Enumerable.Min 메서드

public:
[System::Runtime::CompilerServices::Extension]
 static Nullable<long> Min(System::Collections::Generic::IEnumerable<Nullable<long>> ^ source);

public static long? Min (this System.Collections.Generic.IEnumerable<Nullable<long>> source);

static member Min : seq<Nullable<int64>> -> Nullable<int64>

<Extension()>
Public Function Min (source As IEnumerable(Of Nullable(Of Long))) As Nullable(Of Long)

매개 변수

반환

Nullable<Int64>

시퀀스의 최솟값에 해당하는 Nullable<Int64> 형식(C#) 또는 Nullable(Of Int64) 형식(Visual Basic의 경우) 값입니다.A value of type Nullable<Int64> in C# or Nullable(Of Int64) in Visual Basic that corresponds to the minimum value in the sequence.

예외

설명

Min(IEnumerable<Nullable<Int64>>)메서드는의 구현을 사용 하 여 Int64 IComparable<T> 값을 비교 합니다.The Min(IEnumerable<Nullable<Int64>>) method uses the Int64 implementation of IComparable<T> to compare values.

소스 시퀀스가 비어 있거나 값만 포함 하는 경우 null 이 함수는를 반환 null 합니다.If the source sequence is empty or contains only values that are null, this function returns null.

Visual Basic 쿼리 식 구문에서 절은 Aggregate Into Min() 의 호출로 변환 Min 됩니다.In Visual Basic query expression syntax, an Aggregate Into Min() clause translates to an invocation of Min.

추가 정보

• Aggregate 절 (Visual Basic)Aggregate Clause (Visual Basic)

public:
[System::Runtime::CompilerServices::Extension]
 static Nullable<int> Min(System::Collections::Generic::IEnumerable<Nullable<int>> ^ source);

public static int? Min (this System.Collections.Generic.IEnumerable<Nullable<int>> source);

static member Min : seq<Nullable<int>> -> Nullable<int>

<Extension()>
Public Function Min (source As IEnumerable(Of Nullable(Of Integer))) As Nullable(Of Integer)

매개 변수

반환

Nullable<Int32>

시퀀스의 최솟값에 해당하는 Nullable<Int32> 형식(C#) 또는 Nullable(Of Int32) 형식(Visual Basic의 경우) 값입니다.A value of type Nullable<Int32> in C# or Nullable(Of Int32) in Visual Basic that corresponds to the minimum value in the sequence.

예외

예제

다음 코드 예제에서는를 사용 하 여 시퀀스의 최소값을 확인 하는 방법을 보여 줍니다 Min(IEnumerable<Nullable<Int32>>) .The following code example demonstrates how to use Min(IEnumerable<Nullable<Int32>>) to determine the minimum value in a sequence.

int?[] grades = { 78, 92, null, 99, 37, 81 };

int? min = grades.Min();

Console.WriteLine("The lowest grade is {0}.", min);

/*
 This code produces the following output:

 The lowest grade is 37.
*/

Dim grades() As Nullable(Of Integer) = {78, 92, Nothing, 99, 37, 81}
Dim min As Nullable(Of Integer) = grades.Min()

' Display the output.
Console.WriteLine($"The lowest grade is {min}")

' This code produces the following output:
'
' The lowest grade is 37

설명

Min(IEnumerable<Nullable<Int32>>)메서드는의 구현을 사용 하 여 Int32 IComparable<T> 값을 비교 합니다.The Min(IEnumerable<Nullable<Int32>>) method uses the Int32 implementation of IComparable<T> to compare values.

소스 시퀀스가 비어 있거나 값만 포함 하는 경우 null 이 함수는를 반환 null 합니다.If the source sequence is empty or contains only values that are null, this function returns null.

Visual Basic 쿼리 식 구문에서 절은 Aggregate Into Min() 의 호출로 변환 Min 됩니다.In Visual Basic query expression syntax, an Aggregate Into Min() clause translates to an invocation of Min.

추가 정보

• Aggregate 절 (Visual Basic)Aggregate Clause (Visual Basic)

public:
[System::Runtime::CompilerServices::Extension]
 static float Min(System::Collections::Generic::IEnumerable<float> ^ source);

public static float Min (this System.Collections.Generic.IEnumerable<float> source);

static member Min : seq<single> -> single

<Extension()>
Public Function Min (source As IEnumerable(Of Single)) As Single

매개 변수

반환

Single

시퀀스의 최소값입니다.The minimum value in the sequence.

예외

설명

Min(IEnumerable<Single>)메서드는의 구현을 사용 하 여 Single IComparable<T> 값을 비교 합니다.The Min(IEnumerable<Single>) method uses the Single implementation of IComparable<T> to compare values.

Visual Basic 쿼리 식 구문에서 절은 Aggregate Into Min() 의 호출로 변환 Min 됩니다.In Visual Basic query expression syntax, an Aggregate Into Min() clause translates to an invocation of Min.

추가 정보

• Aggregate 절 (Visual Basic)Aggregate Clause (Visual Basic)

public:
[System::Runtime::CompilerServices::Extension]
 static Nullable<float> Min(System::Collections::Generic::IEnumerable<Nullable<float>> ^ source);

public static float? Min (this System.Collections.Generic.IEnumerable<Nullable<float>> source);

static member Min : seq<Nullable<single>> -> Nullable<single>

<Extension()>
Public Function Min (source As IEnumerable(Of Nullable(Of Single))) As Nullable(Of Single)

매개 변수

반환

Nullable<Single>

시퀀스의 최솟값에 해당하는 Nullable<Single> 형식(C#) 또는 Nullable(Of Single) 형식(Visual Basic의 경우) 값입니다.A value of type Nullable<Single> in C# or Nullable(Of Single) in Visual Basic that corresponds to the minimum value in the sequence.

예외

설명

Min(IEnumerable<Nullable<Single>>)메서드는의 구현을 사용 하 여 Single IComparable<T> 값을 비교 합니다.The Min(IEnumerable<Nullable<Single>>) method uses the Single implementation of IComparable<T> to compare values.

소스 시퀀스가 비어 있거나 값만 포함 하는 경우 null 이 함수는를 반환 null 합니다.If the source sequence is empty or contains only values that are null, this function returns null.

