Enumerable.Sum メソッド

定義

数値のシーケンスの合計を計算します。Computes the sum of a sequence of numeric values.

オーバーロード

Sum(IEnumerable<Nullable<Int32>>)

null 許容の Int32 値のシーケンスの合計を計算します。Computes the sum of a sequence of nullable Int32 values.

Sum(IEnumerable<Nullable<Single>>)

null 許容の Single 値のシーケンスの合計を計算します。Computes the sum of a sequence of nullable Single values.

Sum(IEnumerable<Nullable<Int64>>)

null 許容の Int64 値のシーケンスの合計を計算します。Computes the sum of a sequence of nullable Int64 values.

Sum(IEnumerable<Single>)

Single 値のシーケンスの合計を計算します。Computes the sum of a sequence of Single values.

Sum(IEnumerable<Nullable<Double>>)

null 許容の Double 値のシーケンスの合計を計算します。Computes the sum of a sequence of nullable Double values.

Sum(IEnumerable<Int32>)

Int32 値のシーケンスの合計を計算します。Computes the sum of a sequence of Int32 values.

Sum(IEnumerable<Int64>)

Int64 値のシーケンスの合計を計算します。Computes the sum of a sequence of Int64 values.

Sum(IEnumerable<Double>)

Double 値のシーケンスの合計を計算します。Computes the sum of a sequence of Double values.

Sum(IEnumerable<Decimal>)

Decimal 値のシーケンスの合計を計算します。Computes the sum of a sequence of Decimal values.

Sum(IEnumerable<Nullable<Decimal>>)

null 許容の Decimal 値のシーケンスの合計を計算します。Computes the sum of a sequence of nullable Decimal values.

Sum<TSource>(IEnumerable<TSource>, Func<TSource,Single>)

入力シーケンスの各要素に対して変換関数を呼び出して取得する Single 値のシーケンスの合計を計算します。Computes the sum of the sequence of Single values that are obtained by invoking a transform function on each element of the input sequence.

Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Single>>)

入力シーケンスの各要素に対して変換関数を呼び出して取得する null 許容の Single 値のシーケンスの合計を計算します。Computes the sum of the sequence of nullable Single values that are obtained by invoking a transform function on each element of the input sequence.

Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Int64>>)

入力シーケンスの各要素に対して変換関数を呼び出して取得する null 許容の Int64 値のシーケンスの合計を計算します。Computes the sum of the sequence of nullable Int64 values that are obtained by invoking a transform function on each element of the input sequence.

Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Int32>>)

入力シーケンスの各要素に対して変換関数を呼び出して取得する null 許容の Int32 値のシーケンスの合計を計算します。Computes the sum of the sequence of nullable Int32 values that are obtained by invoking a transform function on each element of the input sequence.

Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Double>>)

入力シーケンスの各要素に対して変換関数を呼び出して取得する null 許容の Double 値のシーケンスの合計を計算します。Computes the sum of the sequence of nullable Double values that are obtained by invoking a transform function on each element of the input sequence.

Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Decimal>>)

入力シーケンスの各要素に対して変換関数を呼び出して取得する null 許容の Decimal 値のシーケンスの合計を計算します。Computes the sum of the sequence of nullable Decimal values that are obtained by invoking a transform function on each element of the input sequence.

Sum<TSource>(IEnumerable<TSource>, Func<TSource,Int64>)

入力シーケンスの各要素に対して変換関数を呼び出して取得する Int64 値のシーケンスの合計を計算します。Computes the sum of the sequence of Int64 values that are obtained by invoking a transform function on each element of the input sequence.

Sum<TSource>(IEnumerable<TSource>, Func<TSource,Int32>)

入力シーケンスの各要素に対して変換関数を呼び出して取得する Int32 値のシーケンスの合計を計算します。Computes the sum of the sequence of Int32 values that are obtained by invoking a transform function on each element of the input sequence.

Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>)

入力シーケンスの各要素に対して変換関数を呼び出して取得する Double 値のシーケンスの合計を計算します。Computes the sum of the sequence of Double values that are obtained by invoking a transform function on each element of the input sequence.

Sum<TSource>(IEnumerable<TSource>, Func<TSource,Decimal>)

入力シーケンスの各要素に対して変換関数を呼び出して取得する Decimal 値のシーケンスの合計を計算します。Computes the sum of the sequence of Decimal values that are obtained by invoking a transform function on each element of the input sequence.

Sum(IEnumerable<Nullable<Int32>>)

null 許容の Int32 値のシーケンスの合計を計算します。Computes the sum of a sequence of nullable Int32 values.

public:
[System::Runtime::CompilerServices::Extension]
 static Nullable<int> Sum(System::Collections::Generic::IEnumerable<Nullable<int>> ^ source);
public static int? Sum (this System.Collections.Generic.IEnumerable<Nullable<int>> source);
static member Sum : seq<Nullable<int>> -> Nullable<int>
<Extension()>
Public Function Sum (source As IEnumerable(Of Nullable(Of Integer))) As Nullable(Of Integer)

パラメーター

source
IEnumerable<Nullable<Int32>>

合計を計算する対象となる null 許容の Int32 値のシーケンス。A sequence of nullable Int32 values to calculate the sum of.

戻り値

Nullable<Int32>

シーケンスの値の合計。The sum of the values in the sequence.

例外

sourcenullです。source is null.

合計が MaxValueを超えています。The sum is larger than MaxValue.

次のコード例は、を使用してシーケンスの値を合計する方法を示して Sum(IEnumerable<Nullable<Single>>) います。The following code example demonstrates how to use Sum(IEnumerable<Nullable<Single>>) to sum the values of a sequence.

注意

このコード例で使用するオーバーロードされたメソッドのオーバーロードは、このトピックで説明する特定のオーバーロードとは異なります。This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. コード例をこのトピックに適用するには、ソース シーケンスの要素を適切な数値型の要素に置き換えます。To extend the example to this topic, substitute the elements of the source sequence with elements of the appropriate numerical type.

float?[] points = { null, 0, 92.83F, null, 100.0F, 37.46F, 81.1F };

float? sum = points.Sum();

Console.WriteLine("Total points earned: {0}", sum);

/*
 This code produces the following output:

 Total points earned: 311.39
*/
' Create an array of Nullable Single values.
Dim points() As Nullable(Of Single) =
{Nothing, 0, 92.83F, Nothing, 100.0F, 37.46F, 81.1F}

' Get the sum of values in the list.
Dim sum As Nullable(Of Single) = points.Sum()

' Display the output.
Console.WriteLine($"Total points earned: {sum}")

' This code produces the following output:
'
' Total points earned: 311.39

注釈

に要素が含まれていない場合、このメソッドは0を返し source ます。This method returns zero if source contains no elements.

結果には、の値は含まれません nullThe result does not include values that are null.

Visual Basic のクエリ式の構文では、 Aggregate Into Sum() 句はの呼び出しに変換 Sum します。In Visual Basic query expression syntax, an Aggregate Into Sum() clause translates to an invocation of Sum.

こちらもご覧ください

適用対象

Sum(IEnumerable<Nullable<Single>>)

null 許容の Single 値のシーケンスの合計を計算します。Computes the sum of a sequence of nullable Single values.

public:
[System::Runtime::CompilerServices::Extension]
 static Nullable<float> Sum(System::Collections::Generic::IEnumerable<Nullable<float>> ^ source);
public static float? Sum (this System.Collections.Generic.IEnumerable<Nullable<float>> source);
static member Sum : seq<Nullable<single>> -> Nullable<single>
<Extension()>
Public Function Sum (source As IEnumerable(Of Nullable(Of Single))) As Nullable(Of Single)

パラメーター

source
IEnumerable<Nullable<Single>>

合計を計算する対象となる null 許容の Single 値のシーケンス。A sequence of nullable Single values to calculate the sum of.

戻り値

Nullable<Single>

シーケンスの値の合計。The sum of the values in the sequence.

例外

sourcenullです。source is null.

