DataGridViewDataErrorEventArgs.Exception 속성

정의

네임스페이스:

System.Windows.Forms

어셈블리:

System.Windows.Forms.dll

오류를 나타내는 예외를 가져옵니다.

public:
 property Exception ^ Exception { Exception ^ get(); };

public Exception? Exception { get; }

member this.Exception : Exception

Public ReadOnly Property Exception As Exception

속성 값

Exception

오류를 나타내는 Exception입니다.

예제

다음 코드 예제를 확인 하는 방법을 보여 줍니다는 Exception 속성입니다. 이 예제는에서 사용할 수 있는 보다 큰 예제의 일부는 DataGridViewComboBoxColumn 클래스 개요 항목입니다.

private:
    void DataGridView1_DataError(Object^ sender, DataGridViewDataErrorEventArgs^ anError)
    {

        MessageBox::Show("Error happened " + anError->Context.ToString());

        if (anError->Context == DataGridViewDataErrorContexts::Commit)
        {
            MessageBox::Show("Commit error");
        }
        if (anError->Context == DataGridViewDataErrorContexts::CurrentCellChange)
        {
            MessageBox::Show("Cell change");
        }
        if (anError->Context == DataGridViewDataErrorContexts::Parsing)
        {
            MessageBox::Show("parsing error");
        }
        if (anError->Context == DataGridViewDataErrorContexts::LeaveControl)
        {
            MessageBox::Show("leave control error");
        }

        if (dynamic_cast<ConstraintException^>(anError->Exception) != nullptr)
        {
            DataGridView^ view = (DataGridView^)sender;
            view->Rows[anError->RowIndex]->ErrorText = "an error";
            view->Rows[anError->RowIndex]->Cells[anError->ColumnIndex]->ErrorText = "an error";

            anError->ThrowException = false;
        }
    }

private void DataGridView1_DataError(object sender, DataGridViewDataErrorEventArgs anError)
{

    MessageBox.Show("Error happened " + anError.Context.ToString());

    if (anError.Context == DataGridViewDataErrorContexts.Commit)
    {
        MessageBox.Show("Commit error");
    }
    if (anError.Context == DataGridViewDataErrorContexts.CurrentCellChange)
    {
        MessageBox.Show("Cell change");
    }
    if (anError.Context == DataGridViewDataErrorContexts.Parsing)
    {
        MessageBox.Show("parsing error");
    }
    if (anError.Context == DataGridViewDataErrorContexts.LeaveControl)
    {
        MessageBox.Show("leave control error");
    }

    if ((anError.Exception) is ConstraintException)
    {
        DataGridView view = (DataGridView)sender;
        view.Rows[anError.RowIndex].ErrorText = "an error";
        view.Rows[anError.RowIndex].Cells[anError.ColumnIndex].ErrorText = "an error";

        anError.ThrowException = false;
    }
}

Private Sub DataGridView1_DataError(ByVal sender As Object, _
ByVal e As DataGridViewDataErrorEventArgs) _
Handles DataGridView1.DataError

    MessageBox.Show("Error happened " _
        & e.Context.ToString())

    If (e.Context = DataGridViewDataErrorContexts.Commit) _
        Then
        MessageBox.Show("Commit error")
    End If
    If (e.Context = DataGridViewDataErrorContexts _
        .CurrentCellChange) Then
        MessageBox.Show("Cell change")
    End If
    If (e.Context = DataGridViewDataErrorContexts.Parsing) _
        Then
        MessageBox.Show("parsing error")
    End If
    If (e.Context = _
        DataGridViewDataErrorContexts.LeaveControl) Then
        MessageBox.Show("leave control error")
    End If

    If (TypeOf (e.Exception) Is ConstraintException) Then
        Dim view As DataGridView = CType(sender, DataGridView)
        view.Rows(e.RowIndex).ErrorText = "an error"
        view.Rows(e.RowIndex).Cells(e.ColumnIndex) _
            .ErrorText = "an error"

        e.ThrowException = False
    End If
End Sub

설명

둘 이상의 예외를 처리 하 DataGridViewDataErrorEventHandler를 설정 하 여 처리기의 끝에서 다시 예외를 throw 합니다 ThrowException 속성을 true입니다.

추가 정보

• DataGridView
• DataError