Visual Basic 쿼리 식 구문에서 절은 Aggregate Into Min() 의 호출로 변환 Min 됩니다.In Visual Basic query expression syntax, an Aggregate Into Min() clause translates to an invocation of Min.

추가 정보

• Aggregate 절 (Visual Basic)Aggregate Clause (Visual Basic)

public:
[System::Runtime::CompilerServices::Extension]
 static Nullable<double> Min(System::Collections::Generic::IEnumerable<Nullable<double>> ^ source);

public static double? Min (this System.Collections.Generic.IEnumerable<Nullable<double>> source);

static member Min : seq<Nullable<double>> -> Nullable<double>

<Extension()>
Public Function Min (source As IEnumerable(Of Nullable(Of Double))) As Nullable(Of Double)

매개 변수

반환

Nullable<Double>

시퀀스의 최솟값에 해당하는 Nullable<Double> 형식(C#) 또는 Nullable(Of Double) 형식(Visual Basic의 경우) 값입니다.A value of type Nullable<Double> in C# or Nullable(Of Double) in Visual Basic that corresponds to the minimum value in the sequence.

예외

설명

Min(IEnumerable<Nullable<Double>>)메서드는의 구현을 사용 하 여 Double IComparable<T> 값을 비교 합니다.The Min(IEnumerable<Nullable<Double>>) method uses the Double implementation of IComparable<T> to compare values.

소스 시퀀스가 비어 있거나 값만 포함 하는 경우 null 이 함수는를 반환 null 합니다.If the source sequence is empty or contains only values that are null, this function returns null.

Visual Basic 쿼리 식 구문에서 절은 Aggregate Into Min() 의 호출로 변환 Min 됩니다.In Visual Basic query expression syntax, an Aggregate Into Min() clause translates to an invocation of Min.

추가 정보

• Aggregate 절 (Visual Basic)Aggregate Clause (Visual Basic)

public:
[System::Runtime::CompilerServices::Extension]
 static double Min(System::Collections::Generic::IEnumerable<double> ^ source);

public static double Min (this System.Collections.Generic.IEnumerable<double> source);

static member Min : seq<double> -> double

<Extension()>
Public Function Min (source As IEnumerable(Of Double)) As Double

매개 변수

반환

Double

시퀀스의 최소값입니다.The minimum value in the sequence.

예외

예제

다음 코드 예제에서는를 사용 하 여 시퀀스의 최소값을 확인 하는 방법을 보여 줍니다 Min(IEnumerable<Double>) .The following code example demonstrates how to use Min(IEnumerable<Double>) to determine the minimum value in a sequence.

double[] doubles = { 1.5E+104, 9E+103, -2E+103 };

double min = doubles.Min();

Console.WriteLine("The smallest number is {0}.", min);

/*
 This code produces the following output:

 The smallest number is -2E+103.
*/

' Create an array of double values.
Dim doubles() As Double = {1.5E+104, 9.0E+103, -2.0E+103}

' Determine the smallest number in the array.
Dim min As Double = doubles.Min()

' Display the result.
Console.WriteLine($"The smallest number is {min}")

' This code produces the following output:
'
' The smallest number is -2E+103

설명

Min(IEnumerable<Double>)메서드는의 구현을 사용 하 여 Double IComparable<T> 값을 비교 합니다.The Min(IEnumerable<Double>) method uses the Double implementation of IComparable<T> to compare values.

Visual Basic 쿼리 식 구문에서 절은 Aggregate Into Min() 의 호출로 변환 Min 됩니다.In Visual Basic query expression syntax, an Aggregate Into Min() clause translates to an invocation of Min.

추가 정보

• Aggregate 절 (Visual Basic)Aggregate Clause (Visual Basic)

public:
[System::Runtime::CompilerServices::Extension]
 static long Min(System::Collections::Generic::IEnumerable<long> ^ source);

public static long Min (this System.Collections.Generic.IEnumerable<long> source);

static member Min : seq<int64> -> int64

<Extension()>
Public Function Min (source As IEnumerable(Of Long)) As Long

매개 변수

반환

Int64

시퀀스의 최소값입니다.The minimum value in the sequence.

예외

설명

Min(IEnumerable<Int64>)메서드는의 구현을 사용 하 여 Int64 IComparable<T> 값을 비교 합니다.The Min(IEnumerable<Int64>) method uses the Int64 implementation of IComparable<T> to compare values.

Visual Basic 쿼리 식 구문에서 절은 Aggregate Into Min() 의 호출로 변환 Min 됩니다.In Visual Basic query expression syntax, an Aggregate Into Min() clause translates to an invocation of Min.

추가 정보

• Aggregate 절 (Visual Basic)Aggregate Clause (Visual Basic)

public:
[System::Runtime::CompilerServices::Extension]
 static int Min(System::Collections::Generic::IEnumerable<int> ^ source);

public static int Min (this System.Collections.Generic.IEnumerable<int> source);

static member Min : seq<int> -> int

<Extension()>
Public Function Min (source As IEnumerable(Of Integer)) As Integer

매개 변수

반환

Int32

시퀀스의 최소값입니다.The minimum value in the sequence.

예외

설명

Min(IEnumerable<Int32>)메서드는의 구현을 사용 하 여 Int32 IComparable<T> 값을 비교 합니다.The Min(IEnumerable<Int32>) method uses the Int32 implementation of IComparable<T> to compare values.

Visual Basic 쿼리 식 구문에서 절은 Aggregate Into Min() 의 호출로 변환 Min 됩니다.In Visual Basic query expression syntax, an Aggregate Into Min() clause translates to an invocation of Min.

추가 정보

• Aggregate 절 (Visual Basic)Aggregate Clause (Visual Basic)

public:
[System::Runtime::CompilerServices::Extension]
 static Nullable<System::Decimal> Min(System::Collections::Generic::IEnumerable<Nullable<System::Decimal>> ^ source);

public static decimal? Min (this System.Collections.Generic.IEnumerable<Nullable<decimal>> source);

static member Min : seq<Nullable<decimal>> -> Nullable<decimal>

<Extension()>
Public Function Min (source As IEnumerable(Of Nullable(Of Decimal))) As Nullable(Of Decimal)

매개 변수

반환

Nullable<Decimal>

시퀀스의 최솟값에 해당하는 Nullable<Decimal> 형식(C#) 또는 Nullable(Of Decimal) 형식(Visual Basic의 경우)의 값입니다.A value of type Nullable<Decimal> in C# or Nullable(Of Decimal) in Visual Basic that corresponds to the minimum value in the sequence.