次のコード例は、を使用してシーケンスの値を合計する方法を示して Sum(IEnumerable<Nullable<Single>>) います。The following code example demonstrates how to use Sum(IEnumerable<Nullable<Single>>) to sum the values of a sequence.

float?[] points = { null, 0, 92.83F, null, 100.0F, 37.46F, 81.1F };

float? sum = points.Sum();

Console.WriteLine("Total points earned: {0}", sum);

/*
 This code produces the following output:

 Total points earned: 311.39
*/
' Create an array of Nullable Single values.
Dim points() As Nullable(Of Single) =
{Nothing, 0, 92.83F, Nothing, 100.0F, 37.46F, 81.1F}

' Get the sum of values in the list.
Dim sum As Nullable(Of Single) = points.Sum()

' Display the output.
Console.WriteLine($"Total points earned: {sum}")

' This code produces the following output:
'
' Total points earned: 311.39

注釈

に要素が含まれていない場合、このメソッドは0を返し source ます。This method returns zero if source contains no elements.

結果には、の値は含まれません nullThe result does not include values that are null.

Visual Basic のクエリ式の構文では、 Aggregate Into Sum() 句はの呼び出しに変換 Sum します。In Visual Basic query expression syntax, an Aggregate Into Sum() clause translates to an invocation of Sum.

こちらもご覧ください

適用対象

Sum(IEnumerable<Nullable<Int64>>)

null 許容の Int64 値のシーケンスの合計を計算します。Computes the sum of a sequence of nullable Int64 values.

public:
[System::Runtime::CompilerServices::Extension]
 static Nullable<long> Sum(System::Collections::Generic::IEnumerable<Nullable<long>> ^ source);
public static long? Sum (this System.Collections.Generic.IEnumerable<Nullable<long>> source);
static member Sum : seq<Nullable<int64>> -> Nullable<int64>
<Extension()>
Public Function Sum (source As IEnumerable(Of Nullable(Of Long))) As Nullable(Of Long)

パラメーター

source
IEnumerable<Nullable<Int64>>

合計を計算する対象となる null 許容の Int64 値のシーケンス。A sequence of nullable Int64 values to calculate the sum of.

戻り値

Nullable<Int64>

シーケンスの値の合計。The sum of the values in the sequence.

例外

sourcenullです。source is null.

合計が MaxValueを超えています。The sum is larger than MaxValue.

次のコード例は、を使用してシーケンスの値を合計する方法を示して Sum(IEnumerable<Nullable<Single>>) います。The following code example demonstrates how to use Sum(IEnumerable<Nullable<Single>>) to sum the values of a sequence.

注意

このコード例で使用するオーバーロードされたメソッドのオーバーロードは、このトピックで説明する特定のオーバーロードとは異なります。This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. コード例をこのトピックに適用するには、ソース シーケンスの要素を適切な数値型の要素に置き換えます。To extend the example to this topic, substitute the elements of the source sequence with elements of the appropriate numerical type.

float?[] points = { null, 0, 92.83F, null, 100.0F, 37.46F, 81.1F };

float? sum = points.Sum();

Console.WriteLine("Total points earned: {0}", sum);

/*
 This code produces the following output:

 Total points earned: 311.39
*/
' Create an array of Nullable Single values.
Dim points() As Nullable(Of Single) =
{Nothing, 0, 92.83F, Nothing, 100.0F, 37.46F, 81.1F}

' Get the sum of values in the list.
Dim sum As Nullable(Of Single) = points.Sum()

' Display the output.
Console.WriteLine($"Total points earned: {sum}")

' This code produces the following output:
'
' Total points earned: 311.39

注釈

に要素が含まれていない場合、このメソッドは0を返し source ます。This method returns zero if source contains no elements.

結果には、の値は含まれません nullThe result does not include values that are null.

Visual Basic のクエリ式の構文では、 Aggregate Into Sum() 句はの呼び出しに変換 Sum します。In Visual Basic query expression syntax, an Aggregate Into Sum() clause translates to an invocation of Sum.

こちらもご覧ください

適用対象

Sum(IEnumerable<Single>)

Single 値のシーケンスの合計を計算します。Computes the sum of a sequence of Single values.

public:
[System::Runtime::CompilerServices::Extension]
 static float Sum(System::Collections::Generic::IEnumerable<float> ^ source);
public static float Sum (this System.Collections.Generic.IEnumerable<float> source);
static member Sum : seq<single> -> single
<Extension()>
Public Function Sum (source As IEnumerable(Of Single)) As Single

パラメーター

source
IEnumerable<Single>

合計を計算する対象となる Single 値のシーケンス。A sequence of Single values to calculate the sum of.

戻り値

Single

シーケンスの値の合計。The sum of the values in the sequence.

例外

sourcenullです。source is null.

次のコード例は、を使用してシーケンスの値を合計する方法を示して Sum(IEnumerable<Single>) います。The following code example demonstrates how to use Sum(IEnumerable<Single>) to sum the values of a sequence.

List<float> numbers = new List<float> { 43.68F, 1.25F, 583.7F, 6.5F };

float sum = numbers.Sum();

Console.WriteLine("The sum of the numbers is {0}.", sum);

/*
 This code produces the following output:

 The sum of the numbers is 635.13.
*/
' Create a list of Single values.
Dim numbers As New List(Of Single)(New Single() _
                               {43.68F, 1.25F, 583.7F, 6.5F})

' Get the sum of values in the list.
Dim sum As Single = numbers.Sum()

' Display the output.
Console.WriteLine($"The sum of the numbers is {sum}")

' This code produces the following output:
'
' The sum of the numbers is 635.13

注釈

に要素が含まれていない場合、このメソッドは0を返し source ます。This method returns zero if source contains no elements.

Visual Basic のクエリ式の構文では、 Aggregate Into Sum() 句はの呼び出しに変換 Sum します。In Visual Basic query expression syntax, an Aggregate Into Sum() clause translates to an invocation of Sum.

こちらもご覧ください

適用対象

Sum(IEnumerable<Nullable<Double>>)

null 許容の Double 値のシーケンスの合計を計算します。Computes the sum of a sequence of nullable Double values.

public:
[System::Runtime::CompilerServices::Extension]
 static Nullable<double> Sum(System::Collections::Generic::IEnumerable<Nullable<double>> ^ source);
public static double? Sum (this System.Collections.Generic.IEnumerable<Nullable<double>> source);
static member Sum : seq<Nullable<double>> -> Nullable<double>
<Extension()>
Public Function Sum (source As IEnumerable(Of Nullable(Of Double))) As Nullable(Of Double)

パラメーター

source
IEnumerable<Nullable<Double>>

合計を計算する対象となる null 許容の Double 値のシーケンス。A sequence of nullable Double values to calculate the sum of.

戻り値

Nullable<Double>

シーケンスの値の合計。The sum of the values in the sequence.

例外

sourcenullです。source is null.

次のコード例は、を使用してシーケンスの値を合計する方法を示して Sum(IEnumerable<Nullable<Single>>) います。The following code example demonstrates how to use Sum(IEnumerable<Nullable<Single>>) to sum the values of a sequence.

注意

このコード例で使用するオーバーロードされたメソッドのオーバーロードは、このトピックで説明する特定のオーバーロードとは異なります。This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. コード例をこのトピックに適用するには、ソース シーケンスの要素を適切な数値型の要素に置き換えます。To extend the example to this topic, substitute the elements of the source sequence with elements of the appropriate numerical type.

float?[] points = { null, 0, 92.83F, null, 100.0F, 37.46F, 81.1F };

float? sum = points.Sum();

Console.WriteLine("Total points earned: {0}", sum);

/*
 This code produces the following output:

 Total points earned: 311.39
*/
' Create an array of Nullable Single values.
Dim points() As Nullable(Of Single) =
{Nothing, 0, 92.83F, Nothing, 100.0F, 37.46F, 81.1F}

' Get the sum of values in the list.
Dim sum As Nullable(Of Single) = points.Sum()

' Display the output.
Console.WriteLine($"Total points earned: {sum}")

' This code produces the following output:
'
' Total points earned: 311.39

注釈

に要素が含まれていない場合、このメソッドは0を返し source ます。This method returns zero if source contains no elements.

