OutArgument<T>.FromExpression(Activity<Location<T>>) Metodo

  • Riferimento

Definizione

Spazio dei nomi:
System.Activities
Assembly:
System.Activities.dll

Inizializza e restituisce un nuovo OutArgument<T> costruito utilizzando il Activity<TResult> specificato.

public:
 static System::Activities::OutArgument<T> ^ FromExpression(System::Activities::Activity<System::Activities::Location<T> ^> ^ expression);
public static System.Activities.OutArgument<T> FromExpression (System.Activities.Activity<System.Activities.Location<T>> expression);
static member FromExpression : System.Activities.Activity<System.Activities.Location<'T>> -> System.Activities.OutArgument<'T>
Public Shared Function FromExpression (expression As Activity(Of Location(Of T))) As OutArgument(Of T)

Parametri

expression
Activity<Location<T>>

Valore dell'argomento.

Restituisce

OutArgument<T>

Nuovo argomento.

Si applica a