DateTime.Subtraction Operator

  • Referensi

Definisi

Ruang nama:
System
Rakitan:
System.Runtime.dll
Rakitan:
mscorlib.dll
Rakitan:
netstandard.dll

Mengurangi DateTime atauTimeSpan dari yang ditentukan DateTime.

Overload

Subtraction(DateTime, DateTime)

Mengurangi tanggal dan waktu tertentu dari tanggal dan waktu tertentu lainnya dan mengembalikan interval waktu.
Subtraction(DateTime, TimeSpan)

Mengurangi interval waktu tertentu dari tanggal dan waktu tertentu dan mengembalikan tanggal dan waktu baru.

Subtraction(DateTime, DateTime)

Sumber:
DateTime.cs
Sumber:
DateTime.cs
Sumber:
DateTime.cs

Mengurangi tanggal dan waktu tertentu dari tanggal dan waktu tertentu lainnya dan mengembalikan interval waktu.

public:
 static TimeSpan operator -(DateTime d1, DateTime d2);
public static TimeSpan operator - (DateTime d1, DateTime d2);
static member ( - ) : DateTime * DateTime -> TimeSpan
Public Shared Operator - (d1 As DateTime, d2 As DateTime) As TimeSpan

Parameter

d1
DateTime

Nilai tanggal dan waktu yang akan dikurangi dari (minuend).

d2
DateTime

Nilai tanggal dan waktu untuk mengurangi (subtrahend).

Mengembalikan

TimeSpan

Interval waktu antara d1 dan d2; yaitu, d1 minus d2.

Contoh

Contoh berikut menunjukkan Subtract metode dan operator pengurangan.

System::DateTime date1 = System::DateTime( 1996, 6, 3, 22, 15, 0 );
System::DateTime date2 = System::DateTime( 1996, 12, 6, 13, 2, 0 );
System::DateTime date3 = System::DateTime( 1996, 10, 12, 8, 42, 0 );

// diff1 gets 185 days, 14 hours, and 47 minutes.
System::TimeSpan diff1 = date2.Subtract( date1 );

// date4 gets 4/9/1996 5:55:00 PM.
System::DateTime date4 = date3.Subtract( diff1 );

// diff2 gets 55 days 4 hours and 20 minutes.
System::TimeSpan diff2 = date2 - date3;

// date5 gets 4/9/1996 5:55:00 PM.
System::DateTime date5 = date1 - diff2;

open System

let date1 = DateTime(1996, 6, 3, 22, 15, 0)
let date2 = DateTime(1996, 12, 6, 13, 2, 0)
let date3 = DateTime(1996, 10, 12, 8, 42, 0)

// diff1 gets 185 days, 14 hours, and 47 minutes.
let diff1 = date2.Subtract date1

// date4 gets 4/9/1996 5:55:00 PM.
let date4 = date3.Subtract diff1

// diff2 gets 55 days 4 hours and 20 minutes.
let diff2 = date2 - date3

// date5 gets 4/9/1996 5:55:00 PM.
let date5 = date1 - diff2

System.DateTime date1 = new System.DateTime(1996, 6, 3, 22, 15, 0);
System.DateTime date2 = new System.DateTime(1996, 12, 6, 13, 2, 0);
System.DateTime date3 = new System.DateTime(1996, 10, 12, 8, 42, 0);

// diff1 gets 185 days, 14 hours, and 47 minutes.
System.TimeSpan diff1 = date2.Subtract(date1);

// date4 gets 4/9/1996 5:55:00 PM.
System.DateTime date4 = date3.Subtract(diff1);

// diff2 gets 55 days 4 hours and 20 minutes.
System.TimeSpan diff2 = date2 - date3;

// date5 gets 4/9/1996 5:55:00 PM.
System.DateTime date5 = date1 - diff2;

Dim date1 As New System.DateTime(1996, 6, 3, 22, 15, 0)
Dim date2 As New System.DateTime(1996, 12, 6, 13, 2, 0)
Dim date3 As New System.DateTime(1996, 10, 12, 8, 42, 0)

Dim diff1 As System.TimeSpan
' diff1 gets 185 days, 14 hours, and 47 minutes.
diff1 = date2.Subtract(date1)

Dim date4 As System.DateTime
' date4 gets 4/9/1996 5:55:00 PM.
date4 = date3.Subtract(diff1)

Dim diff2 As System.TimeSpan
' diff2 gets 55 days 4 hours and 20 minutes.
diff2 = System.DateTime.op_Subtraction(date2, date3)

Dim date5 As System.DateTime
' date5 gets 4/9/1996 5:55:00 PM.
date5 = System.DateTime.op_Subtraction(date1, diff2)

Keterangan

Metode Subtraction(DateTime, DateTime) ini tidak mempertimbangkan nilai Kind properti dari dua DateTime nilai saat melakukan pengurangan. Sebelum mengurangi DateTime objek, pastikan bahwa objek mewakili waktu dalam zona waktu yang sama. Jika tidak, hasilnya akan mencakup perbedaan antara zona waktu.