結果には、の値は含まれません nullThe result does not include values that are null.

Visual Basic のクエリ式の構文では、 Aggregate Into Sum() 句はの呼び出しに変換 Sum します。In Visual Basic query expression syntax, an Aggregate Into Sum() clause translates to an invocation of Sum.

こちらもご覧ください

適用対象

Sum(IEnumerable<Int32>)

Int32 値のシーケンスの合計を計算します。Computes the sum of a sequence of Int32 values.

public:
[System::Runtime::CompilerServices::Extension]
 static int Sum(System::Collections::Generic::IEnumerable<int> ^ source);
public static int Sum (this System.Collections.Generic.IEnumerable<int> source);
static member Sum : seq<int> -> int
<Extension()>
Public Function Sum (source As IEnumerable(Of Integer)) As Integer

パラメーター

source
IEnumerable<Int32>

合計を計算する対象となる Int32 値のシーケンス。A sequence of Int32 values to calculate the sum of.

戻り値

Int32

シーケンスの値の合計。The sum of the values in the sequence.

例外

sourcenullです。source is null.

合計が MaxValueを超えています。The sum is larger than MaxValue.

次のコード例は、を使用してシーケンスの値を合計する方法を示して Sum(IEnumerable<Single>) います。The following code example demonstrates how to use Sum(IEnumerable<Single>) to sum the values of a sequence.

注意

このコード例で使用するオーバーロードされたメソッドのオーバーロードは、このトピックで説明する特定のオーバーロードとは異なります。This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. コード例をこのトピックに適用するには、ソース シーケンスの要素を適切な数値型の要素に置き換えます。To extend the example to this topic, substitute the elements of the source sequence with elements of the appropriate numerical type.

List<float> numbers = new List<float> { 43.68F, 1.25F, 583.7F, 6.5F };

float sum = numbers.Sum();

Console.WriteLine("The sum of the numbers is {0}.", sum);

/*
 This code produces the following output:

 The sum of the numbers is 635.13.
*/
' Create a list of Single values.
Dim numbers As New List(Of Single)(New Single() _
                               {43.68F, 1.25F, 583.7F, 6.5F})

' Get the sum of values in the list.
Dim sum As Single = numbers.Sum()

' Display the output.
Console.WriteLine($"The sum of the numbers is {sum}")

' This code produces the following output:
'
' The sum of the numbers is 635.13

注釈

に要素が含まれていない場合、このメソッドは0を返し source ます。This method returns zero if source contains no elements.

Visual Basic のクエリ式の構文では、 Aggregate Into Sum() 句はの呼び出しに変換 Sum します。In Visual Basic query expression syntax, an Aggregate Into Sum() clause translates to an invocation of Sum.

こちらもご覧ください

適用対象

Sum(IEnumerable<Int64>)

Int64 値のシーケンスの合計を計算します。Computes the sum of a sequence of Int64 values.

public:
[System::Runtime::CompilerServices::Extension]
 static long Sum(System::Collections::Generic::IEnumerable<long> ^ source);
public static long Sum (this System.Collections.Generic.IEnumerable<long> source);
static member Sum : seq<int64> -> int64
<Extension()>
Public Function Sum (source As IEnumerable(Of Long)) As Long

パラメーター

source
IEnumerable<Int64>

合計を計算する対象となる Int64 値のシーケンス。A sequence of Int64 values to calculate the sum of.

戻り値

Int64

シーケンスの値の合計。The sum of the values in the sequence.

例外

sourcenullです。source is null.

合計が MaxValueを超えています。The sum is larger than MaxValue.

次のコード例は、を使用してシーケンスの値を合計する方法を示して Sum(IEnumerable<Single>) います。The following code example demonstrates how to use Sum(IEnumerable<Single>) to sum the values of a sequence.

注意

このコード例で使用するオーバーロードされたメソッドのオーバーロードは、このトピックで説明する特定のオーバーロードとは異なります。This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. コード例をこのトピックに適用するには、ソース シーケンスの要素を適切な数値型の要素に置き換えます。To extend the example to this topic, substitute the elements of the source sequence with elements of the appropriate numerical type.

List<float> numbers = new List<float> { 43.68F, 1.25F, 583.7F, 6.5F };

float sum = numbers.Sum();

Console.WriteLine("The sum of the numbers is {0}.", sum);

/*
 This code produces the following output:

 The sum of the numbers is 635.13.
*/
' Create a list of Single values.
Dim numbers As New List(Of Single)(New Single() _
                               {43.68F, 1.25F, 583.7F, 6.5F})

' Get the sum of values in the list.
Dim sum As Single = numbers.Sum()

' Display the output.
Console.WriteLine($"The sum of the numbers is {sum}")

' This code produces the following output:
'
' The sum of the numbers is 635.13

注釈

に要素が含まれていない場合、このメソッドは0を返し source ます。This method returns zero if source contains no elements.

Visual Basic のクエリ式の構文では、 Aggregate Into Sum() 句はの呼び出しに変換 Sum します。In Visual Basic query expression syntax, an Aggregate Into Sum() clause translates to an invocation of Sum.

こちらもご覧ください

適用対象

Sum(IEnumerable<Double>)

Double 値のシーケンスの合計を計算します。Computes the sum of a sequence of Double values.

public:
[System::Runtime::CompilerServices::Extension]
 static double Sum(System::Collections::Generic::IEnumerable<double> ^ source);
public static double Sum (this System.Collections.Generic.IEnumerable<double> source);
static member Sum : seq<double> -> double
<Extension()>
Public Function Sum (source As IEnumerable(Of Double)) As Double

パラメーター

source
IEnumerable<Double>

合計を計算する対象となる Double 値のシーケンス。A sequence of Double values to calculate the sum of.

戻り値

Double

シーケンスの値の合計。The sum of the values in the sequence.

例外

sourcenullです。source is null.

次のコード例は、を使用してシーケンスの値を合計する方法を示して Sum(IEnumerable<Single>) います。The following code example demonstrates how to use Sum(IEnumerable<Single>) to sum the values of a sequence.

注意

このコード例で使用するオーバーロードされたメソッドのオーバーロードは、このトピックで説明する特定のオーバーロードとは異なります。This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. コード例をこのトピックに適用するには、ソース シーケンスの要素を適切な数値型の要素に置き換えます。To extend the example to this topic, substitute the elements of the source sequence with elements of the appropriate numerical type.

List<float> numbers = new List<float> { 43.68F, 1.25F, 583.7F, 6.5F };

float sum = numbers.Sum();

Console.WriteLine("The sum of the numbers is {0}.", sum);

/*
 This code produces the following output:

 The sum of the numbers is 635.13.
*/
' Create a list of Single values.
Dim numbers As New List(Of Single)(New Single() _
                               {43.68F, 1.25F, 583.7F, 6.5F})

' Get the sum of values in the list.
Dim sum As Single = numbers.Sum()

' Display the output.
Console.WriteLine($"The sum of the numbers is {sum}")

' This code produces the following output:
'
' The sum of the numbers is 635.13

注釈

に要素が含まれていない場合、このメソッドは0を返し source ます。This method returns zero if source contains no elements.

Visual Basic のクエリ式の構文では、 Aggregate Into Sum() 句はの呼び出しに変換 Sum します。In Visual Basic query expression syntax, an Aggregate Into Sum() clause translates to an invocation of Sum.

こちらもご覧ください

適用対象

Sum(IEnumerable<Decimal>)

Decimal 値のシーケンスの合計を計算します。Computes the sum of a sequence of Decimal values.

public:
[System::Runtime::CompilerServices::Extension]
 static System::Decimal Sum(System::Collections::Generic::IEnumerable<System::Decimal> ^ source);
public static decimal Sum (this System.Collections.Generic.IEnumerable<decimal> source);
static member Sum : seq<decimal> -> decimal
<Extension()>
Public Function Sum (source As IEnumerable(Of Decimal)) As Decimal

パラメーター

source
IEnumerable<Decimal>

合計を計算する対象となる Decimal 値のシーケンス。A sequence of Decimal values to calculate the sum of.