예외

설명

Min(IEnumerable<Nullable<Decimal>>)메서드는의 구현을 사용 하 여 Decimal IComparable<T> 값을 비교 합니다.The Min(IEnumerable<Nullable<Decimal>>) method uses the Decimal implementation of IComparable<T> to compare values.

소스 시퀀스가 비어 있거나 값만 포함 하는 경우 null 이 함수는를 반환 null 합니다.If the source sequence is empty or contains only values that are null, this function returns null.

Visual Basic 쿼리 식 구문에서 절은 Aggregate Into Min() 의 호출로 변환 Min 됩니다.In Visual Basic query expression syntax, an Aggregate Into Min() clause translates to an invocation of Min.

추가 정보

• Aggregate 절 (Visual Basic)Aggregate Clause (Visual Basic)

public:
[System::Runtime::CompilerServices::Extension]
 static System::Decimal Min(System::Collections::Generic::IEnumerable<System::Decimal> ^ source);

public static decimal Min (this System.Collections.Generic.IEnumerable<decimal> source);

static member Min : seq<decimal> -> decimal

<Extension()>
Public Function Min (source As IEnumerable(Of Decimal)) As Decimal

매개 변수

반환

Decimal

시퀀스의 최소값입니다.The minimum value in the sequence.

예외

설명

Min(IEnumerable<Decimal>)메서드는의 구현을 사용 하 여 Decimal IComparable<T> 값을 비교 합니다.The Min(IEnumerable<Decimal>) method uses the Decimal implementation of IComparable<T> to compare values.

Visual Basic 쿼리 식 구문에서 절은 Aggregate Into Min() 의 호출로 변환 Min 됩니다.In Visual Basic query expression syntax, an Aggregate Into Min() clause translates to an invocation of Min.

추가 정보

• Aggregate 절 (Visual Basic)Aggregate Clause (Visual Basic)

public:
generic <typename TSource, typename TResult>
[System::Runtime::CompilerServices::Extension]
 static TResult Min(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, TResult> ^ selector);

public static TResult Min<TSource,TResult> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,TResult> selector);

public static TResult Min<TSource,TResult> (this System.Collections.Generic.IEnumerable<TSource>? source, Func<TSource,TResult>? selector);

static member Min : seq<'Source> * Func<'Source, 'Result> -> 'Result

<Extension()>
Public Function Min(Of TSource, TResult) (source As IEnumerable(Of TSource), selector As Func(Of TSource, TResult)) As TResult

형식 매개 변수

매개 변수

반환

TResult

시퀀스의 최소값입니다.The minimum value in the sequence.

예외

예제

다음 코드 예제에서는를 사용 하 여 Min<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) 프로젝션 된 값 시퀀스의 최소값을 확인 하는 방법을 보여 줍니다.The following code example demonstrates how to use Min<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) to determine the minimum value in a sequence of projected values.

class Pet
{
    public string Name { get; set; }
    public int Age { get; set; }
}

public static void MinEx4()
{
    Pet[] pets = { new Pet { Name="Barley", Age=8 },
                   new Pet { Name="Boots", Age=4 },
                   new Pet { Name="Whiskers", Age=1 } };

    int min = pets.Min(pet => pet.Age);

    Console.WriteLine("The youngest animal is age {0}.", min);
}

/*
 This code produces the following output:

 The youngest animal is age 1.
*/

Structure Pet
    Public Name As String
    Public Age As Integer
End Structure

Sub MinEx4()
    ' Create an array of Pet objects.
    Dim pets() As Pet = {New Pet With {.Name = "Barley", .Age = 8},
                     New Pet With {.Name = "Boots", .Age = 4},
                     New Pet With {.Name = "Whiskers", .Age = 1}}

    ' Find the youngest pet by passing a 
    ' lambda expression to the Min() method.
    Dim min As Integer = pets.Min(Function(pet) pet.Age)

    ' Display the result.
    Console.WriteLine($"The youngest pet is age {min}")
End Sub

' This code produces the following output:
'
' The youngest pet is age 1

설명

형식이 TResult 를 구현 하 IComparable<T> 는 경우이 메서드는 해당 구현을 사용 하 여 값을 비교 합니다.If type TResult implements IComparable<T>, this method uses that implementation to compare values. 그렇지 않으면 형식이을 구현 하는 경우 TResult IComparable 해당 구현을 사용 하 여 값을 비교 합니다.Otherwise, if type TResult implements IComparable, that implementation is used to compare values.

Visual Basic 쿼리 식 구문에서 절은 Aggregate Into Min() 의 호출로 변환 Min 됩니다.In Visual Basic query expression syntax, an Aggregate Into Min() clause translates to an invocation of Min.

추가 정보

• Aggregate 절 (Visual Basic)Aggregate Clause (Visual Basic)

public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
 static float Min(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, float> ^ selector);

public static float Min<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,float> selector);

static member Min : seq<'Source> * Func<'Source, single> -> single

<Extension()>
Public Function Min(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Single)) As Single

형식 매개 변수

매개 변수

반환

Single

시퀀스의 최소값입니다.The minimum value in the sequence.

예외

예제

다음 코드 예제에서는를 사용 하 여 Min<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) 프로젝션 된 값 시퀀스의 최소값을 확인 하는 방법을 보여 줍니다.The following code example demonstrates how to use Min<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) to determine the minimum value in a sequence of projected values.

class Pet
{
    public string Name { get; set; }
    public int Age { get; set; }
}

public static void MinEx4()
{
    Pet[] pets = { new Pet { Name="Barley", Age=8 },
                   new Pet { Name="Boots", Age=4 },
                   new Pet { Name="Whiskers", Age=1 } };

    int min = pets.Min(pet => pet.Age);

    Console.WriteLine("The youngest animal is age {0}.", min);
}

/*
 This code produces the following output:

 The youngest animal is age 1.
*/

Structure Pet
    Public Name As String
    Public Age As Integer
End Structure

Sub MinEx4()
    ' Create an array of Pet objects.
    Dim pets() As Pet = {New Pet With {.Name = "Barley", .Age = 8},
                     New Pet With {.Name = "Boots", .Age = 4},
                     New Pet With {.Name = "Whiskers", .Age = 1}}

    ' Find the youngest pet by passing a 
    ' lambda expression to the Min() method.
    Dim min As Integer = pets.Min(Function(pet) pet.Age)

    ' Display the result.
    Console.WriteLine($"The youngest pet is age {min}")
End Sub

' This code produces the following output:
'
' The youngest pet is age 1

설명

Min<TSource>(IEnumerable<TSource>, Func<TSource,Single>)메서드는의 구현을 사용 하 여 Single IComparable<T> 값을 비교 합니다.The Min<TSource>(IEnumerable<TSource>, Func<TSource,Single>) method uses the Single implementation of IComparable<T> to compare values.

selector의 멤버를 숫자 형식으로 프로젝션 하는 함수를 제공 하는 경우이 메서드를 임의 값의 시퀀스에 적용할 수 있습니다 source Single .You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Single.