Catatan

Metode ini DateTimeOffset.Subtraction(DateTimeOffset, DateTimeOffset) memang mempertimbangkan perbedaan antara zona waktu saat melakukan pengurangan.

Metode yang setara untuk operator ini adalah DateTime.Subtract(DateTime)

Lihat juga

Berlaku untuk

Subtraction(DateTime, TimeSpan)

Sumber:
DateTime.cs
Sumber:
DateTime.cs
Sumber:
DateTime.cs

Mengurangi interval waktu tertentu dari tanggal dan waktu tertentu dan mengembalikan tanggal dan waktu baru.

public:
 static DateTime operator -(DateTime d, TimeSpan t);
public static DateTime operator - (DateTime d, TimeSpan t);
static member ( - ) : DateTime * TimeSpan -> DateTime
Public Shared Operator - (d As DateTime, t As TimeSpan) As DateTime

Parameter

d
DateTime

Nilai tanggal dan waktu yang akan dikurangi.

t
TimeSpan

Interval waktu untuk mengurangi.

Mengembalikan

DateTime

Objek yang nilainya adalah nilai d dikurangi tnilai .

Pengecualian

ArgumentOutOfRangeException

DateTime Hasilnya kurang dari DateTime.MinValue atau lebih besar dari DateTime.MaxValue.

Contoh

Contoh berikut menunjukkan Subtract metode dan operator pengurangan.

System::DateTime date1 = System::DateTime( 1996, 6, 3, 22, 15, 0 );
System::DateTime date2 = System::DateTime( 1996, 12, 6, 13, 2, 0 );
System::DateTime date3 = System::DateTime( 1996, 10, 12, 8, 42, 0 );

// diff1 gets 185 days, 14 hours, and 47 minutes.
System::TimeSpan diff1 = date2.Subtract( date1 );

// date4 gets 4/9/1996 5:55:00 PM.
System::DateTime date4 = date3.Subtract( diff1 );

// diff2 gets 55 days 4 hours and 20 minutes.
System::TimeSpan diff2 = date2 - date3;

// date5 gets 4/9/1996 5:55:00 PM.
System::DateTime date5 = date1 - diff2;

open System

let date1 = DateTime(1996, 6, 3, 22, 15, 0)
let date2 = DateTime(1996, 12, 6, 13, 2, 0)
let date3 = DateTime(1996, 10, 12, 8, 42, 0)

// diff1 gets 185 days, 14 hours, and 47 minutes.
let diff1 = date2.Subtract date1

// date4 gets 4/9/1996 5:55:00 PM.
let date4 = date3.Subtract diff1

// diff2 gets 55 days 4 hours and 20 minutes.
let diff2 = date2 - date3

// date5 gets 4/9/1996 5:55:00 PM.
let date5 = date1 - diff2

System.DateTime date1 = new System.DateTime(1996, 6, 3, 22, 15, 0);
System.DateTime date2 = new System.DateTime(1996, 12, 6, 13, 2, 0);
System.DateTime date3 = new System.DateTime(1996, 10, 12, 8, 42, 0);

// diff1 gets 185 days, 14 hours, and 47 minutes.
System.TimeSpan diff1 = date2.Subtract(date1);

// date4 gets 4/9/1996 5:55:00 PM.
System.DateTime date4 = date3.Subtract(diff1);

// diff2 gets 55 days 4 hours and 20 minutes.
System.TimeSpan diff2 = date2 - date3;

// date5 gets 4/9/1996 5:55:00 PM.
System.DateTime date5 = date1 - diff2;

Dim date1 As New System.DateTime(1996, 6, 3, 22, 15, 0)
Dim date2 As New System.DateTime(1996, 12, 6, 13, 2, 0)
Dim date3 As New System.DateTime(1996, 10, 12, 8, 42, 0)

Dim diff1 As System.TimeSpan
' diff1 gets 185 days, 14 hours, and 47 minutes.
diff1 = date2.Subtract(date1)

Dim date4 As System.DateTime
' date4 gets 4/9/1996 5:55:00 PM.
date4 = date3.Subtract(diff1)

Dim diff2 As System.TimeSpan
' diff2 gets 55 days 4 hours and 20 minutes.
diff2 = System.DateTime.op_Subtraction(date2, date3)

Dim date5 As System.DateTime
' date5 gets 4/9/1996 5:55:00 PM.
date5 = System.DateTime.op_Subtraction(date1, diff2)

Keterangan

Metode ini mengurangi nilai tick dari t nilai dticks .

Metode yang setara untuk operator ini adalah DateTime.Subtract(DateTime)

Lihat juga

Berlaku untuk