarios

Este método devuelve cero si source no contiene ningún elemento.This method returns zero if source contains no elements.

El resultado de no incluyen valores que son null.The result doesnot include values that are null.

En la sintaxis de expresión de consulta de Visual Basic, un Aggregate Into Sum() cláusula se convierte en una invocación de Sum.In Visual Basic query expression syntax, an Aggregate Into Sum() clause translates to an invocation of Sum.

Consulte también:

Sum<TSource>(IEnumerable<TSource>, Func<TSource,Single>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Single>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Single>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Single>)

Calcula la suma de una secuencia de valores Single que se obtiene al invocar una función de transformación en cada elemento de la secuencia de entrada.Computes the sum of the sequence of Single values that are obtained by invoking a transform function on each element of the input sequence.

public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
 static float Sum(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, float> ^ selector);
public static float Sum<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,float> selector);
static member Sum : seq<'Source> * Func<'Source, single> -> single
<Extension()>
Public Function Sum(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Single)) As Single

Parámetros de tipo

TSource

Tipo de los elementos de source.The type of the elements of source.

Parámetros

source
IEnumerable<TSource>

Secuencia de valores que se usan para calcular una suma.A sequence of values that are used to calculate a sum.

selector
Func<TSource,Single>

Función de transformación que se va a aplicar a cada elemento.A transform function to apply to each element.

Devoluciones

Suma de los valores proyectados.The sum of the projected values.

Excepciones

source o selector es null.source or selector is null.

Ejemplos

En el ejemplo de código siguiente se muestra cómo usar Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) para sumar los valores proyectados de una secuencia.The following code example demonstrates how to use Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) to sum the projected values of a sequence.

Nota

En este ejemplo de código se usa una sobrecarga de este método sobrecargado diferente de la carga específica que se describe en este tema.This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. Para ampliar el ejemplo a este tema, cambie el cuerpo de la función selector.To extend the example to this topic, change the body of the selector function.

class Package
{
    public string Company { get; set; }
    public double Weight { get; set; }
}

public static void SumEx1()
{
    List<Package> packages =
        new List<Package> 
            { new Package { Company = "Coho Vineyard", Weight = 25.2 },
              new Package { Company = "Lucerne Publishing", Weight = 18.7 },
              new Package { Company = "Wingtip Toys", Weight = 6.0 },
              new Package { Company = "Adventure Works", Weight = 33.8 } };

    double totalWeight = packages.Sum(pkg => pkg.Weight);

    Console.WriteLine("The total weight of the packages is: {0}", totalWeight);
}

/*
 This code produces the following output:

 The total weight of the packages is: 83.7
*/
Structure Package
    Public Company As String
    Public Weight As Double
End Structure

Sub SumEx1()
    ' Create a list of Package values.
    Dim packages As New List(Of Package)(New Package() _
     {New Package With {.Company = "Coho Vineyard", .Weight = 25.2},
      New Package With {.Company = "Lucerne Publishing", .Weight = 18.7},
      New Package With {.Company = "Wingtip Toys", .Weight = 6.0},
      New Package With {.Company = "Adventure Works", .Weight = 33.8}})

    ' Sum the values from each item's Weight property.
    Dim totalWeight As Double = packages.Sum(Function(pkg) _
                                             pkg.Weight)

    ' Display the result.
    MsgBox("The total weight of the packages is: " & totalWeight)
End Sub

' This code produces the following output:
'
' The total weight of the packages is: 83.7

Comentarios

El Sum<TSource>(IEnumerable<TSource>, Func<TSource,Single>) método devuelve cero si source no contiene ningún elemento.The Sum<TSource>(IEnumerable<TSource>, Func<TSource,Single>) method returns zero if source contains no elements.

Puede aplicar este método en una secuencia de valores arbitrarios si proporciona una función, selector, que proyecta los miembros de source en un tipo numérico, específicamente Single.You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Single.

En la sintaxis de expresión de consulta de Visual Basic, un Aggregate Into Sum() cláusula se convierte en una invocación de Sum.In Visual Basic query expression syntax, an Aggregate Into Sum() clause translates to an invocation of Sum.

Consulte también:

Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Single>>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Single>>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Single>>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Single>>)

Calcula la suma de una secuencia de valores Single que aceptan valores NULL que se obtiene al invocar una función de transformación en cada elemento de la secuencia de entrada.Computes the sum of the sequence of nullable Single values that are obtained by invoking a transform function on each element of the input sequence.

public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
 static Nullable<float> Sum(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, Nullable<float>> ^ selector);
public static Nullable<float> Sum<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,Nullable<float>> selector);
static member Sum : seq<'Source> * Func<'Source, Nullable<single>> -> Nullable<single>
<Extension()>
Public Function Sum(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Nullable(Of Single))) As Nullable(Of Single)

Parámetros de tipo

TSource

Tipo de los elementos de source.The type of the elements of source.