Visual Basic 쿼리 식 구문에서 절은 Aggregate Into Min() 의 호출로 변환 Min 됩니다.In Visual Basic query expression syntax, an Aggregate Into Min() clause translates to an invocation of Min.

추가 정보

• Aggregate 절 (Visual Basic)Aggregate Clause (Visual Basic)

public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
 static Nullable<float> Min(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, Nullable<float>> ^ selector);

public static float? Min<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,Nullable<float>> selector);

static member Min : seq<'Source> * Func<'Source, Nullable<single>> -> Nullable<single>

<Extension()>
Public Function Min(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Nullable(Of Single))) As Nullable(Of Single)

형식 매개 변수

매개 변수

반환

Nullable<Single>

시퀀스의 최솟값에 해당하는 Nullable<Single> 형식(C#) 또는 Nullable(Of Single) 형식(Visual Basic의 경우) 값입니다.The value of type Nullable<Single> in C# or Nullable(Of Single) in Visual Basic that corresponds to the minimum value in the sequence.

예외

예제

다음 코드 예제에서는를 사용 하 여 Min<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) 프로젝션 된 값 시퀀스의 최소값을 확인 하는 방법을 보여 줍니다.The following code example demonstrates how to use Min<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) to determine the minimum value in a sequence of projected values.

class Pet
{
    public string Name { get; set; }
    public int Age { get; set; }
}

public static void MinEx4()
{
    Pet[] pets = { new Pet { Name="Barley", Age=8 },
                   new Pet { Name="Boots", Age=4 },
                   new Pet { Name="Whiskers", Age=1 } };

    int min = pets.Min(pet => pet.Age);

    Console.WriteLine("The youngest animal is age {0}.", min);
}

/*
 This code produces the following output:

 The youngest animal is age 1.
*/

Structure Pet
    Public Name As String
    Public Age As Integer
End Structure

Sub MinEx4()
    ' Create an array of Pet objects.
    Dim pets() As Pet = {New Pet With {.Name = "Barley", .Age = 8},
                     New Pet With {.Name = "Boots", .Age = 4},
                     New Pet With {.Name = "Whiskers", .Age = 1}}

    ' Find the youngest pet by passing a 
    ' lambda expression to the Min() method.
    Dim min As Integer = pets.Min(Function(pet) pet.Age)

    ' Display the result.
    Console.WriteLine($"The youngest pet is age {min}")
End Sub

' This code produces the following output:
'
' The youngest pet is age 1

설명

Min<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Single>>)메서드는의 구현을 사용 하 여 Single IComparable<T> 값을 비교 합니다.The Min<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Single>>) method uses the Single implementation of IComparable<T> to compare values.

selector의 멤버를 숫자 형식 (예를 들어, source Nullable<Single> c # 또는 Visual Basic)으로 프로젝션 하는 함수를 제공 하는 경우이 메서드를 임의 값의 시퀀스에 적용할 수 있습니다 Nullable(Of Single) .You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Nullable<Single> in C# or Nullable(Of Single) in Visual Basic.

Visual Basic 쿼리 식 구문에서 절은 Aggregate Into Min() 의 호출로 변환 Min 됩니다.In Visual Basic query expression syntax, an Aggregate Into Min() clause translates to an invocation of Min.

추가 정보

• Aggregate 절 (Visual Basic)Aggregate Clause (Visual Basic)

public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
 static Nullable<long> Min(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, Nullable<long>> ^ selector);

public static long? Min<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,Nullable<long>> selector);

static member Min : seq<'Source> * Func<'Source, Nullable<int64>> -> Nullable<int64>

<Extension()>
Public Function Min(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Nullable(Of Long))) As Nullable(Of Long)

형식 매개 변수

매개 변수

반환

Nullable<Int64>

시퀀스의 최솟값에 해당하는 Nullable<Int64> 형식(C#) 또는 Nullable(Of Int64) 형식(Visual Basic의 경우) 값입니다.The value of type Nullable<Int64> in C# or Nullable(Of Int64) in Visual Basic that corresponds to the minimum value in the sequence.

예외

예제

다음 코드 예제에서는를 사용 하 여 Min<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) 프로젝션 된 값 시퀀스의 최소값을 확인 하는 방법을 보여 줍니다.The following code example demonstrates how to use Min<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) to determine the minimum value in a sequence of projected values.

class Pet
{
    public string Name { get; set; }
    public int Age { get; set; }
}

public static void MinEx4()
{
    Pet[] pets = { new Pet { Name="Barley", Age=8 },
                   new Pet { Name="Boots", Age=4 },
                   new Pet { Name="Whiskers", Age=1 } };

    int min = pets.Min(pet => pet.Age);

    Console.WriteLine("The youngest animal is age {0}.", min);
}

/*
 This code produces the following output:

 The youngest animal is age 1.
*/

Structure Pet
    Public Name As String
    Public Age As Integer
End Structure

Sub MinEx4()
    ' Create an array of Pet objects.
    Dim pets() As Pet = {New Pet With {.Name = "Barley", .Age = 8},
                     New Pet With {.Name = "Boots", .Age = 4},
                     New Pet With {.Name = "Whiskers", .Age = 1}}

    ' Find the youngest pet by passing a 
    ' lambda expression to the Min() method.
    Dim min As Integer = pets.Min(Function(pet) pet.Age)

    ' Display the result.
    Console.WriteLine($"The youngest pet is age {min}")
End Sub

' This code produces the following output:
'
' The youngest pet is age 1

설명

Min<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Int64>>)메서드는의 구현을 사용 하 여 Int64 IComparable<T> 값을 비교 합니다.The Min<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Int64>>) method uses the Int64 implementation of IComparable<T> to compare values.

selector의 멤버를 숫자 형식 (예를 들어, source Nullable<Int64> c # 또는 Visual Basic)으로 프로젝션 하는 함수를 제공 하는 경우이 메서드를 임의 값의 시퀀스에 적용할 수 있습니다 Nullable(Of Int64) .You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Nullable<Int64> in C# or Nullable(Of Int64) in Visual Basic.

