Size3D.Equality(Size3D, Size3D) 연산자

정의

Size3D 구조체가 같은지 여부를 비교합니다.Compares two Size3D structures for equality. 해당 Size3D, XY 속성의 값이 같으면 두 Z 구조체가 같습니다.Two Size3D structures are equal if the values of their X, Y, and Z properties are the same.

public:
 static bool operator ==(System::Windows::Media::Media3D::Size3D size1, System::Windows::Media::Media3D::Size3D size2);
public static bool operator == (System.Windows.Media.Media3D.Size3D size1, System.Windows.Media.Media3D.Size3D size2);
static member ( = ) : System.Windows.Media.Media3D.Size3D * System.Windows.Media.Media3D.Size3D -> bool
Public Shared Operator == (size1 As Size3D, size2 As Size3D) As Boolean

매개 변수

size1
Size3D

비교할 첫 번째 Size3D 구조체입니다.The first Size3D structure to compare.

size2
Size3D

비교할 두 번째 Size3D 구조체입니다.The second Size3D structure to compare.

반환

size1size2X, YZ 구성 요소가 같으면 true이고, 그렇지 않으면 false입니다.true if the X, Y, and Z components of size1 and size2 are equal; otherwise, false.

예제

다음 예제에서는 오버 로드 된 같음 연산자를 사용 하 여 두 가지 경우를 확인 하는 방법을 보여 줍니다 Size3D 구조체가 동일 합니다.The following example shows how to use the overloaded equality operator to check if two Size3D structures are equal.

// Checks if two Size3D structures are equal using the overloaded == operator. 
// Returns a Boolean.

// Declaring Size3D structure without initializing x,y,z values
Size3D size1 = new Size3D();

// Declaring Size3D structure and initializing x,y,z values
Size3D size2 = new Size3D(5, 10, 15);
Boolean areEqual;

// Assigning values to size1
size1.X = 2;
size1.Y = 4;
size1.Z = 6;

// Checking for equality
areEqual = size1 == size2;

// areEqual is False

// Displaying Results
syntaxString = " areEqual = size1 == size2;";
resultType = "Boolean";
operationString = "Checking if two Size3D structures are equal";
ShowResults(areEqual.ToString(), syntaxString, resultType, operationString);
' Checks if two Size3D structures are equal using the overloaded == operator. 
' Returns a Boolean.

' Declaring Size3D structure without initializing x,y,z values
Dim size1 As New Size3D()

' Declaring Size3D structure and initializing x,y,z values
Dim size2 As New Size3D(5, 10, 15)
Dim areEqual As Boolean

' Assigning values to size1
size1.X = 2
size1.Y = 4
size1.Z = 6

' Checking for equality
areEqual = size1 = size2

' areEqual is False

' Displaying Results
syntaxString = " areEqual = size1 == size2"
resultType = "Boolean"
operationString = "Checking if two Size3D structures are equal"
ShowResults(areEqual.ToString(), syntaxString, resultType, operationString)

설명

때문에 Double 간 비교에서 산술 작업을 수행할 때 값 정밀도 떨어질 수 Size3D 논리적으로 동일한 인스턴스가 실패할 수 있습니다.Because Double values can lose precision when arithmetic operations are performed on them, a comparison between two Size3D instances that are logically equal might fail.

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