DataGridViewColumn.DataPropertyName Propriété

Définition

Obtient ou définit le nom de la propriété de source de données ou de la colonne de base de données à laquelle DataGridViewColumn est lié.

public:
 property System::String ^ DataPropertyName { System::String ^ get(); void set(System::String ^ value); };
[System.ComponentModel.Browsable(true)]
[System.ComponentModel.TypeConverter("System.Windows.Forms.Design.DataMemberFieldConverter, System.Design, Version=4.0.0.0, Culture=neutral, PublicKeyToken=b03f5f7f11d50a3a")]
public string DataPropertyName { get; set; }
[System.ComponentModel.Browsable(true)]
[System.ComponentModel.TypeConverter("System.Windows.Forms.Design.DataMemberFieldConverter, System.Windows.Forms.Design, Version=4.0.0.0, Culture=neutral, PublicKeyToken=b03f5f7f11d50a3a")]
public string DataPropertyName { get; set; }
[System.ComponentModel.Browsable(true)]
[System.ComponentModel.TypeConverter("System.Windows.Forms.Design.DataMemberFieldConverter, System.Design, Version=2.0.0.0, Culture=neutral, PublicKeyToken=b03f5f7f11d50a3a")]
public string DataPropertyName { get; set; }
[<System.ComponentModel.Browsable(true)>]
[<System.ComponentModel.TypeConverter("System.Windows.Forms.Design.DataMemberFieldConverter, System.Design, Version=4.0.0.0, Culture=neutral, PublicKeyToken=b03f5f7f11d50a3a")>]
member this.DataPropertyName : string with get, set
[<System.ComponentModel.Browsable(true)>]
[<System.ComponentModel.TypeConverter("System.Windows.Forms.Design.DataMemberFieldConverter, System.Windows.Forms.Design, Version=4.0.0.0, Culture=neutral, PublicKeyToken=b03f5f7f11d50a3a")>]
member this.DataPropertyName : string with get, set
[<System.ComponentModel.Browsable(true)>]
[<System.ComponentModel.TypeConverter("System.Windows.Forms.Design.DataMemberFieldConverter, System.Design, Version=2.0.0.0, Culture=neutral, PublicKeyToken=b03f5f7f11d50a3a")>]
member this.DataPropertyName : string with get, set
Public Property DataPropertyName As String

Valeur de propriété

String

Nom qui ne respecte pas la casse de la propriété ou de la colonne de base de données associée à DataGridViewColumn.

Attributs

Exemples

L’exemple de code suivant montre comment choisir la propriété qui sera représentée par chaque colonne.

public enum Title
{
    King,
    Sir
};
Public Enum Title
    King
    Sir
End Enum
private void EnumsAndComboBox_Load(object sender, System.EventArgs e)
{
    // Populate the data source.
    bindingSource1.Add(new Knight(Title.King, "Uther", true));
    bindingSource1.Add(new Knight(Title.King, "Arthur", true));
    bindingSource1.Add(new Knight(Title.Sir, "Mordred", false));
    bindingSource1.Add(new Knight(Title.Sir, "Gawain", true));
    bindingSource1.Add(new Knight(Title.Sir, "Galahad", true));

    // Initialize the DataGridView.
    dataGridView1.AutoGenerateColumns = false;
    dataGridView1.AutoSize = true;
    dataGridView1.DataSource = bindingSource1;

    dataGridView1.Columns.Add(CreateComboBoxWithEnums());

    // Initialize and add a text box column.
    DataGridViewColumn column = new DataGridViewTextBoxColumn();
    column.DataPropertyName = "Name";
    column.Name = "Knight";
    dataGridView1.Columns.Add(column);

    // Initialize and add a check box column.
    column = new DataGridViewCheckBoxColumn();
    column.DataPropertyName = "GoodGuy";
    column.Name = "Good";
    dataGridView1.Columns.Add(column);

    // Initialize the form.
    this.Controls.Add(dataGridView1);
    this.AutoSize = true;
    this.Text = "DataGridView object binding demo";
}