戻り値

Decimal

シーケンスの値の合計。The sum of the values in the sequence.

例外

sourcenullです。source is null.

合計が MaxValueを超えています。The sum is larger than MaxValue.

次のコード例は、を使用してシーケンスの値を合計する方法を示して Sum(IEnumerable<Single>) います。The following code example demonstrates how to use Sum(IEnumerable<Single>) to sum the values of a sequence.

注意

このコード例で使用するオーバーロードされたメソッドのオーバーロードは、このトピックで説明する特定のオーバーロードとは異なります。This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. コード例をこのトピックに適用するには、ソース シーケンスの要素を適切な数値型の要素に置き換えます。To extend the example to this topic, substitute the elements of the source sequence with elements of the appropriate numerical type.

List<float> numbers = new List<float> { 43.68F, 1.25F, 583.7F, 6.5F };

float sum = numbers.Sum();

Console.WriteLine("The sum of the numbers is {0}.", sum);

/*
 This code produces the following output:

 The sum of the numbers is 635.13.
*/
' Create a list of Single values.
Dim numbers As New List(Of Single)(New Single() _
                               {43.68F, 1.25F, 583.7F, 6.5F})

' Get the sum of values in the list.
Dim sum As Single = numbers.Sum()

' Display the output.
Console.WriteLine($"The sum of the numbers is {sum}")

' This code produces the following output:
'
' The sum of the numbers is 635.13

注釈

Sum(IEnumerable<Decimal>) 要素が含まれていない場合、メソッドは0を返し source ます。The Sum(IEnumerable<Decimal>) method returns zero if source contains no elements.

Visual Basic のクエリ式の構文では、 Aggregate Into Sum() 句はの呼び出しに変換 Sum します。In Visual Basic query expression syntax, an Aggregate Into Sum() clause translates to an invocation of Sum.

こちらもご覧ください

適用対象

Sum(IEnumerable<Nullable<Decimal>>)

null 許容の Decimal 値のシーケンスの合計を計算します。Computes the sum of a sequence of nullable Decimal values.

public:
[System::Runtime::CompilerServices::Extension]
 static Nullable<System::Decimal> Sum(System::Collections::Generic::IEnumerable<Nullable<System::Decimal>> ^ source);
public static decimal? Sum (this System.Collections.Generic.IEnumerable<Nullable<decimal>> source);
static member Sum : seq<Nullable<decimal>> -> Nullable<decimal>
<Extension()>
Public Function Sum (source As IEnumerable(Of Nullable(Of Decimal))) As Nullable(Of Decimal)

パラメーター

source
IEnumerable<Nullable<Decimal>>

合計を計算する対象となる null 許容の Decimal 値のシーケンス。A sequence of nullable Decimal values to calculate the sum of.

戻り値

Nullable<Decimal>

シーケンスの値の合計。The sum of the values in the sequence.

例外

sourcenullです。source is null.

合計が MaxValueを超えています。The sum is larger than MaxValue.

次のコード例は、を使用してシーケンスの値を合計する方法を示して Sum(IEnumerable<Nullable<Single>>) います。The following code example demonstrates how to use Sum(IEnumerable<Nullable<Single>>) to sum the values of a sequence.

注意

このコード例で使用するオーバーロードされたメソッドのオーバーロードは、このトピックで説明する特定のオーバーロードとは異なります。This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. コード例をこのトピックに適用するには、ソース シーケンスの要素を適切な数値型の要素に置き換えます。To extend the example to this topic, substitute the elements of the source sequence with elements of the appropriate numerical type.

float?[] points = { null, 0, 92.83F, null, 100.0F, 37.46F, 81.1F };

float? sum = points.Sum();

Console.WriteLine("Total points earned: {0}", sum);

/*
 This code produces the following output:

 Total points earned: 311.39
*/
' Create an array of Nullable Single values.
Dim points() As Nullable(Of Single) =
{Nothing, 0, 92.83F, Nothing, 100.0F, 37.46F, 81.1F}

' Get the sum of values in the list.
Dim sum As Nullable(Of Single) = points.Sum()

' Display the output.
Console.WriteLine($"Total points earned: {sum}")

' This code produces the following output:
'
' Total points earned: 311.39

注釈

に要素が含まれていない場合、このメソッドは0を返し source ます。This method returns zero if source contains no elements.

結果には、の値は含まれ null ません。The result doesnot include values that are null.

Visual Basic のクエリ式の構文では、 Aggregate Into Sum() 句はの呼び出しに変換 Sum します。In Visual Basic query expression syntax, an Aggregate Into Sum() clause translates to an invocation of Sum.

こちらもご覧ください

適用対象

Sum<TSource>(IEnumerable<TSource>, Func<TSource,Single>)

入力シーケンスの各要素に対して変換関数を呼び出して取得する Single 値のシーケンスの合計を計算します。Computes the sum of the sequence of Single values that are obtained by invoking a transform function on each element of the input sequence.

public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
 static float Sum(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, float> ^ selector);
public static float Sum<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,float> selector);
static member Sum : seq<'Source> * Func<'Source, single> -> single
<Extension()>
Public Function Sum(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Single)) As Single

型パラメーター

TSource

source の要素の型。The type of the elements of source.

パラメーター

source
IEnumerable<TSource>

合計の計算に使用される値のシーケンス。A sequence of values that are used to calculate a sum.

selector
Func<TSource,Single>

各要素に適用する変換関数。A transform function to apply to each element.

戻り値

Single

射影された値の合計。The sum of the projected values.

例外

source または selectornull です。source or selector is null.

次のコード例は、を使用し Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) て、シーケンスの射影された値を合計する方法を示しています。The following code example demonstrates how to use Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) to sum the projected values of a sequence.

注意

このコード例で使用するオーバーロードされたメソッドのオーバーロードは、このトピックで説明する特定のオーバーロードとは異なります。This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. コード例をこのトピックに適用するには、selector 関数の本体を変更します。To extend the example to this topic, change the body of the selector function.

class Package
{
    public string Company { get; set; }
    public double Weight { get; set; }
}

public static void SumEx1()
{
    List<Package> packages =
        new List<Package>
            { new Package { Company = "Coho Vineyard", Weight = 25.2 },
              new Package { Company = "Lucerne Publishing", Weight = 18.7 },
              new Package { Company = "Wingtip Toys", Weight = 6.0 },
              new Package { Company = "Adventure Works", Weight = 33.8 } };

    double totalWeight = packages.Sum(pkg => pkg.Weight);

    Console.WriteLine("The total weight of the packages is: {0}", totalWeight);
}

/*
 This code produces the following output:

 The total weight of the packages is: 83.7
*/
Structure Package
    Public Company As String
    Public Weight As Double
End Structure

Sub SumEx1()
    ' Create a list of Package values.
    Dim packages As New List(Of Package)(New Package() _
     {New Package With {.Company = "Coho Vineyard", .Weight = 25.2},
      New Package With {.Company = "Lucerne Publishing", .Weight = 18.7},
      New Package With {.Company = "Wingtip Toys", .Weight = 6.0},
      New Package With {.Company = "Adventure Works", .Weight = 33.8}})

    ' Sum the values from each item's Weight property.
    Dim totalWeight As Double = packages.Sum(Function(pkg) _
                                             pkg.Weight)

    ' Display the result.
    Console.WriteLine($"The total weight of the packages is: {totalWeight}")
End Sub

' This code produces the following output:
'
' The total weight of the packages is: 83.7

注釈

Sum<TSource>(IEnumerable<TSource>, Func<TSource,Single>) 要素が含まれていない場合、メソッドは0を返し source ます。The Sum<TSource>(IEnumerable<TSource>, Func<TSource,Single>) method returns zero if source contains no elements.

このメソッドは、 selector のメンバーを数値型に射影する関数 () を指定した場合に、任意の値のシーケンスに適用でき source Single ます。You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Single.

Visual Basic のクエリ式の構文では、 Aggregate Into Sum() 句はの呼び出しに変換 Sum します。In Visual Basic query expression syntax, an Aggregate Into Sum() clause translates to an invocation of Sum.

