BigInteger.Remainder(BigInteger, BigInteger) BigInteger.Remainder(BigInteger, BigInteger) BigInteger.Remainder(BigInteger, BigInteger) BigInteger.Remainder(BigInteger, BigInteger) Method

Определение

Выполняет целочисленное деление двух значений BigInteger и возвращает остаток.Performs integer division on two BigInteger values and returns the remainder.

public:
 static System::Numerics::BigInteger Remainder(System::Numerics::BigInteger dividend, System::Numerics::BigInteger divisor);
public static System.Numerics.BigInteger Remainder (System.Numerics.BigInteger dividend, System.Numerics.BigInteger divisor);
static member Remainder : System.Numerics.BigInteger * System.Numerics.BigInteger -> System.Numerics.BigInteger
Public Shared Function Remainder (dividend As BigInteger, divisor As BigInteger) As BigInteger

Параметры

dividend
BigInteger BigInteger BigInteger BigInteger

Значение, которое необходимо разделить.The value to be divided.

divisor
BigInteger BigInteger BigInteger BigInteger

Значение, на которое необходимо разделить.The value to divide by.

Возвраты

Остаток от деления dividend на divisor.The remainder after dividing dividend by divisor.

Исключения

Значение параметра divisor равно нулю (0).divisor is 0 (zero).

Примеры

В следующем примере сравнивается остаток от DivRem метода с остатком, возвращенным Remainder методом, чтобы определить, что два метода вычисляют идентичные остатки.The following example compares the remainder from the DivRem method with the remainder returned by the Remainder method to establish that the two methods calculate identical remainders.

using System;
using System.Numerics;

public class Example
{
   public static void Main()
   {
      BigInteger dividend1 = BigInteger.Pow(Int64.MaxValue, 3);
      BigInteger dividend2 = dividend1 * BigInteger.MinusOne;
      BigInteger divisor1 = Int32.MaxValue;
      BigInteger divisor2 = divisor1 * BigInteger.MinusOne;
      BigInteger remainder1, remainder2;
      BigInteger divRem1 = BigInteger.Zero;
      BigInteger divRem2 = BigInteger.Zero;
       
      remainder1 = BigInteger.Remainder(dividend1, divisor1);
      remainder2 = BigInteger.Remainder(dividend2, divisor1);

      BigInteger.DivRem(dividend1, divisor1, out divRem1);
      Console.WriteLine("BigInteger.Remainder({0}, {1}) = {2}", 
                        dividend1, divisor1, remainder1);
      Console.WriteLine("BigInteger.DivRem({0}, {1}) = {2}", 
                        dividend1, divisor1, divRem1);                    
      if (remainder1.Equals(divRem1))
         Console.WriteLine("The remainders are equal.\n");
      
      BigInteger.DivRem(dividend2, divisor2, out divRem2);
      Console.WriteLine("BigInteger.Remainder({0}, {1}) = {2}", 
                        dividend2, divisor2, remainder2);
      Console.WriteLine("BigInteger.DivRem({0}, {1}) = {2}", 
                        dividend2, divisor2, divRem2);                    
      if (remainder2.Equals(divRem2))
         Console.WriteLine("The remainders are equal.\n");
   }
}
// The example displays the following output:
//    BigInteger.Remainder(7.8463771692333509522426190271E+56, 2147483647) = 1
//    BigInteger.DivRem(7.8463771692333509522426190271E+56, 2147483647) = 1
//    The remainders are equal.
//    
//    BigInteger.Remainder(-7.8463771692333509522426190271E+56, -2147483647) = -1
//    BigInteger.DivRem(-7.8463771692333509522426190271E+56, -2147483647) = -1
//    The remainders are equal.
Imports System.Numerics

Module Example
   Public Sub Main()
      Dim dividend1 As BigInteger = BigInteger.Pow(Int64.MaxValue, 3)
      Dim dividend2 As BigInteger = dividend1 * BigInteger.MinusOne
      Dim divisor1 As BigInteger = Int32.MaxValue
      Dim divisor2 As BigInteger = divisor1 * BigInteger.MinusOne
      Dim remainder1, remainder2 As BigInteger
      Dim divRem1 As BigInteger = BigInteger.Zero
      Dim divRem2 As BigInteger = BigInteger.Zero
       
      remainder1 = BigInteger.Remainder(dividend1, divisor1)
      remainder2 = BigInteger.Remainder(dividend2, divisor1)

      BigInteger.DivRem(dividend1, divisor1, divRem1)
      Console.WriteLine("BigInteger.Remainder({0}, {1}) = {2}", 
                        dividend1, divisor1, remainder1)
      Console.WriteLine("BigInteger.DivRem({0}, {1}) = {2}", 
                        dividend1, divisor1, divRem1)                    
      If remainder1.Equals(divRem1) Then Console.WriteLine("The remainders are equal.")
      Console.WriteLine()
      
      BigInteger.DivRem(dividend2, divisor2, divRem2)
      Console.WriteLine("BigInteger.Remainder({0}, {1}) = {2}", 
                        dividend2, divisor2, remainder2)
      Console.WriteLine("BigInteger.DivRem({0}, {1}) = {2}", 
                        dividend2, divisor2, divRem2)                    
      If remainder2.Equals(divRem2) Then Console.WriteLine("The remainders are equal.")
      Console.WriteLine()
   End Sub
End Module
' The example displays the following output:
'    BigInteger.Remainder(7.8463771692333509522426190271E+56, 2147483647) = 1
'    BigInteger.DivRem(7.8463771692333509522426190271E+56, 2147483647) = 1
'    The remainders are equal.
'    
'    BigInteger.Remainder(-7.8463771692333509522426190271E+56, -2147483647) = -1
'    BigInteger.DivRem(-7.8463771692333509522426190271E+56, -2147483647) = -1
'    The remainders are equal.

Комментарии

Знак остатка — это знак dividend параметра.The sign of the remainder is the sign of the dividend parameter.

Remainder Метод реализуется для языков, которые не поддерживают пользовательские операторы.The Remainder method is implemented for languages that do not support custom operators. Его поведение идентично поведению деления с помощью оператора модуля.Its behavior is identical to division using the modulus operator.

При необходимости метод автоматически выполняет неявное преобразование других целочисленных типов в BigInteger объекты перед выполнением операции модуля.If necessary, the method automatically performs implicit conversion of other integral types to BigInteger objects before it performs the modulus operation.

Применяется к

Дополнительно