Visual Basic 쿼리 식 구문에서 절은 Aggregate Into Min() 의 호출로 변환 Min 됩니다.In Visual Basic query expression syntax, an Aggregate Into Min() clause translates to an invocation of Min.

추가 정보

• Aggregate 절 (Visual Basic)Aggregate Clause (Visual Basic)

public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
 static Nullable<int> Min(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, Nullable<int>> ^ selector);

public static int? Min<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,Nullable<int>> selector);

static member Min : seq<'Source> * Func<'Source, Nullable<int>> -> Nullable<int>

<Extension()>
Public Function Min(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Nullable(Of Integer))) As Nullable(Of Integer)

형식 매개 변수

매개 변수

반환

Nullable<Int32>

시퀀스의 최솟값에 해당하는 Nullable<Int32> 형식(C#) 또는 Nullable(Of Int32) 형식(Visual Basic의 경우) 값입니다.The value of type Nullable<Int32> in C# or Nullable(Of Int32) in Visual Basic that corresponds to the minimum value in the sequence.

예외

예제

다음 코드 예제에서는를 사용 하 여 Min<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) 프로젝션 된 값 시퀀스의 최소값을 확인 하는 방법을 보여 줍니다.The following code example demonstrates how to use Min<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) to determine the minimum value in a sequence of projected values.

class Pet
{
    public string Name { get; set; }
    public int Age { get; set; }
}

public static void MinEx4()
{
    Pet[] pets = { new Pet { Name="Barley", Age=8 },
                   new Pet { Name="Boots", Age=4 },
                   new Pet { Name="Whiskers", Age=1 } };

    int min = pets.Min(pet => pet.Age);

    Console.WriteLine("The youngest animal is age {0}.", min);
}

/*
 This code produces the following output:

 The youngest animal is age 1.
*/

Structure Pet
    Public Name As String
    Public Age As Integer
End Structure

Sub MinEx4()
    ' Create an array of Pet objects.
    Dim pets() As Pet = {New Pet With {.Name = "Barley", .Age = 8},
                     New Pet With {.Name = "Boots", .Age = 4},
                     New Pet With {.Name = "Whiskers", .Age = 1}}

    ' Find the youngest pet by passing a 
    ' lambda expression to the Min() method.
    Dim min As Integer = pets.Min(Function(pet) pet.Age)

    ' Display the result.
    Console.WriteLine($"The youngest pet is age {min}")
End Sub

' This code produces the following output:
'
' The youngest pet is age 1

설명

Min<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Int32>>)메서드는의 구현을 사용 하 여 Int32 IComparable<T> 값을 비교 합니다.The Min<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Int32>>) method uses the Int32 implementation of IComparable<T> to compare values.

selector소스의 멤버를 숫자 형식 (예를 들어, Nullable<Int32> c # 또는 Visual Basic)으로 프로젝션 하는 함수를 제공 하는 경우이 메서드를 임의 값의 시퀀스에 적용할 수 있습니다 Nullable(Of Int32) .You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Nullable<Int32> in C# or Nullable(Of Int32) in Visual Basic.

Visual Basic 쿼리 식 구문에서 절은 Aggregate Into Min() 의 호출로 변환 Min 됩니다.In Visual Basic query expression syntax, an Aggregate Into Min() clause translates to an invocation of Min.

추가 정보

• Aggregate 절 (Visual Basic)Aggregate Clause (Visual Basic)

public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
 static Nullable<double> Min(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, Nullable<double>> ^ selector);

public static double? Min<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,Nullable<double>> selector);

static member Min : seq<'Source> * Func<'Source, Nullable<double>> -> Nullable<double>

<Extension()>
Public Function Min(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Nullable(Of Double))) As Nullable(Of Double)

형식 매개 변수

매개 변수

반환

Nullable<Double>

시퀀스의 최솟값에 해당하는 Nullable<Double> 형식(C#) 또는 Nullable(Of Double) 형식(Visual Basic의 경우) 값입니다.The value of type Nullable<Double> in C# or Nullable(Of Double) in Visual Basic that corresponds to the minimum value in the sequence.

예외

예제

다음 코드 예제에서는를 사용 하 여 Min<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) 프로젝션 된 값 시퀀스의 최소값을 확인 하는 방법을 보여 줍니다.The following code example demonstrates how to use Min<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) to determine the minimum value in a sequence of projected values.

class Pet
{
    public string Name { get; set; }
    public int Age { get; set; }
}

public static void MinEx4()
{
    Pet[] pets = { new Pet { Name="Barley", Age=8 },
                   new Pet { Name="Boots", Age=4 },
                   new Pet { Name="Whiskers", Age=1 } };

    int min = pets.Min(pet => pet.Age);

    Console.WriteLine("The youngest animal is age {0}.", min);
}

/*
 This code produces the following output:

 The youngest animal is age 1.
*/

Structure Pet
    Public Name As String
    Public Age As Integer
End Structure

Sub MinEx4()
    ' Create an array of Pet objects.
    Dim pets() As Pet = {New Pet With {.Name = "Barley", .Age = 8},
                     New Pet With {.Name = "Boots", .Age = 4},
                     New Pet With {.Name = "Whiskers", .Age = 1}}

    ' Find the youngest pet by passing a 
    ' lambda expression to the Min() method.
    Dim min As Integer = pets.Min(Function(pet) pet.Age)

    ' Display the result.
    Console.WriteLine($"The youngest pet is age {min}")
End Sub

' This code produces the following output:
'
' The youngest pet is age 1

설명

Min<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Double>>)메서드는의 구현을 사용 하 여 Double IComparable<T> 값을 비교 합니다.The Min<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Double>>) method uses the Double implementation of IComparable<T> to compare values.

selector의 멤버를 숫자 형식 (예를 들어, source Nullable<Double> c # 또는 Visual Basic)으로 프로젝션 하는 함수를 제공 하는 경우이 메서드를 임의 값의 시퀀스에 적용할 수 있습니다 Nullable(Of Double) .You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Nullable<Double> in C# or Nullable(Of Double) in Visual Basic.