こちらもご覧ください

適用対象

Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Single>>)

入力シーケンスの各要素に対して変換関数を呼び出して取得する null 許容の Single 値のシーケンスの合計を計算します。Computes the sum of the sequence of nullable Single values that are obtained by invoking a transform function on each element of the input sequence.

public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
 static Nullable<float> Sum(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, Nullable<float>> ^ selector);
public static float? Sum<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,Nullable<float>> selector);
static member Sum : seq<'Source> * Func<'Source, Nullable<single>> -> Nullable<single>
<Extension()>
Public Function Sum(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Nullable(Of Single))) As Nullable(Of Single)

型パラメーター

TSource

source の要素の型。The type of the elements of source.

パラメーター

source
IEnumerable<TSource>

合計の計算に使用される値のシーケンス。A sequence of values that are used to calculate a sum.

selector
Func<TSource,Nullable<Single>>

各要素に適用する変換関数。A transform function to apply to each element.

戻り値

Nullable<Single>

射影された値の合計。The sum of the projected values.

例外

source または selectornull です。source or selector is null.

次のコード例は、を使用し Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) て、シーケンスの射影された値を合計する方法を示しています。The following code example demonstrates how to use Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) to sum the projected values of a sequence.

注意

このコード例で使用するオーバーロードされたメソッドのオーバーロードは、このトピックで説明する特定のオーバーロードとは異なります。This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. コード例をこのトピックに適用するには、selector 関数の本体を変更します。To extend the example to this topic, change the body of the selector function.

class Package
{
    public string Company { get; set; }
    public double Weight { get; set; }
}

public static void SumEx1()
{
    List<Package> packages =
        new List<Package>
            { new Package { Company = "Coho Vineyard", Weight = 25.2 },
              new Package { Company = "Lucerne Publishing", Weight = 18.7 },
              new Package { Company = "Wingtip Toys", Weight = 6.0 },
              new Package { Company = "Adventure Works", Weight = 33.8 } };

    double totalWeight = packages.Sum(pkg => pkg.Weight);

    Console.WriteLine("The total weight of the packages is: {0}", totalWeight);
}

/*
 This code produces the following output:

 The total weight of the packages is: 83.7
*/
Structure Package
    Public Company As String
    Public Weight As Double
End Structure

Sub SumEx1()
    ' Create a list of Package values.
    Dim packages As New List(Of Package)(New Package() _
     {New Package With {.Company = "Coho Vineyard", .Weight = 25.2},
      New Package With {.Company = "Lucerne Publishing", .Weight = 18.7},
      New Package With {.Company = "Wingtip Toys", .Weight = 6.0},
      New Package With {.Company = "Adventure Works", .Weight = 33.8}})

    ' Sum the values from each item's Weight property.
    Dim totalWeight As Double = packages.Sum(Function(pkg) _
                                             pkg.Weight)

    ' Display the result.
    Console.WriteLine($"The total weight of the packages is: {totalWeight}")
End Sub

' This code produces the following output:
'
' The total weight of the packages is: 83.7

注釈

に要素が含まれていない場合、このメソッドは0を返し source ます。This method returns zero if source contains no elements.

結果には、の値は含まれません nullThe result does not include values that are null.

関数 () を指定すると、このメソッドを任意の値のシーケンスに適用できます。この関数は、 selector のメンバーを source Nullable<Single> C# または Visual Basic で数値型に射影し Nullable(Of Single) ます。You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Nullable<Single> in C# or Nullable(Of Single) in Visual Basic.

Visual Basic のクエリ式の構文では、 Aggregate Into Sum() 句はの呼び出しに変換 Sum します。In Visual Basic query expression syntax, an Aggregate Into Sum() clause translates to an invocation of Sum.

こちらもご覧ください

適用対象

Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Int64>>)

入力シーケンスの各要素に対して変換関数を呼び出して取得する null 許容の Int64 値のシーケンスの合計を計算します。Computes the sum of the sequence of nullable Int64 values that are obtained by invoking a transform function on each element of the input sequence.

public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
 static Nullable<long> Sum(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, Nullable<long>> ^ selector);
public static long? Sum<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,Nullable<long>> selector);
static member Sum : seq<'Source> * Func<'Source, Nullable<int64>> -> Nullable<int64>
<Extension()>
Public Function Sum(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Nullable(Of Long))) As Nullable(Of Long)

型パラメーター

TSource

source の要素の型。The type of the elements of source.

パラメーター

source
IEnumerable<TSource>

合計の計算に使用される値のシーケンス。A sequence of values that are used to calculate a sum.

selector
Func<TSource,Nullable<Int64>>

各要素に適用する変換関数。A transform function to apply to each element.

戻り値

Nullable<Int64>

射影された値の合計。The sum of the projected values.

例外

source または selectornull です。source or selector is null.

合計が MaxValueを超えています。The sum is larger than MaxValue.

次のコード例は、を使用し Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) て、シーケンスの射影された値を合計する方法を示しています。The following code example demonstrates how to use Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) to sum the projected values of a sequence.

注意

このコード例で使用するオーバーロードされたメソッドのオーバーロードは、このトピックで説明する特定のオーバーロードとは異なります。This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. コード例をこのトピックに適用するには、selector 関数の本体を変更します。To extend the example to this topic, change the body of the selector function.

class Package
{
    public string Company { get; set; }
    public double Weight { get; set; }
}

public static void SumEx1()
{
    List<Package> packages =
        new List<Package>
            { new Package { Company = "Coho Vineyard", Weight = 25.2 },
              new Package { Company = "Lucerne Publishing", Weight = 18.7 },
              new Package { Company = "Wingtip Toys", Weight = 6.0 },
              new Package { Company = "Adventure Works", Weight = 33.8 } };

    double totalWeight = packages.Sum(pkg => pkg.Weight);

    Console.WriteLine("The total weight of the packages is: {0}", totalWeight);
}

/*
 This code produces the following output:

 The total weight of the packages is: 83.7
*/
Structure Package
    Public Company As String
    Public Weight As Double
End Structure

Sub SumEx1()
    ' Create a list of Package values.
    Dim packages As New List(Of Package)(New Package() _
     {New Package With {.Company = "Coho Vineyard", .Weight = 25.2},
      New Package With {.Company = "Lucerne Publishing", .Weight = 18.7},
      New Package With {.Company = "Wingtip Toys", .Weight = 6.0},
      New Package With {.Company = "Adventure Works", .Weight = 33.8}})

    ' Sum the values from each item's Weight property.
    Dim totalWeight As Double = packages.Sum(Function(pkg) _
                                             pkg.Weight)

    ' Display the result.
    Console.WriteLine($"The total weight of the packages is: {totalWeight}")
End Sub

' This code produces the following output:
'
' The total weight of the packages is: 83.7

注釈

に要素が含まれていない場合、このメソッドは0を返し source ます。This method returns zero if source contains no elements.

結果には、の値は含まれません nullThe result does not include values that are null.

関数 () を指定すると、このメソッドを任意の値のシーケンスに適用できます。この関数は、 selector のメンバーを数値型に射影します。 source 具体的には、 Nullable<Int64> C# または Nullable(Of Int64) で Visual BasicYou can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Nullable<Int64> in C# or Nullable(Of Int64) in Visual Basic

Visual Basic のクエリ式の構文では、 Aggregate Into Sum() 句はの呼び出しに変換 Sum します。In Visual Basic query expression syntax, an Aggregate Into Sum() clause translates to an invocation of Sum.

こちらもご覧ください

適用対象

Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Int32>>)

入力シーケンスの各要素に対して変換関数を呼び出して取得する null 許容の Int32 値のシーケンスの合計を計算します。Computes the sum of the sequence of nullable Int32 values that are obtained by invoking a transform function on each element of the input sequence.

public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
 static Nullable<int> Sum(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, Nullable<int>> ^ selector);
public static int? Sum<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,Nullable<int>> selector);
static member Sum : seq<'Source> * Func<'Source, Nullable<int>> -> Nullable<int>
<Extension()>
Public Function Sum(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Nullable(Of Integer))) As Nullable(Of Integer)

型パラメーター

TSource

source の要素の型。The type of the elements of source.