Parámetros

source
IEnumerable<TSource>

Secuencia de valores que se usan para calcular una suma.A sequence of values that are used to calculate a sum.

selector
Func<TSource,Nullable<Single>>

Función de transformación que se va a aplicar a cada elemento.A transform function to apply to each element.

Devoluciones

Suma de los valores proyectados.The sum of the projected values.

Excepciones

source o selector es null.source or selector is null.

Ejemplos

En el ejemplo de código siguiente se muestra cómo usar Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) para sumar los valores proyectados de una secuencia.The following code example demonstrates how to use Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) to sum the projected values of a sequence.

Nota

En este ejemplo de código se usa una sobrecarga de este método sobrecargado diferente de la carga específica que se describe en este tema.This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. Para ampliar el ejemplo a este tema, cambie el cuerpo de la función selector.To extend the example to this topic, change the body of the selector function.

class Package
{
    public string Company { get; set; }
    public double Weight { get; set; }
}

public static void SumEx1()
{
    List<Package> packages =
        new List<Package> 
            { new Package { Company = "Coho Vineyard", Weight = 25.2 },
              new Package { Company = "Lucerne Publishing", Weight = 18.7 },
              new Package { Company = "Wingtip Toys", Weight = 6.0 },
              new Package { Company = "Adventure Works", Weight = 33.8 } };

    double totalWeight = packages.Sum(pkg => pkg.Weight);

    Console.WriteLine("The total weight of the packages is: {0}", totalWeight);
}

/*
 This code produces the following output:

 The total weight of the packages is: 83.7
*/
Structure Package
    Public Company As String
    Public Weight As Double
End Structure

Sub SumEx1()
    ' Create a list of Package values.
    Dim packages As New List(Of Package)(New Package() _
     {New Package With {.Company = "Coho Vineyard", .Weight = 25.2},
      New Package With {.Company = "Lucerne Publishing", .Weight = 18.7},
      New Package With {.Company = "Wingtip Toys", .Weight = 6.0},
      New Package With {.Company = "Adventure Works", .Weight = 33.8}})

    ' Sum the values from each item's Weight property.
    Dim totalWeight As Double = packages.Sum(Function(pkg) _
                                             pkg.Weight)

    ' Display the result.
    MsgBox("The total weight of the packages is: " & totalWeight)
End Sub

' This code produces the following output:
'
' The total weight of the packages is: 83.7

Comentarios

Este método devuelve cero si source no contiene ningún elemento.This method returns zero if source contains no elements.

El resultado no incluyen valores que son null.The result does not include values that are null.

Puede aplicar este método en una secuencia de valores arbitrarios si proporciona una función, selector, que proyecta los miembros de source en un tipo numérico, específicamente Nullable<Single> en C# o Nullable(Of Single) en Visual Basic.You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Nullable<Single> in C# or Nullable(Of Single) in Visual Basic.

En la sintaxis de expresión de consulta de Visual Basic, un Aggregate Into Sum() cláusula se convierte en una invocación de Sum.In Visual Basic query expression syntax, an Aggregate Into Sum() clause translates to an invocation of Sum.

Consulte también:

Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Int64>>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Int64>>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Int64>>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Int64>>)

Calcula la suma de una secuencia de valores Int64 que aceptan valores NULL que se obtiene al invocar una función de transformación en cada elemento de la secuencia de entrada.Computes the sum of the sequence of nullable Int64 values that are obtained by invoking a transform function on each element of the input sequence.

public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
 static Nullable<long> Sum(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, Nullable<long>> ^ selector);
public static Nullable<long> Sum<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,Nullable<long>> selector);
static member Sum : seq<'Source> * Func<'Source, Nullable<int64>> -> Nullable<int64>
<Extension()>
Public Function Sum(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Nullable(Of Long))) As Nullable(Of Long)

Parámetros de tipo

TSource

Tipo de los elementos de source.The type of the elements of source.

Parámetros

source
IEnumerable<TSource>

Secuencia de valores que se usan para calcular una suma.A sequence of values that are used to calculate a sum.

selector
Func<TSource,Nullable<Int64>>

Función de transformación que se va a aplicar a cada elemento.A transform function to apply to each element.

Devoluciones

Suma de los valores proyectados.The sum of the projected values.

Excepciones

source o selector es null.source or selector is null.

Ejemplos

En el ejemplo de código siguiente se muestra cómo usar Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) para sumar los valores proyectados de una secuencia.The following code example demonstrates how to use Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) to sum the projected values of a sequence.