Visual Basic 쿼리 식 구문에서 절은 Aggregate Into Min() 의 호출로 변환 Min 됩니다.In Visual Basic query expression syntax, an Aggregate Into Min() clause translates to an invocation of Min.

추가 정보

• Aggregate 절 (Visual Basic)Aggregate Clause (Visual Basic)

public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
 static long Min(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, long> ^ selector);

public static long Min<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,long> selector);

static member Min : seq<'Source> * Func<'Source, int64> -> int64

<Extension()>
Public Function Min(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Long)) As Long

형식 매개 변수

매개 변수

반환

Int64

시퀀스의 최소값입니다.The minimum value in the sequence.

예외

예제

다음 코드 예제에서는를 사용 하 여 Min<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) 프로젝션 된 값 시퀀스의 최소값을 확인 하는 방법을 보여 줍니다.The following code example demonstrates how to use Min<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) to determine the minimum value in a sequence of projected values.

class Pet
{
    public string Name { get; set; }
    public int Age { get; set; }
}

public static void MinEx4()
{
    Pet[] pets = { new Pet { Name="Barley", Age=8 },
                   new Pet { Name="Boots", Age=4 },
                   new Pet { Name="Whiskers", Age=1 } };

    int min = pets.Min(pet => pet.Age);

    Console.WriteLine("The youngest animal is age {0}.", min);
}

/*
 This code produces the following output:

 The youngest animal is age 1.
*/

Structure Pet
    Public Name As String
    Public Age As Integer
End Structure

Sub MinEx4()
    ' Create an array of Pet objects.
    Dim pets() As Pet = {New Pet With {.Name = "Barley", .Age = 8},
                     New Pet With {.Name = "Boots", .Age = 4},
                     New Pet With {.Name = "Whiskers", .Age = 1}}

    ' Find the youngest pet by passing a 
    ' lambda expression to the Min() method.
    Dim min As Integer = pets.Min(Function(pet) pet.Age)

    ' Display the result.
    Console.WriteLine($"The youngest pet is age {min}")
End Sub

' This code produces the following output:
'
' The youngest pet is age 1

설명

Min<TSource>(IEnumerable<TSource>, Func<TSource,Int64>)메서드는의 구현을 사용 하 여 Int64 IComparable<T> 값을 비교 합니다.The Min<TSource>(IEnumerable<TSource>, Func<TSource,Int64>) method uses the Int64 implementation of IComparable<T> to compare values.

selector의 멤버를 숫자 형식으로 프로젝션 하는 함수를 제공 하는 경우이 메서드를 임의 값의 시퀀스에 적용할 수 있습니다 source Int64 .You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Int64.

Visual Basic 쿼리 식 구문에서 절은 Aggregate Into Min() 의 호출로 변환 Min 됩니다.In Visual Basic query expression syntax, an Aggregate Into Min() clause translates to an invocation of Min.

추가 정보

• Aggregate 절 (Visual Basic)Aggregate Clause (Visual Basic)

public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
 static int Min(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, int> ^ selector);

public static int Min<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,int> selector);

static member Min : seq<'Source> * Func<'Source, int> -> int

<Extension()>
Public Function Min(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Integer)) As Integer

형식 매개 변수

매개 변수

반환

Int32

시퀀스의 최소값입니다.The minimum value in the sequence.

예외

예제

다음 코드 예제에서는를 사용 하 여 Min<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) 프로젝션 된 값 시퀀스의 최소값을 확인 하는 방법을 보여 줍니다.The following code example demonstrates how to use Min<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) to determine the minimum value in a sequence of projected values.

class Pet
{
    public string Name { get; set; }
    public int Age { get; set; }
}

public static void MinEx4()
{
    Pet[] pets = { new Pet { Name="Barley", Age=8 },
                   new Pet { Name="Boots", Age=4 },
                   new Pet { Name="Whiskers", Age=1 } };

    int min = pets.Min(pet => pet.Age);

    Console.WriteLine("The youngest animal is age {0}.", min);
}

/*
 This code produces the following output:

 The youngest animal is age 1.
*/

Structure Pet
    Public Name As String
    Public Age As Integer
End Structure

Sub MinEx4()
    ' Create an array of Pet objects.
    Dim pets() As Pet = {New Pet With {.Name = "Barley", .Age = 8},
                     New Pet With {.Name = "Boots", .Age = 4},
                     New Pet With {.Name = "Whiskers", .Age = 1}}

    ' Find the youngest pet by passing a 
    ' lambda expression to the Min() method.
    Dim min As Integer = pets.Min(Function(pet) pet.Age)

    ' Display the result.
    Console.WriteLine($"The youngest pet is age {min}")
End Sub

' This code produces the following output:
'
' The youngest pet is age 1

설명

Min<TSource>(IEnumerable<TSource>, Func<TSource,Int32>)메서드는의 구현을 사용 하 여 Int32 IComparable<T> 값을 비교 합니다.The Min<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) method uses the Int32 implementation of IComparable<T> to compare values.

selector의 멤버를 숫자 형식으로 프로젝션 하는 함수를 제공 하는 경우이 메서드를 임의 값의 시퀀스에 적용할 수 있습니다 source Int32 .You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Int32.

Visual Basic 쿼리 식 구문에서 절은 Aggregate Into Min() 의 호출로 변환 Min 됩니다.In Visual Basic query expression syntax, an Aggregate Into Min() clause translates to an invocation of Min.

추가 정보

• Aggregate 절 (Visual Basic)Aggregate Clause (Visual Basic)

public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
 static double Min(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, double> ^ selector);

public static double Min<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,double> selector);

static member Min : seq<'Source> * Func<'Source, double> -> double

<Extension()>
Public Function Min(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Double)) As Double

형식 매개 변수

매개 변수

반환

Double

시퀀스의 최소값입니다.The minimum value in the sequence.

