Compartilhar via


XmlChoiceIdentifierAttribute Construtores

Definição

Inicializa uma nova instância da classe XmlChoiceIdentifierAttribute.

Sobrecargas

XmlChoiceIdentifierAttribute()

Inicializa uma nova instância da classe XmlChoiceIdentifierAttribute.

XmlChoiceIdentifierAttribute(String)

Inicializa uma nova instância da classe XmlChoiceIdentifierAttribute.

XmlChoiceIdentifierAttribute()

Inicializa uma nova instância da classe XmlChoiceIdentifierAttribute.

public:
 XmlChoiceIdentifierAttribute();
public XmlChoiceIdentifierAttribute ();
Public Sub New ()

Exemplos

O exemplo a seguir serializa uma classe nomeada Choices que inclui dois campos MyChoice e ManyChoices. Ela XmlChoiceIdentifierAttribute é aplicada a cada campo que especifica (por meio da propriedade) outro membro de MemberName classe que obtém ou define uma enumeração que detecta o valor do membro. O MyChoice campo pode ser definido como um único valor, com um membro de enumeração correspondente encontrado no EnumType campo. O ManyChoices campo retorna uma matriz de objetos. O ChoiceArray campo retorna uma matriz de valores de enumeração. Para cada membro da matriz no ManyChoices campo, um membro correspondente é encontrado na matriz retornada pelo ChoiceArray campo.

#using <System.dll>
#using <System.xml.dll>

using namespace System;
using namespace System::Xml;
using namespace System::Xml::Serialization;
using namespace System::IO;

[XmlType(IncludeInSchema=false)]

public enum class ItemChoiceType
{
   None, Word, Number, DecimalNumber
};

public enum class MoreChoices
{
   None, Item, Amount, Temp
};

public ref class Choices
{
public:

   // The MyChoice field can be set to any one of 
   // the types below. 

   [XmlChoiceIdentifier("EnumType")]
   [XmlElement("Word",String::typeid)]
   [XmlElement("Number",Int32::typeid)]
   [XmlElement("DecimalNumber",Double::typeid)]
   Object^ MyChoice;

   // Don't serialize this field. The EnumType field
   // contains the enumeration value that corresponds
   // to the MyChoice field value.

   [XmlIgnore]
   ItemChoiceType EnumType;

   // The ManyChoices field can contain an array
   // of choices. Each choice must be matched to
   // an array item in the ChoiceArray field.

   [XmlChoiceIdentifier("ChoiceArray")]
   [XmlElement("Item",String::typeid)]
   [XmlElement("Amount",Int32::typeid)]
   [XmlElement("Temp",Double::typeid)]
   array<Object^>^ManyChoices;

   // TheChoiceArray field contains the enumeration
   // values, one for each item in the ManyChoices array.

   [XmlIgnore]
   array<MoreChoices>^ChoiceArray;
};

void SerializeObject( String^ filename );
void DeserializeObject( String^ filename );
int main()
{
   SerializeObject( "Choices.xml" );
   DeserializeObject( "Choices.xml" );
}

void SerializeObject( String^ filename )
{
   XmlSerializer^ mySerializer = gcnew XmlSerializer( Choices::typeid );
   TextWriter^ writer = gcnew StreamWriter( filename );
   Choices^ myChoices = gcnew Choices;

   // Set the MyChoice field to a string. Set the
   // EnumType to Word.
   myChoices->MyChoice = "Book";
   myChoices->EnumType = ItemChoiceType::Word;

   // Populate an object array with three items, one
   // of each enumeration type. Set the array to the 
   // ManyChoices field.
   array<Object^>^strChoices = {"Food",5,98.6};
   myChoices->ManyChoices = strChoices;

   // For each item in the ManyChoices array, add an
   // enumeration value.
   array<MoreChoices>^ itmChoices = {MoreChoices::Item,MoreChoices::Amount,MoreChoices::Temp};
   myChoices->ChoiceArray = itmChoices;
   mySerializer->Serialize( writer, myChoices );
   writer->Close();
}

void DeserializeObject( String^ filename )
{
   XmlSerializer^ ser = gcnew XmlSerializer( Choices::typeid );

   // A FileStream is needed to read the XML document.
   FileStream^ fs = gcnew FileStream( filename,FileMode::Open );
   Choices^ myChoices = safe_cast<Choices^>(ser->Deserialize( fs ));
   fs->Close();

   // Disambiguate the MyChoice value using the enumeration.
   if ( myChoices->EnumType == ItemChoiceType::Word )
   {
      Console::WriteLine( "Word: {0}", myChoices->MyChoice->ToString() );
   }
   else
   if ( myChoices->EnumType == ItemChoiceType::Number )
   {
      Console::WriteLine( "Number: {0}", myChoices->MyChoice->ToString() );
   }
   else
   if ( myChoices->EnumType == ItemChoiceType::DecimalNumber )
   {
      Console::WriteLine( "DecimalNumber: {0}", myChoices->MyChoice->ToString() );
   }