Nota

En este ejemplo de código se usa una sobrecarga de este método sobrecargado diferente de la carga específica que se describe en este tema.This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. Para ampliar el ejemplo a este tema, cambie el cuerpo de la función selector.To extend the example to this topic, change the body of the selector function.

class Package
{
    public string Company { get; set; }
    public double Weight { get; set; }
}

public static void SumEx1()
{
    List<Package> packages =
        new List<Package> 
            { new Package { Company = "Coho Vineyard", Weight = 25.2 },
              new Package { Company = "Lucerne Publishing", Weight = 18.7 },
              new Package { Company = "Wingtip Toys", Weight = 6.0 },
              new Package { Company = "Adventure Works", Weight = 33.8 } };

    double totalWeight = packages.Sum(pkg => pkg.Weight);

    Console.WriteLine("The total weight of the packages is: {0}", totalWeight);
}

/*
 This code produces the following output:

 The total weight of the packages is: 83.7
*/
Structure Package
    Public Company As String
    Public Weight As Double
End Structure

Sub SumEx1()
    ' Create a list of Package values.
    Dim packages As New List(Of Package)(New Package() _
     {New Package With {.Company = "Coho Vineyard", .Weight = 25.2},
      New Package With {.Company = "Lucerne Publishing", .Weight = 18.7},
      New Package With {.Company = "Wingtip Toys", .Weight = 6.0},
      New Package With {.Company = "Adventure Works", .Weight = 33.8}})

    ' Sum the values from each item's Weight property.
    Dim totalWeight As Double = packages.Sum(Function(pkg) _
                                             pkg.Weight)

    ' Display the result.
    MsgBox("The total weight of the packages is: " & totalWeight)
End Sub

' This code produces the following output:
'
' The total weight of the packages is: 83.7

Comentarios

Este método devuelve cero si source no contiene ningún elemento.This method returns zero if source contains no elements.

El resultado no incluyen valores que son null.The result does not include values that are null.

Puede aplicar este método en una secuencia de valores arbitrarios si proporciona una función, selector, que proyecta los miembros de source en un tipo numérico, específicamente Nullable<Int64> en C# o Nullable(Of Int64) en Visual BasicYou can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Nullable<Int64> in C# or Nullable(Of Int64) in Visual Basic

En la sintaxis de expresión de consulta de Visual Basic, un Aggregate Into Sum() cláusula se convierte en una invocación de Sum.In Visual Basic query expression syntax, an Aggregate Into Sum() clause translates to an invocation of Sum.

Consulte también:

Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Int32>>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Int32>>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Int32>>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Int32>>)

Calcula la suma de una secuencia de valores Int32 que aceptan valores NULL que se obtiene al invocar una función de transformación en cada elemento de la secuencia de entrada.Computes the sum of the sequence of nullable Int32 values that are obtained by invoking a transform function on each element of the input sequence.

public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
 static Nullable<int> Sum(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, Nullable<int>> ^ selector);
public static Nullable<int> Sum<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,Nullable<int>> selector);
static member Sum : seq<'Source> * Func<'Source, Nullable<int>> -> Nullable<int>
<Extension()>
Public Function Sum(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Nullable(Of Integer))) As Nullable(Of Integer)

Parámetros de tipo

TSource

Tipo de los elementos de source.The type of the elements of source.

Parámetros

source
IEnumerable<TSource>

Secuencia de valores que se usan para calcular una suma.A sequence of values that are used to calculate a sum.

selector
Func<TSource,Nullable<Int32>>

Función de transformación que se va a aplicar a cada elemento.A transform function to apply to each element.

Devoluciones

Suma de los valores proyectados.The sum of the projected values.

Excepciones

source o selector es null.source or selector is null.

Ejemplos

En el ejemplo de código siguiente se muestra cómo usar Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) para sumar los valores proyectados de una secuencia.The following code example demonstrates how to use Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) to sum the projected values of a sequence.

Nota

En este ejemplo de código se usa una sobrecarga de este método sobrecargado diferente de la carga específica que se describe en este tema.This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. Para ampliar el ejemplo a este tema, cambie el cuerpo de la función selector.To extend the example to this topic, change the body of the selector function.

class Package
{
    public string Company { get; set; }
    public double Weight { get; set; }
}

public static void SumEx1()
{
    List<Package> packages =
        new List<Package> 
            { new Package { Company = "Coho Vineyard", Weight = 25.2 },
              new Package { Company = "Lucerne Publishing", Weight = 18.7 },
              new Package { Company = "Wingtip Toys", Weight = 6.0 },
              new Package { Company = "Adventure Works", Weight = 33.8 } };

    double totalWeight = packages.Sum(pkg => pkg.Weight);