パラメーター

source
IEnumerable<TSource>

合計の計算に使用される値のシーケンス。A sequence of values that are used to calculate a sum.

selector
Func<TSource,Nullable<Int32>>

各要素に適用する変換関数。A transform function to apply to each element.

戻り値

Nullable<Int32>

射影された値の合計。The sum of the projected values.

例外

source または selectornull です。source or selector is null.

合計が MaxValueを超えています。The sum is larger than MaxValue.

次のコード例は、を使用し Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) て、シーケンスの射影された値を合計する方法を示しています。The following code example demonstrates how to use Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) to sum the projected values of a sequence.

注意

このコード例で使用するオーバーロードされたメソッドのオーバーロードは、このトピックで説明する特定のオーバーロードとは異なります。This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. コード例をこのトピックに適用するには、selector 関数の本体を変更します。To extend the example to this topic, change the body of the selector function.

class Package
{
    public string Company { get; set; }
    public double Weight { get; set; }
}

public static void SumEx1()
{
    List<Package> packages =
        new List<Package>
            { new Package { Company = "Coho Vineyard", Weight = 25.2 },
              new Package { Company = "Lucerne Publishing", Weight = 18.7 },
              new Package { Company = "Wingtip Toys", Weight = 6.0 },
              new Package { Company = "Adventure Works", Weight = 33.8 } };

    double totalWeight = packages.Sum(pkg => pkg.Weight);

    Console.WriteLine("The total weight of the packages is: {0}", totalWeight);
}

/*
 This code produces the following output:

 The total weight of the packages is: 83.7
*/
Structure Package
    Public Company As String
    Public Weight As Double
End Structure

Sub SumEx1()
    ' Create a list of Package values.
    Dim packages As New List(Of Package)(New Package() _
     {New Package With {.Company = "Coho Vineyard", .Weight = 25.2},
      New Package With {.Company = "Lucerne Publishing", .Weight = 18.7},
      New Package With {.Company = "Wingtip Toys", .Weight = 6.0},
      New Package With {.Company = "Adventure Works", .Weight = 33.8}})

    ' Sum the values from each item's Weight property.
    Dim totalWeight As Double = packages.Sum(Function(pkg) _
                                             pkg.Weight)

    ' Display the result.
    Console.WriteLine($"The total weight of the packages is: {totalWeight}")
End Sub

' This code produces the following output:
'
' The total weight of the packages is: 83.7

注釈

に要素が含まれていない場合、このメソッドは0を返し source ます。This method returns zero if source contains no elements.

結果には、の値は含まれません nullThe result does not include values that are null.

関数 () を指定すると、このメソッドを任意の値のシーケンスに適用できます。この関数は、 selector のメンバーを source Nullable<Int32> C# または Visual Basic で数値型に射影し Nullable(Of Int32) ます。You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Nullable<Int32> in C# or Nullable(Of Int32) in Visual Basic.

Visual Basic のクエリ式の構文では、 Aggregate Into Sum() 句はの呼び出しに変換 Sum します。In Visual Basic query expression syntax, an Aggregate Into Sum() clause translates to an invocation of Sum.

こちらもご覧ください

適用対象

Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Double>>)

入力シーケンスの各要素に対して変換関数を呼び出して取得する null 許容の Double 値のシーケンスの合計を計算します。Computes the sum of the sequence of nullable Double values that are obtained by invoking a transform function on each element of the input sequence.

public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
 static Nullable<double> Sum(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, Nullable<double>> ^ selector);
public static double? Sum<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,Nullable<double>> selector);
static member Sum : seq<'Source> * Func<'Source, Nullable<double>> -> Nullable<double>
<Extension()>
Public Function Sum(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Nullable(Of Double))) As Nullable(Of Double)

型パラメーター

TSource

source の要素の型。The type of the elements of source.

パラメーター

source
IEnumerable<TSource>

合計の計算に使用される値のシーケンス。A sequence of values that are used to calculate a sum.

selector
Func<TSource,Nullable<Double>>

各要素に適用する変換関数。A transform function to apply to each element.

戻り値

Nullable<Double>

射影された値の合計。The sum of the projected values.

例外

source または selectornull です。source or selector is null.

次のコード例は、を使用し Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) て、シーケンスの射影された値を合計する方法を示しています。The following code example demonstrates how to use Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) to sum the projected values of a sequence.

注意

このコード例で使用するオーバーロードされたメソッドのオーバーロードは、このトピックで説明する特定のオーバーロードとは異なります。This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. コード例をこのトピックに適用するには、selector 関数の本体を変更します。To extend the example to this topic, change the body of the selector function.

class Package
{
    public string Company { get; set; }
    public double Weight { get; set; }
}

public static void SumEx1()
{
    List<Package> packages =
        new List<Package>
            { new Package { Company = "Coho Vineyard", Weight = 25.2 },
              new Package { Company = "Lucerne Publishing", Weight = 18.7 },
              new Package { Company = "Wingtip Toys", Weight = 6.0 },
              new Package { Company = "Adventure Works", Weight = 33.8 } };

    double totalWeight = packages.Sum(pkg => pkg.Weight);

    Console.WriteLine("The total weight of the packages is: {0}", totalWeight);
}

/*
 This code produces the following output:

 The total weight of the packages is: 83.7
*/
Structure Package
    Public Company As String
    Public Weight As Double
End Structure

Sub SumEx1()
    ' Create a list of Package values.
    Dim packages As New List(Of Package)(New Package() _
     {New Package With {.Company = "Coho Vineyard", .Weight = 25.2},
      New Package With {.Company = "Lucerne Publishing", .Weight = 18.7},
      New Package With {.Company = "Wingtip Toys", .Weight = 6.0},
      New Package With {.Company = "Adventure Works", .Weight = 33.8}})

    ' Sum the values from each item's Weight property.
    Dim totalWeight As Double = packages.Sum(Function(pkg) _
                                             pkg.Weight)

    ' Display the result.
    Console.WriteLine($"The total weight of the packages is: {totalWeight}")
End Sub

' This code produces the following output:
'
' The total weight of the packages is: 83.7

注釈

に要素が含まれていない場合、このメソッドは0を返し source ます。This method returns zero if source contains no elements.

結果には、の値は含まれません nullThe result does not include values that are null.

関数 () を指定すると、このメソッドを任意の値のシーケンスに適用できます。この関数は、 selector のメンバーを source Nullable<Double> C# または Visual Basic で数値型に射影し Nullable(Of Double) ます。You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Nullable<Double> in C# or Nullable(Of Double) in Visual Basic.

Visual Basic のクエリ式の構文では、 Aggregate Into Sum() 句はの呼び出しに変換 Sum します。In Visual Basic query expression syntax, an Aggregate Into Sum() clause translates to an invocation of Sum.

こちらもご覧ください

適用対象

Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Decimal>>)

入力シーケンスの各要素に対して変換関数を呼び出して取得する null 許容の Decimal 値のシーケンスの合計を計算します。Computes the sum of the sequence of nullable Decimal values that are obtained by invoking a transform function on each element of the input sequence.

public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
 static Nullable<System::Decimal> Sum(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, Nullable<System::Decimal>> ^ selector);
public static decimal? Sum<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,Nullable<decimal>> selector);
static member Sum : seq<'Source> * Func<'Source, Nullable<decimal>> -> Nullable<decimal>
<Extension()>
Public Function Sum(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Nullable(Of Decimal))) As Nullable(Of Decimal)

型パラメーター

TSource

source の要素の型。The type of the elements of source.

パラメーター

source
IEnumerable<TSource>

合計の計算に使用される値のシーケンス。A sequence of values that are used to calculate a sum.

selector
Func<TSource,Nullable<Decimal>>

各要素に適用する変換関数。A transform function to apply to each element.

戻り値

Nullable<Decimal>

射影された値の合計。The sum of the projected values.

例外

source または selectornull です。source or selector is null.

合計が MaxValueを超えています。The sum is larger than MaxValue.