DataGridViewComboBoxColumn CreateComboBoxWithEnums()
{
    DataGridViewComboBoxColumn combo = new DataGridViewComboBoxColumn();
    combo.DataSource = Enum.GetValues(typeof(Title));
    combo.DataPropertyName = "Title";
    combo.Name = "Title";
    return combo;
}
#region "business object"
private class Knight
{
    private string hisName;
    private bool good;
    private Title hisTitle;

    public Knight(Title title, string name, bool good)
    {
        hisTitle = title;
        hisName = name;
        this.good = good;
    }

    public Knight()
    {
        hisTitle = Title.Sir;
        hisName = "<enter name>";
        good = true;
    }

    public string Name
    {
        get
        {
            return hisName;
        }

        set
        {
            hisName = value;
        }
    }

    public bool GoodGuy
    {
        get
        {
            return good;
        }
        set
        {
            good = value;
        }
    }

    public Title Title
    {
        get
        {
            return hisTitle;
        }
        set
        {
            hisTitle = value;
        }
    }
}
#endregion
    Private Sub SetupGrid()
        knights = New List(Of Knight)
        knights.Add(New Knight(Title.King, "Uther", True))
        knights.Add(New Knight(Title.King, "Arthur", True))
        knights.Add(New Knight(Title.Sir, "Mordred", False))
        knights.Add(New Knight(Title.Sir, "Gawain", True))
        knights.Add(New Knight(Title.Sir, "Galahad", True))

        ' Initialize the DataGridView.
        dataGridView1.AutoGenerateColumns = False
        dataGridView1.AutoSize = True
        dataGridView1.DataSource = knights

        dataGridView1.Columns.Add(CreateComboBoxWithEnums())

        ' Initialize and add a text box column.
        Dim column As DataGridViewColumn = _
            New DataGridViewTextBoxColumn()
        column.DataPropertyName = "Name"
        column.Name = "Knight"
        dataGridView1.Columns.Add(column)

        ' Initialize and add a check box column.
        column = New DataGridViewCheckBoxColumn()
        column.DataPropertyName = "GoodGuy"
        column.Name = "Good"
        dataGridView1.Columns.Add(column)

        ' Initialize the form.
        Controls.Add(dataGridView1)
        Me.AutoSize = True
        Me.Text = "DataGridView object binding demo"
    End Sub

    Private Function CreateComboBoxWithEnums() As DataGridViewComboBoxColumn
        Dim combo As New DataGridViewComboBoxColumn()
        combo.DataSource = [Enum].GetValues(GetType(Title))
        combo.DataPropertyName = "Title"
        combo.Name = "Title"
        Return combo
    End Function

#Region "business object"
    Private Class Knight
        Private hisName As String
        Private good As Boolean
        Private hisTitle As Title

        Public Sub New(ByVal title As Title, ByVal name As String, _
            ByVal good As Boolean)

            hisTitle = title
            hisName = name
            Me.good = good
        End Sub

        Public Property Name() As String
            Get
                Return hisName
            End Get

            Set(ByVal Value As String)
                hisName = Value
            End Set
        End Property

        Public Property GoodGuy() As Boolean
            Get
                Return good
            End Get
            Set(ByVal Value As Boolean)
                good = Value
            End Set
        End Property

        Public Property Title() As Title
            Get
                Return hisTitle
            End Get
            Set(ByVal Value As Title)
                hisTitle = Value
            End Set
        End Property
    End Class
#End Region

Remarques

Lorsque la AutoGenerateColumns propriété a la valeur true , chaque colonne affecte automatiquement DataPropertyName à sa propriété le nom d’une propriété ou d’une colonne de base de données dans la source de données spécifiée par la DataSource propriété. Cette liaison peut également être effectuée manuellement, ce qui est utile lorsque vous souhaitez afficher uniquement un sous-ensemble des propriétés ou des colonnes de base de données disponibles dans la source de données. Dans ce cas, affectez AutoGenerateColumns à la propriété la false valeur, puis ajoutez-les manuellement DataGridViewColumn , en définissant la valeur de chaque DataPropertyName propriété sur les propriétés ou les colonnes de base de données de la source de données que vous souhaitez afficher.

S’applique à

Voir aussi