    Console.WriteLine("The total weight of the packages is: {0}", totalWeight);
}

/*
 This code produces the following output:

 The total weight of the packages is: 83.7
*/
Structure Package
    Public Company As String
    Public Weight As Double
End Structure

Sub SumEx1()
    ' Create a list of Package values.
    Dim packages As New List(Of Package)(New Package() _
     {New Package With {.Company = "Coho Vineyard", .Weight = 25.2},
      New Package With {.Company = "Lucerne Publishing", .Weight = 18.7},
      New Package With {.Company = "Wingtip Toys", .Weight = 6.0},
      New Package With {.Company = "Adventure Works", .Weight = 33.8}})

    ' Sum the values from each item's Weight property.
    Dim totalWeight As Double = packages.Sum(Function(pkg) _
                                             pkg.Weight)

    ' Display the result.
    MsgBox("The total weight of the packages is: " & totalWeight)
End Sub

' This code produces the following output:
'
' The total weight of the packages is: 83.7

Comentarios

Este método devuelve cero si source no contiene ningún elemento.This method returns zero if source contains no elements.

El resultado no incluyen valores que son null.The result does not include values that are null.

Puede aplicar este método en una secuencia de valores arbitrarios si proporciona una función, selector, que proyecta los miembros de source en un tipo numérico, específicamente Nullable<Int32> en C# o Nullable(Of Int32) en Visual Basic.You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Nullable<Int32> in C# or Nullable(Of Int32) in Visual Basic.

En la sintaxis de expresión de consulta de Visual Basic, un Aggregate Into Sum() cláusula se convierte en una invocación de Sum.In Visual Basic query expression syntax, an Aggregate Into Sum() clause translates to an invocation of Sum.

Consulte también:

Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Double>>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Double>>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Double>>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Double>>)

Calcula la suma de una secuencia de valores Double que aceptan valores NULL que se obtiene al invocar una función de transformación en cada elemento de la secuencia de entrada.Computes the sum of the sequence of nullable Double values that are obtained by invoking a transform function on each element of the input sequence.

public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
 static Nullable<double> Sum(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, Nullable<double>> ^ selector);
public static Nullable<double> Sum<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,Nullable<double>> selector);
static member Sum : seq<'Source> * Func<'Source, Nullable<double>> -> Nullable<double>
<Extension()>
Public Function Sum(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Nullable(Of Double))) As Nullable(Of Double)

Parámetros de tipo

TSource

Tipo de los elementos de source.The type of the elements of source.

Parámetros

source
IEnumerable<TSource>

Secuencia de valores que se usan para calcular una suma.A sequence of values that are used to calculate a sum.

selector
Func<TSource,Nullable<Double>>

Función de transformación que se va a aplicar a cada elemento.A transform function to apply to each element.

Devoluciones

Suma de los valores proyectados.The sum of the projected values.

Excepciones

source o selector es null.source or selector is null.

Ejemplos

En el ejemplo de código siguiente se muestra cómo usar Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) para sumar los valores proyectados de una secuencia.The following code example demonstrates how to use Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) to sum the projected values of a sequence.

Nota

En este ejemplo de código se usa una sobrecarga de este método sobrecargado diferente de la carga específica que se describe en este tema.This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. Para ampliar el ejemplo a este tema, cambie el cuerpo de la función selector.To extend the example to this topic, change the body of the selector function.

class Package
{
    public string Company { get; set; }
    public double Weight { get; set; }
}

public static void SumEx1()
{
    List<Package> packages =
        new List<Package> 
            { new Package { Company = "Coho Vineyard", Weight = 25.2 },
              new Package { Company = "Lucerne Publishing", Weight = 18.7 },
              new Package { Company = "Wingtip Toys", Weight = 6.0 },
              new Package { Company = "Adventure Works", Weight = 33.8 } };

    double totalWeight = packages.Sum(pkg => pkg.Weight);

    Console.WriteLine("The total weight of the packages is: {0}", totalWeight);
}

/*
 This code produces the following output:

 The total weight of the packages is: 83.7
*/
Structure Package
    Public Company As String
    Public Weight As Double
End Structure

Sub SumEx1()
    ' Create a list of Package values.
    Dim packages As New List(Of Package)(New Package() _
     {New Package With {.Company = "Coho Vineyard", .Weight = 25.2},
      New Package With {.Company = "Lucerne Publishing", .Weight = 18.7},
      New Package With {.Company = "Wingtip Toys", .Weight = 6.0},
      New Package With {.Company = "Adventure Works", .Weight = 33.8}})

    ' Sum the values from each item's Weight property.
    Dim totalWeight As Double = packages.Sum(Function(pkg) _
                                             pkg.Weight)

    ' Display the result.
    MsgBox("The total weight of the packages is: " & totalWeight)
End Sub

' This code produces the following output:
'
' The total weight of the packages is: 83.7

Comentarios

Este método devuelve cero si source no contiene ningún elemento.This method returns zero if source contains no elements.