예외

예제

다음 코드 예제에서는를 사용 하 여 Min<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) 프로젝션 된 값 시퀀스의 최소값을 확인 하는 방법을 보여 줍니다.The following code example demonstrates how to use Min<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) to determine the minimum value in a sequence of projected values.

class Pet
{
    public string Name { get; set; }
    public int Age { get; set; }
}

public static void MinEx4()
{
    Pet[] pets = { new Pet { Name="Barley", Age=8 },
                   new Pet { Name="Boots", Age=4 },
                   new Pet { Name="Whiskers", Age=1 } };

    int min = pets.Min(pet => pet.Age);

    Console.WriteLine("The youngest animal is age {0}.", min);
}

/*
 This code produces the following output:

 The youngest animal is age 1.
*/

Structure Pet
    Public Name As String
    Public Age As Integer
End Structure

Sub MinEx4()
    ' Create an array of Pet objects.
    Dim pets() As Pet = {New Pet With {.Name = "Barley", .Age = 8},
                     New Pet With {.Name = "Boots", .Age = 4},
                     New Pet With {.Name = "Whiskers", .Age = 1}}

    ' Find the youngest pet by passing a 
    ' lambda expression to the Min() method.
    Dim min As Integer = pets.Min(Function(pet) pet.Age)

    ' Display the result.
    Console.WriteLine($"The youngest pet is age {min}")
End Sub

' This code produces the following output:
'
' The youngest pet is age 1

설명

Min<TSource>(IEnumerable<TSource>, Func<TSource,Double>)메서드는의 구현을 사용 하 여 Double IComparable<T> 값을 비교 합니다.The Min<TSource>(IEnumerable<TSource>, Func<TSource,Double>) method uses the Double implementation of IComparable<T> to compare values.

selector의 멤버를 숫자 형식으로 프로젝션 하는 함수를 제공 하는 경우이 메서드를 임의 값의 시퀀스에 적용할 수 있습니다 source Double .You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Double.

Visual Basic 쿼리 식 구문에서 절은 Aggregate Into Min() 의 호출로 변환 Min 됩니다.In Visual Basic query expression syntax, an Aggregate Into Min() clause translates to an invocation of Min.

추가 정보

• Aggregate 절 (Visual Basic)Aggregate Clause (Visual Basic)

public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
 static System::Decimal Min(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, System::Decimal> ^ selector);

public static decimal Min<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,decimal> selector);

static member Min : seq<'Source> * Func<'Source, decimal> -> decimal

<Extension()>
Public Function Min(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Decimal)) As Decimal

형식 매개 변수

매개 변수

반환

Decimal

시퀀스의 최소값입니다.The minimum value in the sequence.

예외

예제

다음 코드 예제에서는를 사용 하 여 Min<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) 프로젝션 된 값 시퀀스의 최소값을 확인 하는 방법을 보여 줍니다.The following code example demonstrates how to use Min<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) to determine the minimum value in a sequence of projected values.

class Pet
{
    public string Name { get; set; }
    public int Age { get; set; }
}

public static void MinEx4()
{
    Pet[] pets = { new Pet { Name="Barley", Age=8 },
                   new Pet { Name="Boots", Age=4 },
                   new Pet { Name="Whiskers", Age=1 } };

    int min = pets.Min(pet => pet.Age);

    Console.WriteLine("The youngest animal is age {0}.", min);
}

/*
 This code produces the following output:

 The youngest animal is age 1.
*/

Structure Pet
    Public Name As String
    Public Age As Integer
End Structure

Sub MinEx4()
    ' Create an array of Pet objects.
    Dim pets() As Pet = {New Pet With {.Name = "Barley", .Age = 8},
                     New Pet With {.Name = "Boots", .Age = 4},
                     New Pet With {.Name = "Whiskers", .Age = 1}}

    ' Find the youngest pet by passing a 
    ' lambda expression to the Min() method.
    Dim min As Integer = pets.Min(Function(pet) pet.Age)

    ' Display the result.
    Console.WriteLine($"The youngest pet is age {min}")
End Sub

' This code produces the following output:
'
' The youngest pet is age 1

설명

Min<TSource>(IEnumerable<TSource>, Func<TSource,Decimal>)메서드는의 구현을 사용 하 여 Decimal IComparable<T> 값을 비교 합니다.The Min<TSource>(IEnumerable<TSource>, Func<TSource,Decimal>) method uses the Decimal implementation of IComparable<T> to compare values.

selector의 멤버를 숫자 형식으로 프로젝션 하는 함수를 제공 하는 경우이 메서드를 임의 값의 시퀀스에 적용할 수 있습니다 source Decimal .You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Decimal.

Visual Basic 쿼리 식 구문에서 절은 Aggregate Into Min() 의 호출로 변환 Min 됩니다.In Visual Basic query expression syntax, an Aggregate Into Min() clause translates to an invocation of Min.

추가 정보

• Aggregate 절 (Visual Basic)Aggregate Clause (Visual Basic)

public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
 static TSource Min(System::Collections::Generic::IEnumerable<TSource> ^ source);

public static TSource Min<TSource> (this System.Collections.Generic.IEnumerable<TSource> source);

public static TSource Min<TSource> (this System.Collections.Generic.IEnumerable<TSource>? source);

static member Min : seq<'Source> -> 'Source

<Extension()>
Public Function Min(Of TSource) (source As IEnumerable(Of TSource)) As TSource

형식 매개 변수

매개 변수

반환

TSource

시퀀스의 최소값입니다.The minimum value in the sequence.

예외

예제

다음 코드 예제에서는를 사용 하 여 Min<TSource>(IEnumerable<TSource>) 개체 시퀀스의 최소값을 확인 하는 방법을 보여 줍니다 IComparable<T> .The following code example demonstrates how to use Min<TSource>(IEnumerable<TSource>) to determine the minimum value in a sequence of IComparable<T> objects.