次のコード例は、を使用し Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) て、シーケンスの射影された値を合計する方法を示しています。The following code example demonstrates how to use Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) to sum the projected values of a sequence.

注意

このコード例で使用するオーバーロードされたメソッドのオーバーロードは、このトピックで説明する特定のオーバーロードとは異なります。This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. コード例をこのトピックに適用するには、selector 関数の本体を変更します。To extend the example to this topic, change the body of the selector function.

class Package
{
    public string Company { get; set; }
    public double Weight { get; set; }
}

public static void SumEx1()
{
    List<Package> packages =
        new List<Package>
            { new Package { Company = "Coho Vineyard", Weight = 25.2 },
              new Package { Company = "Lucerne Publishing", Weight = 18.7 },
              new Package { Company = "Wingtip Toys", Weight = 6.0 },
              new Package { Company = "Adventure Works", Weight = 33.8 } };

    double totalWeight = packages.Sum(pkg => pkg.Weight);

    Console.WriteLine("The total weight of the packages is: {0}", totalWeight);
}

/*
 This code produces the following output:

 The total weight of the packages is: 83.7
*/
Structure Package
    Public Company As String
    Public Weight As Double
End Structure

Sub SumEx1()
    ' Create a list of Package values.
    Dim packages As New List(Of Package)(New Package() _
     {New Package With {.Company = "Coho Vineyard", .Weight = 25.2},
      New Package With {.Company = "Lucerne Publishing", .Weight = 18.7},
      New Package With {.Company = "Wingtip Toys", .Weight = 6.0},
      New Package With {.Company = "Adventure Works", .Weight = 33.8}})

    ' Sum the values from each item's Weight property.
    Dim totalWeight As Double = packages.Sum(Function(pkg) _
                                             pkg.Weight)

    ' Display the result.
    Console.WriteLine($"The total weight of the packages is: {totalWeight}")
End Sub

' This code produces the following output:
'
' The total weight of the packages is: 83.7

注釈

に要素が含まれていない場合、このメソッドは0を返し source ます。This method returns zero if source contains no elements.

結果には、の値は含まれません nullThe result does not included values that are null.

関数 () を指定すると、このメソッドを任意の値のシーケンスに適用できます。この関数は、 selector のメンバーを source Nullable<Decimal> C# または Visual Basic で数値型に射影し Nullable(Of Decimal) ます。You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Nullable<Decimal> in C# or Nullable(Of Decimal) in Visual Basic.

Visual Basic のクエリ式の構文では、 Aggregate Into Sum() 句はの呼び出しに変換 Sum します。In Visual Basic query expression syntax, an Aggregate Into Sum() clause translates to an invocation of Sum.

こちらもご覧ください

適用対象

Sum<TSource>(IEnumerable<TSource>, Func<TSource,Int64>)

入力シーケンスの各要素に対して変換関数を呼び出して取得する Int64 値のシーケンスの合計を計算します。Computes the sum of the sequence of Int64 values that are obtained by invoking a transform function on each element of the input sequence.

public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
 static long Sum(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, long> ^ selector);
public static long Sum<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,long> selector);
static member Sum : seq<'Source> * Func<'Source, int64> -> int64
<Extension()>
Public Function Sum(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Long)) As Long

型パラメーター

TSource

source の要素の型。The type of the elements of source.

パラメーター

source
IEnumerable<TSource>

合計の計算に使用される値のシーケンス。A sequence of values that are used to calculate a sum.

selector
Func<TSource,Int64>

各要素に適用する変換関数。A transform function to apply to each element.

戻り値

Int64

射影された値の合計。The sum of the projected values.

例外

source または selectornull です。source or selector is null.

合計が MaxValueを超えています。The sum is larger than MaxValue.

次のコード例は、を使用し Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) て、シーケンスの射影された値を合計する方法を示しています。The following code example demonstrates how to use Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) to sum the projected values of a sequence.

注意

このコード例で使用するオーバーロードされたメソッドのオーバーロードは、このトピックで説明する特定のオーバーロードとは異なります。This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. コード例をこのトピックに適用するには、selector 関数の本体を変更します。To extend the example to this topic, change the body of the selector function.

class Package
{
    public string Company { get; set; }
    public double Weight { get; set; }
}

public static void SumEx1()
{
    List<Package> packages =
        new List<Package>
            { new Package { Company = "Coho Vineyard", Weight = 25.2 },
              new Package { Company = "Lucerne Publishing", Weight = 18.7 },
              new Package { Company = "Wingtip Toys", Weight = 6.0 },
              new Package { Company = "Adventure Works", Weight = 33.8 } };

    double totalWeight = packages.Sum(pkg => pkg.Weight);

    Console.WriteLine("The total weight of the packages is: {0}", totalWeight);
}

/*
 This code produces the following output:

 The total weight of the packages is: 83.7
*/
Structure Package
    Public Company As String
    Public Weight As Double
End Structure

Sub SumEx1()
    ' Create a list of Package values.
    Dim packages As New List(Of Package)(New Package() _
     {New Package With {.Company = "Coho Vineyard", .Weight = 25.2},
      New Package With {.Company = "Lucerne Publishing", .Weight = 18.7},
      New Package With {.Company = "Wingtip Toys", .Weight = 6.0},
      New Package With {.Company = "Adventure Works", .Weight = 33.8}})

    ' Sum the values from each item's Weight property.
    Dim totalWeight As Double = packages.Sum(Function(pkg) _
                                             pkg.Weight)

    ' Display the result.
    Console.WriteLine($"The total weight of the packages is: {totalWeight}")
End Sub

' This code produces the following output:
'
' The total weight of the packages is: 83.7

注釈

に要素が含まれていない場合、このメソッドは0を返し source ます。This method returns zero if source contains no elements.

このメソッドは、 selector のメンバーを数値型に射影する関数 () を指定した場合に、任意の値のシーケンスに適用でき source Int64 ます。You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Int64.

Visual Basic のクエリ式の構文では、 Aggregate Into Sum() 句はの呼び出しに変換 Sum します。In Visual Basic query expression syntax, an Aggregate Into Sum() clause translates to an invocation of Sum.

こちらもご覧ください

適用対象

Sum<TSource>(IEnumerable<TSource>, Func<TSource,Int32>)

入力シーケンスの各要素に対して変換関数を呼び出して取得する Int32 値のシーケンスの合計を計算します。Computes the sum of the sequence of Int32 values that are obtained by invoking a transform function on each element of the input sequence.

public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
 static int Sum(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, int> ^ selector);
public static int Sum<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,int> selector);
static member Sum : seq<'Source> * Func<'Source, int> -> int
<Extension()>
Public Function Sum(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Integer)) As Integer

型パラメーター

TSource

source の要素の型。The type of the elements of source.

パラメーター

source
IEnumerable<TSource>

合計の計算に使用される値のシーケンス。A sequence of values that are used to calculate a sum.

selector
Func<TSource,Int32>

各要素に適用する変換関数。A transform function to apply to each element.

戻り値

Int32

射影された値の合計。The sum of the projected values.

例外

source または selectornull です。source or selector is null.

合計が MaxValueを超えています。The sum is larger than MaxValue.

次のコード例は、を使用し Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) て、シーケンスの射影された値を合計する方法を示しています。The following code example demonstrates how to use Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) to sum the projected values of a sequence.