El resultado no incluyen valores que son null.The result does not include values that are null.

Puede aplicar este método en una secuencia de valores arbitrarios si proporciona una función, selector, que proyecta los miembros de source en un tipo numérico, específicamente Nullable<Double> en C# o Nullable(Of Double) en Visual Basic.You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Nullable<Double> in C# or Nullable(Of Double) in Visual Basic.

En la sintaxis de expresión de consulta de Visual Basic, un Aggregate Into Sum() cláusula se convierte en una invocación de Sum.In Visual Basic query expression syntax, an Aggregate Into Sum() clause translates to an invocation of Sum.

Consulte también:

Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Decimal>>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Decimal>>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Decimal>>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Decimal>>)

Calcula la suma de una secuencia de valores Decimal que aceptan valores NULL que se obtiene al invocar una función de transformación en cada elemento de la secuencia de entrada.Computes the sum of the sequence of nullable Decimal values that are obtained by invoking a transform function on each element of the input sequence.

public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
 static Nullable<System::Decimal> Sum(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, Nullable<System::Decimal>> ^ selector);
public static Nullable<decimal> Sum<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,Nullable<decimal>> selector);
static member Sum : seq<'Source> * Func<'Source, Nullable<decimal>> -> Nullable<decimal>
<Extension()>
Public Function Sum(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Nullable(Of Decimal))) As Nullable(Of Decimal)

Parámetros de tipo

TSource

Tipo de los elementos de source.The type of the elements of source.

Parámetros

source
IEnumerable<TSource>

Secuencia de valores que se usan para calcular una suma.A sequence of values that are used to calculate a sum.

selector
Func<TSource,Nullable<Decimal>>

Función de transformación que se va a aplicar a cada elemento.A transform function to apply to each element.

Devoluciones

Suma de los valores proyectados.The sum of the projected values.

Excepciones

source o selector es null.source or selector is null.

Ejemplos

En el ejemplo de código siguiente se muestra cómo usar Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) para sumar los valores proyectados de una secuencia.The following code example demonstrates how to use Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) to sum the projected values of a sequence.

Nota

En este ejemplo de código se usa una sobrecarga de este método sobrecargado diferente de la carga específica que se describe en este tema.This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. Para ampliar el ejemplo a este tema, cambie el cuerpo de la función selector.To extend the example to this topic, change the body of the selector function.

class Package
{
    public string Company { get; set; }
    public double Weight { get; set; }
}

public static void SumEx1()
{
    List<Package> packages =
        new List<Package> 
            { new Package { Company = "Coho Vineyard", Weight = 25.2 },
              new Package { Company = "Lucerne Publishing", Weight = 18.7 },
              new Package { Company = "Wingtip Toys", Weight = 6.0 },
              new Package { Company = "Adventure Works", Weight = 33.8 } };

    double totalWeight = packages.Sum(pkg => pkg.Weight);

    Console.WriteLine("The total weight of the packages is: {0}", totalWeight);
}

/*
 This code produces the following output:

 The total weight of the packages is: 83.7
*/
Structure Package
    Public Company As String
    Public Weight As Double
End Structure

Sub SumEx1()
    ' Create a list of Package values.
    Dim packages As New List(Of Package)(New Package() _
     {New Package With {.Company = "Coho Vineyard", .Weight = 25.2},
      New Package With {.Company = "Lucerne Publishing", .Weight = 18.7},
      New Package With {.Company = "Wingtip Toys", .Weight = 6.0},
      New Package With {.Company = "Adventure Works", .Weight = 33.8}})

    ' Sum the values from each item's Weight property.
    Dim totalWeight As Double = packages.Sum(Function(pkg) _
                                             pkg.Weight)

    ' Display the result.
    MsgBox("The total weight of the packages is: " & totalWeight)
End Sub

' This code produces the following output:
'
' The total weight of the packages is: 83.7

Comentarios

Este método devuelve cero si source no contiene ningún elemento.This method returns zero if source contains no elements.

El resultado no incluyen valores que son null.The result does not included values that are null.

Puede aplicar este método en una secuencia de valores arbitrarios si proporciona una función, selector, que proyecta los miembros de source en un tipo numérico, específicamente Nullable<Decimal> en C# o Nullable(Of Decimal) en Visual Basic.You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Nullable<Decimal> in C# or Nullable(Of Decimal) in Visual Basic.