   // Disambiguate the ManyChoices values using the enumerations.
   for ( int i = 0; i < myChoices->ManyChoices->Length; i++ )
   {
      if ( myChoices->ChoiceArray[ i ] == MoreChoices::Item )
            Console::WriteLine( "Item: {0}", myChoices->ManyChoices[ i ] );
      else
      if ( myChoices->ChoiceArray[ i ] == MoreChoices::Amount )
            Console::WriteLine( "Amount: ", myChoices->ManyChoices[ i ]->ToString() );
      if ( myChoices->ChoiceArray[ i ] == MoreChoices::Temp )
            Console::WriteLine( "Temp: {0}", myChoices->ManyChoices[ i ]->ToString() );
   }
}
using System;
using System.Xml;
using System.Xml.Serialization;
using System.IO;

public class Choices{
   // The MyChoice field can be set to any one of 
   // the types below. 
   [XmlChoiceIdentifier("EnumType")]
   [XmlElement("Word", typeof(string))]
   [XmlElement("Number", typeof(int))]
   [XmlElement("DecimalNumber", typeof(double))]
   public object MyChoice;

   // Don't serialize this field. The EnumType field
   // contains the enumeration value that corresponds
   // to the MyChoice field value.
   [XmlIgnore]
   public ItemChoiceType EnumType;

   // The ManyChoices field can contain an array
   // of choices. Each choice must be matched to
   // an array item in the ChoiceArray field.
   [XmlChoiceIdentifier("ChoiceArray")]
   [XmlElement("Item", typeof(string))]
   [XmlElement("Amount", typeof(int))]
   [XmlElement("Temp", typeof(double))]
   public object[] ManyChoices;

   // TheChoiceArray field contains the enumeration
   // values, one for each item in the ManyChoices array.
   [XmlIgnore]
   public MoreChoices[] ChoiceArray;
}

[XmlType(IncludeInSchema=false)]
public enum ItemChoiceType{
   None,
   Word, 
   Number,
   DecimalNumber
}

public enum MoreChoices{
   None,
   Item,
   Amount,
   Temp
}

public class Test{
   static void Main(){
      Test t = new Test();
      t.SerializeObject("Choices.xml");
      t.DeserializeObject("Choices.xml");
   }

   private void SerializeObject(string filename){
      XmlSerializer mySerializer = 
      new XmlSerializer(typeof(Choices));
      TextWriter writer = new StreamWriter(filename);
      Choices myChoices = new Choices();

      // Set the MyChoice field to a string. Set the
      // EnumType to Word.
      myChoices.MyChoice= "Book";
      myChoices.EnumType = ItemChoiceType.Word;

      // Populate an object array with three items, one
      // of each enumeration type. Set the array to the 
      // ManyChoices field.
      object[] strChoices = new object[]{"Food",  5, 98.6};
      myChoices.ManyChoices=strChoices;

      // For each item in the ManyChoices array, add an
      // enumeration value.
      MoreChoices[] itmChoices = new MoreChoices[]
      {MoreChoices.Item, 
      MoreChoices.Amount,
      MoreChoices.Temp};
      myChoices.ChoiceArray=itmChoices;
      
      mySerializer.Serialize(writer, myChoices);
      writer.Close();
   }

   private void DeserializeObject(string filename){
      XmlSerializer ser = new XmlSerializer(typeof(Choices));

      // A FileStream is needed to read the XML document.
      FileStream fs = new FileStream(filename, FileMode.Open);
      Choices myChoices = (Choices)
      ser.Deserialize(fs);
      fs.Close();

      // Disambiguate the MyChoice value using the enumeration.
      if(myChoices.EnumType == ItemChoiceType.Word){
           Console.WriteLine("Word: " +  
            myChoices.MyChoice.ToString());
        }
      else if(myChoices.EnumType == ItemChoiceType.Number){
           Console.WriteLine("Number: " +
            myChoices.MyChoice.ToString());
        }
      else if(myChoices.EnumType == ItemChoiceType.DecimalNumber){
           Console.WriteLine("DecimalNumber: " +
            myChoices.MyChoice.ToString());
        }

      // Disambiguate the ManyChoices values using the enumerations.
      for(int i = 0; i<myChoices.ManyChoices.Length; i++){
      if(myChoices.ChoiceArray[i] == MoreChoices.Item)
        Console.WriteLine("Item: " + (string) myChoices.ManyChoices[i]);
      else if(myChoices.ChoiceArray[i] == MoreChoices.Amount)
        Console.WriteLine("Amount: " + myChoices.ManyChoices[i].ToString());
      if(myChoices.ChoiceArray[i] == MoreChoices.Temp)
        Console.WriteLine("Temp: " + (string) myChoices.ManyChoices[i].ToString());
        }
   }
}
Imports System.Xml
Imports System.Xml.Serialization
Imports System.IO