/// <summary>
/// This class implements IComparable in order to
/// be able to compare different Pet objects.
/// </summary>
class Pet : IComparable<Pet>
{
    public string Name { get; set; }
    public int Age { get; set; }

    /// <summary>
    /// Compares this Pet's age to another Pet's age.
    /// </summary>
    /// <param name="other">The Pet to compare this Pet to.</param>
    /// <returns>-1 if this Pet's age is smaller,
    /// 0 if the Pets' ages are equal, or
    /// 1 if this Pet's age is greater.</returns>
    int IComparable<Pet>.CompareTo(Pet other)
    {
        if (other.Age > this.Age)
            return -1;
        else if (other.Age == this.Age)
            return 0;
        else
            return 1;
    }
}

public static void MinEx3()
{
    Pet[] pets = { new Pet { Name="Barley", Age=8 },
                   new Pet { Name="Boots", Age=4 },
                   new Pet { Name="Whiskers", Age=1 } };

    Pet min = pets.Min();

    Console.WriteLine(
        "The 'minimum' animal is {0}.",
        min.Name);
}

/*
 This code produces the following output:

 The 'minimum' animal is Whiskers.
*/

' This class implements IComparable 
' and has a custom 'CompareTo' implementation.
Class Pet
    Implements IComparable(Of Pet)

    Public Name As String
    Public Age As Integer

    ''' <summary>
    ''' Compares this Pet's age to another Pet's age.
    ''' </summary>
    ''' <param name="other">The Pet to compare this Pet to.</param>
    ''' <returns>-1 if this Pet's age is smaller,
    ''' 0 if the Pets' ages are equal,
    ''' or 1 if this Pet's age is greater.</returns>
    Function CompareTo(ByVal other As Pet) As Integer _
    Implements IComparable(Of Pet).CompareTo

        If (other.Age > Me.Age) Then
            Return -1
        ElseIf (other.Age = Me.Age) Then
            Return 0
        Else
            Return 1
        End If
    End Function
End Class

Sub MinEx3()
    ' Create an array of Pet objects.
    Dim pets() As Pet = {New Pet With {.Name = "Barley", .Age = 8},
                     New Pet With {.Name = "Boots", .Age = 4},
                     New Pet With {.Name = "Whiskers", .Age = 1}}

    ' Determine the "minimum" pet in the array,
    ' according to the custom CompareTo() implementation.
    Dim min As Pet = pets.Min()

    ' Display the result.
    Console.WriteLine($"The 'minimum' pet is {min.Name}")
End Sub

' This code produces the following output:
'
' The 'minimum' pet is Whiskers

설명

형식이 TSource 를 구현 하 IComparable<T> 는 경우이 메서드는 해당 구현을 사용 하 여 값을 비교 합니다.If type TSource implements IComparable<T>, this method uses that implementation to compare values. 그렇지 않으면 형식이을 구현 하는 경우 TSource IComparable 해당 구현을 사용 하 여 값을 비교 합니다.Otherwise, if type TSource implements IComparable, that implementation is used to compare values.

TSource가 참조 형식이 고 소스 시퀀스가 비어 있거나 값만 포함 하는 경우 null 이 함수는를 반환 null 합니다.If TSource is a reference type and the source sequence is empty or contains only values that are null, this function returns null.

Visual Basic 쿼리 식 구문에서 절은 Aggregate Into Min() 의 호출로 변환 Min 됩니다.In Visual Basic query expression syntax, an Aggregate Into Min() clause translates to an invocation of Min.

추가 정보

• Aggregate 절 (Visual Basic)Aggregate Clause (Visual Basic)

public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
 static Nullable<System::Decimal> Min(System::Collections::Generic::IEnumerable<TSource> ^ source, Func<TSource, Nullable<System::Decimal>> ^ selector);

public static decimal? Min<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,Nullable<decimal>> selector);

static member Min : seq<'Source> * Func<'Source, Nullable<decimal>> -> Nullable<decimal>

<Extension()>
Public Function Min(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Nullable(Of Decimal))) As Nullable(Of Decimal)

형식 매개 변수

매개 변수

반환

Nullable<Decimal>

시퀀스의 최솟값에 해당하는 Nullable<Decimal> 형식(C#) 또는 Nullable(Of Decimal) 형식(Visual Basic의 경우)의 값입니다.The value of type Nullable<Decimal> in C# or Nullable(Of Decimal) in Visual Basic that corresponds to the minimum value in the sequence.

예외

예제

다음 코드 예제에서는를 사용 하 여 Min<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) 프로젝션 된 값 시퀀스의 최소값을 확인 하는 방법을 보여 줍니다.The following code example demonstrates how to use Min<TSource>(IEnumerable<TSource>, Func<TSource,Int32>) to determine the minimum value in a sequence of projected values.

class Pet
{
    public string Name { get; set; }
    public int Age { get; set; }
}

public static void MinEx4()
{
    Pet[] pets = { new Pet { Name="Barley", Age=8 },
                   new Pet { Name="Boots", Age=4 },
                   new Pet { Name="Whiskers", Age=1 } };

    int min = pets.Min(pet => pet.Age);

    Console.WriteLine("The youngest animal is age {0}.", min);
}

/*
 This code produces the following output:

 The youngest animal is age 1.
*/

Structure Pet
    Public Name As String
    Public Age As Integer
End Structure

Sub MinEx4()
    ' Create an array of Pet objects.
    Dim pets() As Pet = {New Pet With {.Name = "Barley", .Age = 8},
                     New Pet With {.Name = "Boots", .Age = 4},
                     New Pet With {.Name = "Whiskers", .Age = 1}}

    ' Find the youngest pet by passing a 
    ' lambda expression to the Min() method.
    Dim min As Integer = pets.Min(Function(pet) pet.Age)

    ' Display the result.
    Console.WriteLine($"The youngest pet is age {min}")
End Sub

' This code produces the following output:
'
' The youngest pet is age 1

설명

Min<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Decimal>>)메서드는의 구현을 사용 하 여 Decimal IComparable<T> 값을 비교 합니다.The Min<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Decimal>>) method uses the Decimal implementation of IComparable<T> to compare values.

selector의 멤버를 숫자 형식 (예를 들어, source Nullable<Decimal> c # 또는 Visual Basic)으로 프로젝션 하는 함수를 제공 하는 경우이 메서드를 임의 값의 시퀀스에 적용할 수 있습니다 Nullable(Of Decimal) .You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Nullable<Decimal> in C# or Nullable(Of Decimal) in Visual Basic.

Visual Basic 쿼리 식 구문에서 절은 Aggregate Into Min() 의 호출로 변환 Min 됩니다.In Visual Basic query expression syntax, an Aggregate Into Min() clause translates to an invocation of Min.

추가 정보

• Aggregate 절 (Visual Basic)Aggregate Clause (Visual Basic)