En la sintaxis de expresión de consulta de Visual Basic, un Aggregate Into Sum() cláusula se convierte en una invocación de Sum.In Visual Basic query expression syntax, an Aggregate Into Sum() clause translates to an invocation of Sum.

Consulte también:

Sum<TSource>(IEnumerable<TSource>, Func<TSource,Int64>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Int64>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Int64>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Int64>)

Calcula la suma de una secuencia de valores Int64 que se obtiene al invocar una función de transformación en cada elemento de la secuencia de entrada.Computes the sum of the sequence of Int64 values that are obtained by invoking a transform function on each element of the input sequence.

public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
 static long Sum(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, long> ^ selector);
public static long Sum<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,long> selector);
static member Sum : seq<'Source> * Func<'Source, int64> -> int64
<Extension()>
Public Function Sum(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Long)) As Long

Parámetros de tipo

TSource

Tipo de los elementos de source.The type of the elements of source.

Parámetros

source
IEnumerable<TSource>

Secuencia de valores que se usan para calcular una suma.A sequence of values that are used to calculate a sum.

selector
Func<TSource,Int64>

Función de transformación que se va a aplicar a cada elemento.A transform function to apply to each element.

Devoluciones

Suma de los valores proyectados.The sum of the projected values.

Excepciones

source o selector es null.source or selector is null.

Ejemplos

En el ejemplo de código siguiente se muestra cómo usar Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) para sumar los valores proyectados de una secuencia.The following code example demonstrates how to use Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) to sum the projected values of a sequence.

Nota

En este ejemplo de código se usa una sobrecarga de este método sobrecargado diferente de la carga específica que se describe en este tema.This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. Para ampliar el ejemplo a este tema, cambie el cuerpo de la función selector.To extend the example to this topic, change the body of the selector function.

class Package
{
    public string Company { get; set; }
    public double Weight { get; set; }
}

public static void SumEx1()
{
    List<Package> packages =
        new List<Package> 
            { new Package { Company = "Coho Vineyard", Weight = 25.2 },
              new Package { Company = "Lucerne Publishing", Weight = 18.7 },
              new Package { Company = "Wingtip Toys", Weight = 6.0 },
              new Package { Company = "Adventure Works", Weight = 33.8 } };

    double totalWeight = packages.Sum(pkg => pkg.Weight);

    Console.WriteLine("The total weight of the packages is: {0}", totalWeight);
}

/*
 This code produces the following output:

 The total weight of the packages is: 83.7
*/
Structure Package
    Public Company As String
    Public Weight As Double
End Structure

Sub SumEx1()
    ' Create a list of Package values.
    Dim packages As New List(Of Package)(New Package() _
     {New Package With {.Company = "Coho Vineyard", .Weight = 25.2},
      New Package With {.Company = "Lucerne Publishing", .Weight = 18.7},
      New Package With {.Company = "Wingtip Toys", .Weight = 6.0},
      New Package With {.Company = "Adventure Works", .Weight = 33.8}})

    ' Sum the values from each item's Weight property.
    Dim totalWeight As Double = packages.Sum(Function(pkg) _
                                             pkg.Weight)

    ' Display the result.
    MsgBox("The total weight of the packages is: " & totalWeight)
End Sub

' This code produces the following output:
'
' The total weight of the packages is: 83.7

Comentarios

Este método devuelve cero si source no contiene ningún elemento.This method returns zero if source contains no elements.

Puede aplicar este método en una secuencia de valores arbitrarios si proporciona una función, selector, que proyecta los miembros de source en un tipo numérico, específicamente Int64.You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Int64.

En la sintaxis de expresión de consulta de Visual Basic, un Aggregate Into Sum() cláusula se convierte en una invocación de Sum.In Visual Basic query expression syntax, an Aggregate Into Sum() clause translates to an invocation of Sum.

Consulte también:

Sum<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Int32>)

Calcula la suma de una secuencia de valores Int32 que se obtiene al invocar una función de transformación en cada elemento de la secuencia de entrada.Computes the sum of the sequence of Int32 values that are obtained by invoking a transform function on each element of the input sequence.

public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
 static int Sum(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, int> ^ selector);
public static int Sum<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,int> selector);
static member Sum : seq<'Source> * Func<'Source, int> -> int
<Extension()>
Public Function Sum(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Integer)) As Integer

Parámetros de tipo

TSource

Tipo de los elementos de source.The type of the elements of source.

Parámetros

source
IEnumerable<TSource>

Secuencia de valores que se usan para calcular una suma.A sequence of values that are used to calculate a sum.

selector
Func<TSource,Int32>

Función de transformación que se va a aplicar a cada elemento.A transform function to apply to each element.

Devoluciones

Suma de los valores proyectados.The sum of the projected values.

Excepciones

source o selector es null.source or selector is null.