Public Class Choices
   ' The MyChoice field can be set to any one of 
   ' the types below. 
   <XmlChoiceIdentifier("EnumType"), _
   XmlElement("Word", GetType(String)), _
   XmlElement("Number", GetType(Integer)), _
   XmlElement("DecimalNumber", GetType(double))> _
   Public MyChoice As Object 

   ' Don't serialize this field. The EnumType field
   ' contains the enumeration value that corresponds
   ' to the MyChoice field value.
   <XmlIgnore> _
   Public EnumType As ItemChoiceType 

   'The ManyChoices field can contain an array
   ' of choices. Each choice must be matched to
   ' an array item in the ChoiceArray field.
   <XmlChoiceIdentifier("ChoiceArray"), _
   XmlElement("Item", GetType(string)), _
   XmlElement("Amount", GetType(Integer)), _
   XmlElement("Temp", GetType(double))> _
   Public ManyChoices() As Object

   ' TheChoiceArray field contains the enumeration
   ' values, one for each item in the ManyChoices array.
   <XmlIgnore> _
   Public ChoiceArray() As MoreChoices
End Class

<XmlType(IncludeInSchema:=false)> _
Public Enum ItemChoiceType
   None
   Word 
   Number
   DecimalNumber
End Enum

<XmlType(IncludeInSchema:=false)> _
Public Enum MoreChoices
   None
   Item
   Amount
   Temp
End Enum

Public Class Test
   Shared Sub Main()
      Dim t  As Test = New Test()
      t.SerializeObject("Choices.xml")
      t.DeserializeObject("Choices.xml")
   End Sub

   private Sub SerializeObject(filename As string)
      Dim mySerializer As XmlSerializer = _
      New XmlSerializer(GetType(Choices))
      Dim writer As TextWriter = New StreamWriter(filename)
      Dim myChoices As Choices = New Choices()

      ' Set the MyChoice field to a string. Set the
      ' EnumType to Word.
      myChoices.MyChoice= "Book"
      myChoices.EnumType = ItemChoiceType.Word

      ' Populate an object array with three items, one
      ' of each enumeration type. Set the array to the 
      ' ManyChoices field.
      Dim strChoices () As Object = New object(){"Food",  5, 98.6}
      myChoices.ManyChoices=strChoices

      ' For each item in the ManyChoices array, add an
      ' enumeration value.
      Dim itmChoices () As MoreChoices = New MoreChoices() _
      {MoreChoices.Item, _
      MoreChoices.Amount, _
      MoreChoices.Temp}
      myChoices.ChoiceArray=itmChoices
      
      mySerializer.Serialize(writer, myChoices)
      writer.Close()
   End Sub

   private Sub DeserializeObject(filename As string)
      Dim ser As XmlSerializer = New XmlSerializer(GetType(Choices))
      

      ' A FileStream is needed to read the XML document.
      Dim fs As FileStream = New FileStream(filename, FileMode.Open)
      
      Dim myChoices As Choices = CType(ser.Deserialize(fs), Choices)

      fs.Close()

      ' Disambiguate the MyChoice value Imports the enumeration.
      if myChoices.EnumType = ItemChoiceType.Word Then
           Console.WriteLine("Word: " & _
           myChoices.MyChoice.ToString())
        
      else if myChoices.EnumType = ItemChoiceType.Number Then 
           Console.WriteLine("Number: " & _
            myChoices.MyChoice.ToString())
        
      else if myChoices.EnumType = ItemChoiceType.DecimalNumber Then
         Console.WriteLine("DecimalNumber: " & _
            myChoices.MyChoice.ToString())
        End If

      ' Disambiguate the ManyChoices values Imports the enumerations.
      Dim i As Integer
      for i = 0 to myChoices.ManyChoices.Length -1
      if myChoices.ChoiceArray(i) = MoreChoices.Item Then
        Console.WriteLine("Item: " +  _
        myChoices.ManyChoices(i).ToString())
      else if myChoices.ChoiceArray(i) = MoreChoices.Amount Then
        Console.WriteLine("Amount: " + _
        myChoices.ManyChoices(i).ToString())
      else if (myChoices.ChoiceArray(i) = MoreChoices.Temp)
        Console.WriteLine("Temp: " + _
        myChoices.ManyChoices(i).ToString())
        End If
        Next i
      
   End Sub
End Class

Aplica-se a

XmlChoiceIdentifierAttribute(String)

Inicializa uma nova instância da classe XmlChoiceIdentifierAttribute.

public:
 XmlChoiceIdentifierAttribute(System::String ^ name);
public XmlChoiceIdentifierAttribute (string name);
public XmlChoiceIdentifierAttribute (string? name);
new System.Xml.Serialization.XmlChoiceIdentifierAttribute : string -> System.Xml.Serialization.XmlChoiceIdentifierAttribute
Public Sub New (name As String)

Parâmetros

name
String

O nome do membro que retorna a enumeração usada para detectar uma opção.

Aplica-se a