注意

このコード例で使用するオーバーロードされたメソッドのオーバーロードは、このトピックで説明する特定のオーバーロードとは異なります。This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. コード例をこのトピックに適用するには、selector 関数の本体を変更します。To extend the example to this topic, change the body of the selector function.

class Package
{
    public string Company { get; set; }
    public double Weight { get; set; }
}

public static void SumEx1()
{
    List<Package> packages =
        new List<Package>
            { new Package { Company = "Coho Vineyard", Weight = 25.2 },
              new Package { Company = "Lucerne Publishing", Weight = 18.7 },
              new Package { Company = "Wingtip Toys", Weight = 6.0 },
              new Package { Company = "Adventure Works", Weight = 33.8 } };

    double totalWeight = packages.Sum(pkg => pkg.Weight);

    Console.WriteLine("The total weight of the packages is: {0}", totalWeight);
}

/*
 This code produces the following output:

 The total weight of the packages is: 83.7
*/
Structure Package
    Public Company As String
    Public Weight As Double
End Structure

Sub SumEx1()
    ' Create a list of Package values.
    Dim packages As New List(Of Package)(New Package() _
     {New Package With {.Company = "Coho Vineyard", .Weight = 25.2},
      New Package With {.Company = "Lucerne Publishing", .Weight = 18.7},
      New Package With {.Company = "Wingtip Toys", .Weight = 6.0},
      New Package With {.Company = "Adventure Works", .Weight = 33.8}})

    ' Sum the values from each item's Weight property.
    Dim totalWeight As Double = packages.Sum(Function(pkg) _
                                             pkg.Weight)

    ' Display the result.
    Console.WriteLine($"The total weight of the packages is: {totalWeight}")
End Sub

' This code produces the following output:
'
' The total weight of the packages is: 83.7

注釈

に要素が含まれていない場合、このメソッドは0を返し source ます。This method returns zero if source contains no elements.

このメソッドは、 selector のメンバーを数値型に射影する関数 () を指定した場合に、任意の値のシーケンスに適用でき source Int32 ます。You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Int32.

Visual Basic のクエリ式の構文では、 Aggregate Into Sum() 句はの呼び出しに変換 Sum します。In Visual Basic query expression syntax, an Aggregate Into Sum() clause translates to an invocation of Sum.

こちらもご覧ください

適用対象

Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>)

入力シーケンスの各要素に対して変換関数を呼び出して取得する Double 値のシーケンスの合計を計算します。Computes the sum of the sequence of Double values that are obtained by invoking a transform function on each element of the input sequence.

public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
 static double Sum(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, double> ^ selector);
public static double Sum<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,double> selector);
static member Sum : seq<'Source> * Func<'Source, double> -> double
<Extension()>
Public Function Sum(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Double)) As Double

型パラメーター

TSource

source の要素の型。The type of the elements of source.

パラメーター

source
IEnumerable<TSource>

合計の計算に使用される値のシーケンス。A sequence of values that are used to calculate a sum.

selector
Func<TSource,Double>

各要素に適用する変換関数。A transform function to apply to each element.

戻り値

Double

射影された値の合計。The sum of the projected values.

例外

source または selectornull です。source or selector is null.

次のコード例は、を使用し Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) て、シーケンスの射影された値を合計する方法を示しています。The following code example demonstrates how to use Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) to sum the projected values of a sequence.

class Package
{
    public string Company { get; set; }
    public double Weight { get; set; }
}

public static void SumEx1()
{
    List<Package> packages =
        new List<Package>
            { new Package { Company = "Coho Vineyard", Weight = 25.2 },
              new Package { Company = "Lucerne Publishing", Weight = 18.7 },
              new Package { Company = "Wingtip Toys", Weight = 6.0 },
              new Package { Company = "Adventure Works", Weight = 33.8 } };

    double totalWeight = packages.Sum(pkg => pkg.Weight);

    Console.WriteLine("The total weight of the packages is: {0}", totalWeight);
}

/*
 This code produces the following output:

 The total weight of the packages is: 83.7
*/
Structure Package
    Public Company As String
    Public Weight As Double
End Structure

Sub SumEx1()
    ' Create a list of Package values.
    Dim packages As New List(Of Package)(New Package() _
     {New Package With {.Company = "Coho Vineyard", .Weight = 25.2},
      New Package With {.Company = "Lucerne Publishing", .Weight = 18.7},
      New Package With {.Company = "Wingtip Toys", .Weight = 6.0},
      New Package With {.Company = "Adventure Works", .Weight = 33.8}})

    ' Sum the values from each item's Weight property.
    Dim totalWeight As Double = packages.Sum(Function(pkg) _
                                             pkg.Weight)

    ' Display the result.
    Console.WriteLine($"The total weight of the packages is: {totalWeight}")
End Sub

' This code produces the following output:
'
' The total weight of the packages is: 83.7

注釈

に要素が含まれていない場合、このメソッドは0を返し source ます。This method returns zero if source contains no elements.

このメソッドは、 selector のメンバーを数値型に射影する関数 () を指定した場合に、任意の値のシーケンスに適用でき source Double ます。You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Double.

Visual Basic のクエリ式の構文では、 Aggregate Into Sum() 句はの呼び出しに変換 Sum します。In Visual Basic query expression syntax, an Aggregate Into Sum() clause translates to an invocation of Sum.

こちらもご覧ください

適用対象

Sum<TSource>(IEnumerable<TSource>, Func<TSource,Decimal>)

入力シーケンスの各要素に対して変換関数を呼び出して取得する Decimal 値のシーケンスの合計を計算します。Computes the sum of the sequence of Decimal values that are obtained by invoking a transform function on each element of the input sequence.

public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
 static System::Decimal Sum(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, System::Decimal> ^ selector);
public static decimal Sum<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,decimal> selector);
static member Sum : seq<'Source> * Func<'Source, decimal> -> decimal
<Extension()>
Public Function Sum(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Decimal)) As Decimal

型パラメーター

TSource

source の要素の型。The type of the elements of source.

パラメーター

source
IEnumerable<TSource>

合計の計算に使用される値のシーケンス。A sequence of values that are used to calculate a sum.

selector
Func<TSource,Decimal>

各要素に適用する変換関数。A transform function to apply to each element.

戻り値

Decimal

射影された値の合計。The sum of the projected values.

例外

source または selectornull です。source or selector is null.

合計が MaxValueを超えています。The sum is larger than MaxValue.

次のコード例は、を使用し Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) て、シーケンスの射影された値を合計する方法を示しています。The following code example demonstrates how to use Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) to sum the projected values of a sequence.

注意

このコード例で使用するオーバーロードされたメソッドのオーバーロードは、このトピックで説明する特定のオーバーロードとは異なります。This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. コード例をこのトピックに適用するには、selector 関数の本体を変更します。To extend the example to this topic, change the body of the selector function.

class Package
{
    public string Company { get; set; }
    public double Weight { get; set; }
}

public static void SumEx1()
{
    List<Package> packages =
        new List<Package>
            { new Package { Company = "Coho Vineyard", Weight = 25.2 },
              new Package { Company = "Lucerne Publishing", Weight = 18.7 },
              new Package { Company = "Wingtip Toys", Weight = 6.0 },
              new Package { Company = "Adventure Works", Weight = 33.8 } };

    double totalWeight = packages.Sum(pkg => pkg.Weight);

    Console.WriteLine("The total weight of the packages is: {0}", totalWeight);
}

/*
 This code produces the following output:

 The total weight of the packages is: 83.7
*/
Structure Package
    Public Company As String
    Public Weight As Double
End Structure

Sub SumEx1()
    ' Create a list of Package values.
    Dim packages As New List(Of Package)(New Package() _
     {New Package With {.Company = "Coho Vineyard", .Weight = 25.2},
      New Package With {.Company = "Lucerne Publishing", .Weight = 18.7},
      New Package With {.Company = "Wingtip Toys", .Weight = 6.0},
      New Package With {.Company = "Adventure Works", .Weight = 33.8}})

    ' Sum the values from each item's Weight property.
    Dim totalWeight As Double = packages.Sum(Function(pkg) _
                                             pkg.Weight)

    ' Display the result.
    Console.WriteLine($"The total weight of the packages is: {totalWeight}")
End Sub

' This code produces the following output:
'
' The total weight of the packages is: 83.7

注釈

に要素が含まれていない場合、このメソッドは0を返し source ます。This method returns zero if source contains no elements.

このメソッドは、 selector のメンバーを数値型に射影する関数 () を指定した場合に、任意の値のシーケンスに適用でき source Decimal ます。You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Decimal.

Visual Basic のクエリ式の構文では、 Aggregate Into Sum() 句はの呼び出しに変換 Sum します。In Visual Basic query expression syntax, an Aggregate Into Sum() clause translates to an invocation of Sum.

こちらもご覧ください

適用対象