Ejemplos

En el ejemplo de código siguiente se muestra cómo usar Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) para sumar los valores proyectados de una secuencia.The following code example demonstrates how to use Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) to sum the projected values of a sequence.

Nota

En este ejemplo de código se usa una sobrecarga de este método sobrecargado diferente de la carga específica que se describe en este tema.This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. Para ampliar el ejemplo a este tema, cambie el cuerpo de la función selector.To extend the example to this topic, change the body of the selector function.

class Package
{
    public string Company { get; set; }
    public double Weight { get; set; }
}

public static void SumEx1()
{
    List<Package> packages =
        new List<Package> 
            { new Package { Company = "Coho Vineyard", Weight = 25.2 },
              new Package { Company = "Lucerne Publishing", Weight = 18.7 },
              new Package { Company = "Wingtip Toys", Weight = 6.0 },
              new Package { Company = "Adventure Works", Weight = 33.8 } };

    double totalWeight = packages.Sum(pkg => pkg.Weight);

    Console.WriteLine("The total weight of the packages is: {0}", totalWeight);
}

/*
 This code produces the following output:

 The total weight of the packages is: 83.7
*/
Structure Package
    Public Company As String
    Public Weight As Double
End Structure

Sub SumEx1()
    ' Create a list of Package values.
    Dim packages As New List(Of Package)(New Package() _
     {New Package With {.Company = "Coho Vineyard", .Weight = 25.2},
      New Package With {.Company = "Lucerne Publishing", .Weight = 18.7},
      New Package With {.Company = "Wingtip Toys", .Weight = 6.0},
      New Package With {.Company = "Adventure Works", .Weight = 33.8}})

    ' Sum the values from each item's Weight property.
    Dim totalWeight As Double = packages.Sum(Function(pkg) _
                                             pkg.Weight)

    ' Display the result.
    MsgBox("The total weight of the packages is: " & totalWeight)
End Sub

' This code produces the following output:
'
' The total weight of the packages is: 83.7

Comentarios

Este método devuelve cero si source no contiene ningún elemento.This method returns zero if source contains no elements.

Puede aplicar este método en una secuencia de valores arbitrarios si proporciona una función, selector, que proyecta los miembros de source en un tipo numérico, específicamente Int32.You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Int32.

En la sintaxis de expresión de consulta de Visual Basic, un Aggregate Into Sum() cláusula se convierte en una invocación de Sum.In Visual Basic query expression syntax, an Aggregate Into Sum() clause translates to an invocation of Sum.

Consulte también:

Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>)

Calcula la suma de una secuencia de valores Double que se obtiene al invocar una función de transformación en cada elemento de la secuencia de entrada.Computes the sum of the sequence of Double values that are obtained by invoking a transform function on each element of the input sequence.

public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
 static double Sum(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, double> ^ selector);
public static double Sum<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,double> selector);
static member Sum : seq<'Source> * Func<'Source, double> -> double
<Extension()>
Public Function Sum(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Double)) As Double

Parámetros de tipo

TSource

Tipo de los elementos de source.The type of the elements of source.

Parámetros

source
IEnumerable<TSource>

Secuencia de valores que se usan para calcular una suma.A sequence of values that are used to calculate a sum.

selector
Func<TSource,Double>

Función de transformación que se va a aplicar a cada elemento.A transform function to apply to each element.

Devoluciones

Suma de los valores proyectados.The sum of the projected values.

Excepciones

source o selector es null.source or selector is null.

Ejemplos

En el ejemplo de código siguiente se muestra cómo usar Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) para sumar los valores proyectados de una secuencia.The following code example demonstrates how to use Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) to sum the projected values of a sequence.

class Package
{
    public string Company { get; set; }
    public double Weight { get; set; }
}

public static void SumEx1()
{
    List<Package> packages =
        new List<Package> 
            { new Package { Company = "Coho Vineyard", Weight = 25.2 },
              new Package { Company = "Lucerne Publishing", Weight = 18.7 },
              new Package { Company = "Wingtip Toys", Weight = 6.0 },
              new Package { Company = "Adventure Works", Weight = 33.8 } };

    double totalWeight = packages.Sum(pkg => pkg.Weight);

    Console.WriteLine("The total weight of the packages is: {0}", totalWeight);
}

/*
 This code produces the following output:

 The total weight of the packages is: 83.7
*/
Structure Package
    Public Company As String
    Public Weight As Double
End Structure

Sub SumEx1()
    ' Create a list of Package values.
    Dim packages As New List(Of Package)(New Package() _
     {New Package With {.Company = "Coho Vineyard", .Weight = 25.2},
      New Package With {.Company = "Lucerne Publishing", .Weight = 18.7},
      New Package With {.Company = "Wingtip Toys", .Weight = 6.0},
      New Package With {.Company = "Adventure Works", .Weight = 33.8}})

    ' Sum the values from each item's Weight property.
    Dim totalWeight As Double = packages.Sum(Function(pkg) _
                                             pkg.Weight)

    ' Display the result.
    MsgBox("The total weight of the packages is: " & totalWeight)
End Sub

' This code produces the following output:
'
' The total weight of the packages is: 83.7

Comentarios

Este método devuelve cero si source no contiene ningún elemento.This method returns zero if source contains no elements.

Puede aplicar este método en una secuencia de valores arbitrarios si proporciona una función, selector, que proyecta los miembros de source en un tipo numérico, específicamente Double.You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Double.

En la sintaxis de expresión de consulta de Visual Basic, un Aggregate Into Sum() cláusula se convierte en una invocación de Sum.In Visual Basic query expression syntax, an Aggregate Into Sum() clause translates to an invocation of Sum.

Consulte también:

Sum<TSource>(IEnumerable<TSource>, Func<TSource,Decimal>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Decimal>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Decimal>) Sum<TSource>(IEnumerable<TSource>, Func<TSource,Decimal>)

Calcula la suma de una secuencia de valores Decimal que se obtiene al invocar una función de transformación en cada elemento de la secuencia de entrada.Computes the sum of the sequence of Decimal values that are obtained by invoking a transform function on each element of the input sequence.

public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
 static System::Decimal Sum(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, System::Decimal> ^ selector);
public static decimal Sum<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,decimal> selector);
static member Sum : seq<'Source> * Func<'Source, decimal> -> decimal
<Extension()>
Public Function Sum(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Decimal)) As Decimal

Parámetros de tipo

TSource

Tipo de los elementos de source.The type of the elements of source.

Parámetros

source
IEnumerable<TSource>

Secuencia de valores que se usan para calcular una suma.A sequence of values that are used to calculate a sum.

selector
Func<TSource,Decimal>

Función de transformación que se va a aplicar a cada elemento.A transform function to apply to each element.

Devoluciones

Suma de los valores proyectados.The sum of the projected values.

Excepciones

source o selector es null.source or selector is null.

Ejemplos

En el ejemplo de código siguiente se muestra cómo usar Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) para sumar los valores proyectados de una secuencia.The following code example demonstrates how to use Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) to sum the projected values of a sequence.

Nota

En este ejemplo de código se usa una sobrecarga de este método sobrecargado diferente de la carga específica que se describe en este tema.This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. Para ampliar el ejemplo a este tema, cambie el cuerpo de la función selector.To extend the example to this topic, change the body of the selector function.

class Package
{
    public string Company { get; set; }
    public double Weight { get; set; }
}

public static void SumEx1()
{
    List<Package> packages =
        new List<Package> 
            { new Package { Company = "Coho Vineyard", Weight = 25.2 },
              new Package { Company = "Lucerne Publishing", Weight = 18.7 },
              new Package { Company = "Wingtip Toys", Weight = 6.0 },
              new Package { Company = "Adventure Works", Weight = 33.8 } };

    double totalWeight = packages.Sum(pkg => pkg.Weight);

    Console.WriteLine("The total weight of the packages is: {0}", totalWeight);
}

/*
 This code produces the following output:

 The total weight of the packages is: 83.7
*/
Structure Package
    Public Company As String
    Public Weight As Double
End Structure

Sub SumEx1()
    ' Create a list of Package values.
    Dim packages As New List(Of Package)(New Package() _
     {New Package With {.Company = "Coho Vineyard", .Weight = 25.2},
      New Package With {.Company = "Lucerne Publishing", .Weight = 18.7},
      New Package With {.Company = "Wingtip Toys", .Weight = 6.0},
      New Package With {.Company = "Adventure Works", .Weight = 33.8}})

    ' Sum the values from each item's Weight property.
    Dim totalWeight As Double = packages.Sum(Function(pkg) _
                                             pkg.Weight)

    ' Display the result.
    MsgBox("The total weight of the packages is: " & totalWeight)
End Sub

' This code produces the following output:
'
' The total weight of the packages is: 83.7

Comentarios

Este método devuelve cero si source no contiene ningún elemento.This method returns zero if source contains no elements.

Puede aplicar este método en una secuencia de valores arbitrarios si proporciona una función, selector, que proyecta los miembros de source en un tipo numérico, específicamente Decimal.You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Decimal.

En la sintaxis de expresión de consulta de Visual Basic, un Aggregate Into Sum() cláusula se convierte en una invocación de Sum.In Visual Basic query expression syntax, an Aggregate Into Sum() clause translates to an invocation of Sum.

Consulte también:

Se aplica a